Based on the family the graph below belongs to, which equation could represent the graph?
On a coordinate plane, a curve starts at (0, 2) and curves up and to the right in quadrant 1.
y = 2 Superscript x Baseline 3
y = log (2 x) + 3
y = 2 x squared + 2
y = StartFraction 1 Over 2 x EndFraction + 2
Answer:
Second option [tex]y=\text{log}(2\text{x})+3[/tex]
Solution:
Based on the family of graphs shown in the attached file, the equation could represent the graph is [tex]y=\text{log}(2\text{x})+3[/tex]
This graph is the graph of the function [tex]y=\text{log}(\text{x})[/tex] stretched horizontally by a factor of 2 and translated 3 units upward.
Answer:
B
Step-by-step explanation:
Edge 2023
Find the measure of the arc. Assume that lines which appear to be tangent are tangent
Answer:
190°
Step-by-step explanation:
56 = (1/2)(x - 78)
112 = x - 78
190 = x
x = 190
Answer: 190°
I'm a pretty sure that the answer is 190°, Hope this helps (:
Sue deposited $1,500 into two different accounts.
- She deposited $600 into an account that pays 7.5% simple interest.
- She deposited $900 into an account that pays 6% compounded annually.
If Sue does not deposit additional money into the accounts and she doesn't withdraw any
money from the accounts, which is closest to the total balance she will have in the two
accounts at the end of 5 years?
F $2,029.40
G $2,005.68
H $529.40
J $1,995.00
The total balance that Sue will have in the two accounts after 5 years can be calculated as follows:
Balance of the first account with simple interest:
FV = P(1 + rt)
FV = $600(1 + 0.075 x 5)
FV = $825
Balance of the second account with compounded interest:
FV = P(1 + r)^n
FV = $900(1 + 0.06)^5
FV = $1,286.87
Total balance = $825 + $1,286.87
Total balance = $2,111.87
The closest answer choice to this amount is F) $2,029.40, which is only off by a small margin. Therefore, the answer is F) $2,029.40.
i already have the chart filled out i just need some help with the conclusion
.
.chart:
Location
Timeline
Human Impact Measurements
Recommendation to Decrease Human Impact
New York City
Water Pollution
(in parts per million)
50 years ago
625ppm
create gardens on all of the rooftops
Present Day
893ppm
Future Development Impact
843ppm
Amazon Rainforest
Levels of CO2
(in parts per million)
50 years ago
CO2 levels: 318 ppm
Limit the amount of timber that can be removed per year
Present Day
CO2 levels: 402 ppm
Future Development Impact
CO2 levels: 378 ppm
Sahara Desert
Loss of land by Erosion
(in meters)
50 years ago
Erosion: 1.2 meters
Build better enclosures to decrease overgrazing by livestock
Present Day
Erosion: 3.5 meters
Future Development Impact
Erosion: 2.6 meters
.Conclusion:
Your conclusion will include a summary of the lab results and an interpretation of the results. Please write in complete sentences.
.
When recommending solutions to decrease human impact, which location were you able to make the greatest positive impact? Please explain your selection by using data from the simulation.
.
What recommendations would you give to your local community to help to decrease the local effects of human impact on the environment? List 2 recommendations and how they will positively impact your community.
.
What recommendations would you give to the global governments to help decrease the global effects of human impact on the environment? List 2 recommendations and how they will positively impact our planet.
tell me if i missed anything! and please give me good answers!
This report highlights the impact of human activity on three different locations: New York City, the Amazon Rainforest, and the Sahara Desert. The measurements were taken 50 years ago, in the present day, and the predicted future development impact.
## New York City
Water pollution in parts per million (ppm) was measured in New York City. Fifty years ago, the water pollution was 625ppm, and presently, it has increased to 893ppm. The predicted future development impact is 843ppm. To decrease human impact on this location, it is recommended to create gardens on all of the rooftops. The plants will help absorb some of the pollutants and reduce runoff into waterways.
## Amazon Rainforest
CO2 levels in parts per million (ppm) were measured in the Amazon Rainforest. Fifty years ago, the CO2 levels were 318ppm, and presently, it has increased to 402ppm. The predicted future development impact is 378ppm. To decrease human impact on this location, it is recommended to limit the amount of timber that can be removed per year. The Amazon Rainforest is often referred to as the "lungs of the planet" due to its ability to absorb carbon dioxide and produce oxygen. By limiting deforestation, the amount of carbon dioxide released into the atmosphere will decrease, and the rainforest will continue to produce oxygen, benefiting both the local and global environment.
## Sahara Desert
The loss of land by erosion in meters was measured in the Sahara Desert. Fifty years ago, the erosion was 1.2 meters, and presently, it has increased to 3.5 meters. The predicted future development impact is 2.6 meters. To decrease human impact on this location, it is recommended to build better enclosures to decrease overgrazing by livestock. Overgrazing leads to soil compaction, which makes it difficult for vegetation to grow and prevents the soil from holding water. By implementing better enclosures, the livestock will be limited to a smaller area, allowing the vegetation to recover and hold the soil in place.
## Conclusion
In conclusion, all three locations experienced an increase in human impact over the years. By analyzing the data, the location that could benefit the most from decreasing human impact is the Amazon Rainforest. Limiting the amount of timber that can be removed per year will have a positive impact on this location. However, it is important to continue monitoring all three locations to ensure that the human impact is decreasing and not increasing.
## Recommendations for Local Communities
To decrease the local effects of human impact on the environment, two recommendations are:
1. Reduce the use of single-use plastics, such as straws and bags, to decrease pollution. Single-use plastics are a major source of pollution in our oceans, and by reducing our reliance on them, we can help reduce the amount of plastic that ends up in our waterways.
2. Plant more trees and vegetation to increase the amount of oxygen in the air. Trees and plants produce oxygen through photosynthesis, which helps clean the air we breathe. By planting more trees and vegetation in our communities, we can help reduce the amount of pollution in the air and create a healthier environment for ourselves and future generations.
## Recommendations for Global Governments
To decrease the global effects of human impact on the environment, two recommendations are:
1. Invest in renewable energy sources, such as solar and wind power, to decrease the use of fossil fuels. Fossil fuels are a major contributor to greenhouse gas emissions, which are responsible for climate change. By investing in renewable energy sources, we can decrease our reliance on fossil fuels and reduce our carbon footprint.
2. Implement policies to decrease deforestation and promote reforestation to decrease the loss of wildlife habitats and increase the amount of oxygen in the air. Deforestation is a major contributor to climate change, as it releases carbon dioxide into the atmosphere and reduces the amount of oxygen produced by trees. By implementing policies to decrease deforestation and promote reforestation, we can help mitigate the effects of climate change and create a healthier environment for all living beings.
Can you solve this question?
a) find the derivative=?
b) find the derivative=?
A. the derivative of y = log_a(x) is: y' = log_a(x) / (x ln(a))
B. the derivative of y = log_8(x) is: y' = 1 / (x ln(8 ln(10)))
a) Using the chain rule and the given identity, we have:
y = log_a(x)
ln(y) = ln(log_a(x))
ln(y) = ln(x) / ln(a)
y' / y = 1 / (x ln(a))
Multiplying both sides by y and simplifying, we get:
y' = y / (x ln(a))
y' = log_a(x) / (x ln(a))
Therefore, the derivative of y = log_a(x) is: y' = log_a(x) / (x ln(a))
b) Using the change of base formula for logarithms, we have:
y = log_8(x)
y = log(x) / log(8)
Using the chain rule, we have:
y' = (1 / (x ln(10))) * (1 / ln(8)) * d/dx [log(x)]
Using the chain rule for the natural logarithm, we have:
y' = (1 / (x ln(10))) * (1 / ln(8)) * (1/x)
Simplifying, we get:
y' = 1 / (x ln(8 ln(10)))
Therefore, the derivative of y = log_8(x) is:
y' = 1 / (x ln(8 ln(10)))
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Determine if the information given represents a liner,exponetial, or quadratic function and explain why.
Answer:
linear
Step-by-step explanation:
this is a linear function!
linear functions follow y = mx+b, where m is the slope and b is the y-intercept
let's write our y = mx+b equation
for each value that x increases, y increases by DOUBLE that amount. slope is y/x, so since y increases by 2 and x increases by 1, the slope is 2/1 which is 2.
the y-intercept is where the line passes the x axis, or when x is 0. in this table, it gives you your y-intercept, which is -6
your equation is y=2x+(-6); which simplified to y=2x-6
if you plug in the y and x values, you'll get the same thing. i hope this helped!
Pls help its unit rates n stuff
Answer:
Step-by-step explanation:
1. u would do 315/15 bc y/x=k
2. u would do 81/9
3. u would do 56/2
so basically for the next ones just do the money divided by oz to find the unit rate. Note always do y/x y is the dependent variable and x is the independent variable
Draw the image of ABC under a dilation whose center is C and scale factor is 2.
To draw the image of ABC under a dilation whose center is C and scale factor is 2, there are several steps by which we can draw the triangle.
What are the steps to draw the image ?Draw the original ABC triangle. A, B, and C are the vertices.
Make a point C' that is twice as far away from C as any other point on the triangle ABC. Draw a ray from C through any vertex of the triangle to accomplish this. (say, B). Then, double the length of the ray to find point C'.
Connect point C' to each vertex of the triangle with lines. A' and B' are the points where these lines intersect the original triangle.
Your new triangle A'B'C' is the dilation of ABC with centre C and scale factor 2.
The sides of the new triangle A'B'C' are twice as long as the sides of the original triangle ABC, and the angle between any two corresponding sides in both triangles is the same.
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What is the equation of the line that passes through the point (-3,4)(−3,4) and has a slope of -2−2?
Answer:
slope intercept form= y=2x+2
point form= y+4=2*(x+3)
Step-by-step explanation:
Answer y = -2x -2 is your equation of the line crossing those points
Step by step
To find your equation of the line, use slope (-2) and the points (-3, 4) and point slope formula y- y1 = m (x - x1)
y - 4 = -2 ( x - -3)
Simplify
y - 4 = -2x -6
Add 4 to each side to isolate y
y -4 +4 = -2x -6 +4
Simplify
y = -2x -2 is your equation of the line crossing those points
A merchant mixed 12 lb of a cinnamon tea with 3 lb of spice tea. The 15-pound mixture cost $39. A second mixture included 16 lb of the cinnamon tea and 6 lb of the spice tea. The 22-pound mixture cost $58. Find the
cost per pound of the cinnamon tea and of the spice tea.
cinnamon
spice
Answer:
Step-by-step explanation:
Let x be the cost per pound of the cinnamon tea and y be the cost per pound of the spice tea.
From the first mixture, we have:
12x + 3y = 39
From the second mixture, we have:
16x + 6y = 58
We can solve this system of equations by elimination. Multiplying the first equation by 2 and subtracting it from the second equation gives:
16x + 6y = 58
(24x + 6y = 78)
-8x = -20
Dividing both sides by -8 gives:
x = 2.5
Substituting this value of x into the first equation, we get:
12(2.5) + 3y = 39
Simplifying, we get:
30 + 3y = 39
Subtracting 30 from both sides gives:
3y = 9
Dividing both sides by 3 gives:
y = 3
Therefore, the cost per pound of the cinnamon tea is $2.50 and the cost per pound of the spice tea is $3.
A fair coin is tossed 7 times. Compute the probability of tossing 7 heads in a row.
Enter your response as a reduced fraction.
Answer:
1/128
Step-by-step explanation:
The probability of tossing a head is 1/2.
Each toss is an independent event.
We toss 7 times and get a head each time.
1/2 * 1/2* 1/2* 1/2* 1/2* 1/2* 1/2
1/128
15 points! please help me out!
Answer: 260 ft^2
Step-by-step explanation:
Find the area of the triangle: 0.5*height*base = 0.5*10*20 = 100 ft^2
Find the area of the rectangle: 20*8 = 160 ft^2
Add them together: 160+100 = 260 ft^2
Solve for x. Round to the nearest tenth.
x =
Find the value of x. Then tell whether the side lengths for a pythagorean triple
The value of x, given the measurements of the other sides of the triangle, would be 8.
The side lengths of the triangle form a Pythagorean triple.
How to find the value of x in the triangle ?To determine if the side lengths form a Pythagorean triple, we need to apply the Pythagorean theorem.
Using the Pythagorean theorem, we get:
6^2 + x^2 = 10^2
36 + x^2 = 100
x^2 = 100 - 36
x^2 = 64
x = 8
To determine if the side lengths form a Pythagorean triple, we need to check if the Pythagorean theorem holds true. Plugging in the values, we get:
6^2 + 8^2 = 10^2
36 + 64 = 100
100 = 100
The theorem holds true so this is indeed a Pythagorean triple.
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The full question is:
Find the value of x. Then tell whether the side lengths form a Pythagorean triple.
10, 6
Find the probability of exactly 3 successes
in 6 trials of a binomial experiment in
which the probability of success is 75%.
P = [?]%
The prοbability οf exactly 3 successes in 6 trials οf a binοmial experiment with a prοbability οf success οf 75% is 31.1%, rοunded tο the nearest tenth οf a percent.
What is the prοbability?Prοbability is the study οf the chances οf οccurrence οf a result, which are οbtained by the ratiο between favοrable cases and pοssible cases.
Tο find the prοbability οf exactly 3 successes in 6 trials οf a binοmial experiment, we use the fοrmula:
The prοbability οf r successes in n trials is [tex]\rm _nC_r(p)^r(q)^{n-r[/tex], where p is the prοbability οf success οn a given trial and q = 1-p.
In this prοblem, n = 6, r = 3, p = q = 0.75
Sο, P(3 successes in 6 trials) = [tex]\rm _6C_3(0.75)^3(0.75)^3[/tex] = 0.13184 ≈ 13.2%
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Danny is opening a savings account with an initial deposit of 45$. He saves $3 per day
The equation of the line is slope intercept form is y = 3x + 45.
What is a graph?
The set of ordered pairings (x, y) where f(x) = y makes up the graph of a function.
These pairs are Cartesian coordinates of points in two-dimensional space and so constitute a subset of this plane in the general case when f(x) are real values.
Given, Danny is opening a savings account with an initial deposit of $45 and he saves $3 per day.
Let y be the total amount he saves and x is the no. of days.
As he starts with $45 deposit it'll be added as a constant.
∴ The equation of the required line is y = 3x + 45.
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Hey can someone please help me with this math question!! As soon as possible!
The values of x that could make the triangle into different types of triangles are:
Right triangle - 10 Acute triangle - 9Obtuse triangle - 11How to find the values of x ?For a triangle to be valid, the sum of the lengths of any two sides must be greater than the length of the third side.
Right Triangle:
A triangle is a right triangle if it satisfies the Pythagorean theorem: a² + b² = c², where c is the longest side (hypotenuse).
6² + 8² = x²
36 + 64 = x²
100 = x²
x = 10
Acute Triangle:
A triangle is acute if the sum of the squares of the two shorter sides is greater than the square of the longest side. Since we already know that the right triangle has x = 10, we can choose a value for x that is less than 10 to form an acute triangle.
Let's take x = 9:
6² + 8² > 9²
36 + 64 > 81
100 > 81
Obtuse Triangle:
A triangle is obtuse if the sum of the squares of the two shorter sides is less than the square of the longest side. We can choose a value for x that is greater than 10 to form an obtuse triangle.
Let's take x = 11:
6² + 8² < 11²
36 + 64 < 121
100 < 121
The possible values of x for each triangle type are:
Right Triangle: x = 10
Acute Triangle: x = 9
Obtuse Triangle: x = 11
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Determine whether the statement is always true, sometimes true, or never true. Give examples. Both sides of an equation can be multiplied by the same number without changing the solution of the equation. A number can be added to both sides of an equation changing the solution of the equation.
The solution of the equation is x = 2. If we had multiplied both sides by a different number, such as 3 or -4.
What is solution of the equation ?
The solution of an equation is the value(s) of the variable(s) that make the equation a true statement. In other words, it is the value(s) that satisfy the equation.
For example, consider the equation 3x + 4 = 13. To find the solution, we need to determine the value of x that makes the equation true. the solution of the equation 3x + 4 = 13 is x = 3.
According to the question:
The first statement, "Both sides of an equation can be multiplied by the same number without changing the solution of the equation" is always true.
Example: Consider the equation 3x = 6. If we multiply both sides of this equation by 2, we get:
2 * 3x = 2 * 6
6x = 12
The solution of the equation is x = 2. If we had multiplied both sides by a different number, such as 3 or -4, we would still get the same solution.
The second statement, "A number can be added to both sides of an equation changing the solution of the equation" is sometimes true.
Example: Consider the equation 2x = 4. If we add 3 to both sides of the equation, we get:
2x + 3 = 4 + 3
2x + 3 = 7
The solution of the equation is x = 2.5. Adding 3 to both sides did not change the solution.
However, if we add a number that is equal to or related to the variable, the solution will change. For example, if we add x to both sides of the equation 2x = 4, we get:
2x + x = 4 + x
3x = 4 + x
The solution of the equation is x = 4/2 = 2, which is different from the previous solution of x = 2. Therefore, the statement "A number can be added to both sides of an equation changing the solution of the equation" is sometimes true, depending on the number being added.
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A plane flies horizontally at an altitude of 5 km and passes directly over a tracking telescope on the ground. When the angle of elevation is /6, this angle is decreasing at a rate of /3 rad/min.
How fast is the plane traveling (in km/min) at that time? (Round your answer to two decimal places.)
Answer:
# rad u cant take 67 from it its going 35 mps
Step-by-step explanation:
Find The surface area of tHe triangle prism 3,4,4,5
To find the surface area of a triangular prism with side lengths 3, 4, 4, and 5, we can use the formula:
Surface Area = 2(Area of the base) + (Perimeter of the base) x (Height of the prism)
First, let's find the area of the base. Since the base is a triangle, we can use the formula for the area of a triangle:
Area of base = (1/2) x base x height
The base of the triangle is the side with length 5, and the height can be found using the Pythagorean theorem:
height^2 = 4^2 - (3/2)^2
height^2 = 16 - 2.25
height^2 = 13.75
height = sqrt(13.75)
So the area of the base is:
Area of base = (1/2) x 5 x sqrt(13.75)
Area of base = 10.825
Next, let's find the perimeter of the base. Since the base is a triangle with side lengths 3, 4, and 5, the perimeter is:
Perimeter of base = 3 + 4 + 5
Perimeter of base = 12
Finally, let's find the height of the prism. We can use the Pythagorean theorem again:
height^2 = 4^2 - (3/2)^2
height^2 = 16 - 2.25
height^2 = 13.75
height = sqrt(13.75)
So the height of the prism is also sqrt(13.75).
Now we can plug these values into the formula for the surface area:
Surface Area = 2(Area of the base) + (Perimeter of the base) x (Height of the prism)
Surface Area = 2(10.825) + 12 x sqrt(13.75)
Surface Area = 21.65 + 41.4
Surface Area = 63.05
Therefore, the surface area of the triangular prism with side lengths 3, 4, 4, and 5 is 63.05 square units.
Each side of a regular hexagon measures 20 inches. What is the exact area of the hexagon?
Answer:
1039.23 square inches
Step-by-step explanation:
a = 20 inches
[tex]\sf \boxed{\text{\bf Area of regular hexagon = $\dfrac{3\sqrt{3}}{2}a^2$}}[/tex]
[tex]= \dfrac{3\sqrt{3}}{2}*20*20\\\\= 3\sqrt{3}*200\\\\= 1039.23 \ inches^2[/tex]
WANT POINTS??
The graph shows g(x) = x2 − 8x + 15.
graph of parabola falling from the left, passing through 2 comma 3 to about 4 comma negative 1, and rising to the right, passing through 6 comma 3
What are the x-intercepts of g(x)?
(0, 3) and (0, 5)
(0, 4) and (0, 5)
(3, 0) and (5, 0)
(4, 0) and (5, 0)
Answer:
(3, 0) and (5, 0)
Step-by-step explanation:
Parabola equation is
g(x) = x²- 8x + 15
x-intercepts are the x-values when y = 0
Solve for x at g(x)=
==> x² - 8x + 15 = 0
This is a quadratic equation which has two solutions
Factoring x² - 8x + 15 gives (x - 3)(x - 5) which makes the quadratic equation
(x - 3)(x - 5) = 0
==> x - 3 = 0 giving x = 3 as one solution and x - 5 = 0 giving x = 5 as the other solution
At both intercepts, y = 0
So the correct answer is
(3, 0) and (5, 0)
You are paid 1.5 times your normal hourly rate for each hour you work over 32 hours in a week. You work 33 hours this week and earn 545.38 . What is your normal hourly rate?
The normal hourly rate is 16.28 units
What is unit rate?
A unit rate is the cost for only one of anything. This is expressed as a ratio with a denominator of 1. For instance, if you covered 70 yards in 10 seconds, you did so at an average speed of 7 yards per second. Although both of the ratios—70 yards in 10 seconds and 7 yards in one second—are rates, only the latter is a unit rate.
Let r be your rate you get paid per hour normally.
Total = 33 hours
Extra hour = 33 -32 = 1 hour
We have
32r + 1.5r = 545.38
=> 33.5r = 545.38
=> r = 545.38 /33.5 = 16.28
The normal hourly rate is 16.28 units
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CAN SOMEONE HELP WITH THIS QUESTION?
The red car is actually traveling at a speed of 45 feet per second.
What is the concept of related rates and how does it apply to this problem?
Related rates is a calculus topic that deals with finding the rate of change of one variable with respect to another variable. In this problem, the distance between the police car and the red car is decreasing at a constant rate, and we need to find the speed of the red car. The key is to set up an equation that relates the variables involved and differentiate it with respect to time, using the chain rule. This allows us to find the rate of change of the variables with respect to time, and then solve for the desired rate of change.
Calculating the actual speed of the red car :
Let's call the distance between the police car and the red car "d" and the speed of the red car "v". We want to find [tex]dv/dt[/tex], the rate of change of v with respect to time.
From the problem statement, we know that [tex]dd/dt = -75[/tex] feet per second, since the distance between the cars is decreasing at a rate of 75 feet per second.
To find [tex]dv/dt[/tex], we need to use the Pythagorean theorem to relate d and v. We have a right triangle with legs of length 30 and 160, and hypotenuse d. Using the Pythagorean theorem, we get:
[tex]d^2 = 30^2 + 160^2[/tex]
[tex]d= \sqrt{(30^2 + 160^2)} =161.24[/tex] feet
Now we take the derivative of both sides of this equation with respect to time:
[tex]2\times\d(dd/dt) = 0.5\times(2d)\times(dv/dt)[/tex]
[tex]dd/dt = -75[/tex]
[tex]d = 161.24[/tex]
Substituting these values, we get:
[tex]2(161.24)(-75) = 0.5(2(161.24))(dv/dt)[/tex]
Simplifying and solving for [tex]dv/dt,[/tex] we get:
[tex]dv/dt = (-2)(161.24)(-75)/(2(161.24))[/tex]
[tex]dv/dt = 45[/tex] feet per second
Therefore, the red car is actually traveling at a speed of 45 feet per second.
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Justin is standing on a bridge, and his eye level is 28 feet above the surface of the water. If he spots a fish on the surface of the water 75 feet downstream from the point he is standing above, what is the angle of depression from his eye level to the fish?
Assuming that the 75 feet measurement is the distance from where Justin is at the ground level to the fish (and not the diagonal distance from his location to the fish), the angle is given by arctan(28/75) = 28.472 degrees. This is probably the right answer.
If the 75 feet measurement is the diagonal distance, the angle is arcsin(28/75) = 21.921 degrees.
We know this from a relation of right triangle trigonometry. Tell me if you need more clarification.
2 logx 2 + logx 6 = 2
I really need this answer on properties of logarithms: practice
Answer:
Step-by-step explanation:
Simplify the expressionApply the logarithm power identityApply the logarithm product identitySimplify the expression2Exponentiate both sides
log10(4x8)=2log10(48)=2
48=102
x=258=258√
I have a barn that is a regular hexagon, as shown. Each side of the barn is 100 feet long. I tether my burro to point A with a 150 foot rope. Find the area of the region in which my burro can graze. Round your answer to nearest foot squared.
The area of the region in which the burro can graze will be 833 pi square feet.
What is the value of the area?Each interior vertex angle of a regular hexagon is (n - 2)·180°/n = (6 - 2)·180°o/6 = 120°
I'll break up the area into three sections.
There is one major section, going 150' along one side in a circular arc to 150' along the adjacent side.
Since the interior angle is 120°, the exterior angle will be 240°.
The area of this section will be: (240°/360°)·pi·radius2 = (2/3)·pi·1502 = 15,000 pi
Then, on each end, around the corner of the barn, the goat can go in a circular arc with radius = 50'.
This angle will be 60°, or one-sixth or a circle.
The area of each section will be (1/6)·pi·502 = 416 2/3 pi
Total area: 15,000 pi + 416 2/3 pi + 416 2/3 pi = 833 1/3 pi square feet.
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3/2 equals 4x x=
?????
Answer:
0.375
Step-by-step explanation:
3/2 equals 1 and a half, and 1 and a half divided by 4 will get you 0.325
Answer:
4x - 2 = 3x + 1. Solution We substitute the value 3 for x in the equation and see if the left-hand member equals the right-hand member. 4(3) - 2 = 3(3) + 1.
Math
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◄) Turner plays running back on his middle school football team. He likes to predict how
many yards he will run the ball in each game. In last night's game, Turner ran for 50 yards.
He had predicted he'd run for 40% less than that. How many yards had Turner predicted he
would run for?
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Turner had predicted he would run for 30 yards in the game.
Define percentageIn terms of a number out of 100, a % is a means to express a proportion or a fraction. It is represented by the symbol "%". For example, if 25 out of 100 students in a class are girls, we can say that the percentage of girls in the class is 25%.
To find out how many yards Turner predicted he would run for, we can use the following steps:
Convert the percentage reduction to a decimal: 40% = 0.4Subtract the reduction from 1 to find the percentage of the original amount: 1 - 0.4 = 0.6Multiply the percentage by the actual amount to find the predicted amount: 0.6 x 50 = 30Therefore, Turner had predicted he would run for 30 yards in the game.
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3 Mathematical Habit 3 Construct viable arguments
The diagram shows a rectangular prism. The areas of the faces a
6 square centimeters, 10 square centimeters, and 15 square centim
What is the volume of the rectangular prism?
15 cm²
6 cm²
10 cm²
As a result, the rectangular prism has a volume of 1 cubic centimeter.
What is the simple definition of volume?The volume of an object is the area enclosed inside its three-dimensional boundaries. It is referred to as an object's capability on occasion.
We must multiply the rectangular prism's length, width, and height to determine its volume. Although we don't directly know these values, we can use the regions of the faces to locate them.
Let's use the letters l, w, and h to denote the prism's length, breadth, and height, respectively. The area of a top and bottom sides is thus determined to be lw = 10 cm², the front and rear faces are lh = 15 cm², and the left and right sides are wh = 6 cm².
These equations can be used to solve for every variable using the following descriptions of the other variables:
l = 10/w
h = 15/l
w = 6/h
When we add these expressions to the volume formula, we obtain:
V = lwh = (10/w)(6/h)(15/l) = 900/whl = 900/(6×10×15) = 1 cm³
As a result, the rectangular prism has a volume of 1 cubic centimeter.
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