The car moves 50 km while accelerating.
What is acceleration?
In mechanics, speed increase is the pace of progress of the speed of an article regarding time. Speed increases are vector amounts. The direction of an item's speed increase is given by the direction of the net power following up on that article. For instance, when a vehicle begins from a halt (zero speed, in an inertial casing of reference) and goes in an orderly fashion at speeding up, it is advancing toward movement. In the event that the vehicle turns, a speed increase happens toward the new bearing and changes its movement vector. The speed increase of the vehicle in its momentum bearing of movement is known as a straight (or distracting during roundabout movements) speed increase, the response to which the travelers on board insight as a drive pushing them once again into their seats. While taking a different path, the affecting speed increases.
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a rocket was launched into the air from a podium 6 feet off the ground. the rocket path is represented by the equation h(t)
The average rate of change of height from the initial launch to the maximum height is 180 feet.
The given function is
[tex]h(t) = -16t^{2} +120t+6[/tex]
The average rate of change of h(t) from t=a to t=b is given by:
[tex]\frac{h(b)-h(a)}{b-a}[/tex]
Vertical Velocity will be zero at maximum height. To find maximum height we differentiate the equation to get an equation for the velocity and set it to zero.
On differentiating we get,
h'(t) = -16(2)t + 120
h'(t) = -32t + 120
now equating to zero we get
t = 3.75 s
This is the time at which the rocket reaches maximum height.
The initial launch occurs at t = 0
substituting it in the original equation we get
[tex]h(t)[/tex] = [tex]-16(0)^{2}+120(0)+6[/tex]
[tex]h(t) = 6[/tex]
The average rate of change from the initial launch to the maximum height is:
[tex]\frac{h(3.75)-h(0)}{3.75-0}[/tex]
= [tex]\frac{681-6}{3.75}[/tex]
= 180
Hence the average rate of change from the initial launch to the maximum height is 180 feet.
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Suppose you are facing a tall makeup mirror on a vertical wall. Fluorescent tubes framing the mirror carry a clockwise electric current.(i) What is the direction of the magnetic field created by that current at the center of the mirror? (a) left (b) right (c) horizontally toward you (d) horizontally away from you (e) no direction because the field has zero magnitude
The direction of the field the current creates at a point on the wall outside the frame to the right is horizontally towards you.
If the direction of a magnetic field around a vertical electrical wire is counter clockwise, what direction is the electrical current moving?The current will flow from the bottom of the wire to the top if the magnetic field around a vertical electrical wire is counter clockwise in direction. A magnetic field, a vector field that describes the magnetic influence on moving electric charges, electric currents, and magnetic materials. When a charge moves through a magnetic field, a force that is perpendicular to both its own velocity and the magnetic field operates on it.
A permanent magnet's magnetic field pulls on ferromagnetic materials like iron and draws or repels other magnets. Since the direction and strength of a magnetic field can vary depending on the location, it can be mathematically described by a function that gives each point a vector.
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A ray of light is incident at an angle of 30° on the angle through which the ray is minimally a glass prism of refractive index 1.5. Calculate deviated in the prism. (The medium surrounding the prism is air)
Typically, the "refracted angle" is used to refer to the "angle of deviation."
Snell's Law is simply applied in this case.
Since n1sin1 = n2sin2,
The incidence angle is 1
The refracted angle is 2
The appropriate indices of refraction are n1 and n2.
the standard value for air, n1, is 1.
n2 = 1.5
What is the first rule of Snell?As a result, the refractive indices of the two media may be related through the angle associated with incidence and refraction. The incident ray, the refracted ray, and the normal ray are all said to be on the same plane.
Snell's Law is particularly significant for optical technologies like fibre optics. According to Snell's Law, the refractive indices of the materials at the contact are proportional to the ratio of the sine of the angles of incidence and transmission.
The extension is obeyed by the e-ray Because the refractive index of an e-ray changes with the angle between the wave vector and optical axis, Snell's law applies. It is important to consider e-ray propagation in the uniaxial crystal.
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A nonconducting ring of radius 10.0 cm is uniformly charged with a total positive charge 10.0μC. The ring rotates at a constant angular speed 20.0 rad/ s about an axis through its center, perpendicular to the plane of the ring. What is the magnitude of the magnetic field on the axis of the ring 5.00 cm from its center?
The magnitude of the magnetic field on the axis of the ring 5 cm from its center is 143 pT.
The radius of the nonconducting ring is R = 10 cm.
The ring is uniformly charged q = 10 μC.
The angular speed of the ring, ω = 20 rad/s
The ring is x = 5 cm from the center of the ring.
Now,
R = 10 cm = 0.1 m
q = 10.0 μC = 10 × 10⁻⁶ C
x = 5 cm = 0.05 m
The magnetic field on the axis of a current loop is given as:
[tex]B =\frac{\mu_{0}IR^{2}}{4 \pi(x^{2}+R^{2})^{\frac{3}{2} }}[/tex]
Now, [tex]I = \frac{q}{\frac{2 \pi}{\omega} }[/tex]
So, the magnitude of the magnetic field which is directed away from the center is:
[tex]B =\frac{\mu_{0} \omega qR^{2}}{4 \pi(x^{2}+R^{2})^{\frac{3}{2} }}[/tex]
[tex]B = \frac{\mu_{0} \times(200) \times (10 \times 10^{-6}) \times (0.1)^{2}}{4 \pi((0.05)^{2}+(0.1)^{2})^\frac{3}{2} }[/tex]
B = 1.43 × 10⁻¹⁰ T
B = 143 pT
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Pressure is a derived quantity with a formula suxh as Force per unit area what do you think which base quantities will be involved to form this derived quantity.
Answer:
you can find answer in this
Explanation:
https://physics.nist.gov/cuu/Units/units.html
to determine your line of , you would need to know the angle your location (line) makes with the equatorial plane at earth's center.
To determine your line of latitude , you would need to know the angle your location (line) makes with the equatorial plane at earth's center.
What is Line of latitude?This is also referred to as parallels and it is defined as the imaginary lines that divide the Earth. They run from east to west and are used to specify the north and south sides of the Earth.
To determine the line of latitude , it is imperative to know the angle your location (line) makes with the equatorial plane at earth's center which is therefore the reason why it was chosen as the most appropriate choice.
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A car increases its speed from 30 km/h to 60 km/h in 5 seconds. Its acceleration s (a) 1.66 m/s² (b) 5 km/h² (c) 16.6 km/h² (d) 5m/s²
Answer: 6 km/h²
Explanation:
Final Speed= 60 km/h
Initial Speed= 30 km/h
Time= 5 sec
Now,
60= 30 + Acceleration*5
⇒Acceleration = 6 km/h²
as a ferromagnetic object gets closer to the magnet, the magnetic force pulling the object decreases exponentially.
Ferromagnetic substance are strongly attractive to a magnet.
Ferromagnetic material are those materials which shows magnetic property also in the absence of external magnetic field
It's Atom have permanent dipole moment present in domains.
These are used in the industry.
example of ferromagnetic substance are nickel, iron ,Cobalt etc
When ferromagnetic object is placed in a magnetic field the domains will oriented in the direction of magnetic field even after the removal of applied magnetic field it will not change the shows that it become a permanent magnet.
Magnetic force on ferromagnetic object depends on the strength of the object and also size of the object
The given question is incomplete. The complete question is.
as a ferromagnetic object gets closer to the magnet, the magnetic force pulling the object decreases exponentially
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A cubical surface surrounds a point charge q . Describe what happens to the total flux through the surface if (e) the charge is moved outside the surface.
Gauss law explains that the electric flux is defined as the electric field multiplied by the area of the surface in a plane perpendicular to the field.
Mathematically,
Φ=Q ϵo
Where;
Q is enclosed charge
ϵo is the permittivity of the free space
In the case where the charge is moved outside the surface, the flux in the electric field becomes zero because the enclosed charge becomes zero. Thus, the electric field will change due to the movement outside the surface. The only instances where flux is kept constant are when it is moved within the surface or the enclosing object is changed.
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Imagine that the entire Sun, of mass MS , collapses to a sphere of radius Rg such that the work required to remove a small mass m from the surface would be equal to its rest energy mc² . This radius is called the gravitational radius for the Sun.
(b) Find a numerical value for Rg .
The value of radius (Rg) is 1.475km .
Given,
The mass of the sun = Ms
Radius of the sphere = Rg
work required to remove a small mass (m) from the surface would be equal to its rest energy mc^2 .
The given radius (Rg) is called the gravitational radius for the sun.
We know,
Gravitational potential energy or work done
= Ug = GMs×m/Rg
the given rest energy = E =mc^2
As, it is given that the required work or energy is equal to rest energy,
thus, Ug=E
GMs×m/Rg = mc^2
Rg = GMs/c^2
We know,
G = 6.67×10^-11 N. m^2/kg^2
Ms = 1.99×10^30 kg
c = 3×10^8 m/s
Thus, Rg = 6.67×10^-11 × 1.99×10^30 / (3×10^8)^2
Rg = (13.2733×10^19)/(9×10^16 )
Rg = 1.4748×10^3 m
Rg = 1.475km
Hence, The value of radius (Rg) is 1.475km .
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A ball is thrown up in the air and then caught 10 seconds later. How high did it go and what was the initial speed up? (6)
Answer:
high=125m
speed up=50m s-¹
Explanation:
consider acceleration due to gravity = 10m s-²
upward as positive
in t=5s
ball rest momentarily velocity=0
you can know this by drawing s-t graph
consider the upward movement t=0-5s
we now have v=0 t=5 a= -10 and need find u
so use a=[v-u]/t
-10=[0-u]/5
-50=-u
u=50 ms-¹
then let find the displacement
s = (v+u)t*1/2
s= 50*5*1/2
s=125m
Find the net electric flux through (c) What can you conclude about the charges, if any, inside the cylindrical surface?
The net flux is positive so the charge in the cylinder is positive To be a uniform field, the field lines mug originate from a plane of charge The net charge inside the cylinder is positive and is distributed on a plane parallel to the ends of the cylinder.
Electric flux, property of an electric field that may be thought of as the number of electric lines of force (or electric field lines) that intersect a given area. Electric field lines are considered to originate on positive electric charges and to terminate on negative charges.
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Plasma is one of the fundamental states of matter and consists of a:
A) liquid at high temperature
B) totally or partially ionized gas, electrically neutral
C) partially ionized gas, with electric charge
D) partially ionized liquid
E) partially ionized liquid, electrically neutral
Answer:
a
Explanation:
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What creates a magnetic field? More than one answer may be correct. (a) a stationary object with electric charge (b) a moving object with electric charge (c) a stationary conductor carrying electric current (d) a difference in electric potential (e) a charged capacitor disconnected from a battery and at rest Note: In Chapter 34, we will see that a changing electric field also creates a magnetic field
Electricity can be applied to a wire to produce a magnetic field. Charged particles that are in motion produce all magnetic fields. Due to the continually moving electrons inside, even the magnet on your refrigerator is magnetic.
Describe the magnetic field?Magnetic forces can be observed in a magnetic field, an electric current, a changing electric field, or a vector field around a magnet. Magnetic compass needles and other permanent magnets line in the direction of magnetic fields similar to those found on Earth. Electrically charged particles are forced to move in a circular or helical path via magnetic fields. The operation of electric motors is generated by this force, which is applied to electric currents in wires in a magnetic field.
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it's possible to transfer electric charge to an object so that its net electric charge is 6.5 times the fundamental electric charge, e.
It's possible to transfer electric charge to an object so that its net electric charge is 6.5 times the fundamental electric charge e. it is a false statement. because any charge can only be integral multiple of the fundamental charge e.
What is electric charge?A neutral body gets charged if it gains or losses some electrons.
There are two types of charges: positive charge and negative charge.
It is the property of substances due to which a body produce and experience electric effect.
S.I. unit of charge is coulomb.
Q = It
Where, Q = charge,
I = electric current,
t = time
Quantisation of charge :charge is quantised. it means that charge on a body is always equal to the integral multiple of basic unit of charge i.e. charge of one electron.
Q = ne
e = 1.6 ×10^-19 C .
A charge of magnitude 1C contains about 6×10^18 electrons.
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special clothes needed or worn in church
Answer: If you want to know how to dress for church, something modest and comfortable should be fine. Generally, graphic tees that show off sports team logos or bands should never be worn to church. Solid-colored tops are fine, and even something with a pattern should be OK to wear.
Explanation:
M The following charges are located inside a submarine: 5.00μC,-9.00μC, 27.0μC , and -84.0μC (b) Is the number of electric field lines leaving the submarine greater than, equal to, or less than the number entering it?
Since the net electric flux which is − 6.89 × 10^6 V⋅m through the hull of the submarine is negative, the number of electric field lines leaving the submarine is less than the number entering it.
A submarine (or sub) is a watercraft capable of independent operation underwater. It differs from a submersible, which has the more limited underwater capability. Most large submarines consist of a cylindrical body with hemispherical (or conical) ends and a vertical structure, usually located amidships, that houses communications and sensing devices as well as periscopes. In modern submarines, this structure is the "sail".
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Why does hitting a magnet with a hammer cause the magnetism to be reduced?
Hitting a magnet with a hammer cause the magnetism to be Physical disruption and vibration damage the material's order, demagnetizing it.
Explanation:There are numerous methods for demagnetizing a magnet.
A magnet, as we know, has magnetic moments, which are the arrangements of molecules in a specific direction.
The hammer causes the magnetic poles of the magnet to point in opposite directions, causing the magnet to bend.
When we repeatedly hammer on a magnet, the magnetic dipoles inside the magnet are released from their ordered configuration.
Magnetism is known to be caused by the presence of magnetic moments.
As a result, when we hammer it, the dipoles are perturbed, lose their orientation, and magnetic moments cease to exist. As a result, the magnet will become demagnetized.
What is Magnetism?The force that magnets use to either attract or repel one another is known as magnetism.
Electric charges in motion are what generate magnetism. Every substance is made of small particles known as atoms.
Electrons, which are charged particles, are found in every atom. Electrons spin like tops around an atom's nucleus, or center. Their mobility causes an electric current to flow, causing each electron to act as a miniature magnet.
Another strongly magnetic substance must enter the magnetic field of an existing magnet in order to be magnetized. A magnet's magnetic field is the area of magnetic force that surrounds it.
An electric current can magnetize some compounds.
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A karate expert executes a swift blow and breaks a cement block with her bare hand. The magnitude of the force on her hand is.
3.141592653589793238
Explanation:
3.141592653589793238
A bicyclist traveling at 5 m/s hits a fence, the bicyclist files over the fence. Which
of Newton's Laws does this BEST describe?
1.Newton’s 1st Law
2.Newton's 2nd Law
3.Newton's 3rd Law
The Newton's Laws that BEST describe the situation is Newton's second law of motion.
What is Newton's second law of motion?
Newton's second law of motion states, the force exerted by an object is directly proportional to the product of mass and acceleration of the object.
Also, the law can also be states as force is equal to the rate of change of momentum.
F ∝ Δp
Ft = m(v2 - v1)
The force exerted on the bicyclist by the fence is equal to the change in momentum of the bicyclist. The bicyclist was able to fly over the fence because there is a change in his momentum.
Thus, the Newton's Laws that BEST describe the situation is Newton's second law of motion.
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A small car weighs 10168.25 N. What is its mass?
Answer:
1036.5kg
...................
Consider cyclic processes completely characterized by each of the following net energy inputs and outputs. In each case, the energy transfers listed are the only ones occurring. Classify each process as (a) possible, (b) impossible according to the first law of thermodynamics, (c) impossible according to the second law of thermodynamics, or (d) impossible according to both the first and second laws.(vi) Input is 5J of energy transferred by heat, and output is 3J of work plus 2J of energy transferred b
The situation is possible based on the first law of thermodynamics.
What is thermodynamics?The term thermodynamics has to do with the study of heat. Heat is that which causes the temperature of a body to change. We know that according to the first law of thermodynamics, energy could neither be created nor destroyed but can be converted from one form to another.
The second law of thermodynamics states that, the conversion of energy is not 100% efficient as some of the energy could be lost as heat. We can now fit in the scenario described into the laws of thermodynamics.
We can see that, if we input is 5J of energy transferred by heat, and output is 3J of work plus 2J of energy transferred by heat, then the situation is possible based on the first law of thermodynamics.
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The power output of a certain public-address speaker is 6.00W . Suppose it broadcasts equally in all directions.(b) At what distance from the speaker would the sound be barely audible?
The distance from the speaker would the sound be barely audible is 477.46km.
What is distance?It's how far away two objects or locations are measured numerically as distance. Distance in physics or common language can refer to a physical length or an assumption based on other factors (e.g. "two counties over"). Sometimes the symbol |AB| is used to indicate how far apart two points are. "Distance from A to B" and "Distance from B to A" are typically equivalent terms. A distance function or metric in mathematics is an extension of the idea of physical distance; it defines what it means for components in a space to be "near to" or "far away" from one another. Distance is a non-numerical unit of measurement in the social sciences and psychology.
Explanation:
Sound audible(barely) = 0dB
I= 10.709*I/[tex]10^{-10}[/tex]=0
I= [tex]10^{-12}[/tex]*[tex]10^{0}[/tex]=[tex]10^{-12}[/tex]w/[tex]m^{2}[/tex]
[tex]distance(r)=\sqrt[]{\frac{P}{4\pi I} } =\sqrt[]{\frac{6}{4\pi * 10^{-12} } } =477.46 km[/tex]
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Help please ;((((((((
Answer:
42- electromagnetic force
Explanation:
electrons keep orbiting around the nucleus thanks to electromagnetic force :)
hope this helped!
Happens at the start of the game and after every touchdown. in flag football you may throw or punt the ball.
The correct answer is punt/kickoff
In gridiron football, a drive is started with a kickoff. The "kicking team" often kicks the ball to the "receiving team" of the opposite team during a kickoff. Until the player with the ball is tackled by the kicking team, goes out of bounds, scores a touchdown, or the play is otherwise deemed dead, the receiving team is then allowed to return the ball, i.e., attempt to move it towards the kicking team's end zone. Every half of play, the start of various overtime forms, and after scoring plays all feature kickoffs. At the beginning of each half, following a try, and following a successful field goal, the ball is sent into play through a kickoff.
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Complete question
Happens at the start of the game and after every touchdown. in flag football you may throw or punt the ball. options 1. Interception 2. Fumble
3. Punt/Kickoff 4. Down
an iron bolt of mass 72.0 g hangs from a string 38.8 cm long. the top end of the string is fixed. without touching it, a magnet attracts the bolt so that it remains stationary, but is displaced horizontally 27.0 cm to the right from the previously vertical line of the string.
The weight of the iron bolt is 0.706N
What do you mean by the vertical line of the string?A line that is perpendicular to the surface or another line that is regarded as the base is the vertical line. In coordinate geometry, the vertical lines are often perpendicular to the horizontal lines and parallel to the y-axis. Any straight line that runs from top to bottom or bottom to top is considered to be a vertical line. Standing lines are another name for vertical lines. The vertical lines that we typically draw connect the bases of a square or a rectangle. We shall examine the idea of the vertical line and its characteristics in this essay.
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Joe walks 36m north followed by 90m east. What is his magnitude of displacement
from the start?
Answer: 90m - 36m = 54 m from the start! Best of luck!
10 pts the classic millikan oil drop experiment was the first to obtain an accurate measurement of the charge on an electron. in it, oil drops were suspended against the gravitational force by a vertical electric field. consider an oil drop with a weight of 1.2 x 10-14n, if the drop has a single excess electron, find the magnitude (in n/c) of the electric field needed to balance its weight. your should round your answer to an integer, indicate only the number, do not include the unit.
the magnitude of the electric field needed to balance its weight is
0.75 ×10⁵N/C
The oil drop method was performed by Robert A Millikan in 1909.
It is used to determine the size of the charge on an atom.
Millikan used vacuum pump oil for this his experiment.
to find out the magnitude of electric field
W = q E,
W = weight (W = mg)
q = charge (1.6×10⁻¹⁴C)
E = Electric field
→ oil drops were suspended against the gravitational force by a vertical electric field such that its weight is balanced by the electron force i.e.
W = 1.2× 10⁻¹⁴
1.2× 10⁻¹⁴ = q × E
E = 1.2× 10⁻¹⁴N/ 1.6×10⁻¹⁹C
E = 0.75 ×10⁵N/C
the magnitude of the electric field needed to balance its weight is
0.75 ×10⁵N/C
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Review. For a certain type of steel, stress is always proportional to strain with Young's modulus 20 × 10¹⁰ N/m² . The steel has density 7.86× 10³kg / m³. It will fail by bending permanently if subjected to compressive stress greater than its yield strength бy = 400MPa. A .rod 80.0cm long, made
of this steel, is fired at 12.0 m/s straight at a very hard wall.(b) After the front end of the rod hits the wall and stops, the back end of the rod keeps moving as described by Newton's first law until it is stopped by excess pressure in a sound wave moving back through the rod. What time interval elapses before the back end of the rod receives the message that it should stop?
[tex]1.58\times 10^{-4}\ \mathrm{s}$[/tex] is the time interval elapses before the back end of the rod receives the message that it should stop.
Given:
Length of the rod, L = 80 cm = 0.800 m
Young's modulus, Y = [tex]20 \times 10^{10}\;N/m^{2}[/tex]
steel density, [tex]\rho = 7.86 \times 10^{3}\;kg/m^{3}[/tex]
The speed of the wave in the rod is,
[tex]$v = \sqrt{\frac{Y}{\rho}} = \sqrt{\frac{20\times 10^{10}\ \mathrm{N/m^2}}{7.86\times 10^3\ \mathrm{kg/m^3}}} = 5044\ \mathrm{m/s}$[/tex]
Consequently, the length of the rod's end is traveled by the wave in at
[tex]$t=\frac{L}{v} = \frac{0.800\ \mathrm{m}}{5044\ \mathrm{m/s}} = 1.58\times 10^{-4}\ \mathrm{s}$[/tex]
Hence, [tex]1.58\times 10^{-4}\ \mathrm{s}$[/tex] is the time interval elapses before the back end of the rod receives the message that it should stop.
What are Newtons Laws?The three fundamental laws of classical mechanics known as Newton's laws of motion describe how an object's motion and the forces acting on it interact. The following paraphrase of these statutes is available
Unless a force acts upon a body, it remains at rest or in continual straight-line motion.
When a force acts on a body, the force is equal to the time rate at which the body's momentum changes.
When two bodies exert force on one another, the direction and amount of the force are opposed.
Isaac Newton first identified the three laws of motion in his 1687 book Philosophize Naturalis Principia Mathematica (Mathematical Principles of Natural Philosophy).
They served as the cornerstone for classical mechanics as Newton used them to examine and explain the motion of numerous physical objects and systems. The conceptual foundations of classical physics have been reconstructed in several ways since Newton, utilizing various mathematical techniques that have revealed insights that were hidden in the original, Newtonian formulation.
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Q|C The speed of a one-dimensional compressional wave traveling along a thin copper rod is 3.56 km/s . The rod is given a sharp hammer blow at one end. A listener at the far end of the rod hears the sound twice, transmitted through the metal and through air, with a time interval Δt between the two pulses.(d) Imagine that the copper rod is replaced by another material through which the speed of sound is v_r . What is the length of the rod in terms of t and v_r ?
The length of rod in terms v(r) and t is L = [ Δt / (1/343) - (1/v(r)) ].
3.56 km/s is the speed of a one-dimensional compressional wave moving along a thin copper rod.
At one end of the rod, a hard hammer strike is delivered. With a time interval of Δt between the two pulses, a listener at the other end of the rod hears the sound twice as it travels through the metal and the air.
The time interval is given by t = L/v.
We know, The speed of air, v(air) = 343 m/s
Now,
When the copper rod is swapped out for a different substance and the sound speed is measured as v(r).
The delay between pulses arrivals is:
Δt = L [(1/v(air)) - (1/v(copper))]
Then,
L = [ Δt / (1/v(air)) - (1/v(r)) ]
L = [ Δt / (1/343) - (1/v(r)) ]
Here L is the length of the rod, Δt is in seconds and v(r) is the speed of sound in the rod.
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