a child-care center has 200 feet of fencing to enclose two adjacent rectangular safe play areas (of equal size). find the dimensions that will produce the maximum enclosed area. 5

Answers

Answer 1

The dimensions that will produce the maximum enclosed area for two adjacent rectangular safe play areas of equal size with 200 feet of fencing is 100 feet by 100 feet.

To solve this problem, use the area of a rectangle formula A = lw, where l is the length and w is the width.

Since the two play areas must be of equal size, let's call the length and width l and w, respectively.

We know that the total length of fencing is 200 feet, so l + w = 200 feet.

We can then solve for l by rearranging the equation as l = 200 - w.

We then substitute this into the area equation to get A = (200 - w)w.

To maximize the area, differentiate this equation to get A' = w - 200.

Set this to 0 and solve for w to get w = 100. Since l + w = 200, l = 100 as well.

Therefore, the maximum enclosed area is produced by dimensions of l = 100 feet and w = 100 feet.

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Related Questions

Need help too figure out these questions these are 2 outa 10 i have too do but these the hardest

Answers

Answer:

1. I don't know

2. 10

Step-by-step explanation:

[tex]c=\sqrt{a^{2}+b^{2} } = \sqrt{6^{2}+8^{2} } = \sqrt{36+64} = \sqrt{100} = 10[/tex]

Answer is
1) area of shaded area = 14.13 m
area of the remainder of circle = 345.87

2) hypotenuse = 10cm

Step by step
1)
Area of a circle is A=TT r^2
A= (3.14) (6)^2
A= 3.14 x 36
A= 113.04
Now we want to find out just the shaded area

There is 360 degrees in a circle
We are finding 45 degrees of 360 = 1/8
1/8 of 113.04 = 14.13 m

2) hypotenuse is found using formula
a^2 + b^2 = c^2
6^2 + 8^2 = c^2
36 + 64 = c^2
100 = c^2

√100 = √c^2
10 cm = c

how would i do this cause im very lost someone please help

Answers

The decrease in the time spent exercising is 0.74.

Describe Scatter plot?

A scatter plot is a type of data visualization that is used to display the relationship between two continuous variables. It consists of a set of data points, each representing an observation, plotted as a point on a two-dimensional graph with one variable on the x-axis and the other variable on the y-axis.

Scatter plots are often used to identify patterns or relationships between two variables, such as correlation or causation. If the points on the plot tend to form a pattern, such as a straight line, then there may be a relationship between the two variables. If the points do not form a pattern, then there may be no relationship between the two variables.

The answers are quite straightforward.

(a) Here, we substitute x=4

(b) Again, we substitute x= 0

(c) Here, if y1=y2-y1= (-0.74x- 0.74+8.54)-(-0.74x + 8.54)= y2-y1= -0.74x- 0.74+8.54 + 0.74x + 8.54= y2- y1= 0.74.

Thus, the decrease in the time spent exercising is 0.74.

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The complete question is

Find the X
geometry
pt.2

Answers

The angle of x in the given circle is 51 degrees.

What is theorem of secant and tangent line in circle?

In the case when a tangent line and a secant line originate from the same external point, the mean of the exterior angle is equal to half the difference between the major arc and the minor arc that are created by the tangent and secant lines.

From the given figure we observe that the secant line and tangent line start from the same exterior angle.

Thus, according to the theorem of secant and tangent line of circle we have:

angle x = (DA - DB) /2

angle x = (178 - 76) / 2

angle x = 102 /2

angle x = 51 degrees.

Hence, the angle of x in the given circle is 51 degrees.

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merrell claims that he randomly assigned rats to treatment groups. does the data shown in the dotplots above support his claim? why or why not? g

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The data shown in the dot plots above doesn't support Merrell's claim that he randomly assigned rats to treatment groups. It doesn't support it because the dot plots are not similarly distributed.

There are a few discrepancies in the data that are not possible if rats were randomly assigned to treatment groups.

Difference between the two dot plots:

There is a noticeable difference between the two dot plots.

The dot plot on the left shows that most rats in Group 1 weigh between 200 and 240 grams.

On the other hand, in Group 2, most rats weigh between 240 and 280 grams.

The two groups' data are not similarly distributed, and there is an overlap in the weight of rats in the two groups. Furthermore, the data suggests that heavier rats were placed in Group 2 while lighter rats were placed in Group 1.

This difference implies that rats were not randomly assigned to treatment groups.

Other information should be considered:

The information shown in the dot plots alone is not enough to conclude that the rats were not randomly assigned to treatment groups.

We must investigate further and gather more information to confirm our assumptions about the rats' treatment groups. Randomization guarantees that each rat has an equal probability of being assigned to a treatment group.

The two groups must be equivalent in every aspect except for the treatment they get.

Therefore, it's essential to confirm that there was no selection bias in the rat selection process.

This means that rats were picked randomly from a large population, and no specific rat characteristics influenced the selection process.

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a 1-kilogram mass is attached to a spring whose constant is 16 n/m, and the entire system is then submerged in a liquid that imparts a damping force numerically equal to 10 times the instantaneous velocity. determine the initial conditions and equations of motion if the following is true.

Answers

The final equation of motion for the system is: x(t) = [(8v0 - 2x0)/6]*[tex]e^{(-2t)} + [(2x0 - 8v0)/6]*e^{(-8t).[/tex]

To determine the initial conditions and equations of motion, we can use the following steps:

Write down the equation of motion for the system. The equation of motion for a mass-spring-damper system is given by:

m * [tex]d^2x/dt^2[/tex] + c * dx/dt + k * x = 0

where m is the mass, c is the damping coefficient, k is the spring constant, x is the displacement from the equilibrium position, and t is time.

In this case, the mass is 1 kg, the spring constant is 16 N/m, and the damping coefficient is 10 times the instantaneous velocity, or 10 * dx/dt.

Substituting these values into the equation of motion, we get:

1 * [tex]d^2x/dt^2[/tex] + 10 * dx/dt + 16 * x = 0

Determine the initial conditions. The initial conditions refer to the position and velocity of the mass at time t = 0.

Let x(0) be the initial displacement of the mass from the equilibrium position, and let v(0) be the initial velocity of the mass. Then the initial conditions are:

x(0) = ?

v(0) = ?

These values are typically given in the problem statement.

Solve the differential equation. To solve the differential equation, we can use the characteristic equation method. First, we assume that the displacement of the mass is of the form:

x(t) = A[tex]e^{(rt)[/tex]

where A and r are constants to be determined.

Taking the first and second derivatives of x(t), we get:

dx/dt = Are^(rt)

d^2x/dt^2 = Ar^2*e^(rt)

Substituting these expressions into the equation of motion, we get:

A * ([tex]r^2[/tex] + 10r + 16) * [tex]e^{(rt)[/tex]= 0

Since [tex]e^{(rt)[/tex]is never zero, we can divide both sides by it and simplify to obtain the characteristic equation:

[tex]r^2 + 10r + 16 = 0[/tex]

Solving for r using the quadratic formula, we get:

r1 = -2

r2 = -8

Therefore, the general solution for the displacement of the mass is:

[tex]x(t) = Ae^{(-2t)} + Be^{(-8t)[/tex]

where A and B are constants determined by the initial conditions.

To find A and B, we use the initial conditions x(0) = x0 and v(0) = v0. Taking the derivative of x(t) and setting t = 0, we get:

v(0) = -2A - 8B

Using the second initial condition, we get:

x(0) = A + B = x0

Solving for A and B, we get:

A = (8v0 - 2x0)/6

B = (2x0 - 8v0)/6

Therefore, the final equation of motion for the system is:

[tex]x(t) = [(8v0 - 2x0)/6]*e^{(-2t)} + [(2x0 - 8v0)/6]*e^{(-8t)[/tex]

Complete question: A 1-kilogram mass is attached to a spring whose constant is 16 N/m, and the entire system is then submerged in a liquid that imparts a damping force numerically equal to 10 times the instantaneous velocity. Determine the equations of motion if (a) the mass is initially released from rest from a point 1 meter below the equilibrium position, and then (b) the mass is initially released from a point 1 meter below the equilibrium position with an upward velocity of 12 m/s.

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Bao has 39 m of fencing to build a three-sides fence around a rectangular plot of land that sits in a riverbank. (The fourth side of the enclosure would be the river.) The area of the land is 169 square meters. List each set of possible dimensions (length and width) of the field.

Answers

The pοssible dimensiοns (length and width) οf the rectangular plοt are:

Length = 21 meters, width = 8.05 meters

Length = 8.05 meters, width = 21 meters

Let the length οf the rectangular plοt be L and the width be W. Then we knοw that the perimeter οf the rectangular plοt, which is equal tο the length οf fencing Baο has, is given by:

2L + W = 39

Alsο, the area οf the rectangular plοt is given by:

L × W = 169

We can use these twο equatiοns tο sοlve fοr L and W. First, we can sοlve the equatiοn 2L + W = 39 fοr W:

W = 39 - 2L

Substituting this into the equation for the area, we get:

L × (39 - 2L) = 169

Expanding and rearranging this equation, we get a quadratic equation in terms of L:

[tex]-2L^2 + 39L - 169 = 0[/tex]

We can solve for L using the quadratic formula:

[tex]L = [ -39 \± sqrt(39^2 - 4(-2)(-169)) ] / (2(-2))\\L = [ -39 \± sqrt(1681) ] / 4\\L = [ -39 \± 41 ] / 4[/tex]

L = 1/2 or L = 21

If L = 1/2, then W = 38, which gives a negative area and is therefore not possible.

If L = 21, then W = 169/21, which simplifies to W = 8.05 (rounded to two decimal places).

Therefore, the possible dimensions (length and width) of the rectangular plot are:

Length = 21 meters, width = 8.05 meters

Length = 8.05 meters, width = 21 meters

Note that these are the only possible dimensions, as the sum of the length and width must be less than or equal to 19.5 meters (half of the available fencing).

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What is 35 to the nearest degree

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I'm sorry, 35 is not a measure of angle and therefore cannot be rounded to the nearest degree. Are you asking for the sine, cosine, or tangent of 35 degrees?

a farmer want to create a rectangular field with one side alongn a straight stream using 1100 feet of fencing, but there will be fencing only one 3 sides and not on the side bordered by the stream. what dimensions will maximize the area of the field?

Answers

To maximize the area of a rectangular field with one side along a stream using 1100 feet of fencing, the dimensions should be 183.33 feet by 550 feet.

Let's call the length of the field that runs parallel to the stream "x" and the width of the field that runs perpendicular to the stream "y".

The total amount of fencing that the farmer has available is 1100 feet, and we know that three sides of the rectangular field will be fenced. Since one side of the field is already bordered by the stream and does not require fencing, we can set up the following equation:

2x + y = 1100 - x

Simplifying this equation, we get:

3x + y = 1100

We want to maximize the area of the field, which is given by the formula:

A = xy

We can use the equation we derived earlier to solve for y in terms of x:

y = 1100 - 3x

Substituting this into the area formula, we get:

A = x(1100 - 3x)

Expanding the parentheses, we get:

A = 1100x - 3x^2

To find the maximum area, we need to find the value of x that maximizes this equation. We can do this by taking the derivative of A with respect to x and setting it equal to zero:

dA/dx = 1100 - 6x = 0

Solving for x, we get:

x = 183.33 feet

We can use this value of x to find the corresponding value of y:

y = 1100 - 3x = 550 feet

Therefore, the dimensions of the rectangular field that maximize the area are 183.33 feet by 550 feet.

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(01.03 mc) a cell phone company charges $400 for a new phone and then $50 each month after the purchase. if c (t) is a rational function that represents the average monthly cost of owning the cell phone, what is the range of the function?

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the range of the function is at least $400 plus $50 for each month after the purchase. The average monthly cost of owning the cell phone can be represented as:

C(t) = 400 + 50t

Where t is the number of months after the purchase.

Since C(t) is a linear function, its range is all real numbers greater than or equal to 400, since the initial cost of the phone is 400 and the monthly cost is a positive constant. Therefore, the range of C(t) is:

Range of C(t) = {C(t) | C(t) ≥ 400} or [400, ∞)

In other words, the range of the function is all possible average monthly costs of owning the phone, which is at least $400 plus $50 for each month after the purchase.

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if you are dealt 4 cards from a standard deck of 52 cards, what is the probability that you will get 3 black cards?

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The probability of getting 3 black cards out of 4 drawn from a standard deck of 52 cards is approximately 0.253 or 25.3%.

To determine the probability of getting 3 black cards out of 4 cards drawn from a standard deck of 52 cards, we can use the hypergeometric distribution.

There are 26 black cards in the deck, and the total number of ways to choose 4 cards from 52 is given by the binomial coefficient C(52, 4). The number of ways to choose 3 black cards out of 26 is given by the binomial coefficient C(26, 3).

The number of ways to choose the fourth card from the remaining 26 non-black cards is given by the binomial coefficient C(26, 1).

Therefore, the probability of getting 3 black cards out of 4 is:

P(3 black cards) = C(26, 3) * C(26, 1) / C(52, 4)

P(3 black cards) = (2600 * 26) / 270725

P(3 black cards) ≈ 0.253

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Please Help Me I need help

Answers

In response to the stated question, we may state that therefore, the expressions value of vector will be n = 25.73.

what is expression ?

An expression in mathematics is a collection of numbers, variables, and mathematical (such as addition, reduction, multiplication, division, exponentiation, etc.) that express a quantity or value. Expressions might be as basic as "3 + 4" or as complicated as "(3x2 - 2) / (x + 1)". They may also contain functions like "sin(x)" or "log(y)". Expressions can also be evaluated by substituting values for the variables and performing the mathematical operations in the order specified. If x = 2, for example, the formula "3x + 5" equals 3(2) + 5 = 11. Expressions are commonly used in mathematics to describe real-world situations, construct equations, and simplify complicated mathematical topics.

to find vector and magnitude we have

[tex]n^2 = (22.5)^2 + (12.5)^2\\n^2 = 506.25 + 156.25\\n^2 = 662.5\\n = \sqrt(662.5)\\n = 25.73[/tex]

therefore, the value of vector will be n = 25.73.

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suppose that iq scores have a bell-shaped distribution with a mean of 96 and a standard deviation of 17 . using the empirical rule, what percentage of iq scores are less than 79 ? please do not round your answer.

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Suppose that IQ scores have a bell-shaped distribution with a mean of 96 and a standard deviation of 17. Using the empirical rule, 15.87 percentage of IQ scores are less than 79.

The empirical rule says that for a normal distribution, almost all of the data will fall within three standard deviations of the mean.

Specifically:
Approximately 68% of the data falls within one standard deviation of the mean.
Approximately 95% of the data falls within two standard deviations of the mean.
Almost all (99.7%) of the data falls within three standard deviations of the mean.
Given that the mean of IQ scores is 96 and the standard deviation is 17.

Hence the Z score can be calculated as
z=(x−μ)/σ=(79−96)/17=−1
From the standard normal distribution table, the percentage of the data that is less than z = -1 is 15.87%.
Hence the percentage of IQ scores that are less than 79 is approximately 15.87%.

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Suppose you select a number at random from the sample space {1, 2, 3, 4, 5, 6, 7, 8}. probability.

P(the number is positive)

P(the number is even)

Suppose you select a number at random from the sample space {1, 2, 3, 4, 5, 6, 7, 8}. probability.

P(the number is positive)

P(the number is even)

Answers

Answer:

The probability of selecting a number at random from the sample space {1, 2, 3, 4, 5, 6, 7, 8} that is positive is:

There are 8 possible outcomes in the sample space, and 4 of them are positive (1, 2, 3, 4).

Therefore, P(the number is positive) = 4/8 = 1/2 = 0.5

The probability of selecting a number at random from the sample space {1, 2, 3, 4, 5, 6, 7, 8} that is even is:

There are 8 possible outcomes in the sample space, and 4 of them are even (2, 4, 6, 8).

Therefore, P(the number is even) = 4/8 = 1/2 = 0.5

So the probability of selecting a number at random from the sample space {1, 2, 3, 4, 5, 6, 7, 8} that is positive is 0.5 and the probability of selecting a number at random from the same sample space that is even is also 0.5.

simplify 2(2x+5)-(3x-2)

Answers

Solution: x + 12

Step-by-step explanation:

first simplify then distribute!

Answer:x+12

Step-by-step explanation:

we have to multiply number outside of brackets to each of the numbers inside it:

2(2x+5)=4x+10

-(3x-2)=-1(3x-2)=-3x+2

4x+10-3x+2=x+12

2+2+2+2+2+3-3-3-3-21-456--42

Answers

Equations are used in many fields, including physics, engineering, economics, and finance, to model and analyse relationships between variables.

What situation is referred to as an equation?

The expressions on either side of the equal sign are referred to as the left-hand side (LHS) and the right-hand side (RHS) of the equation. Solving an equation involves finding the values of the variables that make the equation true.

Two amounts or values are equal when they are stated as so in a mathematical equation, such as 6 x 4 = 12 x 2. two. Noun with a count.

A situation that requires the consideration of two or more elements in order to perceive or comprehend the total situation is referred to as an equation.

[tex]2+2+2+2+2+3-3-3-3-21-456--42 =[/tex]

[tex]2+2+2+2+2+3 = 13[/tex]

[tex]-3-3-3 = -9[/tex]

[tex]-456--42 = -456+42 = -414[/tex]

Therefore,

[tex]2+2+2+2+2+3-3-3-3-21-456--42 = 13 - 9 - 414 = -410[/tex]

Therefore, the value of the expression is  [tex]2+2+2+2+2+3-3-3-3-21-456--42[/tex]  [tex]= 13 - 9 - 414 = -410[/tex]     . As per the given equation.

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The sum of two numbers is 18. Their difference is -8. Find the two numbers.
Part A
Write a system of equations that represents the situation.
x + y =
x-y =
Part B
Solve the system of equations. Express the coordinates as decimals if necessary.

Answers

The two numbers in the system of equation is 5 and 13.

What is system of equation?

A group of multiple-variable equations that must all be solved concurrently make up a system of equations. Finding values for the variables that satisfy every equation in a system of equations is the objective. Each equation in the system reflects a connection between the variables. In order to find a singular solution or a group of solutions, systems of equations can be solved using a variety of methods, such as substitution or elimination. In many disciplines, including mathematics, physics, engineering, and economics, systems of equations can occur.

Let us suppose the two numbers as x and y.

x + y = 18

x - y = -8

The second equation can be written as:

x + 8 = y

Substitute the value of y in equation 1:

x + x + 8 = 18

2x = 10

x = 5

Substitute the value of x to get y:

x + y = 18

5 + y = 18

y = 13

Hence, the two numbers in the system of equation is 5 and 13.

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Simplify -15x^7/-5x^9

Answers

Answer:

Step-by-step explanation:

3x^16

Answer:

3x^16

Step-by-step explanation:

You walked 3/4 mile, and you ran 7/10 mile. How much farther did you walk than run?

Answers

Answer:

1/20

Step-by-step explanation:

because you turn the denominators to 40, then subtract walk from run and you got your answer

two cards are drawn at random from a pack without replacement. what is the probability that the first is an ace and the second is a queen?

Answers

The probability of drawing an ace and a queen from a pack of cards without replacement is 1/78. This can be explained as follows:

In a standard pack of 52 cards, there are 4 aces and 4 queens. When two cards are drawn without replacement, the probability of drawing an ace and then a queen is 4/52 x 3/51 = 12/2652. This can be simplified to 1/78.

Without replacement means that the card that is drawn is not replaced in the deck before the next card is drawn. In this case, when the first card is an ace, there are only 3 queens left in the deck so the probability of the second card being a queen is 3/51.

To put it another way, the chances of drawing an ace and a queen when the cards are drawn without replacement can be thought of as a ratio of the favorable outcomes to the total number of possible outcomes. There is only one favorable outcome (ace-queen) out of a total of 78 possible outcomes (4 aces and 4 queens combined with the remaining 44 cards). Thus, the probability of drawing an ace and a queen is 1/78.

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in 2022, nba teams score 114 points per game on average with a standard deviation of 6 points per game. suppose that we randomly sample 36 nba scores from this season and consider the sample mean ( ): the average points per game scored in this sample. calculate group of answer choices 0.95

Answers

The probability P(Xˉ−2<114<Xˉ+2) is approximately 0.95. (Option 3)

We know that the population mean is 114 and the standard deviation is 6. We also know that the sample size is 36, which is large enough to apply the central limit theorem. Thus, the distribution of sample means follows a normal distribution with a mean of 114 and a standard deviation of 6/√36=1.

Now, we need to calculate the z-score for the lower and upper bound of the inequality.

z1=(114-2-114)/1=-2

z2=(114+2-114)/1=2

Using a standard normal distribution table, we can find that the area to the left of -2 is 0.0228 and the area to the left of 2 is 0.9772. Thus, the area between -2 and 2 is approximately 0.9772-0.0228=0.9544, which is approximately 0.95.

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Complete Question:

In 2022, NBA teams score 114 points per game on average with a standard deviation of 6 points per game. Suppose that we randomly sample 36 NBA scores from this season and consider the sample mean (

Xˉ ); the average points per game scored in this sample.

Calculate P( Xˉ 2<114< Xˉ +2)

0.475 0.900.950.990.68

HELP ASAP!!! Solve for x if the figure is a rectangle. (Attachment) ignore my attempt​

Answers

The value of x that makes the given image to be a rectangle is: x = 2.5

How to find the length of the diagonal of a rectangle?

The length of the diagonals of a rectangle are equal and congruent to each other. It is also pertinent to note that the diagonals of a rectangle bisect each other at the center. Thus:

From the given parameters, we see that half of the diagonals have been labelled and as such we have:

8x - 3 = 4x + 7

Rearrange to have like terms on same side and so we have:

8x - 4x = 7 + 3

4x = 10

x = 10/4

x = 2.5

Thus, the value of x from the calculation above of the rectangle is 2.5

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Mr. Kha Lipat wants to earn 8% on his investment. How much money should he invest today in order to receive 400. 00 one year from now?

Answers

Mr. Kha Lipat should invest $5,000 today in order to receive $400.00 in interest one year from now at an 8% interest rate.

To calculate how much money Mr. Kha Lipat should invest today to receive $400.00 one year from now at an 8% interest rate, we can use the formula for calculating simple interest though compound intrest:

I = P * r * t

where I is the interest earned, P is the principal (the initial amount invested), r is the interest rate (as a decimal), and t is the time period (in years).

We know that Mr. Kha Lipat wants to earn $400.00 in interest, the interest rate is 8% or 0.08 (as a decimal), and the time period is 1 year. We can plug these values into the formula and solve for P:

I = P * r * t

400 = P * 0.08 * 1

400 = 0.08P

P = 400 / 0.08

P = 5000

Therefore, Mr. Kha Lipat should invest $5,000 today in order to receive $400.00 in interest one year from now at an 8% interest rate.

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compare the 95% and 99% confidence intervals for the hours of sleep a student gets. in at least 2 sentences, explain the difference between these intervals and why this difference occurs.

Answers

Answer:

The 99% confidence interval will be wider than the 95% confidence interval because it encompasses a greater range of possible values, meaning that there is a lower chance of the true population parameter falling outside the interval. The 95% confidence interval means that if the study was repeated many times, 95% of the intervals constructed would contain the true population parameter, whereas the 99% confidence interval means that 99% of the intervals constructed would contain the true population parameter.

Step-by-step explanation:

The following table gives the probability distribution of a random variable X
X 1 2 3 4
P(x) ¼ C ½ 1/8
a) Find the value of the constant C
b) Find

Answers

The value of the constant C is 3/4.

Probability is a branch of mathematics that deals with the likelihood or chance of an event occurring. It is a measure of the likelihood that a specific event will occur, expressed as a value between 0 and 1

The sum of the probabilities for all possible values of X should equal 1

P(1) + P(2) + P(3) + P(4) = 1

Substituting the given values, we get:

C/4 + 1/2 + 1/8 + C/4 = 1

Simplifying the equation, we get:

C/2 + 5/8 = 1

Move 5/8 to right hand side of the equation

C/2 = 3/8

C = (3/8) x 2

C = 3/4

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What is -2(3x+12y-5-17x-16y+4) simplified ?

Answers

Answer: 28x+8y+2

Step-by-step explanation:

Remove parentheses: -2(14x-4y-1)

Solution: 28x+8y+2

Answer:

28x+8y+2

Step-by-step explanation:

1. The orthocenter is outside the triangle. 2. An altitude is the same line segment as an angle bisector. 3. If the perpendicular bisector of one side of a triangle intersects the opposite vertex, then the triangle is isosceles

Answers

The solution of the match is

(1) Orthocenter          (C) The point at which the altitudes of a triangle                                                

                                              meet.

(2) Centroid                 (D) The point at which the medians of a triangle

                                             meet.

(3) Circumcenter         (A) The point of intersection of the perpendicular                  

                                             bisectors of the sides of a triangle.

(4) Incentre                 (B) The point at which the three angle bisectors      

                                             of a triangle meet.

The orthocenter of a triangle is the point where the altitudes of the triangle intersect. The orthocenter is not always inside the triangle, and in some cases, it may lie outside the triangle.

The centroid of a triangle is the point where the three medians of the triangle intersect. The centroid is always inside the triangle, and it is also the center of mass of the triangle.

The circumcenter of a triangle is the point where the perpendicular bisectors of the sides of the triangle intersect.  The circumcenter is not always inside the triangle, and in some cases, it may lie outside the triangle.

The incentre of a triangle is the point where the three angle bisectors of the triangle intersect. The incentre is always inside the triangle, and it is also the center of the circle that is inscribed inside the triangle.

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Complete Question:

Match the following.

(1) Orthocenter         (A) The point of intersection of the perpendicular                  

                                             bisectors of the sides of a triangle.

(2) Centroid                 (B) The point at which the three angle bisectors of

                                             a triangle meet.

(3) Circumcenter         (C) The point at which the altitudes of a triangle

                                              meet.

(4) Incentre                 (D) The point at which the medians of a triangle

                                             meet.

Vectors u and v are shown on the graph. vector u with initial point at the origin and terminal point at 0 comma negative 5, vector v with initial point at the origin and terminal point at negative 7 comma 0 Which of the following vectors represents u + v? a vector that points to the right 7 units and up 5 units b vector that points to the left 7 units and up 5 units c vector that points to the left 7 units and down 5 units d vector that points to the right 7 units and down 5 units

Answers

The resultant vector is 7 units to the left and 5 units down. As a result, graphs option (c) a vector pointing to the left 7 units and down 5 units is the correct answer.

What is graphs?

Mathematicians use graphs to visually display or chart facts or values in order to express them coherently. A graph point usually represents a connection between two or more items. A graph, a non-linear data structure, is made up of nodes (or vertices) and edges. Glue the nodes, also known as vertices, together. This graph includes V=1, 2, 3, 5, and E=1, 2, 1, 3, 2, 4, and (2.5). (3.5). (4.5). Statistical graphs (bar graphs, pie graphs, line graphs, and so on) are graphical representations of exponential development. a logarithmic graph shaped like a triangle

We can add vectors geometrically by setting the starting point of the second vector at the terminal point of the first vector and drawing a vector from the first vector's initial point to the second vector's terminal point.

Next we align the starting point of vector v with the terminal point of vector u and draw a vector from the initial point of vector u to the terminal point of vector v:

The resultant vector is 7 units to the left and 5 units down. As a result, option (c) a vector pointing to the left 7 units and down 5 units is the correct answer.

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Which ONE of the following statements best describes the use of spaces in folder and file names in ArcGIS?
Using spaces in folder names in ArcGIS is permitted but strongly discouraged

Answers

The statement that best describes the use of spaces in folders and files names in ArcGIS is "Using spaces in folder and file names in ArcGIS is permitted but strongly discouraged."

ArcGIS is a geographic information system software that is used for creating, editing, analyzing, and sharing spatial data. The software is widely used by GIS professionals, environmental scientists, geographers, and other experts to manage and analyze spatial data.

In ArcGIS, it is possible to use spaces in folder and file names, but it is not recommended. This is because spaces can cause problems when the software tries to access files with spaces in their names. Therefore, it is better to use underscores or hyphens instead of spaces when naming folders and files in ArcGIS. This helps to avoid issues when working with data in ArcGIS.
The statement "Using spaces in folder names in ArcGIS is permitted but strongly discouraged" is the best description of the use of spaces in folder and file names in ArcGIS.

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mathematics homework

Answers

Answer:

Step-by-step explanation:

(g * h)(24)

gh*24

24gh

Describe the pay at the digital source. Use complete sentences and include at least one specific example from the table that you made for part a

Answers

The pay at the Digital Source is a variable amount that depends on the employee's job position and experience level. The pay is represented in dollars per hour, and it ranges from $12 per hour for a new employee in a low-level position to $60 per hour for a senior developer with extensive experience.

For example, if we look at the table created in part a, we can see that a junior developer with less than a year of experience will earn $18 per hour, while a senior developer with more than 10 years of experience will earn $60 per hour. This means that the pay at the Digital Source is directly related to the employee's experience and job position.

Additionally, the table also shows that the pay rate increases as the employee gains more experience and moves up the career ladder. For instance, a junior developer with less than a year of experience will earn $18 per hour, but a mid-level developer with 3-5 years of experience will earn $35 per hour. This shows that employees are rewarded for their skills and experience, and they have the opportunity to advance their careers and earn higher pay rates.

In summary, the pay at the Digital Source is a variable amount that depends on the employee's job position and experience level. The pay rate ranges from $12 per hour to $60 per hour, and it increases as the employee gains more experience and moves up the career ladder. The company values the skills and expertise of their employees and rewards them accordingly.

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