write a net ionic equation for the reaction that occurs when aqueos solutions of sodium hydroxide and hypochlorus aicd are combined
[tex]HClO_4 + NaOH[/tex] → [tex]NaClO_4 + H_2O[/tex] Is the net ionic reaction when sodium hydroxide and hypochlorous acid is combined.
When the combine acid and base, neutralization reaction occurs which results in formation of salt and water because
Acid + Base → Salt + Water
This reaction is known as neutralization reaction.
Here, Sodium hydroxide is base and hypochlorous acid is an acid .
So salt [tex]NaClO_4[/tex] and water is formed.
This reaction is also an example of double displacement reaction.
[tex]HClO_4 and NaOH[/tex] breaks into [tex]H^{+} , ClO_4^{-} and Na^{+} , OH^{-}[/tex] ions respectively and displaces other ion from other compound.
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y = A x + 1/₂ B x²
If y = 23.2, x = 1.40, and B = 3.63, what is A?
A is 14.03 in the given equation y = Ax + (Bx^2)/2, if we substitute y = 23.2, x = 1.40 and B = 3.63.
This is an algebraic equation with two variables of order 2. The values of x, y and the coefficient of x^2 is given here.
The given equation y = Ax + (Bx^2)/2 has the variables A, x, y, and B.
By substituting the variables y, x, and B, we can get A from the equation.
y = 23.2
x = 1.40
B = 3.63
Substituting these values,
23.2 = A*1.40 + (3.63*1.4^2)/2
23.2 = 1.4A + 3.63*1.96/2
23.2 = 1.4A + 7.1148/2
23.2 - 3.5574 = 1.4A
1.4A = 19.6426
A = 19.6426/1.4
A = 14.03
Therefore, A = 14.03
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A scientist collected a sample from the forest floor. Which piece of evidence supports
that the sample is a living thing?
A The sample was green, the color of chloroplasts.
B The sample was small and could only be seen with a microscope.
C
The sample was releasing carbon dioxide gas.
D The sample was made of one or more cells.
The answer would be
A. The sample was green, the color of chloroplast
Hope this helps
some molecules such as iodine have two atom to make up th ubstamce, while others have thousands. a molecule of sugar has 45 atoms. if ugar crystal has 1000 molecules how many atoms are present
Through unit conversion, it has been determined that a crystal of sugar contains 45,000 atoms.
The problem can be solved through unit conversion. The atoms of the table sugar, with a molecular formula of C12H22O11, are 12 carbon atoms, 22 hydrogen atoms, and 11 oxygen atoms. As stated in the problem, a molecule of sugar has 45 atoms and a crystal of sugar has 1000 molecules.
In solving for the number of atoms in a sugar crystal, we will be getting the product between the number of molecules per crystal of sugar to the number of atoms per molecule.
(1000 molecules of sugar/crystal of sugar) * (45 atoms of sugar/molecule of sugar) = 45,000 atoms of sugar/crystal of sugar.
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From the options provided for each element below, choose the properties that it may have based on its location in the periodic tableNeon (Ne):
shiny
a conductor
a gas
From the options provided for the element, a gas is a property that neon may have based on its location in the periodic table.
Neon is an inert gas. The elements of group 8 A are the inert gases. They are - Helium (He), Neon (Ne), Argon (Ar), Krypton (Kr), Xenon (Xe) and Radon (Rn). Inert gases are stable and they are not reactive chemically.. Inert gases are also called as noble gases.
Neon element is a gas which cannot be shiny or dull. It is clear and colorless. So, it cannot have this property.
Neon element is an inert gas. They have complete valence shells and do not have any free electrons. Therefore, they are poor conductors of electricity.
Neon element belongs to the group 8, which is inert gas. Therefore, it has property of gas.
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if 2 kg of butane gas was burnt in a plentiful amount of oxygen, what would be the maximum mass of carbon dioxide released into the atmosphere?
The maximum mass of carbon dioxide released in the atmosphere is 6072 g/mole.
What is mass?Mass is defined as a dimensionless quantity representing the amount of matter in a particle or object.
1 kg = 1000gso 2kg = 2000g
To calculate mass of carbon dioxide released in atmosphere when butane gas is burned is:
Number of mole of butane = given mass/ molar mass
= 2000g/58g/mole = 34.5 moles
1 mole of butane produce 4 mole of CO2
34.5 moles of butane = 4 x 34.5 = 138 mole
Maximum mass of CO2 released = number of mole x molar mass
= 138 mole x 44 g/ mole
= 6072 g/ mole
Thus, the maximum mass of carbon dioxide released in the atmosphere is 6072 g/mole.
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Help with 3 and 4?? Please asap!!
Answer:
A for number 3 and C for number 4
Explanation:
I hope you pass this homework
4. The equation below is
(look at what the reactants and products are)
6CO₂ + 6H₂0
-
C6H1206 +602
The equation below is photosynthesis .
6CO₂ + 6H₂O → [tex]C_{6} H_{12} O_{6}[/tex] + 6O₂
Water and carbon dioxide are converted into food by the process of photosynthesis , which occurs in the presence of sunlight in plants and photosynthetic bacteria . They create oxygen as a byproduct and glucose as the food . The photosynthesis equation is given as ,
6CO₂ + 6H₂O → [tex]C_{6} H_{12} O_{6}[/tex] + 6O₂
This indicates that the reactants, six carbon dioxide molecules and six water molecules, are transformed into a sugar molecule and six oxygen molecules, the products, by light energy being absorbed by chlorophyll (implied by the arrow).
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Which of the following groups/families has an oxidation number/charge of -1?
Answer: I don't know try your best
Explanation:
What is the atomic number of an atom that has two electrons three protons and four neutrons
Answer: 3
Explanation: your protons are your atomic number and the atomic mass is the proton and neutrons totaled
If you have any two gases in different containers that are the same size at the same pressure and same temperature, what is true about the moles of each gas?.
According to Avogadro’s law, the number of moles of each gas is same in the two different containers of same size at same temperature and pressure conditions.
According to Avogadro’s law, equal volume of different gases at same temperature and pressure conditions have equal number of molecules. At standard temperature and pressure conditions, Avogadro's law states that 6.022 x [tex]10^2^3[/tex] molecules of gas is present in 22.4L.
1 mole of gas is equal to the number of atoms of the elements that make up the gas. According to Avogadro’s law, 1 mole of gas contains 6.022 x [tex]10^2^3[/tex] molecules. Therefore, the number of moles of the different gases at same temperature and pressure conditions is same.
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based on your answer in part a, calculate the number of atoms in this amount of 13c ? express your answer numerically in atoms of carbon.
The total number of atoms present in the carbon
atom ¹³C is 2.32 × 10²³ atoms. And the number of electrons present in 2.32 × 10²³ is 1.392 × 10²⁴ electrons.
Carbon is a non-metallic element. It is the element of group 14 of the periodic table. It is tetravalent. It is presented by the symbol 'C'. The atomic number of carbon is 6. And the atomic mass of carbon is 12.011 u. Carbon has four valence electrons.
Total number of atoms present in the carbon atom
[tex] ^{13} C = 2.32 \times 10^{23} \: atoms[/tex]
Total number of electrons present in the carbon atom
[tex] ^{13} C = 1.39 \times 10 ^{24} \: electrons[/tex]
The atomic number of carbon atom
[tex] ^{13} _{6}C = 6[/tex]
The number of electrons present in carbon is,
The atomic number of carbon = the number of electrons
Atomic number = 6
Number of electrons = 6
[tex]The \: number \: of \: electrons \: present \: [/tex]
[tex]in \:2.32 \times 10^{23} \: atoms \: of \: carbon,[/tex]
= Number of electrons present in one carbon atom ×
[tex]2.32 \times 10 ^{23} [/tex]
[tex] = 6 \times 2.32 \times 10 ^{23} [/tex]
[tex] = 1.392 \times 10 ^{24} [/tex]
Therefore, the total number of atoms present in the carbon atom ¹³C is 2.32 × 10²³ atoms. And the number of electrons present in 2.32 × 10²³ is 1.392 × 10²⁴ electrons.
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A chemistry experiment calls for 5 grams of baking soda. your measuring spoon holds 5000 mg of powder. how many will you need for the experiment?
Answer: 1 spoon
Explanation:
Amount needed= 5 grams or 5000 mg
The spoon holds 5000 gm
So, One spoon of baking soda is needed for the experiment.
how many molecules are contained in a 5.15g sample of dimethylmercury?
The molecules in a 5.15 g sample of dimethylmercury is 1.32 x 10²².
Dimethylmercury is a highly volatile, toxic liquid, which is reactive and colourless. Its molecular formula is C₂H₆Hg. It is used in NMR instruments for calibration. It has risks involved, so it has few applications and used in a lesser quantity.
Dimethylmercury C₂H₆Hg has a molecular mass of -
Molecular mass = (12x2) x (1x6) x 200.59 = 230.6 g/mol
Now,
number of moles in 5.15 g of dimethylmercury = 5.15 = 0.022 mol
230.6
1 mole of dimethylmercury contains 6.022 x 10²³ molecules
So, 0.022 moles of dimethylmercury contains 0.022 x (6.022 x 10²³) = 1.32 x 10²² molecules
Molecules contained in 5.15 g sample of dimethylmercury is
1.32 x 10²²
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1. When adding the measurements 4.56 g and 0.01860 g, what is the reported value (to the correct number of significant figures)?
The reported value of adding 4.56 g to 0.01860 g to the correct significant figures will be 4.58 g.
Addition rule guiding significant figuresAccording to one of the rules guiding addition operation in significant figures., the number with the lowest significant figure to the right of the decimal place determines the number of significant figures in the final answer.
Thus, in operation: 4.56 + 0.01860, the number with the lowest significant figures to the right of the decimal place is 4.56 with 2 significant figures after the decimal place.
In other words, the final answer of the operation will also have two significant figures after the decimal.
Hence;
4.56 + 0.01860 = 4.58 g
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why do some elements have parentheses around the atomic mass what do these parentheses indicate about the elements
Some element have parentheses around atomic mass because it form subgroup of atom within a molecule. the number in parentheses is the mass no of most stable isotopes of that element
Parentheses means in a particular structure are repeated in molecule called parentheses. parentheses is used because to help identity that there is more than one polyatomic ion present. parentheses are useless in chemical formula if they don't have a subscript.
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a 4.37-g sample of a certain diatomic gas occupies a volume of 3.00 l at 1.00 atm and a temperature of 45°c. identify this gas.
The diatomic gas is Fluorine
Given:
mass of diatomic gas = 4.37-g
volume of diatomic gas = 3 l
temperature = 45°c = 318 K
R in Lt-atm scale 0.08205736(14) L-atm/K-mol
~ 0.082
To Find:
identify this gas
Solution: Working equation: PV = nRT (Ideal gas law)
n (no of moles) = m(mass)/M (Molecular wt.)
3.1 = (4.37/M) x 0.082 x 318
M = 37.985
Now the only diatomic gas which has closest molecular mass is Fluorine (F2) (37.997). The difference in value is probably coming from approximation.
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The solubility of cacl2 in water is 25g per 50 ml of h2o. How many grams of cacl2 will dissolved to form a saturated solution in 10 ml of water?.
Answer:
5 g
Explanation:
50/10 = 5,
25/5 = 5grams
hope this works: )
A+95. 0+wt%+solution+of+ethanol+(ch3ch2oh,+fm+46. 07)+in+water+has+a+density+of+0. 804+g/ml. +what+is+the+molar+concentration+of+ethanol+in+this+solution?
The molar concentration of ethanol in this solution is 16.58 M.
percentage by weight of ethanol = 95%
M(CH₃CH₂OH) = 46.07 g/mol; molar mass od ethanol
d = 0.804 g/ml; density of the solution
Take 100 ml (0.1 l) of solution:
m(CH₃CH₂OH) = 100 ml × 0.804 g/ml × 0.95
m(CH₃CH₂OH) = 76.38 g; mass of pure ethanol
n(CH₃CH₂OH) = 76.38 ÷ 46.07 g/mol
n(CH₃CH₂OH) = 1.658 mol; amount of pure ethanol
c(CH₃CH₂OH) = 1.658 mol ÷ 0.1 l
c(CH₃CH₂OH) = 16.58 mol/l; the molar concentration of the solution
Molarity is defined as the number of moles of the solute per liter of the solution. It is denoted by M.
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what substance is lost from the leaves of a daffodil plans to make them turn yellow ?
Answer:
Daffodil leaves always turn yellow a few weeks after the plant blooms. This is normal and indicates that their job is finished for the season. The leaves have absorbed sunlight, which creates energy for the production of sugar that replenishes the bulb for the coming growing season.
Explanation:
A student finds another object that looks similar to the first
object. They weigh this second object and record the mass to
be 33.4.g They fill a graduated cylinder about halfway and
record the volume as 12.3mL. The student carefully drops the
object into the graduated cylinder and the water rises to a
volume of 21.7mL.
c) Is this second object, also pure gold? Justify your answer
with a calculation.
The object is not pure gold because it does not the same density as pure gold.
What is density?The density of an object is defined as the ratio of the mass to the volume of an object. We know that the density could be used to characterize an object. This is why we refer to the density of the object as an intrinsic property of the object. Since the density of the object does not change. We could use the density to determine if the second object is gold or not.
Mass of the object = 33.4.g
Inital volume of the water= 12.3mL
Final volume of the water = 21.7mL
Volume of the object = 21.7mL - 12.3mL = 9.4 mL
Density of the object = 33.4.g / 9.4 mL = 3.55 g/mL
The object is not pure gold because it does not the same density as pure gold.
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calculate the mass of iron(iii) oxide fe2o3 that contains a billion ×1.00109 iron atoms. be sure your answer has a unit symbol if necessary, and round it to 3 significant digits.
The mass of Fe2O3 is 8.839 x 10^-14 g
The first step is to determine the number of moles of Iron (III) Oxide that contains a billion O atoms.
1 x 10^9 O atoms*1 mol O/6.022 x 10^23 atoms*1 mol Fe2O3/3 mol O = 5.535 x 10^-16 mol Fe2O3
By using the molar mass of Iron (III) Oxide, we arrive with the mass in grams that contains a billion O atoms.
5.535 x 10^-16 mol Fe2O3*159.69 gram/1 mol Fe2O3
= 8.839 x 10^-14 g Fe2O3
Hence, mass of Fe2O3 is 8.839 x 10^-14 g
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Find the average atomic mass for Mg if 78.99% of Mg atoms are 24Mg with a mass of 23.9850419 amu, 10,00% are 25Mg with a mass of 24.9858370 amu, and 11.01% are 26Mg with a mass of 25.9825930 amu.
The average atomic mass of Mg is 24.30505 u
The average atomic mass of Mg (0.7899 x 23.98504) + (0.100 x 24.98584) + (0.1101 x 25.98259)
= 24.30505 u
The total average mass of the atoms in a naturally occurring sample of an element is the average atomic mass, also known as atomic weight. The most common unit of measurement for average masses is the unified atomic mass unit (u), which is equal to precisely one-twelfth of the mass of a neutral carbon-12 atom.
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I need help please. I need 1-5
Answer:
EBADCExplanation:
P.S - Get a good lighting when taking the pictures because you kinda gave me a hard time reading the questions. Thank you.
Mike has an object thrown in the air. It has the mass of 10kg and is 2 meters above the ground. Calculate the potential energy of the object
Answer:
200J or 196J
Explanation:
mass = 10kg
gravity = 9.8 or 10 ( the answer might vary if u take either 10 or 9.8 as the gravitational value )
height = 2 meter
p.e= mgh
option 1
10×10×2 = 200 Joules
option 2
10×9.8×2 = 196 Joules
better to take 9.8 as gravitational value
hope it helps
types of boiling and give two examples
Answer:
nucleate boiling where small bubbles of vapour form at discrete points, and critical heat flux boiling where the boiling surface is heated above a certain critical temperature and a film of vapor forms on the surface.
Explanation:
hope this helps :3
Answer:mark pls
Explanation:
(1-5) the burning by fossil fuels by humans in 2012 introduced approximately 8 petagrams (pg) of carbon per year into the atmosphere in the form of co2
8 x 10^12 kg C yr^-1 of C were placed in the atmosphere each year.
kg of C yr-^1 = (8 Pg C yr^-1)(10^15 g C/1 Pg C)(1 kg C/1000 g C)
kg of C yr^-1 = 8 x 10^12 kg C yr^-1
Petagrams is unit of mass equal to 1,000,000,000,000,000 (10^15) grams. Symbol: Pg
Sometimes used in Carbon Dioxide numbers, it is equivalent to Metric Gigatons (Giga) 10^9 x (Ton) 10^3 x (kg) 10^3 = 10^15
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Draw the conjugate acid for the following base (lone pairs do not have to be drawn):
Answer:
\ \
=o + H+ ----> =o
/- /
conjugate acid is the product that is differ from the base by one proton
9. High biodiversity is a sign of a healthy ecosystem. There should be a
sufficient number of producers, consumers, and decomposers to have a
balance in the ecosystem.
O True
O False
True, there should be a balance maintained between consumers, producers and Decomposers. An increase or decrease in either of them would lead to an imbalance in the ecosystem.
Answer:false
Explanation:
shi a, mou b, correll jc. association analysis for oxalate concentration in spinach. euphytica. 2016;212(1):17–28
Oxalate concentrations ranged widely from 53.4 to 108.8 mg/g on a dry weight basis and 647.2 to 1286.9 mg/100 g on a fresh weight basis, exhibiting a variation that was close to normal.
Association analysis for oxalate concentration in spinachSpinach oxalate content reduction is a key breeding goal. Conducting association analysis and locating SNP markers connected to oxalate concentration in spinach germplasm were the main objectives of this study. The association analysis of oxalate concentration employed a total of 310 spinach genotypes, including 300 USDA germplasm accessions and ten commercial cultivars. 841 SNPs were found among the genotypes tested for the association study using genotyping by sequencing. Oxalate concentration in spinach varies widely, indicating that it is a complicated quantitative property that may be regulated by a number of genes, each of which has a little impact on the tested spinach panel.With the aid of SNP markers, breeders may be able to choose germplasm for spinach breeding projects with lower oxalate concentrations.learn more about oxalate here
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