a half meter ruler is pivoted at its midpoint and balances whaen a weight of 20N is placed at the 10 cm mark and a weight W is placed at the 45 cm mark on the ruleer. Calculate the weight W

The airplane starts form rest, then accelerates by rate of [tex]3m/s^2[/tex] until it reaches 102m/s at the end of the runway. so we have:

[tex]Vo=0m/s\\Vf=102m/s\\a=3m/s^2\\\\[/tex]

From the equations of uniformly accelerated motion (since the airplane's acceleration is uniform) [tex]'Vf^2=Vo^2+2aS' \\[/tex] is compatible to find the minimum runway length (S).

[tex]Vf^2=Vo^2+2aS\\Vf^2-Vo^2=2aS\\S=Vf^2-Vo^2/2a\\[/tex]

[tex]S=((102m/s)^2-(0m/s)^2)/2m/s^2\\S=(10404m^2/s^2-0m^2/s^2)/2m/s^2\\S=(10404m^2/s^2)/2m/s^2\\S=5202m[/tex]

Answer:

Explanation:

A simple machine is the simplest device that performs work. A simple machine applies a single force to a single load and generally acts as a building block in developing more complex, compound machines. Simple machines usually fall into one of six categories, including: lever, wheel and axle, pulley, inclined plane, wedge and the screw.

I hope this helps you ")

Answer:

A alkali metals hope this helps

Answer: c. alkaline earth metal

Explanation: group II elements in the periodic table are generally found as 2+ ions.  This is because they have lost two electrons to ionic bonding.

The total energy of the coaster at that point is 1274000 J.

Energy can be defined as the ability or the capacity for a body to perform work.

From the question, to calculate the total energy of the coaster at that point, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute the values above into equation 1

Hence, the total energy of the coaster at that point is 1274000 J.

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The magnitude of its Vfy i.e Vertical componet is mathematically given as

V=705.6 m/s

This is further explained below.

Generally, At this point, we need to do an analysis of the vertical motion of the item, which may be thought of as a free fall motion with a constant acceleration.

g = 9.8

As a result, we are able to employ the suvat equation that is as follows:

v = u +at

As a result, the following expression may be used to determine the magnitude of the object's vertical velocity after t = 72 seconds:

v = 0 + (9.8) (72)

V=705.6 m/s

In conclusion, the magnitude

V=705.6 m/s

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Answer:

Explanation:

Given:

m = 5.36 kg

h = 2.2 m

___________

A -?

Work:

A =m·g·h

A = 5.36·9.8·2.2 ≈ 116 J

The player’s initial velocity, given the data from the question is 15.68 m/s

We'll begin by obtaining the time taken for the player to reach the maximum height. This can be obtannnned as follow:

T = 2t

3.2 = 2t

Divide both sides by 2

t = 3.2 / 2

t = 1.6 s

v = u + gt

0 = u + (-9.8 × 1.6)

0 = u - 15.68

Collect like terms

u = 0 + 15.68

u = 15.68 m/s

Thus, the initial velocity of the player is 15.68 m/s

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u = initial speed = 10 m/s

v = final speed = 14 m/s

Impulse is 2000 N/s

Given,

Mass of car = 500 kg

Force = 200 N

Acceleration = F/M

Acceleration = 0.4 m/s^2

Calculating the final speed,

u = initial speed = 10

v = final speed = ?

t = time of acceleration

v = u + at

v = 10 + (0.4 x 10)

v = 14m/s

Impulse = Ft = mv - uv

(200 x 10) = (500 x 14) - (500 x 10)

2000 = 7000 - 5000

2000 = 2000

Hence our answer is correct and the impulse is 2000 N/s.

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Magnus effect generates lift on a Flettner rotor. It is named as Magnus effect, as it was first experimentally investigated by H G Magnus.

A Flettner rotor is a smooth cylinder with a disc plate at the end of it. The disc at the end is called as Thom disc. It optimses aerodynamic efficiency at the end of rotor. The rotor is rotated along its axis by the ship's engines. It is used in ships and airplanes. In ships it is mounted upright whereas in airplanes it is mounted sideways in place of wings.

As air strikes the rotating rotor at right angles to the axis of rotor, the ship moves in the direction perpendicular to both the rotation axis and air flow direction due to aerodynamic force created by Magnus effect.

Therefore, Magnus effect generates lift on a Flettner rotor.

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A horizontal net force F is exerted on an object at rest and with a speed of 4.0 m/s. The object will be 5 kg in weight.

An influence with the capacity to change the motion of an object is called a force. A force acting on an object with mass can cause it to accelerate or modify its velocity. Pushing or pulling is a simple way to explain the force.

According to the question, the given values are :

Initial Velocity, u = 0 at x = 0

Final Velocity, v = 4 m/s at x = 4 m

Work done=Area on graph

1/2 m(v²-u²) = 1/2 × base × height

m (4²-0²) = 4 × 20

m = 5 kg

Hence, the mass of the object will be 5 kg.

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It is an example of acceleration due to the wind.

Acceleration: the rate at which the speed and direction of a moving object vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting. Both effects contribute to the acceleration of all other motions.

Acceleration is a vector quantity since it has both a magnitude and a direction. A vector quantity is also velocity. The velocity vector change during a time interval divided by the time interval is the definition of acceleration.

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Answer:

See below

Explanation:

On Earth , turtle weight  = 5 * 9.81 =49 N

  Moon =  490.5 * 1/6 = 8.18 N

  Jupiter    490.5 * 2.64 = 129.4 N

129.4 - 8.18 N = 121.2 N more on Jupiter than moon

The magnitude of current flowing through the conductor is 0.5A.

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The density of 100 ml of liquid mercury in the graduated cylinder that weighs 25 grams is 13.6 g / ml

ρ = m / V

ρ = Density

m = Mass

V = Volume

V = 100 ml

Mass of cylinder = 25 g

Combined mass of cylinder and mercury = 1385 g

Mass of mercury = 1385 - 25 = 1360 g

ρ = 1360 / 100

ρ = 13.6 g / ml

Density is the amount of molecules present in a given volume of the substance. It is denoted by ρ.

Therefore, the density of 100 ml of liquid mercury in the graduated cylinder that weighs 25 grams is 13.6 g / ml

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Answer:

2.5

Explanation:

you just subtract basic math

Electrons are responsible for the properties of atoms.

The atom is the smallest particle of a substance that can take part in chemical reaction. We know that an atom is composed of smaller particles that are called subatomic particles. The basic subatomic particles are; electrons proton and neutrons.

The protons and the neutrons are bond up in the nucleus and do not contribute to the properties of the atom. The properties of the atom are due to loss or gain of electrons.

Thus electrons are responsible for the properties of atoms.

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When Two Objects Are Charged By Rubbing Or Peeling, both objects have both types of charge, but there are different amounts of each type on each object. (One object has more negative charges than positive chrages and the other object has more positive charges than negative charges); option C.

Charges are the inherent properties of the particles of matter which determines how the atoms will react when placed in an electric filed.

There are two types of charges in an atom:

The electrons in an atom can be easily transferred from one atom to another, hence objects can be charged by rubbing or peeling one against the other.

When when two objects are rubbed or peeled against each other, electrons move from one object to the other.

The object that acquires the electrons become negatively charged whereas the object that loses the electrons become positively charged. However, both objects have both electrons and protons present in them.

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Answer:

because

Explanation:

ok just because

Answer:

2 s

Explanation:

2000 ms  /  1000 ms/s = 2 s

You will gain 150 minutes by driving at an average speed of 5 miles per hour

Speed is the distance travelled per unit. Mathematically, it can be expressed as:

Speed = distance / time

We'll begin by calculating the distance travelled. This can be obtained as follow:

Speed = Distance / time

Cross multiply

Distance = speed × time

Distance = 30 × 0.5

Distance = 15 miles

Speed = distance / time

5 = 15 / time

Cross multiply

5 × time = 15

Divide both side by 5

Time = 15 / 5

Time = 3 hours

Time gained = 180 - 30

Time gained = 150 minutes

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The direction of vector A which is parallel but opposite to the vector I is is 305°

Direction of vector I = 125°

Vector I makes a parallel line with vector A. Consider vector A and I to be collinear. Collinear lines makes up an angle of 180°

[tex]Angle_{A}[/tex] + [tex]Angle_{I}[/tex] = 180°

[tex]Angle_{A}[/tex] + 125° = 180°

[tex]Angle_{A}[/tex] = 55°

Direction of vector A = 360° - 55° = 305°

The direction of a vector is the angle, the vector creates with positive x-axis in counter clockwise direction.

Therefore, the direction of vector A is 305°

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The equation we use is to determine the acceleration of the car, it is a Uniformly Varied Rectilinear Motion (MRUV) is:

             [tex]\boxed{\sf{a=\dfrac{V_{f}-V_{o}}{t}}} \ \ \ \ \ \sf{\longmapsto \ \ \ \ \ Where \ \ \ \ \begin{cases}\sf{V_{f} = Final \ velocity} \\ \sf{V_{o}=Initial \ velocity} \\ \sf{a=Acceleration} \\ \sf{t=Time} \end{cases}}[/tex]

We extract the data of the problem:

We plug these values into the scalar equation above.

                                         [tex]\sf{a=\dfrac{V_{f}-V_{o}}{t}}[/tex]

                                   [tex]\sf{a=\dfrac{20 \ m/s-40m/s}{10 \ s} }[/tex]

                                          [tex]\sf{a=\dfrac{-20 \ m/s}{10 \ s} }[/tex]

                                         [tex]\boxed{\boxed{\boldsymbol{\sf{a=-2 \ m/s^{2} }}}}[/tex]

Rpta: The acceleration of the car was -2 m/s^2.

False. The hammer is not the closest of the three bones in the middle ear to the cochlea.

The three bones in the middle ear are Malleus, Incus and Stapes. Malleus is commonly known as Hammer, Incus as anvil and stapes as stirrup. Hammer is attached to the ear drum, Anvil is the chain of the bones and  Stirrup is attached to the oval window.

Cochlea is a hollow, spiral shaped bone present in the inner ear. So the order of bones from outside to cochlea is Hammer first, followed by Anvil in the middle and Stirrup near the inner ear where cochlea is present.

Therefore, the hammer is not the closest of the three bones in the middle ear to the cochlea

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The Snell's law is also known as second law of refraction.

According to the Snell's law , the ratio of the sine of angle of incidence to the sine angle of refraction is equal to a constant of a light ray for two media . And it is given as,

[tex]\frac{sini}{sinr} = constant[/tex]

Where, [tex]sin i[/tex] is the angle of incidence light ray, [tex]sinr[/tex] is the angle of refracted light ray. Refractive index, also known as this constant and referred to as the second medium with respect to the first medium i.e. (₁μ₂) ,therefore the equation can be written as,

μ₁/μ₂ = ₁μ₂= [tex]\frac{sini}{sinr} = constant[/tex]

Refraction is a phenomena in which a light ray bends as it travels through one medium through another .

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From conservation of energy, the potential energy will begin to reduce as soon as it starts to fall to the ground to gain kinetic energy.

Conservation of energy state that energy can not be created nor destroyed but can only be transformed from one form to another.

Given that a football is punted to its maximum height. At this maximum height, the kinetic energy is zero while the potential energy is maximum.

As soon as it starts to fall to the ground it starts to gain kinetic energy. And what will happen to the potential energy of the football as it starts to gain kinetic energy is the reduction of the potential energy.

Therefore, the potential energy will begin to reduce as soon as it starts to fall to the ground to gain kinetic energy.

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The volume of the rock with a density of 45 g/mL and a mass of 855 grams is 19 ml

We know that,

ρ = m / V

where,

ρ = Density

m = Mass

V = Volume

Given that,

ρ = 45 g / ml

m = 855 g

V = 855 / 45

V = 19 ml

Density is the measure of amount of molecules present in substance. It is denoted by ρ. Its unit is usually g / ml.

Therefore, the volume of the rock with a density of 45 g/mL and a mass of 855 grams is 19 ml

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The height above the ground reached by the rock is 7.7 m.

The time taken for the rock to travel half of a second after it is released is 1.12 seconds.

The velocity of the rock half of a second after it is released is 15.9 m/s.

The velocity of the rock 1.5 seconds after release is 25.7 m/s.

The vertical height traveled by the rock is calculated as follows;

h = u²/2g

h = (11²)/(2 x 9.8)

h = 6.2 m

Height above the ground reached by the rock = 1.5 m + 6.2 m = 7.7 m

t = √2h/g

t = √(2 x 6.2/9.8)

t = 1.12 seconds

v = u + gt

v = 11 m/s   +  (9.5 x 0.5)

v = 15.9 m/s

v = u + gt

v = 11 m/s   +  (9.5 x 1.5)

v = 25.7 m/s

Thus, the height above the ground reached by the rock is 7.7 m.

The time taken for the rock to travel half of a second after it is released is 1.12 seconds.

The velocity of the rock half of a second after it is released is 15.9 m/s.

The velocity of the rock 1.5 seconds after release is 25.7 m/s.

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