A light aircraft travels 6 miles per hour less than three times the speed of a van. If the van can travel 72 miles in the same time it takes the aircraft to travel 204 miles, then what is the average speed of each?

Answer:

80 cm / 180 cm / 120 cm

Step-by-step explanation:

the smallest common multiple of 3, 4 and 2 is 12.

so, to be able to truly compare these fractions we need to bring all denominators to .../12.

1/3 = 4/12

3/4 = 9/12

1/2 = 6/12

in total we have therefore 19 (4+9+6) equally large parts of the ribbon that are then combined :

4 parts for the first segment.

9 parts for the second segment

6 parts for the third segment.

so, one part is

380 cm / 19 = 20 cm

therefore the first segment of the ribbon is

4×20 = 80 cm long

the second segment

9×20 = 180 cm long

the third segment

6×20 = 120 cm long

Answer:

The midpoint is -4

Answer:

Economics and political science but not Geography

is right answer i think

Answer:

11/12.

Step-by-step explanation:

The lowest common denominator of 6 and 4 is 12, so we have

4/6 + 1/4

=  4*2 / 6*2 + 1*3 / 4*3

= 8/12 + 3/12

= 11/12.

Answer:

L = length of arc , R = radius

radian angle = L / R

L = R* radian angle

L = R * 1/3

L = R/3 #1

Area of sector = 1/2 L*R

By substitution using #1

Area of sector = 1/2 * R/3 * R

9 = R^2 /6

R^2= 6*9

R^2= 36

R =✓36

R = 6

Answer:

x = 43°

Step-by-step explanation:

59 + 78 + x = 180

137 + x = 180

(137 - 137) + x = 180 - 137

x = 43°

Answer:

The choose B) a=12, b=12

Step-by-step explanation:

sin45= a/12√2 —> a=12

cos 45= b/12√2 —> b=12

I hope I helped you^_^

9514 1404 393

Answer:

  4n

Step-by-step explanation:

For positive multiple number 'n', the value is 4n.

  a[n] = 4n . . . . . where a[n] is the n-th term of the sequence

Answer:

an = 4n

Step-by-step explanation:

got it right on test

Answer:

is your answer. I HOPE YOUR DAY GOES GREAT.

Answer:

c = (2 - ad) / b

Step-by-step explanation:

Subtract both sides by ad

bc = 2 - ad

Divide both sides by b

c = (2 - ad) / b

The rational expressions that sum to  [tex]\frac{2x+3}{(x+3)(x-5)} = \frac{2x}{(x+3)(x-5)} + \frac{3}{(x+3)(x-5)}[/tex]

The given expression is:

[tex]\frac{2x+3}{x^2-2x-15}[/tex]

Factorize the denominator

[tex]x^2-2x-15\\x^2-5x+3x-15\\x(x-5)+3(x-5)\\(x+3)(x-5)[/tex]

The given expression therefore becomes:

[tex]\frac{2x+3}{(x+3)(x-5)}[/tex]

This can be split into the sum:

[tex]\frac{2x+3}{(x+3)(x-5)} = \frac{2x}{(x+3)(x-5)} + \frac{3}{(x+3)(x-5)}[/tex]

Learn more here: https://brainly.com/question/17103002

Answer: 2x+3/x^2-2x-15 = 13/8(x-5) + 3/8(x+3)

Step-by-step explanation: I took the test and used the answer above and got the answer wrong, then the test gave me this answer:

Answer:

M=11

Step-by-step explanation:

Answer:

11

Step-by-step explanation:

To find the midpoint ( or middle) we take the average of the endpoints

(A+B)/2 = (0+22)/2 = 22/2 = 11

Answer:

765

Step-by-step explanation:

1)4.25/100=0.0425

2)0.0425*3600=153

3)153*5=765

Answer:

. The line passes through the quadrants I, II and III.  ii. The line intersects the Y-axis at (0, 1).

Hi ;-)

[tex]990:(12-9)^2=990:3^2=\\\\=990:(3\cdot3)=990:9=\boxed{110}[/tex]

Answer:

70; The following graph is simply a horizontal line at the value 70.

Step-by-step explanation:

Answer:

Graph A. On a coordinate plane, a curve approaches y = 0 in quadrant 1 and curves up into quadrant 2. It goes through (2, 49) and (0, 100).

Step-by-step explanation:

Edge

Answer:

0.09

Step-by-step explanation:

hope it helps!!!!!!

Read each number from top to bottom. Each digit is in base 20, and as I pointed out in another question of yours, 1 bar = 5, 1 dot = 1, and disk = 0.

(47) Only 1 digit here, with 2 bars and 4 dots. So this is 14.

(49) 3 digits, in order from top to bottom: 19, 0, 6. So this number is

[19]06₂₀ = 19×20² + 0×20¹ + 6×20⁰ = 7606

(51) 3 digits: 8, 8, 8.

888₂₀ = 8×20² + 8×20¹ + 8×20⁰ = 3368

(53) 4 digits: 2, 0, 0, 11.

200[11]₂₀ = 2×20³ + 0×20² + 0×20¹ + 11×20⁰ = 16011

(55) 4 digits: 10, 10, 0, 10.

[10][10]0[10]₂₀ = 10×20³ + 10×20² + 0×20¹ + 10×20⁰ = 84010

(57) 6 digits: 5, 10, 0, 6, 2, 3.

5[10]0623₂₀ = 5×20⁵ + 10×20⁴ + 0×20³ + 6×20² + 2×20¹ + 3×20⁰ = 17602443

(59) 6 digits: 10, 5, 0, 0, 11, 4.

[10]500[11]4₂₀ = 10×20⁵ + 5×20⁴ + 0×20³ + 0×20² + 11×20¹ + 4×20⁰ = 32800224

Answer:

the answer is the second option which is 6⅓

Answer:

6^1/6

Step-by-step explanation:

Rewriting with the exponents as fractions

(6^1/3) ^1/2

We know a^b^c = a^(b*c)

6^(1/3*1/2)

6^1/6

Answer:

5539

Step-by-step explanation:

You should conclude that the number in the thousands place and the one in the 100s place are the same.

x * 1000 + x * 100 + y + x + 4

So you could sum the digits as

3x + y + 4 = 19   Subtract 4 from both sides

3x +  y = 15

x can be six           That means y = 1 which is OK

x can be five          That means y = 3 which is OK

Now we run into a little grief. Can x be 4? No

x cannot be 4          that would mean that y = 19 - 12 = 7 The tens digit is too big.

Come to think of it, x cannot be 6 because then the units digit will be 10 -- not possible.

So the answer is

1000*5 + 100*5 + 10*3 + 9

5539 is the answer.

Thanks for posting.

We want to find a 4-digit number that meets some given conditions. We will find two, which are:

4438 and 5509

A general 4-digit number can be written as:

a*1000 + b*100 + c*10 + d

Where a, b, c, and d are single-digit numbers.

a is the thousands digit

b is the hundreds digit

c is the tens digit

d is the units digit.

Here we know that:

"the value of the digit in the thousands place is 10 times greater than the value of the digit in the hundreds place."

So the first term is 10 times the second term, this means that:

(a*1000) = 10*(b*100)

a*1000 = b*1000

a = b

-the least (the smaller one) digit is in the tens place.

so:

c < a, b, d

- The sun of the digits is 19.

So:

a + b + c+ d = 19

-The digit in the ones place is 4 more than the digit in the hundreds place.

so:

d = b + 4

Now we can rewrite all of these conditions as:

Using the first one, we can replace all the b's by a's in the other conditions, so we have:

Now we can use the third equation and replace it in the second one to get:

2a + c + d = 19

2a + c + (a + 4) = 19

3a + c + 4 = 19

3a + c = 19 - 4

3a + c = 15

Now we need to remember that:

c < a.

So we can try with different values of a.

For example, if a = 3, then:

3*3 + c = 15

9 + c = 15

c = 15 - 9 = 6

here we have c > a, so we can discard this.

If a = 4, then:

3*4 + c = 15

12 + c = 15

c = 15 - 12 = 3

c < a

From this we can construct our number:

a = b = 4

c = 3

d = b + 4 = 4 + 4 = 8

Then the number is:

4438

If a = 5, then:

3*5 + c = 15

15 + c = 15

c = 15 - 15 = 0

c < a

So we also can have:

a = b = 5

c = 0

d = b + 4 = 9

Such that the number is:

5509

And if a is equal to or larger than 6 we have problems, because

3*6 + c = 15

18 + c =15

c = 15 -18 = -3

And c can't be a be a negative number.

So we can conclude that we found two 4-digit numbers that meet all the conditions, and these are:

4438 and 5509

If you want to learn more, you can read:

https://brainly.com/question/19902993

Answer:

3³  = 27

Step-by-step explanation:

I'm guessing you need answer E

Answer:

2,3,5,7,11,13,17,19,23 and 29

Step-by-step explanation:

hope this helps

Answer:

60/125 which can be reduced to 12/25

Step-by-step explanation:

Gina wins

2/5 * 2/5 = 4/25

3/5 * 2*5 * 2/5 = 12 /125

2/5 * 3/5 * 2/5 = 12/125

Fred Wins

3/5 * 3/5 = 9/25

2/5 * 3/5 * 3/5 = 18/125

3/5 * 2/5 * 3/5 = 18/125

P(3 sets) = (18 + 18 + 12 + 12)/125 = 60/125

P(2 sets) = (20 + 45)/125 = 65/125

I found the probability of 2 sets so I could add the results together to see if the probability totals 1. It does. This question is done correctly.

9514 1404 393

Answer:

  14xv^3

Step-by-step explanation:

Coefficients are 28 and 14, which have a GCF of 14.

x exponents are 1 and 6, so the GCF is x^1 = x

y exponents are 8 and 0, so the GCF is y^0 = 1

v exponents are 7 and 3, so the GCF is v^3

The GCF of the two terms is the product of the factors just found:

  14xv^3

Answer:

b)68

Step-by-step explanation:

i think helping you...say correct or no...

Answer:

(a).

[tex]S_{n} = \frac{n}{2} (4n + 20) \\ \\S _{n - 1} = \frac{(n - 1)}{2} (4n - 4 + 20) \\ \\ S _{n - 1} = \frac{(n - 1)}{2} (4n + 16) \\ \\S _{n - 1} = \frac{(n - 1)(4n + 16)}{2} \\ \\ { \boxed{S _{n - 1} = {2 {n}^{2} + 6n - 8}}} \\ [/tex]

(b).

from general equation:

[tex]S _{n - 1} = \frac{(n - 1)}{2} (4n + 16)[/tex]

first term is 4n

common difference:

[tex]16 = \{(n - 1) - 1 \}d \\ 16 = (n - 2)d \\ d = \frac{16}{n - 2} [/tex]

Answer:

[tex]\frac{9}{14}[/tex]

Step-by-step explanation:

1. Add two fractions together.

[tex]\frac{3}{7}[/tex] + [tex]\frac{6}{7}[/tex] = [tex]\frac{9}{7}[/tex]

2. Divide by 2.

[tex]\frac{9}{7}[/tex] ÷ 2 = [tex]\frac{9}{14}[/tex]