The displacement of the victorious snail will be 336.0mm .
The term displacement refers to a change in an object's position. It is a vector quantity and has a direction and magnitude .
We are given here,
Average velocity of snail = Δv = 2.4 mm/s
Time interval taken by snail = Δt = 140 s
The average velocity can be define as, the rate of change in displacement in the particular time interval of the object. The formula can be given as,
Δv = Δx / Δt
Where, Δv is the average velocity, Δx is the change in displacement, Δt is the time interval of an object. Unit can be written as meter/second.
Therefore, the displacement of snail during the race can be calculated by the relation i.e.
Δx = Δv × Δt
Thus , putting the values in above equation we get,
Δx = 2.4mm/s × 140s
Δx = 336.0 mm
Hence, the snail would move 336.0 mm in 140s.
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Determine the upward applied force, in lbf, required to accelerate a 4.5-lb model rocket vertically upward, with an acceleration of 3 g’s. The only other significant force acting on the rocket is gravity, and 1 g 5 32.2 ft/s2.
The upward applied force will be 579.249 lbf.
Mass of the rocket, m = 4.5 lb
Acceleration, a = 3g
as we know g = 32.2 ft/s²
therefore acceleration, a = 3 * 32.174 = 96.522 ft/s²
According to the Newton's second law of motion, which states that the magnitude of the force acting on an object is equal to the product of the object's mass and the acceleration with which it is moving.
Mathematically, it is F = [tex]\frac{mass}{acceleration}[/tex] ;
Upward force (F₀) for the rocket will be the sum of Force applied by the weight (Fₓ) and the force by the acceleration(Fₐ).
i.e. gₙ *F₀ = Fₓ + Fₐ
Fₓ = mg
Fₐ = ma
F₀ = ma + mg
F₀ = m (a + g)
F₀ = 4.5 (96.522 + 32.2)
F₀ = 4.5 * 128.722
F₀ = 579.249 lbf.
The upward applied force, required to accelerate a 4.5-lb model rocket vertically upward will be 579.249 lbf.
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1. A 10kg ball moving at a speed of 6 m/s strikes another 5kg ball at rest with a contact time of 0.5 seconds. The 10kg comes to a complete stop. (a) What average force was exerted on the 10kg ball? (b) What average force was exerted on the 5kg ball? (c) What is the final momentum of the 5kg ball? (d) What is the initial momentum of the 10kg ball?
a)average force was exerted on the 10kg ball= -120 N
b)average force was exerted on the 5kg ball= 60N
c)What is the final momentum of the 5kg ball= 2.5 kg m/s
d) the initial momentum of the 10kg ball=60 kg m/s
The average force can be calculated by formula F=m(vf–vi)/ Δt so, 10 (0-6)/0.5 = -120 N the minus is representing opposite direction
the average force on the 5 kg ball = 5(6-0)/0.5= 60 N
The final momentum of 5 kg ball is 5 X 0.5 =2.5 kg m/s and initial momentum of 10 kg ball = 10 X 6 = 60 Kg m/s.
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Two football players hit each other head on in a football game. One football
player had an acceleration of 4 m/s² and a mass of 150 kg. The second football
player had an acceleration of 2 m/s² and a mass of 200 kg. Calculate the force
each player had when they hit. What will be the net force of both players and who
knocked who back.
Answer:
200N in Player 1's direction
Player 2 is knocked back
Explanation:
Let's start by working out the force exerted by each player by using the equation F=ma, Force = Mass x Acceleration.
Player 1 has an acceleration of 4m/s2 and a mass of 150kg, therefore their force will be: [tex]F = (150)(4)[/tex], [tex]F=600N[/tex]
Player 2 has an acceleration of 2m/s2 and a mass of 200kg, therefore their force will be: [tex]F = (200)(2)[/tex], [tex]F=400N[/tex]
They are both coming from different directions so we can find the net force by subtracting one from the other: [tex]600-400=200N[/tex]
Player 1 has the higher force so the net force will be 200N in the direction Player 1 is travelling in and Player 2 will be the one knocked back.
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A ball dropped from a window strikes the ground at 4.00 s later. How high is the window above the ground?
Answer:
15
Explanation:
a half meter ruler is pivoted at its midpoint and balances whaen a weight of 20N is placed at the 10 cm mark and a weight W is placed at the 45 cm mark on the ruleer. Calculate the weight W
Answer:
W = 15 N
Explanation:
The moments from the center mus be equal for balance to occur
center is at 25 cm ( for a 1/2 meter stick)
moment one : 15 cm * 20 N
moment two : 20 cm * W these must be equal
15 * 20 = 20 * W W = 15 N
story problem questions for newtons 3rd law
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The property that the wire must have to be used in the game is high conductivity.
What is a wire?A wire is a material that is used to carry electric current from one point to another. Thus, we know that when we connect wire to a source, there is a movement of electrons. We can thus see that the wire is able to conduct electricity.
Having said that, the game as shown in the image attached has to do with the formation of a circuit and the flow of electricity in that circuit that is formed.
We can see that the property that the wire must have to be used in the game is high conductivity.
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A car traveling 83.0 km/h on a straight road is 1900 m behind a truck traveling at 61.0 km/h . How much time will it take the car to catch up with the truck?
A car traveling 83.0 km/h on a straight road is 1900 m behind a truck traveling at 61.0 km/h. The required voltage is 10 Volts.
What is Electric Current ?Electric current is defined as the rate at which charge passes a fixed unit cross sectional area.
What is Voltage ?Voltage is defined as the physical quantity required to move charge from one end to other.
What is Resistance ?Resistance is defined as the the factor which opposed the electric current.
It states that voltage is directly proportional to electric current
V=IR
Given:
current (I) = 0.1 A
resistance (R) = 100 Ω
Now from definition of voltage we have:
V = I × R
V = 100 × 0.1
V = 10 volts
Thus from the above conclusion we can say that therefore the required voltage is 10 volts.
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A stone of mass 6.74kg is dropped from rest at a height of 6.02m. What impulse does gravity impart to this stone from the instant is dropped until it hits the ground, assuming negligible air resistance?
The impulse the gravity imparts on the stone from the instant it was dropped until it hits the ground is 72.66 Ns
What is impulse?
This is defined as the change in momentum of an object.
Impulse = change in momentum
Impulse = final moment – Initial momentum
Impulse = force × time
How to determine the timeInitial velocity (u) = 0 m/sAcceleration due to gravity (g) = 9.8 m/s²Height (h) = 6.02 mTime (t) =?h = ½gt²
6.02 = ½ × 9.8 × t²
6.02 = 4.9 × t²
Divide both side by 4.9
t² = 6.02 / 4.9
Take the square root of both side
t = √(6.02 / 4.9)
t = 1.1 s
How to determine the impulseTime (t) = 1.1 sMass (m) = 6.74 kgAcceleration due to gravity (g) = 9.8 m/s²Force (F) = mg = 6.74 × 9.8 = 66.052 NImpulse =?Impulse = Force × time
Impulse = 66.052 × 1.1
Impulse = 72.66 Ns
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During weather that may produce freezing temperatures, Florida orange growers often spray water on their orchards to protect them. Which of the following best explains why this helps protect orange trees and fruit from freezing?
The statement that best explains why this helps protect orange trees and fruit from freezing is that the transfer of thermal energy in water as it freezes protects the orange trees by transferring heat energy from the orange trees and fruit. That is option A.
What is freezing?Freezing is the phase transition that involves the change of a liquid substance into a solid form as it's temperature becomes lower.
During winter seasons which is a weather that can freez the orange fruits, the orange grower sprays water on their orange trees to prevent it from freezing.
The mechanism that prevents the orange from freezing is the transfer of the thermal energy between the water and the orange fruits.
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Explain why sound connot travel in a vaccum
Sound cannot travel through a vacuum because there are no particles to carry the vibrations.
Explanation:
When travelling through air, the speed of sound is about 330 metres per second (m/s).
What is the condition for block b to move downwards
A) mb/ma > sin theta - mew cos theta
B) mb/ma > cos theta + mew sin theta
C) mb/ma > sin theta + mew cos theta
D) mb/ma > cos theta - mew sin theta
And what would the condition for the block to move upwards
A) mb/ma < sin theta - mew cos theta
B) mb/ma < cos theta + mew sin theta
C) mb/ma < sin theta + mew cos theta
D) mb/ma < cos theta - mew sin theta
Answer:
Solution in Photo
Explanation:
To solve this question, draw the Free Body Diagram (FBD) for the whole system such that
theta < 90, it will be more clearer that way.
World should shift its energy dependence from nonrenewable sources to renewable sources. Write your opinion
Answer:
•Renewable energy, often referred to as clean energy, comes from natural sources or processes that are constantly replenished. For example, sunlight or wind keep shining and blowing, even if their availability depends on time and weather.
• Renewable sources of energy are better than nonrenewable sources because they refill themselves over a short period of time.
If a balloon with a weight of 3000 N (306kg) is lifted by an air force of 3300 N, in what will be its acceleration?
Answer:
See below
Explanation:
F = ma net force is 300 N upward
300 = 306 * a a = .980 m/s^2
If f(x) = 2x - 8 and g(x) = x4, what is (g°f)(5)?
080
Clear all
Enter the correct answer.
I
+00
DONE
6 of 15
Exit
The correct answer is 16.
The conventional way to express function is F(x).
You may alternatively describe it as a machine that has input, output, and some other ways they are connected.
You must first evaluate the first function in order to get the value of a composite function like this one. We placed the value for x in parentheses first in that equation because f is on the right side.
f (x) = 2x - 8
f (5) = 2 × 5 - 8
f (5) = 10 - 8
f (5) = 2
Once the first portion of a composite function has an answer, we insert that response into the second part. We insert our response (2) into g because it is on the left side.
g(x) = x^4
g(2) = 2^4
g(2) = 16
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The pressure at the top of Mount Everest is 0.31×105N/m2, and the temperature is −30∘C. The pressure at sea level is 1.0×105N/m2, and the temperature is 20∘C.
Determine how much more frequently you need to breathe on top of Mount Everest to inhale the same amount of oxygen as you do at sea level.
________ times more frequently.
It takes 2.7 times approximately to breath frequently on top of Mount Everest as you do at sea level.
What is Pressure ?Pressure is force per unit area. Pressure in fluid is the product of fluid density, acceleration due to gravity and the height. Pressure is measured in N/m²
Given that the pressure at the top of Mount Everest is 0.31×105N/m2, and the temperature is −30∘C.
From Ideal gas law, PV = nRT
Where
P = 31000 N/m²
T = - 30 + 273 = 243 K
n/V = ?
R = 8.314 1/K/Mol
n/V = P / RT
n/V = 31000 / (8.314 × 243)
n/V = 31000 / 2020.302
n/V = 15.34
When the pressure at sea level is 1.0×105N/m2, and the temperature is 20∘C, then
T = 20 + 273 = 293 K
n/V = 100000 / (8.314 × 293)
n/V = 100000 / 2436.002
n/V = 41.05
To determine how much more frequently you need to breathe on top of Mount Everest to inhale the same amount of oxygen as you do at sea level, you divide the two values. That is,
41.05 / 15.34 = 2.67
Therefore, it takes 2.7 times approximately to breath frequently on top of Mount Everest as you do at sea level.
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What are the reasons Flat Earther's use to prove their claim?
Answer:
The ground we walk on is flat, not round. Gravity doesn't exist. Objects don't fall down, the flat earth(disk) goes up with a force called dark energy. There is a 45 ft tall ice wall to prevent people from falling off the Earth.
Explanation:
Two ropes are attached to a heavy object. The ropes are given to two strong physics students (is there any other kind?) with instructions for each to pull with 1000 N of force. Determine the resultant force if the two students pull: a) in the same direction east.
You drop a 20 Ton object and a
10 Ton object at the same time.
How does the acceleration
compare through the fall
assuming minimal air resistance.
Explanation:
it dosent depend on the weights of the items. I'll reach the ground at same time taking as no air friction or restrictions.
i.e
v = u + gt
whte v is final velocity of the object
u is initial velocity of the object
g is acceleration due to gravity and
t is time. thanks
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Assuming there is little air resistance, the acceleration felt by both objects when one drops a 20-ton object and a 10-ton object at the same time will be the same.
Even though both objects accelerate at the same rate, the forces acting on them will be different because of their different masses. Newton's second law of motion states that an object's force is inversely proportional to its mass (F = ma). The 20-ton object will therefore encounter twice as much force as the 10-ton object, but their rates of acceleration will remain constant.
In conclusion, both the 20-ton and 10-ton objects will accelerate to about 9.8 meters per second squared when dropped simultaneously with little air resistance.
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Which of the following best describes a position versus time graph foran accelerating object?
Answer: I don't really see the answer choices.
Explanation:
A boat travels west at a speed of 20 m/s across a river that is flowing south at 9 m/s. What is the
resultant velocity of the boat?
Answer:
22m/s
Explanation:
This is a vector addition problem. First identify the two vectors: 20m/s in the -x direction and 9m/s in the -y direction. Since neither vector shares an axis component you can use the formula [tex]\sqrt{20^2+9^2\\[/tex] =21.93 (This is the Pythagorean Theorem where your non-hypotenuse sides are your velocity vectors). Round to 2 significant figures and you'll get 22m/s.
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why would astronomers make the planets line up in a straight line on a model?
A rescue helicopter lifts a 50kg rock climber. If he accelerates at 5m/s what is the tension of the rope
The tension of the rope is 750 N.
According to Newton's second law of motion, the mass of a rock climber, m = 50 kg, while lifting a thing upwards with an acceleration, the upward force must be larger than the weight of the object in order to have a net force in upward direction to induce acceleration in upward direction.
accelerating a rock climber upward with a rope,
a= 5 m/s
determining the rope's tension (T)
The following two forces are at work on the rock climber as it is raised:
Rope tension acting upward. The rock climber's weight acting downward. Using Newton's second rule of motion, we may now:
Mass times climber's acceleration equals net upward force.
T−m×g=m×aT
=m×(g+a)T
=50× (10+5) T
=750 N
The complete question is -A rescue helicopter lifts a 50 kg rock climber by a rope from a cliff face. The rock climber is accelerated vertically a 5m/s−² What is the tension in the rope?
a) 350N
b) 500N
c) 750N
d) 1500 N
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Not sure if it’s right can someone make sure
Explanation:
stones a and b will hit the ground at the same time because they are of identical weight I think your right
An engineer in a locomotive Sees a car stuck
on the track at a railroad crossing in front of
the train. When the engineer first sees the
car, the locomotive is 190 m from the crossing
and its spood is 18 m/s.
If the engineer's reaction time is 0.54 m.
what should be the magnitude of the mini-
mum deceleration to avoid an accident?
Answer in units of m/s
The magnitude of the minimum deceleration needed to avoid the accident is –0.89 m/s²
The solution of the question can be obtained by first approaching the relation between Speed, Distance and Time which is given by:
Speed = Distance/Time
Now according to question;
Speed = 18 m/s
Time = 0.54 s
Therefore, Distance = Speed×Time
Distance = 18 × 0.54
Distance = 9.72 m
Thus, the engineer travelled a distance of 9.72 m during the reaction time.
Now, there is a need to find distance between the engineer and the car. This can be obtained by:
Distance between the engineer and the car = Total distance - Distance during the reaction time
Distance between the engineer and the car = 190 – 9.72
Distance between the engineer and the car = 180.28 m
Finally, we need to determine the magnitude of the deceleration needed to avoid the accident. This can be obtained by using newton's third equation of motion, which is represented as:
v² = u² + 2as; where u is the initial velocity, v is the final velocity, a is the acceleration/deceleration and S is the distance.
According to the question;
Initial velocity (u) = 18 m/s
Final velocity (v) = 0 m/s
Distance (s) = 180.28 m
Deceleration (a) =?
Thus, using Newton's third equation of motion
0² = 18² + (2 × a × 180.28)
0 = 324 + 360.56a
=> –324 = 360.56a
=> a = –324 / 360.56
=> a = –0.89 m/s²
Therefore, the magnitude of the deceleration needed to avoid the accident is –0.89 m/s.
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When will you say a body is in Uniform acceleration and Non Uniform acceleration?
Answer:
(i) A body has a uniform acceleration if its velocity changes by equal amounts in equal intervals of time. The motion of a freely falling body is an example of uniform acceleraion.
(ii) A body has a non-uniform acceleration if its velocity changes by unequal intervals of time. The motion of a car on a crowded city road is an example of non-uniform acceleration.
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Temperature is a vector quantity because it can go down as well as up. True or false?
Answer:
Explanation:
temperature is a scalar quantity
One group of nursing home patients drinks orange juice before watching an
informative film. A similar group drinks water before watching the same film.
After the film, both groups are tested for their memory of the film's contents.
Here, the independent variable is:
The Independent variable here in this sentence is the type of drink each group was subjected to intake.
Independent variable in a experiment is the one which stands independent and acts as a control which influences the experiment's outcome. Independent variables are employed in a experiment to test whether the dependent variable changes accordingly.
Here, in this experiment the dependent variable, i.e., the theory to be tested is the memory of the patients. The independent variable here is the type of juice given to the patients, which acts as a control of the experiment's outcome. Any variable which alters the final result of the experiment and which can be controlled through out the experiment is termed as Independent variable.
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What can develop when the temperature of the ocean is 80°F. A. Tornado B. Tsunami C. Thunder Storm D. Hurricane
When the temperature of the ocean is 80°F what is likely to develop is Hurricane. That is option D.
What is Hurricane?Hurricane is a natural disaster that occurs over the tropical large water bodie such as the oceans which is characterized by low-pressure storm.
The factors that can cause the occurrence of hurricane include the following;
Increase in Ocean temperature: waters above 80 degrees Fahrenheit provide energy for a hurricane to form.Water movement: spinning in low-pressure areas of water creates a wave.Low wind shear : low wind shear allows a storm to grow large and strong.Therefore, when the temperature of the ocean is 80°F what is likely to develop is Hurricane.
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Answer: thunderstorm
Explanation:
When the sea surface is at least 80° Fahrenheit (27° Celsius), it can supercharge a thunderstorm. The storm sucks up that heat and water, which make the storm bigger. As it grows, air pressure at the center of the storm continues to drop, which causes the vacuum in the middle to grow stronger.
A car travels at a speed of 55 km/h for 2.4 h. How far has the car traveled during this journey?