Answer: The first step in determining the solution to the system of equations algebraically is [-4,-2].
Step-by-step explanation:
Determining the solution to the system of equations,
so, y=-x²-4x-3 and y= 2x+5, algebraically is to set the two equations are equal to:
-x²-4x-3 =2x+5
Then the solve in this equation
To put all terms into the lest side of the equation and group the terms:
solve it: -x²-4x-3-2x-5=0
-x²+(-4x-2x)+(-3-5)=0
-x²-6x-8=0
now you can multiply this equation by -1
x²+6x+8=0
and solve it using Quadratic equation
x(1,2)=[-b±√[tex]b^{2}[/tex]-4ac]/2a
replace with a=1,b=6,c=8 values
x(1,2)=[-6±√[tex]6^{2}[/tex]-4.8.1]/2.1
x(1,2) =[-6±√4]/2
x(1,2) =[-6±2]/2
x(1,2) =[-4,-2]
The first step in determining the solution to the system of equations algebraically is [-4,-2].
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"The unemployment rate has risen more than a percentage point to 8.9% in February from 7.1% last November." What is the relative change in the unemployment rate expressed as a percentage?
If the unemployment rate has risen more than a percentage point to 8.9% in February from 7.1% last November, then the relative change in the unemployment rate expressed as a percentage is 25.35%
Given,
The unemployment rate in February = 8.9%
The unemployment rate in November = 7.1%
The relative change in unemployment rate = [(unemployment rate in February - unemployment rate in November )÷ unemployment rate in November ] ×100
The relative change in unemployment rate= [tex](\frac{8.9-7.1}{7.1} )100[/tex]
=25.35%
Hence, If the unemployment rate has risen more than a percentage point to 8.9% in February from 7.1% last November, then the relative change in the unemployment rate expressed as a percentage is 25.35%
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What is the equation of a line through the points (0, 9) and (3, 0)?
0-9
3-0 y=-3x + 9
Obecause m=
Obecause m=
Obecause m=
O because m=
0-9
3-0 y=-3x + 3
3-0
0-9;y=-
y=-x+9
3-0
1
0-9; X=-3x+3
[tex](\stackrel{x_1}{0}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{0}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{0}-\stackrel{y1}{9}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{0}}} \implies \cfrac{ -9 }{ 3 }\implies -3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{9}=\stackrel{m}{-3}(x-\stackrel{x_1}{0}) \\\\\\ y-9=-3x\implies y=-3x+9[/tex]
During a science experiment Mary found the mass of two rocks to be 36.81 grams and 52.4 grams what is the total mass of these two rocks
Answer: 89.21g
Step-by-step explanation:
36.81g + 52.40g = 89.21g
Please help
(100 Points)
Answer:
Equation: (14.71-4.48) [divided by] 3 =x
"Answer x": 3.41
Explanation:
14.71-4.48=10.23
10.23/3 = 3.41
3.41
Evaluate 13a+4b when a = 2 and b = 5
Answer:
46
Step-by-step explanation:
13a+4b
Substitute
13(2)+4(5)
Multiply
26+20
Add
46
Vincent earns $892 on Monday and he earns $711 on Tuesday. How much total money does Vincent
earn?
If the third of three consecutive integers is subtracted from 132, the result is the sum of the first and second. What are the integers?
Answer:
gg
Step-by-step explanation:
Answer:
Three consecutive integers are 43, 44, 45
Step-by-step explanation:
Let three consecutive integers be x, (x + 1), (x + 2)
According to the question, if the third of three consecutive integers is subtracted from 132, the result is the sum of the first and second.
[tex] \therefore [/tex]
[tex] \implies \rm 132 - (x + 2) = x + (x + 1) \\ \\ \implies \rm 132 - x - 2 = x + x + 1 \\ \\ \implies \rm 130 - x = 2x + 1 \\ \\ \implies \rm 130 - 1 = 2x + x \\ \\ \implies \rm 129 = 3x \\ \\ \implies \rm 3x = 129 \\ \\ \implies \rm x = \frac{129}{3} \\ \\ \implies \rm x = 43[/tex]
So,
The integers are as follows:
x = 43
x + 1 = 44
x + 2 = 45
30 points!!! But I need a 2 step problem with variables on both side and a fraction that equal 23
The equation of the two-step problem is 2x = x + 2/3
How to determine the two-step problem?The conditions are given as
Fraction = 2/3Variable on both sidesLet the variable in the equation be x
So, a possible equation is as follows
2x = x + 2/3
The solution to the equation is as follows
2x = x + 2/3
Subtract x from both sides
x = 2/3
Hence, the equation of the two-step problem is 2x = x + 2/3
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what is the value of x?!?
please help!
Answer:
x = 25
Step-by-step explanation:
The given angles, x° and (6x+5)° form a linear pair. You want the value of x.
Linear pairTwo angles that together form a straight line are called a linear pair. A linear pair of angles has a total measure of 180°.
x° +(6x +5)° = 180°
7x +5 = 180 . . . . . . . . . divide by °, collect terms
7x = 175 . . . . . . . . . . subtract 5
x = 25 . . . . . . . . . . divide by 7
The value of x is 25.
how can you make the equation true?
111+222=
Answer: 111 + 222 = 333
the midpoint of AB is M (2,0). if the coordinates of A are (-3,3), what are the coordinates of B?
Hence , the coordinate of point B is (7 , -3) .
Midpoint refers to some extent that's within the middle of the road connexion 2 points. A centre could be a purpose lying between 2 points and is within the middle of the road connexion the 2 points. If a line is drawn connexion the 2 points, then the centre could be a purpose at the center of the road and is equal from the 2 points.The centre formula is outlined for the points within the coordinate axes. Let (x₁), (y₁) and (x₂), (y₂) be the endpoints of a line section is given by M = (x₁ + x₂ /2 , y₁ + y₂ /2 ).We have given two coordinate A (-3,3) and M (2,0) .
Let the coordinate of B (x, y) .
Using midpoint formula , we get
[tex](2,0) = ( \frac{-3+x}{2} ,\frac{3+y}{2} )[/tex]
On comparing , we get
[tex]\frac{-3+x}{2} =2\\\ \\-3+x = 4\\x = 7[/tex]
[tex]\frac{3+y}{2} =0\\3+y=0\\y=-3[/tex]
We get coordinate (7 , -3) .
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In the diagram m∠ACB=25° and CE bisects ∠DCF. explain how to find m∠DCE
The measure of ∠ DCE is equal to 57.5° by using the property of bisectors and vertically opposite angles.
We are given a ray diagram.
In the diagram, the measure of angles are given as:
∠ ACB = 25°
∠ ACG = 90°
We need to find the measure of angle ∠ DCE when CE bisects ∠ DCEF.
Now, we know that:
∠ BCG = ∠ DCF ( Vertically opposite angles.) … (1)
Now,
∠ BCG = ∠ ACB + ∠ ACG
∠ BCG = 25° + 90°
∠ BCG = 115° … (2)
∠ DCF = ∠ DCE + ∠ CEF
∠ DCF = ∠ DCE + ∠DCE ( as ∠ DCE = ∠ CEF since CE bisects them)
∠ DCF = 2 ∠ DCE … (3)
Now, put (2) and (3) in (1), we get that:
115° = 2 ∠ DCE
∠ DCE = 115 / 2°
∠ DCE = 57.5°
Therefore, we get that, the measure of ∠ DCE is equal to 57.5° by using the property of bisectors and vertically opposite angles.
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what is the vertex of f(x)=x^2+10x+1
The vertex of f(x)=x²+10x+1 is found to be (-5,-24).
The Vertex of the quadratic equation f(x)=ax²+bx+c is (h,k) where
h=-b/2a and k=f(h).
In the given question
f(x)=x²+10x+1
On comparing with ax²+bx+c
we get a=1 , b=10 , c=1
So , h=-b/2a
h=-10/2(1)
h=-5 ...(i)
k=f(h)
Substituting the value of x=h in f(x) we get
k=(-5)²+10(-5)+1
k=25-50+1
k=-25+1
k=-24
Therefore , the vertex of f(x)=x²+10x+1 is (-5,-24).
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Use equivalent ratios to answer
If out of 7 squares, 4 squares are in grey colour then if there are 15 white squares there will be 20 grey squares by solving through ratios.
Given that out of 7 squares, 4 squares are in grey colour.
We are required to find the number of grey colour squares if there are 15 white squares by using equivalent ratios.
Equivalent ratios are basically the ratios that are the same when we compare them. Two or more ratios can be compared with each other to find whether they are equivalent or not.
Ratio of white squares in 7 total squares=3:4
Total number of squares if there are 15 white squares=15*7/3=35
Number of grey squares=35-15=20
Hence if out of 7 squares, 4 squares are in grey colour then if there are 15 white squares there will be 20 grey squares by solving through ratios.
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need answer asap:
Shelby made a list of her test scores: 88,100,92,80,85,94,90. What is the lowest score she can get on her next test to have a mean score of 90?
ty pls answer quickk
......................
Hello! I'd really appreciate it if someone helped me solve this logarithm! It was my first class but the professor only showed the more simple versions :)
Answer:
(1/3)log(5) +(4/3)log(x) +log(y)
Step-by-step explanation:
You want the expanded form of the expression log(∛5·x^4·y^3).
Rules of logarithmsThe applicable rules of logarithms are ...
log(ab) = log(a) + log(b)
log(a^b) = b·log(a)
In addition to these, you need to know that a root is a fractional power: the cube root is the 1/3 power. Of course, the rules of powers tell you ...
(a^b)^c = a^(bc)
ApplicationYou can express the root as a fractional power before or after taking logs. Either way, you get the same result.
Before
[tex]\log\left(\sqrt[3]{5\cdot x^4y^3}\right)=\log\left(5^{\frac{1}{3}}\cdot x^{\frac{4}{3}}y^{\frac{3}{3}}\right)=\boxed{\dfrac{1}{3}\log(5)+\dfrac{4}{3}\log(x)+\log(y)}[/tex]
After
[tex]\log\left(\sqrt[3]{5\cdot x^4y^3}\right)=\dfrac{1}{3}\log\left(5}\cdot x^{4}y^{3}}\right)=\dfrac{1}{3}\left(\log(5)+4\log(x)+3\log(y)\right)\\\\=\boxed{\dfrac{1}{3}\log(5)+\dfrac{4}{3}\log(x)+\log(y)}[/tex]
__
Additional comment
Working a more complex problem is like working a simple problem, except it has more parts and may require the use of the rules more times. It may be tedious to keep track of all the parts, but it is not difficult.
if you know how to do this problem please let me know, thank you.
As per the question statement, we are given a mathematical expression [tex]|a+5| -1[/tex] is [tex]$\left[\begin{array}{cc}\text { Solution: } & -\infty < a < \infty \\ \text { Interval Notation: } & (-\infty, \infty)\end{array}\right]$[/tex]
As this question involves a modulus function therefore let us suppose that [tex]b=|a+5|-1[/tex]
Find the absolute value vertex. In this case, the vertex for [tex]b=|a+5|-1[/tex] is [tex](-5,-1)[/tex]
Function range definition
The set of values of the dependent variable for which a function is defined
Domain of [tex]$|a-5|-1: \quad-\infty < a < \infty$[/tex]
Extreme Points of [tex]$|a-5|-1: \quad$[/tex] Minimum [tex]$(5,-1)$[/tex]
Find the range for the interval [tex]$-\infty < a < \infty: \quad-1 \leq f(x) < \infty$[/tex]
Combine the ranges of all domain intervals to obtain the function range [tex]$f(x) \geq-1$[/tex]
Axis interception points of [tex]$|a-5|-1: \quad X$[/tex]Intercepts: [tex]$(4,0),(6,0), Y$[/tex]Intercepts:[tex]$(0,4)$[/tex]
x - axis interception points of[tex]$|a-5|-1: \quad(4,0),(6,0)$[/tex]
y - axis interception point of [tex]$|a-5|-1: \quad(0,4)$[/tex]
X Intercepts: [tex]$(4,0),(6,0), Y$[/tex] Intercepts: [tex]$(0,4)$[/tex]
Asymptotes of [tex]$|a-5|-1$[/tex] : None
Vertical asymptotes of [tex]$|a-5|-1$[/tex] : None
Horizontal Asymptotes of [tex]$|a-5|-1$[/tex] : None
Extreme Points of[tex]$|a-5|-1$[/tex] : Minimum [tex]$(5,-1)$[/tex]
First Derivative Test definition
Suppose that [tex]$x=c$[/tex] is a critical point of [tex]$f(x)$[/tex] then,
If [tex]$f^{\prime}(x) > 0$[/tex] to the left of [tex]$x=c$[/tex]and [tex]$f^{\prime}(x) < 0$[/tex] to the right of [tex]$x=c$[/tex] then $x=c$ is a local maximum.
If [tex]$f^{\prime}(x) < 0$[/tex] to the left of [tex]$x=c$[/tex] and [tex]$f^{\prime}(x) > 0$[/tex] to the right of[tex]$x=c$[/tex] then $x=c$ is a local minimum.
If [tex]$f^{\prime}(x)$[/tex] is the same sign on both sides of [tex]$x=c$[/tex] then [tex]$x=c$[/tex]
is neither a local maximum nor a local minimum.
[tex]f^{\prime}(a)=\frac{a-5}{a-5}$$[/tex]
Plug [tex]$a=5$[/tex] into [tex]$|a-5|-1: \quad-1$[/tex]
Minimum [tex]$(5,-1)$[/tex]
Absolute value vertex: The difference between two numbers; a number's positive value.Interval: A collection of values spanning two endpoints.To learn more about such Absolute value vertex:, click on the link given below:
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Kenny and his family went on a backpacking trip. They started hiking at 3:48 P.M. It took 2 hours and 59 minutes to reach their campsite. After they arrived, it took 1 hour and 35 minutes to set up the campsite. What time was it when Kenny and his family finished setting up their campsite?
Based on the time that it took Kenny and his family to reach the campsite and set it up, the time when they finished setting up the campsite was 8:22 pm
How to find the time taken to set up?First, find the time that Kenny and his family reached their campsite:
= 3:48 pm + 2 hours 59 minutes
= 6:47 pm
After getting to the campsite at 6:47 pm, Kenny and his family took 1 hour 35 minutes to finish setting up their campsite:
= 6:47 pm + 1 hour 35 minutes
= 8:22 pm
In conclusion, Kenny and his family finished setting up at 8:22 pm.
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What's the answer someone please help!
Step-by-step explanation:
Across
1.26
2.59
3.19
5.38
6.82
7.62
8.48
9.72
11.40
12.64
Down
1.24
2.59
3.18
4 42
5.32
6.88
7.65
8.42
9.70
10.34
If an employee at Tacos R US gets paid $11.50 per hour. Find his net pay if the
employee works 38 hours in that one week. Employee has a 10% federal tax rate. SS
tax is 6.2% and Medicare tax is 1.45%
the net pay (weekly) is $359.87
How to find the net pay?First, we know that the employee wins $11.50 per hour. The employee works 38 hours per week, then the weekly pay is:
38*$11.50 = $437
Now we need to discount the taxes:
There are 10% from federal tax, 6.2% from social services and 1.45% from medicare.
The total is:
10% + 6.2% + 1.45% = 17.65%
Then we need to discount a 17.65% of the weekly pay, we will get:
$437*(1 - 17.65%/100%) = $437*(1 - 0.1765) = $359.87
We conclude that the net pay (weekly) is $359.87
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HURRY IM TIMED Which benchmark fraction is closest to 9/10-3/10 A. 3/4 B. 1/2 C. 1/4 D. 4/4
Answer:
I am pretty sure it is a i think.
Step-by-step explanation:
just subtract the fractions and you will get 6\10 and the you will simplify and get 3\5. so 3\4 is closest to 3\5.
Find rules for the tables below. State your rules in two different ways: (1) as a sentence; and (2) as a rule, using x for the input and y for the output. a. X 6 0 2 -3 1 Process y -3 9 -21 3 33 Rule: (1) X and Topic 3: Foundations of Y are Linear (2) relationship Y = 6x=3
Answer:6x+3
Step-by-step explanation:
1.
destions. Show your wor
For a recent Broadway musical, orchestra main floor seats cost $148 each, and
balcony seats cost $65 each. A theatre group purchased 30 tickets for an upcoming
show in June. If the total cost of the 30 tickets was $2,614, how many of each type
of ticket did the theatre group buy?
Number of orchestra tickets
Number of balcony tickets
Answer:
Number of orchestra tickets = 8
Number of balcony tickets = 22
Step-by-step explanation:
Let the number of orchestra tickets be x and number of balcony tickets be y.
So, cost of x orchestra tickets = $148 × x = $148x
Cost of y balcony tickets = $65 × x = $65y
Also given, total number of tickets = 30
Cost of 30 tickets = $2,614
So, the system of equations that can ne formed is :
x + y = 30 ....eq 1
148x + 65y = 2614 ....eq 2
Multiplying eq 1 by 148 and subtracting eq 2 by it,
148x + 148y - 148x - 65y = 4440 - 2614
83y = 1826
y = 1826/83 = 22
Substituting y = 22 in eq 1,
x + 22 = 30
So, x = 30 - 22 = 8
Thus,
Number of orchestra tickets = 8
Number of balcony tickets = 22
Figurative language is different from literal language because _____.
A. it means exactly what it says
B.it is unclear
C.it contains meaning other than the actual word for word meaning
D.it is hard to define
Answer:
C i think
Step-by-step explanation:
Answer:
C.
Step-by-step explanation:
Answer A is the definition of literal language, while C is the definition of figurative. So, C is correct.
What is: 14 - (-20) + (-13)
Answer:
21
Step-by-step explanation:
14 - (-20) + (-13) =
= 14 + 20 - 13
= 34 - 13
= 21
A cookie recipe requires 4 2/3 cups of flour. If a person only wanted to make 3/4 of a batch, how many cups of flour would they need? (Do not add the label)
[tex]\begin{array}{ccll} \stackrel{recipe}{batch}&\stackrel{recipe}{flour}\\ \cline{1-2} 1&4\frac{2}{3}\\[1em] \frac{3}{4}&f \end{array}\implies \cfrac{1}{ ~~ \frac{3}{4}~~ }~~ = ~~\cfrac{ ~~ 4\frac{2}{3} ~~ }{f}\implies \cfrac{4}{3}~~ = ~~\cfrac{ ~~ \frac{4\cdot 3+2}{3}~~ }{f}\implies \cfrac{4}{3}=\cfrac{ ~~ \frac{14}{3} ~~ }{f} \\\\\\ \cfrac{4}{3}=\cfrac{14}{3f}\implies 12f=42\implies f=\cfrac{42}{12}\implies f=\cfrac{7}{2}\implies f=3\frac{1}{2}[/tex]
Determine if the conclusion follows logically from the premises. Is this a valid or invalid argument? Premise: No loving persons are thoughtless persons. Premise: No loving persons are aggressive people. Conclusion: No aggressive people are thoughtless persons.
"Premise: No loving persons are thoughtless persons. Premise: No loving persons are aggressive people. Conclusion: No aggressive people are thoughtless persons." This is a Valid Argument
This is further explained below.
What is a Valid Argument?Generally, In the context of deductive reasoning, an argument is considered to be sound if and only if it can be expressed in a way that makes it logically impossible for all of the premises to be true while still leading to an incorrect conclusion.
In conclusion, This is a Valid Argument
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An average middle-income family will spend $242,020 to raise a child born in 2004
from birth to age 17. The graph shows the percents spent for various categories. To
the nearest dollar, how much will be spent to provide housing for the child? Use the
graph to answer.
graph numbers-- housing 34%, food 17%, miscellaneous 11%, child care 11%, health care 7%, clothing 6%, transportation 14%
Work Shown:
34% of $242,020 = 0.34*242020 = 82,286.80
This rounds to 82,287 when rounding to the nearest whole number.
The probability of passing the math class of Professor Goodrum is 59%, the probability of passing Professor Cruise's physics
class is 26%, and the probability of passing both is 17%. What is the probability of passing one or the other?
(Give your answer as a whole percent number.)
probability of passing one or the other:
Answer:
51%
Step-by-step explanation:
Given P(passing math) = 59%, P(passing physics) = 26%, and P(passing both) = 17%, you want to find the probability of passing only one of the courses.
Probability relationsWe can record the given probabilities in a 2-way table (values shown in blue). The table is completed by making sure the totals add up (values shown in black).
The probability of passing one course and failing the other is the sum of the probabilities with a yellow background:
42% +9% = 51%
The probability of passing one or the other is 51%.
__
Additional comment
We can also get there using the relation ...
P(A+B) = P(A) +P(B) -P(AB)
The union of A and B also includes their overlap:
P(A+B) = P(AB') +P(A'B) +P(AB)
In other words, the probability of interest is ...
P(AB') +P(A'B) = P(A) +P(B) -2×P(AB) = 59% +26% -2(17%)
P(AB') +P(A'B) = 51%
A square rug has an area of 35 square ft. What is the exact side length of the rug?
The exact side length of the rug is √35.
What is the area of parallelogram
Let take the area of length as =a
As per the given question
A square rug has an area=35 sq ft
Area is the quantity that measures the number of unit square
As we know
area of square= a^2
Square area formula: A = a²
As already given a^2=35
So a=√35
The exact side length of the rug is √35.
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