Choose a mental math strategy, and find the difference between the speeds of the planets Neptune and Saturn

Choose A Mental Math Strategy, And Find The Difference Between The Speeds Of The Planets Neptune And

Answers

Answer 1

The difference between the speeds of the planets Neptune and Saturn is 9384 miles per hour.

What is speed?

The distance traveled in a unit of time is called speed. It refers to a thing's rate of movement. The scalar quantity known as speed is the velocity vector's magnitude. It has no clear direction. The formula for an object's general speed is [Speed = Distance Time]. M/s is the SI unit of speed.

The speed of an item, which is a scalar quantity in everyday usage and kinematics, is the size of the change in that object's position over time or the size of the change in that object's position per unit of time.

Therefore, the difference between the speeds of the planets Neptune and Saturn will be:

= 21637 - 12253

= 9384 miles per hour.

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Related Questions

2a-18 in algebraic form

Answers

Answer: 2(a-9)

Step-by-step explanation:

2a-18

then factor

which leads to 2(a-9)

Answer: 2(a-9)

Step-by-step explanation: Factor out 2 from the expression 2(a-9)

write the standard form of the equation of the circle with the given characteristics. endpoints of a diameter: (3, 4), (−13, −14)

Answers

The standard equation of the circle will be (x+5)²+(y+5)²= 145

The center of the circle, which is the midpoint between those two locations, may be found first since you know the diameter endpoints.

formula for the midpoint

= ((x1+x2)/2, (y1+y2)/2)

Given points are - (3, 4), (−13, −14)

The circle's center is at (-5,-5)

Therefore, the circle's equation will take the form (x+5)²+(y+5)²=R², where R is the circle's radius.

The distance between a point on the circle and the circle's center in order to get the radius.

Therefore, let's calculate the distance between (-5, -5) and (-13,-14)

Radius R = √((-13+5)²+(-14+5)²) using the distance formula.

= 12.04

equation will be -

(x+5)²+(y+5)²= 145

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A=√15.5(15.5-14) (15.5-11) (15.5-6)

Answers

The value of A is 31.5.

The square root of any number is the factor that we can be multiplied by itself to get that given number. The symbol for square root is √.

Here, we are given an equation as follows-

A=√[15.5(15.5-14) (15.5-11) (15.5-6)]

Let us simplify it step by step. Firstly, we will perform the operations inside the brackets as follows-

A = √[15.5(1.5) (4.5) (9.5)]

Now, multiplying the terms we get-

A = √[15.5(1.5) (4.5) (9.5)]

A = √[(23.25) (42.75)]

A = √[(993.9375)]

Now, we calculate the square root of the number obtained above-

A = 31.5

Thus, the value of A in the equation A=√15.5(15.5-14) (15.5-11) (15.5-6) comes out to be 31.5.

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daisy is making solid spikes for her halloween costume. the spikes are shaped like right circular cones with base radius of 2222 inches and height of 6666 inches. if daisy has 360360360360 cubic inches of material for making the spikes, what is the maximum number of spikes she can make?

Answers

Question :-  Daisy is making solid spikes for her Halloween costume. the spikes are shaped like right circular cones with base radius of 2 inches and height of 6 inches. if daisy has 360 cubic inches of material for making the spikes, what is the maximum number of spikes she can make ?

Answer:- She can only create a maximum of 14 spikes.

Step-by-step explanation:

Given that :-

Daisy is making solid spikes for her Halloween costume.The spikes have a base radius of 2 inches and a height of 6 inches. They are formed like right circular cones.For creating the spikes, Daisy has 360 cubic inches of material.

To find :-

maximum number of spikes made by her.

According to Question,

We have,

base radius of the spikes = 2 inchheight of the spikes = 6 inch

For finding the maximum number of spikes,

We have to divide the volume of the material by the volume of the cone, for producing a maximum number of spikes.

So,

        Maximum spikes = Volume of the material / volume of the cone

Now,

      Volume of the material = 360 cubic inches

       Volume of the cone  = [tex]\frac{1}{3}[/tex] πr²h

Where:

       r = radius = 2 in

      h = height = 6 in

      π = pi = 22/7

         =  [tex]\frac{1}{3}[/tex] × [tex]\frac{22}{7}[/tex] × [tex]2^{2}[/tex] ×6

         = 3.14 × 4 × 2

         = 25.12

So,

        Maximum spikes = Volume of the material / volume of the cone

                                      = [tex]\frac{360}{25.12}[/tex]

                                      = 14.33

∴ The number of spikes must be an integer.

∵          Maximum spikes = 14.

Answer:- She can only create a maximum of 14 spikes.

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Alex has twice the number of hats that Joey has, plus 2 more. The number
of hats Alex has is also 4 times the difference of the number of hats and 5
that Joey has. Find how hats many each of them has.

Answers

From the given Alex and Joey  hats equation we got Alex has 24 hats Joey has 11 hats.

Given that,

Joey only has 2 times more hats than Alex, who has 2 more. The difference between the amount of hats Alex has and the 5 that Joey has is also 4 times the number of hats Alex has.

We have to discover how many hats each one of them has.

Let Alex has x hats Joey has y hats.

From the given

We get

x=2y+2 ------> equation (1)

x=4(y-5) --------> equation (2)

Equating equation (1) and equation (2)

2y+2=4(y-5)

2y+2=4y-20

2y-4y=-20-2

-2y=-22

y=-22/-2

y=11

Take y=11 in equation (1)

x=2(11)+2

x=22+2

x=24

Therefore,  Alex has 24 hats Joey has 11 hats.

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HELP ME PLEASE I need this now
question 1 first picture is to this question
As x decreases without bound, f(x) increases without bound.
As x increases without bound, f(x) approaches the line y = - 4.
As x decreases without bound, f(x) approaches zero.
As x decreases without bound, f(x) approaches the line y = 4.


question 2 the second picture to this question
As x decreases without bound, f(x) approaches the line y = 6.
As x increases without bound, f(x) approaches the line y = 6.
As x increases without bound, f(x) increases without bound.
As x decreases without bound, f(x) increases without bound.

Answers

Answer:

Question 1:

As x decreases without bound, f(x) increases without bound. TRUEAs x increases without bound, f(x) approaches the line y = - 4. TRUEAs x decreases without bound, f(x) approaches zero. FALSEAs x decreases without bound, f(x) approaches the line y = 4. FALSE

Question 2:

As x decreases without bound, f(x) approaches the line y = 6. TRUEAs x increases without bound, f(x) approaches the line y = 6. FALSEAs x increases without bound, f(x) increases without bound. TRUEAs x decreases without bound, f(x) increases without bound. FALSEAs x decreases without bound, f(x) approaches the line y = 6.

Step-by-step explanation:

Question 1:

options

As x decreases without bound, f(x) increases without bound.As x increases without bound, f(x) approaches the line y = - 4.As x decreases without bound, f(x) approaches zero.As x decreases without bound, f(x) approaches the line y = 4.

Solving notes:

As x decreases without bound, f(x) does NOT approach zero.

As x decreases without bound, f(x) does NOT approaches the line y = 4.

_________________________________________________

Question 2:

options

As x decreases without bound, f(x) approaches the line y = 6.As x increases without bound, f(x) approaches the line y = 6.As x increases without bound, f(x) increases without bound.As x decreases without bound, f(x) increases without bound.

Solving notes:

As x increases without bound, f(x) does NOT approach the line y = 6.

As x decreases without bound, f(x) does NOT increase without bound.

each of the following statements can be recast in the if-then form. please rewrite each of the following sentences in the form "if a, then b." a. the product of an odd integer and an even integer is even. b. the square of an odd integer is odd. c. the square of a prime number is not prime. d. the product of two negative integers is negative. (this, of course, is false.) e. the diagonals of a rhombus are perpendicular

Answers

According to the given statements:

a. If the integers x and y are, respectively, even and odd, then xy is even.

b. When x is odd, x2 is also odd.

c. If p is a prime number, p2 is not a prime number.

d. If the integers a and b are negative, then ab is also a negative number.

e. If AC and BD are diagonally arranged in a rhombus, then AC is perpendicular to BD.

What is number system in math's?

A numeral system, also known as a mathematical notation, is a way of writing numbers that uses digits or even other symbols to represent the numbers in a given set in a standardized way. The same set of symbols can represent various numbers in various numeral systems.

According to the given statement:

A. if a, then b the product of an odd integer and an even integer is even.

If the integers x and y are, respectively, even and odd, then xy is even.

B. if a, then b  the square of an odd integer is odd.

When x is odd, x2 is also odd.

C.  if a, then b  the square of a prime number is not prime.

 If p is a prime number, p2 is not a prime number.

D. the product of two negative integers is negative. (this, of course, is false.)

If the integers a and b are negative, then ab is also a negative number.

E.  the diagonals of a rhombus are perpendicular.

If AC and BD are diagonally arranged in a rhombus, then AC is perpendicular to BD.

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I understand that the question you are looking for is:

Each of the following statements can be recast in the if-then form. please rewrite each of the following sentences in the form "if a, then b."

a. the product of an odd integer and an even integer is even.

b. the square of an odd integer is odd.

c. the square of a prime number is not prime.

d. the product of two negative integers is negative. (this, of course, is false.)

e. the diagonals of a rhombus are perpendicular

three houses are located on a straight road. house A is at the end of the road. house b is 4 miles from house a. house c is at least 1 mile from house b. write and solve an inequality to show the possible distances of house a from house c

Answers

The inequality that shows the possible distances of house A from house C is x ≥ 5

What is inequality?

Inequality is defined as the relation which makes a non-equal comparison between two given functions.

An inequality is a mathematical statement that compares two values or expressions using a relational operator, such as less than (<), greater than (>), less than or equal to (≤), greater than or equal to (≥), or not equal to (≠). Inequalities are used to describe relationships between quantities or to express constraints or conditions.

We are given that;

Distance= 4miles

Let x be the distance of house A from house C. Since house B is 4 miles from house A, and house C is at least 1 mile from house B, we can write an inequality that relates x, 4, and 1:

x ≥ 4 + 1

This inequality means that the distance of house A from house C is greater than or equal to the sum of the distances of house A from house B and house B from house C.

To solve this inequality, we need to simplify it by adding 4 and 1:

x ≥ 5

Therefore, by inequality the answer will be x ≥ 5.

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PLEASE HELP!! 80 PTS!! You research the cost of a gallon of gasoline over several years to look for a trend. The table shows your data. What is the equation for a line of best fit? How much would you expect to pay for a tank of gas in the year 2019? Let x be the number of years after 1998.

Answers

Answer: Because the initial value is $26.40, the line must pass through this when x is 0. Thus, the answer is either the first or the second equation.

Next, we calculate the difference between the year 2019 and 1998 and substitute it into the value of x.

2019 - 1998 = 21.

Substituting this into the equation:

y = 1.006(21) + 26.40

y = $47.52

Thus, the first option is correct.

Keitaro walks at a pace of 3 miles per hour and runs at a pace of 6 miles per hour. Each month, he wants to complete at least 36 miles but not more than 90 miles. The system of inequalities represents the number of hours he can walk, w, and the number of hours he can run, r, to reach his goal.

3w + 6r ≥ 36

3w + 6r ≤ 90

A graph shows w on the x-axis, from 0 to 30, and t on the y-axis, from 0 to 24. Two solid lines are shown. The first line has a negative slope and goes through (0, 6) and (12, 0). Everything above and to the right of the line is shaded. The second line has a negative slope and goes through (0, 15) and (30, 0). Everything to the left of the line is shaded.
Which combination of hours can Keitaro walk and run in a month to reach his goal?

2 hours walking; 12 hours running
4 hours walking; 3 hours running
9 hours walking; 12 hours running
12 hours walking; 10 hours running

Answers

Answer:

2 and 12

Step-by-step explanation:

2x3=6

12 x 6=72

6 and 72 is 78

Answer:

2 and 12

Step-by-step explanation:

The points G and H, 19m apart are on the same side of a tree. The angles of elevation of the top T, of the tree from G and H on the horizontal ground with the foot of the tree are 430 and 38° respectively. (1). Illustrate the information in a diagram. (i). Find, correct to one decimal place, the height of the tree.

Answers

Using relations in a right triangle, we have that the height of the tree is of 91.6 meters.

What are the relations in a right triangle?

The relations in a right triangle are given as follows:

The sine of an angle is given by the length of the opposite side to the angle divided by the length of the hypotenuse.The cosine of an angle is given by the length of the adjacent side to the angle divided by the length of the hypotenuse.The tangent of an angle is given by the length of the opposite side to the angle divided by the length of the adjacent side to the angle.

The graph for this problem is given at the end of the answer, and using it and the relations, we can build two equations involving x and the height h, and solve the system of equations for h.

From the triangle involving point G(angle of 43º), we can build the following relation:

tan(43º) = h/x

0.9325 = h/x

x = (1/0.9325)h.

x = 1.0724h (because we want to find h, hence we write x as a function of h).

From the larger triangle, that has the angle of 38º, we have the following relation.

tan(38º) = h/(x + 19).

tan(38º) = h/(1.0724h + 19). (considering that x is a function of h, as we found above).

0.7813 = h/(1.0724h + 19).

Hence, we apply cross multiplication to solve for h, as follows:

h = 0.7813(1.0724h + 19).

h = 0.8379h + 14.8447.

0.1621h = 14.8447

h = 14.8447/0.1621

h = 91.6 meters.

Hence:

The height of the tree is of 91.6 meters.

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someone PLEASE help me with this asap.

Answers

The description and definition and values of the sequence are;

a. Each term of sequence A is produced from the previous term by multiplying the previous term by 2

b. Each term of sequence B is produced from the previous term by adding 10 to the previous term

c. [tex] A(n) = \frac{1}{2} \times 2^{(n-1)} [/tex]

d. B(n) = 2 + (n-1) × 10

e. B(9) > A(9)

What is a sequence of numbers?

A sequence is series of objects that follow each other in a particular order.

a. The terms of sequence A are;

1/4, 1/2, 1, 2, 4

Therefore, each term is produced from the previous term by multiplying the previous term by 2 as follows;

1/4 × 2 = 1/2,

1/2 × 2 = 1

1 × 2 = 2

2 × 2 = 4

b. The values in sequence B are;

2, 12, 22, 32, and 42

Therefore, each term is produced from the previous term by adding 10 to the previous term as follows;

2 + 10 = 1212 + 10 = 2222 + 10 = 3232 + 10 = 42

c. The definition of the nth term of sequence A is found using the formula for a geometric progression as follows;

nth term of a GP is; A(n) = a•r^(n-1)

Where;

a = The first term = 1/4

r = The common ratio = 1/2/(1/4) = 2

The nth term of sequence A is therefore;

[tex] A(n) = \frac{1}{2} \times 2^{(n-1)} [/tex]

d. The definition of the nth term of sequence B is found using the formula for a arithmetic progression as follows;

nth term of a AP is; B(n) = a + (n-1)•d

Where;

a = The first term = 2

d = The common difference = 12 - 2 = 10

The nth term is therefore

B(n) = 2 + (n-1) × 10

e. The value of A(9) is therefore;

[tex] A(9) = \frac{1}{2} \times 2^{(9-1)} = 64 [/tex]

Which gives; A(9) = 64

The value of B(9) = 2 + (9-1) × 10 = 82

B(9) = 82

Which gives;

B(9) = 82 > A(9) = 64

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a subway car passes 4 stations every 10 minutes. at this rate, how many stations will it pass in 2 hours?

Answers

The subway car passes through 48 stations in 2hours

It is given that a subway car passes 4 stations every 10 mins.

Subway car is being referred to the metro system of New York city

It is known to us that an hour has 60 mins

We are given that subway car passes 4 stations every 10 mins

Therefore number of stations passed by subway car in 1 hour

= 60/10 x 4 = 24 stations

We are required to find the number of stations crossed by subway car in 2 hours

Therefore, number of stations crossed by subway car in 2 hours= 24 x 2

= 48  stations

Therefore, the subway car passes 48 stations in 2 hours

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Need help with geometry homework.

Answers

The measure m<D is 26

What is angle sum property?

Angle sum property of triangle states that the sum of interior angles of a triangle is 180°.

Given:

m<ABE = 52

<EBD = <CBD

Now,

<ABE + <EBD + <DBC = 180 (linear pair)

52 + 2<EBD = 180

2<EBD = 128

<EBD = 128/2

<EBD = 64

Now, In ΔDEB using angle sum property

<DEB + <EDB + <DBE = 180

90+ <EDB + 64=180

<EDB = 26

Hence, the measure of <D is 26 degree.

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Please solve this pleaseeeed

Answers

Answer:

multiply input number by 2

Step-by-step explanation:

So, this is our function

y=2x===>

(3, 6), (4, 8), (5, 10), (6, 12), (7, 14)

so according to this functionality the output part is equal to input part multiplied by 2

Draw a line representing the "rise" and a line representing the "run" of the line. State the slope of the line in simplest form.

Answers

Answer: 3/4

Step-by-step explanation:

Kenny can swim 11/15 mile in 1/3 hour what is his average swimming speed In miles per hour

Answers

Answer: 2.2 miles per hour

Step-by-step explanation:

Since we are given his speed in one third of an hour, we can simply triple his speed to get his miles per hour.

[tex]\frac{11}{15} * 3\\= \frac{33}{15}\\\\= 2 \frac{1}{5}[/tex]

or, 2.2 miles per hour

Answer:

2.2mph!

Step-by-step explanation:

a study of a very large number of pregnant women in arkansas reports that the women gained, on average, 14 pounds during their pregnancy and that 18% of the women smoked. the two variables in this study are

Answers

The two dependent variables will be:

1. The women who gained weight during the pregnancy.

2. The women who smoked during the pregnancy.

We are given that a study of a very large number of pregnant women in Arkansas reports that the women gained, on average, 14 pounds during their pregnancy and that 18% of the women smoked.

Now, we need to tell the two variables of the study.

Now, we can see that the independent variable is pregnant women.

Also, the two dependent variables will be:

1. The women who gained weight during the pregnancy.

2. The women who smoked during the pregnancy.

Therefore, the two dependent variables will be:

1. The women who gained weight during the pregnancy.

2. The women who smoked during the pregnancy.

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Find the distance between each pair of points. Round to one decimal place. A(-4, 6) and B(3, -7), and E(-6, -5) and F(2, 0).
AB=(
EF=

Answers

To one decimal place, round. points A(-4, 6), B(3, -7), E(-6, -5) and F (2, 0).

The distance between AB is [tex]\sqrt{185}[/tex]=13.601 and EF is [tex]\sqrt{89}[/tex]=9.433.

Given that,

To one decimal place, round.

Points A(-4, 6), B(3, -7), E(-6, -5) and F (2, 0).

We have to find the distance between two points that are AB and EF.

1. The distance between 2 points A and B.

A(-4, 6) and B(3, -7).

Distance formula is [tex]\sqrt{(x_{2} -x_{1} )^{2} +(y_{2} -y_{1} )^{2} }[/tex]

Here, x₁=-1,x₂=3 and y₁=6,y₂=-7

After substituting we get,

[tex]\sqrt{{(3 -(-1)} )^{2} +(-7 -6 )^{2} }\\[/tex]

[tex]\sqrt{{(3 +1} )^{2} +(-7 -6 )^{2} }\\[/tex]

[tex]\sqrt{{(4} )^{2} +(-13 )^{2} }\\[/tex]

[tex]\sqrt{16 +163}\\[/tex]

[tex]\sqrt{185}[/tex]

13.601

Therefore, the distance between AB is [tex]\sqrt{185}[/tex]=13.601.

2.The distance between 2 points E and F.

E(-6, -5) and F (2, 0).

Distance formula is [tex]\sqrt{(x_{2} -x_{1} )^{2} +(y_{2} -y_{1} )^{2} }[/tex]

Here, x₁=-6,x₂=2 and y₁=-5,y₂=0

After substituting we get,

[tex]\sqrt{{(2 -(-6)} )^{2} +(0 -(-5) )^{2} }\\[/tex]

[tex]\sqrt{{(2 +6} )^{2} +(0 +5 )^{2} }\\[/tex]

[tex]\sqrt{{(8} )^{2} +(5 )^{2} }\\[/tex]

[tex]\sqrt{64 +25}\\[/tex]

[tex]\sqrt{89}[/tex]

9.433

Therefore, the distance between EF is [tex]\sqrt{89}[/tex]=9.433.

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What is another way to write the absolute value inequality |p|<12

Answers

Another way to write the absolute value inequality |p|<12 is

-12 < p < 12

What is absolute values?

This is a term in mathematics that refers to numbers considered regardless of the sign. The concept of absolute values is well appreciated in a number line.  In a case where the signs helps on to position the number but do not have influence in the magnitude or size of the number.

Since absolute values considers the magnitude of the number and not the sign. We can see the equation given to represent values from zero to a point just less than 12 as this will have same magnitude to the point from zero to a point just less than negative 12. The sign just gives the direction.

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A small theater had 8 rows of 26 chairs each. an extra 8 chairs have just been brought in. how many chairs are in the theater now ?

Answers

After 8 chairs have been bought in there are now 216 chairs in the theater.

What is unitary method ?

A unitary method is a mathematical technique for first finding the value of a single unit and then deriving the required units by multiplying with it.

According to the given question, a small theater had 8 rows of 26 chairs each.

∴ The total number of chairs in the theater is (8×26) chairs = 208 chairs.

Later an extra 8 chairs have bought in.

∴ The total no. of chairs in the theater now is (208+8) = 216 chairs.

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2.2 more than the quotient of h and 6 is w

Answers

Answer:

2+x/6=w

step by step

x/62+ step 1taking the equality of sum of steps 1 &2 by w

The number of gallos of water used to water trees i'd 30 times the number of trees

Answers

y = 30x

Calculate  the number of gallos of water used to water trees i'd 30 times the number of trees.

Let's take,

Number of gallons = y

Number of trees = x

Then, according to the problem,

Number of gallons = 30*(Number of trees)

So….. y = 30*x

y = 30x

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Please help asap!!!!

Answers

Answer:

A.2

explanation:

the equation to find circumference is [tex]2\pi (radius)[/tex]

the circumference of A is [tex]2\pi 8 = 50.27[/tex]

the circumference of B is [tex]2\pi 4 = 25.13[/tex]

50.27/25.13 = 2/1

a stack of one dozen cookies of diameter of 5in. exactly fits in a cylindrical container of volume 176.715in^3. Which is the length of each cookie?

Answers

Answer:

Step-by-step explanation:

Discussion

Note: I think the length is supposed to be the height of 1 cookie.

The volume of the 12 cookies (1 dozen=12) is 176,715 in^3

The area of 1 cookie is 5 in

Area = pi * r^2

Area  of one cookie = 3.14 * 5^2

Area of one cookie = 78.5 in ^2 Note this is also the area of the base of the container.

Height of the 12 cookies = Volume / Area of one cookie

Height of the 12 cookies = 176.715/78,5

Height of the 12 cookies = 2.25 inches.

Answer

Thickness (height) of one cookie = 2.25/12

Thickness (height) of one cookie = .188 inches.

what is the simplest form of 14/27 divided by 7/1​

Answers

Answer:

2/27

Step-by-step explanation:

i think this is the answer.

it would be 2/27 because you divide 14/7 and it gives you 2 and then 27/1 gives you 27

A rectangular section of a field is to be fenced. Because one side of the field is bordered by a creek, only 3 sides need to be fenced. The fenced section should have an area of 60 m². Determine the minimum perimeter and dimensions of the fenced area.​

Answers

The minimum perimeter is 23.24m and dimensions of the fenced area is 15.5m x 3.8m.​

Let us assume the length of the fenced area to be L and breadth of the fenced area to be W. As we know, only three sides are to be fenced,

So, the perimeter  P of the fenced would be,

P = L + 2W

Also, it is given that, area of the fence is 60m²,

So, the are should be,

60m² = LW

60m²/L = W

Now, to minimize the perimeter,

P = L + 2W

P = L + 120/L

Differentiating both sides with respect to "L",

d(p)/dL = 1 - 240/L²

To find the value of "L", putting dp/dL equal to 0,

d(P)/dL = 0

1 - 240/L² = 0

L = √240m

Now, from the first derivative test, we know that, the perimeter will be maximum or minimum if value of L>√240 or L<√240 respectively,

For minimum, L should be,

L = √240m

L = 15.5m

Now we know from area,

area = LW

60 = 15.5 x W

W = 60/15.5

W = 3.8m

Hence, the minimum perimeter will be,

L + 2W = 23.24m

The dimensions are,

L = 15.5m

W = 3.8m

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Q. If 140 students want to go on the Mackinac Island field trip and are ALL riding together, how many
cars will they need if each car holds 6 people?
answer choices

Answers

Answer:

24

Step-by-step explanation:

140/6 = 23.3333333333333


You can’t have .3 of a car, so you would need to round up.

23.333333333333333 rounds up to 24

The first step in solving 7 + 3(x - 2) = 2x + 10 is to

Answers

Answer:

x=9

Step-by-step explanation:

Simplify  7+3x−67+3x−6  to  3x+13x+1.

Subtract 11 from both sides

Simplify  2x+10−12x+10−1  to  2x+92x+9.

Subtract 2x2x from both sides.

Simplify  3x−2x3x−2x  to  xx.

Answer: x=9

Step-by-step explanation:

7+3(x-2)=2x+10

7+3x-6=2x+10

1+3x=2x+10

1+3x-2x=2x-2x+10

1+1x=10

1x=9

x=9

A road repair crew spread 13 1/4 tons of gravel evenly over 4.5 feet of road. How many tons of
gravel did they spread on each foot of road?

Answers

If a road repair crew spread 13 1/4 tons of gravel evenly over 4.5 feet of road then 2.39 tons of gravel is spread by them on each foot of road.

This is solved by using unitary method

4.5 feet of road is getting covered by 13 1/4 tons of gravel

Then 1 foot of road will be covered by (13 1/4) /4.5 tons of gravel

= (43/4) / 4.5 tons of gravel

= 2.388 tons of gravel

2.39 tons of gravel is required to cover 1 foot

If a road repair crew spread 13 1/4 tons of gravel evenly over 4.5 feet of road then it requires 2.39 tons of gravel is spread by them on each foot of road.

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