Consider a sign suspended on a boom that is supported by a cable, as shown. What is the proper equation to use for finding the net force in the y direction?

Fnety = (FT)(sin 32°) + Fg
Fnety = (FT)(sin 32°) – Fg
Fnety = (FT)(cos 32°) + Fg
Fnety = (FT)(cos 32°) – Fg

Answers

Answer 1

The proper equation to use for finding the net force in the y direction is B. Fnety = (FT)(sin 32°) – Fg

What is net force?

The total force acting on an object is its net force. The net force can be determined using Newton's second law, which states that F = ma, where: F is the net force. The object's mass is given by m. Acceleration is a.

The total of all forces acting on an object is known as the net force. A mass can accelerate due to net force. A body is subject to another force whether it is at rest or in motion. The net force is a word used in a system where there is a substantial number of forces.

In this case, the proper equation to use for finding the net force in the y direction is B. Fnety = (FT)(sin 32°) – Fg.

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Answer 2

Answer:

B. Fnety = (FT)(sin 32°) – Fg

Explanation:

just did it!


Related Questions


In materials with nickel, iron, or cobalt, what moves around inside, creating the magnetic field?

A.protons
B.neutrons
C.electrons
D.All of the above

Answers

D.all the above in material with novel or iron

a proton, a deuteron and an a-particle are moving with same momentum in a uniform magnetic field. find ratio of their time period

Answers

The ratio of their time period is 1 : 2 : 2.

The momentum of a proton, a deuteron, and an alpha particle is the same in a uniform magnetic field.

The charge of a proton is q = e and the let m(p) be the mass of the proton.

Let m(d) = 2m(p) be the mass of the deuteron and the charge of a deuteron is q =e.

Now, an alpha particle is made up of 4 protons. Therefore the mass of an alpha particle is 4m(p) and the charge on an alpha particle is q = 2e.

The formula for the time period of a moving particle in a uniform magnetic field is given as:

[tex]T = \frac2 \pi m}{qB}[/tex] where B is the magnetic field, m is the mass and q is the charge of the particle.

So, the time period of a proton is:

[tex]T_{1} = \frac{2 \pi m(p)}{eB}[/tex]

The time period of a deuteron is:

[tex]T_{2} = \frac{2 \pi (2m(p))}{eB}[/tex]

And the time period of an alpha particle is:

[tex]T_{3} = \frac{2 \pi ( 4m(p) )}{2eB}[/tex]

Therefore, the ratio is:

[tex]T_{1}: T_{2} : T_{3} =\frac{2 \pi m(p)}{eB} : \frac{2 \pi 2m(p)}{eB} : \frac{2 \pi (4m(p))}{2eB}[/tex]

T₁ : T₂ : T₃ =  1 : 2 : 2

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Scientific theories are able to be changed true or false

Answers

Answer:

true

Explanation:

the earth has a mass of 6x10^24 kg, and a radius of 6400 km. What is the density of the earth in kg/m^2.

Answers

The density of the earth is 3.51×10¹⁰ kg/m³

What is Density?

Density can be defined as the ratio of mass to the volume of a body. The S.I unit of density is kg/m³

To calculate the density of the earth, we use the formula below.

Formula:

D = m/v............ Equation 1

Where:

D = Denstiy of the earthm = Mass of the earthv = Volume of the earth

From the question,

Given:

m = 6×10²⁴ kg

Note: Since the earth is a spherical in shape, we can calculate the volume of the earth using the volume of a sphere

v = 4πr³/3 = (4×3.14×6400000³)/3 = 1.71×10¹⁴ m³

Substitute these values into equation 1

D = (6×10²⁴)/(1.71×10¹⁴) D = 3.51×10¹⁰ kg/m³

Hence, the density of the earth is 3.51×10¹⁰ kg/m³.

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the atoms of each element in a compound cannot be pulled apart

Answers

Answer:

Element of a compound typically cannot be separated by physical means because atoms are chemically bonded together

Explanation:

Compounds are substances composed of two or more elements chemically combined that can be separated into simpler substances only by chemical means

find the velocity of a baseball thrown across a field a distance of 40 meters it takes the ball 4 seconds to cross the field

Answers

The velocity of a baseball thrown across a field is (V)= 10m/s

What is Velocity?

Velocity of a particle is its speed and the direction in which it is moving.

It can also be described as the instantaneous rate of change of the particle's distance traveled.

How can we calculate the values of the velocity?

To calculate the velocity we are using the formula here,

V= S/t

Here we are given,

S= a distance of a baseball thrown= 40m

t= time to travel the distance = 4 seconds.

Now we put the values in the above equation, we get

V= S/t

Or, V = 40/4

Or, V= 10m/s

So, from the above calculation we can conclude that, the velocity of a baseball thrown across a field is (V)= 10m/s

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Different types of brain injuries and what they affect

Answers

Answer:

Explanation:

Traumatic brain injury (TBI) happens when a sudden, external, physical assault damages the brain. It is one of the most common causes of disability and death in adults. TBI is a broad term that describes a vast array of injuries that happen to the brain. The damage can be focal (confined to one area of the brain) or diffuse (happens in more than one area of the brain). The severity of a brain injury can range from a mild concussion to a severe injury that results in coma or even death.

Brain injury may happen in one of two ways:

CLOSE BRAIN INJURY : Closed brain injuries happen when there is a nonpenetrating injury to the brain with no break in the skull. A closed brain injury is caused by a rapid forward or backward movement and shaking of the brain inside the bony skull that results in bruising and tearing of brain tissue and blood vessels. Closed brain injuries are usually caused by car accidents, falls, and increasingly, in sports. Shaking a baby can also result in this type of injury (called shaken baby syndrome).

PENETRATING BRAIN INJURY: Penetrating, or open head injuries happen when there is a break in the skull, such as when a bullet pierces the brain.

DIFFUSE AXONAL INJURY: Is the shearing (tearing) of the brain's long connecting nerve fibers (axons) that happens when the brain is injured as it shifts and rotates inside the bony skull. DAI usually causes coma and injury to many different parts of the brain. The changes in the brain are often microscopic and may not be evident on computed tomography (CT scan) or magnetic resonance imaging (MRI) scans.

PRIMARY BRAIN INJURY: Refers to the sudden and profound injury to the brain that is considered to be more or less complete at the time of impact. This happens at the time of the car accident, gunshot wound, or fall.

SECONDARY BRAIN INJURY : Refers to the changes that evolve over a period of hours to days after the primary brain injury. It includes an entire series of steps or stages of cellular, chemical, tissue, or blood vessel changes in the brain that contribute to further destruction of brain tissue.

If I use the author's last name in my sentence, then _________________ (Choose 2)
Group of answer choices

I only put the page number in parentheses.

I do not need to use it in the in-text citation.

I also need to use it in the in-text citation.

I put the year of publication and the page number.

I put the author's last name, a comma, and the publication date.

Answers

Even if in a piece of writing, you happen to use the author's last name in my sentence, you also need to use it in the in-text citation.

What is referencing?

In academic writing, it is often important to quote the sources that one used in writing up the text. Failure to give accurate citation could be taken as plagiarism by the assessors.

Hence, even if in a piece of writing, you happen to use the author's last name in my sentence, you also need to use it in the in-text citation.

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If more electric field lines leave a gaussian surface than enter it, what can you conclude about the net charge enclosed by that surface?

Answers

The net charge enclosed within the electric field is positive when more electric field lines leave a gaussian surface than enter it.

Remember, that a Gaussian surface is a three-dimensional closed surface that determines the flux of a vector field, often the gravity field, electric field, or magnetic field. A surface with more electric field lines departing than coming in indicates a net positive charge. It is important to note that E-field lines begin with positive charges and end with negative charges. This is characteristic of most gaussian surfaces. So, if more electric field lines exit than enter a gaussian surface, we may deduce that the enclosing net charge is generally positive.

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if two 6-volt sources are connected in parallel to supply a 24-ohm load and the total current is 0.25 a, how much current would each source supply to the load? (round the final answer to three decimal places.)

Answers

V or total voltage is 6 volts because when multiple power supplies of the same voltage are connected in parallel, the applied voltage is same and the current equally divides between the number of power sources.

Divide I(t) or total current 0.25 amps between the two power sources.

Is=I(t)/Ns

Is=0.25amps/2sources

Is=.125amps

Voltage is the difference in electrical potential between two points.

Current is just the rate of flow of electric charge.

Each power source supplies .125amps of current to the load

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A cubical surface surrounds a point charge q . Describe what happens to the total flux through the surface if (a) the charge is doubled,

Answers

According to Gauss law,  the electric flux is defined as the electric field multiplied by the area of the surface in a plane perpendicular to the field.

Gauss law is defined mathematically in Equation 1

Φ=Q ϵo               (1)

Where;

Q is enclosed charge

ϵo is the permittivity of the free space

According to the above gaussian relation, If the charge is doubled, then flux will also be doubled. This is because there is a direct relationship between the total flux and charge present in the electric field. This means that the net electric flux is dependent on the charge moving through the surface of the cube.

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The tank is 51m long and 20m wide.The sea water in the tank is 11m deep and has a density of 1030 kilograms per cubic meters.
Calculate the mass of water in the tank.

Answers

Answer: 1.2 x 10^7kg

Explanation:

Volume of tank = length x width x height

Volume = 51 x 20 x 11

Volume = 11220 m^3

Density = Mass/Volume

Density = 1030 kg/m^3

Volume = 11220 m^3

Mass = m

1030 = m/11220

m = 1030 x 11220

m = 11,556,600 kg or 1.2 x 10^7kg

The concrete sections of a certain superhighway are designed to have a length of 25.0m . The sections are poured and cured at 10.0°C . What minimum spacing should the engineer leave between the sections to eliminate buckling if the concrete is to reach a temperature of 50.0°C ?

Answers

The minimum spacing the engineer should leave between the sections to eliminate buckling is 0.011 m.

To calculate the minimum space the engineer must leave in other to eliminate bulking, we use the coefficient of linear expansivity of steel.

What is coefficient of linear expansivity?

This can be defined as the increase in length, per unit length, per degree rise in temperature.

To calculate the minimum space, we use the fomula below

Formula:

α = ΔL/L₁(t₂-t₁)........... Equation 1

Make L₂ the subject of the equation

ΔL = αL₁(t₂-t₁)........... Equation 2

From the question,

Given:

L₁ = 25 mt₁ = 10°Ct₂ = 50°Cα = 11×10⁻⁶ /K ( Cofficient of Linear expansion of steel)

Substitute these values into equation 2

ΔL = [11×10⁻⁶×25×(50-10)]ΔL = 0.011 m

Hence, the minimum spacing the engineer should leave between the sections to eliminate buckling is 0.011 m.

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At what temperature is the temperature in degrees fahrenheit equal to twice the temperature in degrees celsius?.

Answers

The temperature in degrees Fahrenheit is 320 equal to twice the temperature in degrees Celsius.

What is a temperature scale?

The measurement of temperature as a physical quantity. In order to measure temperature, empirical scales take into account useful and trustworthy factors like the freezing and boiling temperatures of water.

The temperature will be solved as below:-

F = 2C

The temperature in degree centigrade is:-

C = ( 5 / 9 ) ( F - 32 )

Put the value in the equation above:-

F = 2 { 5 / 9 [ F -32 ]}

F = ( 10 / 9 ) [ F - 32 ]

( 9 / 10)F  = F - 32

( 9 / 10)F - F = 32

( -1 / 10)F = -32

F = 320°

Therefore, the temperature in degrees Fahrenheit is 320 equal to twice the temperature in degrees Celsius.

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A tennis ball is dropped from 1.98 m above
the ground. It rebounds to a height of 1.05 m.
The acceleration of gravity is 9.8 m/s².
With what velocity does it leave the ground?

Answers

The ball will leave the ground with the velocity of 4.5 m/s.

What is Velocity ?

Velocity is the distance travelled in a specific direction per time taken. It is measured in m/s

Given that a tennis ball is dropped from 1.98 m above the ground. It rebounds to a height of 1.05 m. The acceleration of gravity is 9.8 m/s².

At maximum height, final velocity is zeroThe maximum height H = 1.05 mThe initial velocity u = 0

Using the formula

v² = u² - 2gH

0 = u² - 2 × 9.8 × 1.05

u² = 20.58

u = √20.58

u = 4.54 m/s

Therefore, the ball will leave the ground with the velocity of 4.5 m/s.

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Two cats jump off a roof that is 23m off the ground. Cat A jumps directly up with a velocity of 7m/s, and cat B jumps directly down with a velocity of 7m/s. How far up does cat A go? How fast does cat A go just before it hits the ground? How fast does cat B go just before it hits the ground? How much longer is cat A in the air than cat B?

Answers

The height reached by cat A is 2.5 m.

The speed of cat A before it hits the ground is 36.4 m/s.

The speed of cat B before it hits the ground is 22.39 m/s.

The time spent in air by cat A than cat B is 1.43 seconds.

Time of motion of cat A

The time of motion of cat A is calculated as follows;

h = vt - ¹/₂gt

-23 = 7t - 4.9t²

4.9t² - 7t - 23 = 0

solve the quadratic equation using formula method;

a = 4.9, b = -7, c = - 23

t = 3.0 seconds

Time of motion of cat B

The time of motion of cat B is calculated as follows;

h = vt - ¹/₂gt

23 = 7t + 4.9t²

4.9t² + 7t - 23 = 0

solve the quadratic equation using formula method;

a = 4.9, b = 7, c = -23

t = 1.57 seconds

Height reached by cat A

h = u²/2g

h = (7²)/(2 x 9.8)

h = 2.5 m

Speed of cat A before it hits the ground

v = u + gt

v = 7  + 3(9.8)

v = 36.4 m/s

Speed of cat B before it hits the ground

v = u + gt

v = 7  + 1.57(9.8)

v = 22.39 m/s

Time spent in air by cat A than cat B

Time difference = 3 s - 1.57 s = 1.43 seconds

Thus, the height reached by cat A is 2.5 m.

The speed of cat A before it hits the ground is 36.4 m/s.

The speed of cat B before it hits the ground is 22.39 m/s.

The time spent in air by cat A than cat B is 1.43 seconds.

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pls help me!! 100 points!!!

"type a definition for each of the following words in YOUR own words."

1) Constants (also called Controls or Control Variables) –


2) Independent variable –


3) Dependent variable –

Answers

Answer:

1) Constants are variables that are kept the same throughout an experiment.

2) An independent variable is a variable that is manipulated by the experimenter.

3) A dependent variable is a variable that is measured by the experimenter.

Explanation:

Which type of energy does not describe potential energy being changed into kenetic energy

Answers

The type of energy that does not describe potential energy being changed into kinetic energy is the energy that exists in the Compression of the spring.

Usually, in many energy sources, the potential energy is changed into kinetic energy but no such energy transmission takes place when a spring is compressed.

Potential energy is considered as the stored energy occupied by an object or system by virtue of its respective position or by the arrangement of parts. However, this energy is not affected by the environment existing outside of the system or subject including air or height. Potential energy is changed into kinetic energy is also not described in the compression of rubber foam.  

On the other hand, the term kinetic energy is termed as the energy of a particular object or particle of a system that is in motion. Contrary to several peculiarities of potential energy, the kinetic energy of a particular object is in relative position to other stationery as well as moving objects present in its own environment which is an immediate type. In general, the kinetic energy of an object will be of higher value if the object is placed at a distance of greater height.  

If we take the case of Potential energy, it is not all transferrable in nature and will depend on the height or the distance and also the mass of the object. On the other hand, Kinetic energy can be easily transferable from one moving object to another which includes the vibrational and rotational types of energy and it depends on the speed, velocity, and mass of the object.

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Consider this situation: A baseball travels upward and
rightward through the air. Of the forces listed, identify which
act upon the baseball.
Tap to select the forces that are present.

Answers

The forces acting on the baseball are air resistance, and force of gravity.

What are forces present during the upward motion of an object?

The forces which act on an object moving upward will either oppose the motion of the object or help to speed up the object.

The forces present during upward motion include;

force of air resistanceforce of gravityapplied force

The forces acting on a baseball thrown upwards which also travels rightward include the following;

force of air resistance which oppose the upward motion of the baseballforce of gravity acting downwards due to the weight of the ball.

Thus, the forces acting on the baseball are air resistance, and force of gravity.

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The complete question is below:

Consider this situation: A baseball travels upward and

rightward through the air. Of the forces listed, identify which

act upon the baseball. (force of air resistance, force of gravity, weight of the ball, frictional force).

An alien spaceship traveling at 0.600 c toward the Earth launches a landing craft. The landing craft travels in the same direction with a speed of 0.800 c relative to the mother ship. As measured on the Earth, the spaceship is 0.200 ly from the Earth when the landing craft is launched.(a) What speed do the Earth-based observers measure for the approaching landing craft?

Answers

The speed does the Earth-based observers measure for the approaching landing craft is 1.016 times the speed of light.

To find the answer, we have to know about the Lorentz transformation.

What speed do the Earth-based observers measure for the approaching landing craft?

It is given that, an alien spaceship traveling at 0.600 c toward the Earth, in the same direction the landing craft travels with a speed of 0.800 c relative to the mother ship. We have to find the speed do the Earth-based observers measure for the approaching landing craft.

Let us consider the earth as S frame and space craft as S' frame, then the expression for the value of speed of the approaching landing craft with respect to the earth frame as,

                  [tex]V_x=V_x'(1-\frac{VV_x}{c^2} )+V\\where,\\V_x'=0.8c\\V=0.6c[/tex]

Substituting values, we get,

             [tex]V_x=0.8c(1-\frac{0.8c*0.6c}{c^2} )+0.6c=1.016c[/tex]

Thus, we can conclude that, the speed does the Earth-based observers measure for the approaching landing craft is 1.016 times the speed of light.

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A long, straight wire is surrounded by a hollow metal cylinder whose axis coincides with that of the wire. The wire has a charge per unit length of λ, and the cylinder has a net charge per unit length of 2λ . From this information, use Gauss's law to find (b) the charge per unit length on the outer surface of the

Answers

The charge per unit length on the outer surface is [tex]3\lambda[/tex]

Charge per unit length of the wire [tex]= {\lambda}[/tex].

Charge per unit length of the cylinder =[tex]{2\lambda}[/tex]

Gauss's law is a principle that connects the distribution of electric charge to the resulting electric field. In its integral form, it asserts that the flux of the electric field out of any closed surface, regardless of how that charge is distributed, is proportional to the electric charge enclosed by the surface.

The total charge per unit length of the cylinder is equal to the charge per unit length of the inner part of the cylinder plus the charge per unit length of the outer part:

Solve for [tex]{\lambda_{\text{out}}}[/tex] :

[tex]\lambda_{\text{out}}=2\lambda-\lambda_{\text{in}}[/tex]

Substitute for [tex]{\lambda_{\text{in}}}[/tex] :

[tex]\lambda_{\text{out}}&=2\lambda-(-\lambda)\\ &={3\lambda}}[/tex]

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A boy walks 25 meters north along a sidewalk before realizing that he has walked in the wrong direction. He turns around and walks 48 m south. What is the distance he traveled?

Answers

I think 73 if im correct if you add it all up 48+25 is 73

HELP PLEASE IMMEDIATILY !!!!!!
- Determine the force required to accelerate a block of ice with a mass of 3.5 kg from 0 to 8 m/s2.

- Determine the acceleration that a cart with a mass of 25 kg experiences when it is being pulled with a force of 50 Newtons.

- Determine the mass of a block of ice that is accelerated to 6 m/s2 by a force of 3 Newtons.

- What is a free body diagram and what information does it contain?

Answer all of them please

Answers

The force required to accelerate the block is 28 N.

The acceleration of a cart with a mass of 25 kg and applied force of 50 N is 2 m/s².

The mass of a block of ice that is accelerated to 6 m/s2 by a force of 3 Newtons is 0.5kg.

A free body diagram is a sketch of forces acting on an object. It consists of the applied force, weight of the object, frictional force and normal reaction.

Force required to accelerate the block

The force required to accelerate the block is calculated as follows;

F = ma

F = 3.5 kg x 8 m/s²

F = 28 N

Acceleration that cart

The acceleration of a cart with a mass of 25 kg and applied force of 50 N is calculated as follows;

a = F/m

a = 50/25

a = 2 m/s²

Mass of the block of ice

The mass of a block of ice that is accelerated to 6 m/s2 by a force of 3 Newtons is calculated as follows;

m = F/a

m = 3 N / 6 m/s²

m = 0.5 kg

What is a free body diagram?

A free body diagram is a sketch of forces acting on an object. It consists of the applied force, weight of the object, frictional force and normal reaction.

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the sun is almost 400 times farther from earth than is the moon. how long does light from the moon take to reach earth?

Answers

About 1.3 seconds the light takes to reach from the moon to the earth.

How long does light from the moon take to reach earth?

We know that the closest object to our earth is the Moon. Its distance from the earth is about 240,000 miles, so light from the Moon takes 1 and 1/3 seconds to get from the Moon to Earth while on the other hand, sun is  almost 400 times farther from earth as compared to the moon so the light reaches from sun is about 8 minutes 30 seconds.

So we can conclude that about 1.3 seconds the light takes to reach from the moon to the earth.

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An athlete is running a race. The athlete’s body needs energy. Which type of organelle in the athlete’s cells supplies the energy for cellular function?.

Answers

Mitochondria is a type of organelle in the athlete’s cells supplies the energy for cellular function.

Since mitochondria are the cellular organelles in charge of producing aerobic ATP, the "health" of mitochondria is crucial for proper cellular operation

Which organelles that give energy to the cell?

Mitochondria. Dictionary Britannica, Inc. Mitochondria, or "powerhouses," are oval-shaped organelles that are present in the majority of eukaryotic cells. During cellular respiration, substances like glucose are converted by mitochondria into ATP, an energy molecule (adenosine triphosphate).

How  Mitochondria  produce ROS?

The generation of ROS by mitochondria can result in oxidative damage to mitochondrial proteins, membranes, and DNA, impairing their capacity to synthesize ATP and perform a wide range of metabolic processes, including the tricarboxylic acid cycle, fatty acid oxidation, the urea cycle, amino acid metabolism, haem synthesis, and FeS center assembly, which are crucial to the normal functioning of most cells. The tendency of mitochondria to release intermembrane space proteins, such as cytochrome c (cyt c), to the cytosol by mitochondrial outer membrane permeabilization (MOMP), and so trigger the cell's apoptotic machinery, can also be increased by mitochondrial oxidative damage. The mitochondrial permeability transition pore (PTP), which opens up the inner membrane to tiny molecules in conditions like ischaemial reperfusion damage, is also induced by mitochondrial ROS generation. So it should come as no surprise that mitochondrial oxidative damage plays a role in a variety of diseases. Additionally, mitochondrial ROS may behave as a modifiable redox signal, impacting a number of activities in the mitochondria, cytosol, and nucleus in a reversible manner.

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if a gas occupies 15 l at pressure of 2.3 atm what would the volume be at 3.1 atm

Answers

The volume occupied by the gas at 3.1 atm pressure will be 11.12 L.

What is Boyle's Law?

When a gas is maintained at a constant temperature and with a certain mass, Boyle's law states that the pressure of the gas is inversely proportional to its volume.

To put it another way, as long as the temperature and volume of the gas remain constant, the pressure and volume of the gas are inversely proportional to one another. In 1662, the Anglo-Irish chemist Robert Boyle proposed the Boyle's law.

According to Boyle's law :

P1V1=P2V2 where,

P1 and P2 are the pressure and,

V1 and V2 are the volume of container.

As per the question, the given values are :

V1=15 L

P1= 2.3 atm and,

P2= 3.1 atm

So by using Boyle's theorem :

2.3 atm× 15 L = 3.1 atm× V2

34.5=3.1 atm × V2

V2=11.12 L

Hence, the volume at 3.1 atm pressure will be 11.12 L.

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a plastic rod that has been charged to − 15 nc touches a metal sphere. afterward, the rod's charge is − 1.0 nc .

Answers

According to the question a plastic rod that has been charged to − 15nc touches a metal sphere. Afterward, the rod's charge is − 1.0nc.The electrons will be transferred from the plastic rod to the metal sphere and the number of electrons ( n ) = 8.73 * 10^10

First of all, write the initial charge on the plastic rod, and then it touches the metallic sphere. Then, a few amounts of charge are transferred to the steel sphere. Later, calculating the price difference between the plastic rod and metal sphere, the kind of charged particle transferred may be decided. Ultimately, the number of electrons may be calculated by the use of the overall charge and the rate of the electron.

The expression of the total charge in electrostatics is Q = ne

Q = charge

n = number of electrons

e = charge of the electron

The initial charge on the plastic rod ( Qplastic ) = -15nC

Final charge on the metal sphere after it was touched by the plastic rod ( Qmetal ) = -1nC

The charge transferred from the metal rod to the sphere = ( Q = Qplastic -   Qmetal )

Therefore Q = - 15nC - ( -1nC )

Q = -14nC

The plastic rod is negatively charged, so the electrons will be transferred to the metal sphere. The electrons will be transferred from the plastic rod to the metal sphere.

The expression of the total charge in electrostatics is Q = ne

The expression for n = Q / e

Q = -14nC

The charge on 1 electron = 1.602 * 10^-19 C.

Number of electrons ( n ) = -14nC ( 10^-9C/1nC ) / -1.602 * 10^-19 C.

Number of electrons ( n ) = 8.73 * 10^10

Threfore the number of electrons ( n ) = 8.73 * 10^10

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To win the game, a place kicker met kick a
football from a point 35 m (38.276 yd) from
the goal, and the ball must clear the crombar,
which is 3.05 m high. When kicked, the ball
leaves the ground with a speed of 20 m/s at
an angle of 45.9 from the horizontal.
The acceleration of gravity is 9.8 m/s²
By how much vertical distance does the ball
clear the crowbar?
Answer in units of m.

Answers

Answer:

2.08 m  (2 d.p.)

Explanation:

Constant Acceleration Equations (SUVAT)

[tex]\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}[/tex]

When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.

-------------------------------------------------------------------------------------

When a body is projected through the air with initial speed (u), at an angle of θ to the horizontal, it will move along a curved path.

Therefore, trigonometry can be used to resolve the body's initial velocity into its vertical and horizontal components:

Horizontal component of u (x) = u cos θVertical component of u (y) = u sin θ

Since the projectile is modeled as moving only under the influence of gravity, the only acceleration the projectile will experience will be acceleration due to gravity.

If the ball is kicked at an initial velocity of 20 m/s from flat ground at an angle of 45.9° then:

Horizontal component of u = 20 cos 45.9°Vertical component of u = 20 sin 45.9°

Resolving horizontally

The horizontal component of velocity is constant, as there is no acceleration horizontally.

Resolving horizontally, taking → as positive:

[tex]s=35 \quad u=20 \cos 45.9^{\circ} \quad v = 20 \cos 45.9^{\circ} \quad a=0[/tex]

[tex]\begin{aligned}\textsf{Using} \quad s&=\left(\dfrac{u+v}{2}\right)t\\\\35&=\left(\dfrac{20 \cos 45.9^{\circ}+20 \cos 45.9^{\circ}}{2}\right)t\\35&=(20 \cos 45.9^{\circ})t\\t&=\dfrac{35}{20 \cos 45.9^{\circ}}\\\implies t&=2.51468288...\; \sf s\end{aligned}[/tex]

Therefore, the time is takes for the ball to reach the crossbar is 2.51 s.

Resolving vertically

Acceleration due to gravity = 9.8 ms⁻²

Resolving vertically, taking ↑ as positive:

[tex]u=20 \sin 45.9^{\circ} \quad a=-9.8 \quad t=2.51468288...[/tex]

[tex]\begin{aligned}\textsf{Using} \quad s&=ut+\dfrac{1}{2}at^2\\\\s&=(20 \sin 45.9^{\circ})(2.51468288...)+\dfrac{1}{2}(-9.8)(2.51468288...)^2\\s&=36.1171982...-30.9857870...\\\implies s&=5.131411132...\; \sf m\end{aligned}[/tex]

Solution

To find by how much the ball clears the crossbar, subtract the height of the crossbar (3.05 m) from found the vertical height of the ball at 2.51 s:

[tex]\implies 5.13141132...-3.05=2.08\; \sf m\;(2 \: d.p.)[/tex]

Therefore, the ball clears the crossbar by 2.08 m (2 d.p.).

In Niels Bohr's 1913 model of the hydrogen atom, the single electron is in a circular orbit of radius 5.29×10⁻¹¹m and its speed is 2.19×10⁶ m/s . (a) What is the magnitude of the magnetic moment due to the electron's motion?

Answers

The magnitude of the magnetic moment due to the electron's motion is [tex]87.87 * 10^{-37}[/tex].

What is magnetic moment?

The magnetic pull and direction of a magnet or other object that produces a magnetic field are referred to as the magnetic moment in electromagnetism. Things that have magnetic moments include electromagnets, permanent magnets, various compounds, elementary particles like electrons, and a number of celestial objects (such as many planets, some moons, stars, etc).

The term "magnetic moment" really refers to the magnetic dipole moment of a system, which is the portion of the magnetic moment that can be represented by an equivalent magnetic dipole or a pair of magnetic north and south poles that are only very slightly apart. The magnetic dipole component is adequate for sufficiently small magnets or over sufficiently large distances.

Calculations:

radius= [tex]5.29 * 10^{-11} m\\[/tex]

velocity=[tex]2.9* 10^{6} m/s[/tex]

Working formula, M=N/A

[tex]I=\frac{charge flow }{time taken} =\frac{e}{time taken\\}[/tex]

[tex]T= \frac{2xr}{v} =\frac{2xx * 5.29 * 10^{-11} }{2.9* 10^{6} }[/tex]

   =[tex]15.16 * 10^{-5} s[/tex]

[tex]I= \frac{1.6 * 10^{-19} }{15.16 * 10^{-5} }[/tex][tex]= 0.10 * 10^{-14}[/tex]

                     =[tex]1 * 10^{-15} C[/tex]

M=[tex]1x (1* 10^{-15} * (5.29 * 10^{-11} )^{2}[/tex]

  =[tex]87.87 * 10^{-37}[/tex]

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A toy doll and a toy robot are standing on a frictionless surface facing each other. The doll has a mass of 0. 20 kg, and the robot has a mass of 0. 30 kg. The robot pushes on the doll with a force of 0. 30 n. The magnitude of the acceleration of the robot is.

Answers

The magnitude of the acceleration of the robot is 1m/s^2 .

Given ,

A toy doll and a toy robot are standing on a frictionless surface facing each other .

The mass of the doll = 0.20kg

The mass of the robot = 0.30kg

Force applied by the robot on the doll = 0.30N

We know the force and mass of the robot , so from this we can calculate the acceleration by applying Newton's laws of motion ,

Thus , F= ma

a = F/m = 0.30N / 0.30k

a = 1 m/s^2

Hence , the magnitude of the acceleration of the robot is 1m/s^2 .

What is acceleration ?

Acceleration is the rate of change in velocity.

Positive acceleration it occurs when an object speeds up. Negative acceleration it occurs when an object slows down.

Acceleration is a change of velocity over a period of time, expressed by the equation,

A=Δv/t

The unit of acceleration is m/s^2.

The dimensional formula of acceleration is [M^0 L^1 T^-2] .

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