Determine by composition whether f(x) = 3x + 18 and g(x)=x-6 are inverses of each other.
O No, f(g(x)) + X
O No, f(g(x)) = x
O Yes, f(g(x)) = g(f(x)) = x
O Yes, f(g(x)) = g(f(x)) * x

Step-by-step explanation:

[tex](3 \sqrt{3 - 2 \sqrt{2)(3 \sqrt{3 - 2 \sqrt{2)} } } } [/tex]

The larger integer number is 18 and the smaller integer number is -14.

Integers are the subset of Rational numbers which contains all numbers except fraction and decimals

Numbers are the building blocks of mathematics. Numbers are used to count ,measure or label quantities.

The different types of numbers are:

Let the smaller number be x. The sum of the numbers is 4 .

So the larger number is 4 - x

Again given that sum of three times the larger number and 2 times the smaller number is 26.

∴3 ( 4-x )+ 2x = 26

or, 12 -3x +2 x = 26

or, -x = 26-12

or, x = -14

Therefore the larger number is 4-(-14)= 18

Hence the larger integer number is 18 and the smaller number is -14 .

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The value of x and y is y=29, X=21.

180-60=120

4y+4=120 get y by itself and remember that what ever you do to one side you do to the other.

Alternate interior angles are congruent so 3x-3=60

What is an angle ?

Angle is the figure formed by two rays, called the sides of the angle, sharing a common endpoint, called the vertex of the angle. Angles formed by two rays lie in the plane that contains the rays. Angles are also formed by the intersection of two planes. These are called dihedral angles.

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The number of hours Hector worked this week is 32 hours.

444 = 15(4) + 12(x)

444 = 60 + 12x

444 - 60 = 12x

384 = 12x

x = 384/12

x = 32 hours

check:

444 = 60 + 12x

444 = 60 + 12(32)

444 = 60 + 384

444 = 444

Therefore, the number of hours Hector worked this week is 32 hours.

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The formula in terms of H is H = V ÷ πr². Value of height is 5.

We are given the formula -

V = πr²H, where V represents volume and H represents height. To rewrite the formula in terms of H, we will shift it to Left Hand Side -

H = V ÷ πr²

Keep the value of Volume and radius in formula to find the height.

H = 45π ÷ π(3)²

Taking square of 3 and cancelling π

H = 45 ÷ 9

Performing division to find the value of height

H = 5

Therefore, the formula is V ÷ πr² and value of height is 5.  

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The complete question is attached in figure.

Answer:

(−∞, 31/5) or x <31/5 (the graph will start a little bit past 6 and will be a open circle and head to the left)

Answer:

x< 6[tex]\frac{1}{5}[/tex]

Step-by-step explanation:

7<-5(x -8) - 2  Distribute the 5

7<-5x + 40 - 2

7<-5x +38  Subtract 38 from both sides

-31<-5x  Divide both sides by -5

[tex]\frac{31}{5}[/tex] >x  When you divide both sides by a negative number, you must flip the sign.

or

x < 6 [tex]\frac{1}{5}[/tex]

Answer:

=sqrt of 30

Step-by-step explanation:

=sqrt of 3×2×5

=sqrt 30

Answer:

$1

Step-by-step explanation:

If you have x dimes, you have 8x nickels.

So, this means x + 8x = 18.

This means you have 2 dimes and 16 nickels, which have a combined value of 2(0.10)+16(0.05)=$1.

Answer:

Step-by-step explanation:

33575357853222467

ufee

Answer:

-2

Step-by-step explanation:

You have to simplify numerator and denominator through factoring. The you should get an expression involving only a + b which is given as -2

Take numerator
[tex]a^2-b^2-12b-36[/tex]

Factor
[tex]-b^2-12b-36[/tex]

[tex]= - (b^2 + 12b + 36)\\\\= -(b+6)^2[/tex]

So numerator becomes
[tex]a^2-\left(b+6\right)^2[/tex]

Apply difference of squares formula: [tex]\displaystyle x^2-y^2=\left(x+y\right)\left(x-y\right)[/tex]

[tex]\mathrm{with\;} x^2 == > a^2, and y^2 == > (b + 6)^2[/tex]

[tex]\implies a^2-\left(b+6\right)^2 \\== \left(a+\left(b+6\right)\right)\left(a-b-6\right)[/tex]

Denominator
[tex]a^2-6a-b^2-6b[/tex]

can be factored as follows

[tex]a^2-b^2 = (a + b) (a -b)[/tex]
[tex]-6a-6b = -6\left(a+b\right)[/tex]

So denominator becomes
[tex]\left(a+b\right)\left(a-b\right)+-6\left(a+b\right)[/tex]

Factor out common term (a+b) to get
[tex]\left(a+b\right)\left(a-b-6\right)[/tex]

So the original expression with Numerator and denominator

[tex]\displaystyle =\frac{\left(a+b+6\right)\left(a-b-6\right)}{\left(a+b\right)\left(a-b-6\right)}[/tex]
Cancel the common factor (a-b-6) to get
[tex]\displaystyle \frac{a+b+6}{a+b}[/tex]

Since a + b = -2, plug in this value of (a+b) in both numerator and denominator to get
[tex]\displaystyle \dfrac{-2 + 6}{-2}[/tex]
[tex]\displaystyle = - 2[/tex]

Answer: -2

The sequence starting with 0 but each number is two times three less than the previous number is as follows:

0, -6, -12, -18, -22

A sequence is defined as an arrangement of numbers in a particular order.

The most common sequence are the arithmetic and the geometric sequence.

The sequence starts with 0 but each number is two times three less than the previous number.

This means the first term of the sequence is 3.

Hence,

2 times 3 less than the previous number means:

Aₙ = Aₙ₋₁ - 2(3)

where,

Let's use the formula to find the other numbers in the sequence,

A₂ = A₂₋₁ - 2(3) = 0 - 6 = -6

A₃ = A₃₋₁ - 2(3) = -6 - 6 = -12

A₄ = A₄₋₁ - 2(3) = -12 - 6 = - 18

A₅ = A₅₋₁ - 2(3) = -18 - 6 = - 22

Therefore, the sequence starting with 0 but each number is two times three less than the previous number is as follows:

0, -6, -12, -18, -22

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Answer: The car was not speeding. It went 27.6 mi/h.

Step-by-step explanation: The equation v=2/5L is given where v is measured in mi/h. L is measured in ft. Since we have the value 69 for L, we sub it into the equation. We end up getting 27.6 mi/h after evaluating.

Answer:

6(5)3(5)² + (3)³

Step-by-step explanation:

Put this into your calculator just like this

To get to 1 we have to divide 60 by 60, and to get 25 we have to multiply 60 with 5/12 or 0.41.

Given that we have to get 1 by dividing 60 by something and multiply 60 by something to get 25.

We are required to find those numbers.

Take first result:

Suppose the number which divides 60 be x.

So,

60/x=1

x=60

Number will be 60.

Take second result:

Suppose the number which multiplied with 60 to get 25 be y.

So,

60*y=25

y=25/60

y=0.41

Number will be 0.41.

Hence to get to 1 we have to divide 60 by 60, and to get 25 we have to multiply 60 with 5/12 or 0.41.

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From rectangle F to G translation is -4 units to the x- direction and -3 units to the y- direction.

From rectangle G to H translation is 6 units to the x- direction and -1 units to the y- direction.

From rectangle F to H translation is 2 units to the x- direction and -4 units to the y- direction.

Given that,

In the picture we have a graph with 3 rectangles that is F, G, and H.

We have to find the translation of the rectangles.

We know that,

The transformation, i.e., f: X X, is a function, f, that maps to itself. Following the transformation, the pre-image X changes into the image X. Any operation, including translation, rotation, reflection, and dilation, may be used to create this transformation. A function can be moved in one direction or another by translation, rotated around a point by rotation, reflected in its mirror image by reflection, and scaled by dilation.

So,

From rectangle F to G translation is -4 units to the x- direction and -3 units to the y- direction.

From rectangle G to H translation is 6 units to the x- direction and -1 units to the y- direction.

From rectangle F to H translation is 2 units to the x- direction and -4 units to the y- direction.

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Using proportional relationships, we have that:

A. The function does not show a direct linear relationship.

B. The function shows a direct linear relationship.

C. The function does not show a direct linear relationship.

A proportional relationship is a function in which the output variable is given by the multiplication of the input variable and the constant of proportionality k, in the case of a direct relationship, as follows:

y = kx

In the case of an inverse relationship, we have that:

y = k/x.

From the format of these equations, we have that:

A function is classified as linear if the exponent of x is of 1, hence item c does not show a linear function.

The functions A, B, C are missing, and are given as follows.

A. 9/x.

B. x/11.

C. x²/8.

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Answer:

[tex]\sf y =\dfrac{-11}{8}x +\dfrac{13}{8}[/tex]

Step-by-step explanation:

Here, m is the slope and b is the y-intercept.

( -1, 3) ;  x₁ = -1  & y₁ = 3

(7, -8) ; x₂ = 7 & y₂ = -8

Slope can be obtained by the formula:

    [tex]\sf \boxed{\bf Slope = \dfrac{y_2-y_1}{x_2-x_1}}[/tex]

                [tex]\sf =\dfrac{-8-3}{7-[-1]}\\\\\\=\dfrac{-8-3}{7+1}\\\\\\=\dfrac{-11}{8}[/tex]

Now, we can find the y-intercept,

[tex]\sf y = \dfrac{-11}{8}x + b\\\\Substitute \ any \ one \ of \ the \ point \ in \ the \ above \ equation.\\\\\text{Here, we are substituting (-1 ,3)}\\\\3 = \dfrac{-11}{8}*(-1) + b\\\\3 = \dfrac{11}{8}+b\\\\b = 3 - \dfrac{11}{8}\\\\b = \dfrac{3*8}{1*8}-\dfrac{11}{8}\\\\b= \dfrac{24-11}{8}\\\\b= \dfrac{13}{8}[/tex]

Slope-intercept form:

          [tex]\sf y =\dfrac{-11}{8}x +\dfrac{13}{8}[/tex]

Using the Pythagorean Theorem and implicit differentiation, it is found that the distance between them is increasing at a rate of 2050 km/h when they are 0.5 hours away from the harbor.

The Pythagorean Theorem relates the length of the legs [tex]l_1[/tex] and [tex]l_2[/tex] of a right triangle with the length of the hypotenuse h, according to the following equation:

[tex]h^2 = l_1^2 + l_2^2[/tex]

For this problem, we have that since the ships are moving west and north, the distance between them as a function of the time will be given by the hypotenuse of a right triangle, as follows:

d² = x² + y².

In which;

Applying implicit differentiation, the rate of change of the position is given as follows:

[tex]2\frac{dd}{dt} = 2x\frac{dx}{dt} + 2y\frac{dy}{dt}[/tex]

[tex]\frac{dd}{dt} = x\frac{dx}{dt} + y\frac{dy}{dt}[/tex]

From the velocities, we have that:

[tex]\frac{dx}{dt} = 40, \frac{dy}{dt} = 50[/tex]

From the velocities, and the time of half an hour, the positions are given as follows:

x = 0.5 x 40 = 20, y = 0.5 x 50 = 25.

Hence:

[tex]\frac{dd}{dt} = x\frac{dx}{dt} + y\frac{dy}{dt}[/tex]

[tex]\frac{dd}{dt} = 20(40) + 25(50)[/tex]

dd/dt = 2050.

The distance between them is increasing at a rate of 2050 km/h when they are 0.5 hours away from the harbor.

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Answer:

120

Step-by-step explanation:

the difference = 24×41-864=120

Abby should write her equation as k = 1.61m.

The correct option is B.

A pair of algebraic equations with the equal symbol (=) in the center and the same value are referred to as an equation.

Given:

Abby knows that 1 mile is about 1.61 kilometers.

To write an equation, which she can use to convert any given distance in miles (m) to kilometers (k):

Let m be the total number of miles and k be the kilometers.

So, the equation is,

k = 1.61m

Where 1.61 is multiplied by m.

Therefore, the equation is k = 1.61m.

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The measure of segment DF from the given question is 21

In line geometry, a line is the distance between two points while an angle is the point where two lines intersect.

Given the following parameters

DE = 4x + 10, EF = 2x-1, and DF = 9x-15,

Required

DF

Using the addition postulate

DE + EF = DF

Substitute

4x+10 + 2x -1= 9x - 15

6x + 11 = 9x - 1

6x - 9x =  -1 - 1

-3x = -12

x = 12/3

x = 4

For DF

DF =  9(4) - 15

DF = 21

Hence the measure of segment DF from the given question is 21

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4K = 120 can be used to find the number of emergency kits K Elise packs. The total number of emergency kits packed by Elsie and her mom are 30.

Here, we are given that Elise puts 4 water bottles into each emergency kit.

Let the number of kits packed = K

Then the total number of bottles packed = 4 × K

= 4K

Also, we are given that Elsie packs a total of 120 bottles.

Thus, we get the following linear equation-

4K = 120

We can use this equation to find the number of emergency kits K Elise packs.

dividing by 4 on both sides, we get

4K/4 = 120/4

K = 30

Hence, the total number of emergency kits packed by Elsie and her mom are 30.

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The answers of the following part are:

a) 22

b) -76

c) -13

For solving this particular sum we need to know the about functions Function is generaaly defined as a set of inputs having one output each. every function as a domain and a co-domain or range. A function is generally denoted by f(x) where x is the variable and it is also the input.The general representation of function is y = f(x).

In the given sum we will just put the values in place of x and will find the answer

The given equation is f(x)=-13+7x

a) Here it is given f(5)  so we will put 5 in all places of x

Substituting the value x as 5 we will get :

f(5) = -13+7*5

= -13+35

=22

the value f(5) will be 22

b) In this part of the vaule of x is given as -9

Substituting the value of x as -9 we get

f(-9)=-13+7*(-9)

= -13-63

= -76

the valur of f(-9) is -76

c) here the value of x is given as 0

Substituting the value of x as 0

f(0)= -13+7*0

= -13+0

=-13

the value of f(0) is -13

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Answer: 1. {a, b, c, d, e}

2. {a, b, d}

3. {c, f, g, h}

4. {a, c}

Step-by-step explanation:

1. AUC ==> Means take all parameters from A and C.

A+C=

{a, b, c, d}+{a, e}={a, b, c, d, e}

2. B∩A ==> Means take the common parameters from B and A

B: {b, e, a, d}

A: {a, b, c, d}

Both B and A have a, b, and d.

So answer is {a, b, d}.

3. B' is every parameter that isn't in B

Reminder: B={b, e, a, d}.

All parameters: {a, b, c, d, e, f, g, h}

Remaining Parameters(B'): {c, f, g, h}

4. A-B∩C'

First, let's find C'.

C' is every parameter that isn't in C.

Reminder: C={a, e}

All parameters: {a, b, c, d, e, f, g, h}

Remaining Parameters(C'): {b, c, d, f, g, h}

Then lets find B∩C'

B: {b, e, a, d}

C': {b, c, d, f, g, h}

Both B and C' have b and d, so B∩C' is {b, d}

A-{b, d}=

{a, b, c, d}-{b, d}={a, c} ==> Answer for 4

Answer:

[tex]\sf 1) \quad \sf A \cup C = \{a, b, c, d, e\}[/tex]

[tex]\sf 2) \quad B \cap A = \{a, b, d\}[/tex]

[tex]\sf 3) \quad B' = \{c, f, g, h \}[/tex]

[tex]\sf 4) \quad A -(B \cap C') = \{a, c \}[/tex]

Step-by-step explanation:

Set Notation

[tex]\begin{array}{|c|c|l|} \cline{1-3} \sf Symbol & \sf N\:\!ame & \sf Meaning \\\cline{1-3} \{ \: \} & \sf Set & \sf A\:collection\:of\:elements\\\cline{1-3} \cup & \sf Union & \sf A \cup B=elements\:in\:A\:or\:B\:(or\:both)}\\\cline{1-3} \cap & \sf Intersection & \sf A \cap B=elements\: in \:both\: A \:and \:B} \\\cline{1-3} \sf ' \:or\: ^c & \sf Complement & \sf A'=elements\: not\: in\: A \\\cline{1-3} \sf - & \sf Difference & \sf A-B=elements \:in \:A \:but\: not\: in \:B}\\\cline{1-3} \end{array}[/tex]

Given sets:

Therefore:

Question 1

[tex]\begin{aligned}\sf A \cup C & = \sf \{a, b, c, d\} \cup \{a,e\}\\& = \sf \{a, b, c, d, e\}\end{aligned}[/tex]

Question 2

[tex]\begin{aligned}\sf B \cap A & = \sf \{b, e, a, d\} \cap \{a, b, c, d\}\\& = \sf \{a, b, d\}\end{aligned}[/tex]

Question 3

[tex]\begin{aligned}\sf B' & = \rm U - \sf B\\& = \sf \{a, b, c, d, e, f, g, h \}-\{b, e, a, d\}\\& = \sf \{c, f, g, h \}\end{aligned}[/tex]

Question 4

[tex]\begin{aligned}\sf A -(B \cap C') & = \sf \{a, b, c, d \}- \left( \{b, e, a, d \} \cap \{b, c, d, f, g, h \} \right)\\& = \sf \{a, b, c, d \}- \{b, d \} \\& = \sf \{a, c \}\end{aligned}[/tex]

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The correct value of m = 6 and b = -9.

The function f(x) is differentiable at x = 3 and we know that if a function is differentiable at some point means that it is continuous at that point also.

Here function is continuous at x = 3 piecewise

m(3) + b = (3)²

3m + b = 9 .....(1)

and function is differentiable at ( x = 3 ) piecewise

d/dx ( m * x + b ) = d/dx (x)² at ( x= 3 )

( m + 0 ) = 2x  at ( x = 3 )

m = 2 * 3

m = 6

By placing the value of m in equation (1)

3m + b = 9

3 * 6 + b = 9

18 + b = 9

b = 9 - 18

b = -9

Therefore, the value of m = 6 and b = -9.

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answer:

1,120,504

Step-by-step explanation:

I don't really have one but I'm sure

2(6k+2)=64

12k+4=64

12k=60

k=5