Find the geometric probabilty of landing in the shaded area of the picture. The small circle has a diameter of 20 in and the larger circle has a diameter of 48 in. Round to the nearest hundredth place. Show and explain all work.

Answer:

1992

Step-by-step explanation:

Let x be the amount invested at 12%.

Then the rest amount is (21360-x) dollars.

The 12% stock earning is 0.12x dollars.

The rest amount loss  is 0.05*(21360-x) dollars.

Your equation is

interest - loss            = total interest,    or

0.12x     - 0.05*(21360-x) = 1992    dollars.

Simplify and solve for x.

Answer:

1

Step-by-step explanation:

that is the answer

because 51213÷3=17071

Answer:

c part is correct answer

Answer: D) 240 cm^3

Step-by-step explanation:

On edge

Answer:

64 km per hour

Step-by-step explanation:

544/8.5=64

Answer:

c

Step-by-step explanation:

thats the anser

9514 1404 393

Answer:

  x = -4

Step-by-step explanation:

Put the given point in the equation and solve for x.

  4x = 5(-3) -1

  4x = -16 . . . . . . simplify

  x = -4

Answer:

soln

Step-by-step explanation:

=21÷x-2s

=21÷7-2×9

=3-18

=-15

B

if it is not correct sory

Diagram B is a proper demonstration of an angle bisector.

Letter A is wrong because they are a set of intersecting ines.

Letter C is wrong because they are a set of parallel lines.

Letter D is wrong because they are also a set of perpendicular lines.

So, now, we know that Letter B is the correct answer. The reason for this is also because ∠ACD is bisected by line B.

I hope that this helped answer your question. Have a good day!

Answer:

B

I just did it and got it right

(a) X has a probabiliity density of

[tex]f_X(x) = \begin{cases}\dfrac1{b-a}&\text{if }a<x<b\\0&\text{otherwise}\end{cases}[/tex]

If the lower quartile is 5 and the upper quartile is 9, then

[tex]\displaystyle \int_a^5 f_X(x)\,\mathrm dx = 0.25 \text{ and } \int_9^b f_X(x)\,\mathrm dx = 0.25[/tex]

Computing the integrals gives the following system of equations:

[tex]\displaystyle \int_a^5\frac{\mathrm dx}{b-a} = \frac{5-a}{b-a} = 0.25 \\\\ \int_9^b \frac{\mathrm dx}{b-a} = \frac{b-9}{b-a} = 0.25[/tex]

5 - a = 0.25 (b - a)   ==>   0.75a + 0.25b = 5   ==>   3a + b = 20

b - 9 = 0.25 (b - a)   ==>   0.25a + 0.75b = 9   ==>   a + 3b = 36

Eliminate a :

(3a + b) - 3 (a + 3b) = 20 - 3×36

-8b = -88

==>   b = 11   ==>   a = 3

and so P(X = x) = 1/(11 - 3) = 1/8 for all 3 < x < 11.

(b)

[tex]\displaystyle P(6<X<7) = \int_6^7f_X(x)\,\mathrm dx = \int_6^7\frac{\mathrm dx}8 = \boxed{\frac18}[/tex]

(c) The distribution function is then

[tex]\displaystyle F_X(x) = \int_{-\infty}^x f_X(t)\,\mathrm dt = \begin{cases}0&\text{if }x\le3 \\ \dfrac x8 &\text{if }3<x<11 \\ 1&\text{if }x\ge11\end{cases}[/tex]

Step-by-step explanation:

Hahahaha this is math.lol

Answer: 11

Step-by-step explanation:

6+27=33

33/3 = 11

Answer:

f(x) = [tex]-2^{x+1}-1[/tex]

Step-by-step explanation:

I. If you see (0, -3) point on the green line

II. Perform x = 0, if y = -3 means the statement is true

    = [tex]-2^{0+1} - 1[/tex]

    = [tex]-2^{1}[/tex] - 1

    = -2 - 1

  y = -3

Got more question or somethin to discuss? Leave comment below

9514 1404 393

Explanation:

Add sin(θ)

  cos(θ) = sin(θ)

Divide by cos(θ)

  1 = sin(θ)/cos(θ) = tan(θ)

Square both sides

  1 = tan²(θ)

Add 1

  2 = tan²(θ) = sec²(θ)

Take the square root

  √2 = sec(θ) . . . . for 0 < θ < π

_____

Additional comment

The equation cos(θ) -sin(θ) = 0 has two solutions: θ = π/4 and θ = 5π/4. For the first-quadrant solution, sec(θ) = √2. For the third-quadrant solution, sec(θ) = -√2.

Answer:

B

Step-by-step explanation:

It just is

Answer:

Area is the total surface covered by the shape and perimeter is the total length of the shape.

Answer:

35

Step-by-step explanation:

all are obeying a constant ratio

Answer:

210

Step-by-step explanation:-133-55-22=210

Plug in maximum value of x (3) and see what you get. The maximum value of the expression when plugged in is C.

[tex]3^3-3\cdot3+5=C[/tex]

[tex]27-9+5=C\implies 23=C[/tex]

Now that means,

[tex]x^3-3x+5\leq 23[/tex] for any x in [tex][0,3][/tex]

Hope this helps :)

let length be x

ATQ

[tex]\\ \sf\longmapsto \dfrac{2}{8}\times x=28[/tex]

[tex]\\ \sf\longmapsto \dfrac{2x}{8}=28[/tex]

[tex]\\ \sf\longmapsto \dfrac{x}{4}=28[/tex]

[tex]\\ \sf\longmapsto x=4(28)[/tex]

[tex]\\ \sf\longmapsto x=112[/tex]

Answer:

5m

Step-by-step explanation:

Applying Pythagoras theorem:

a² + b² = c² (where a is base length, b is the height and c is the hypotenuse of the right triangle)

3² + 4² = c²

c² = 9 + 16 = 25

c = x = [tex]\sqrt{25}[/tex] = 5

∴ x = 5m

Answer: x = 1

Step-by-step explanation:

Given

3/2 + (1/2)x = 2x

Multiply 2 on both sides to cancel out the denominator

2 · [3/2 + (1/2)x] = 2 · 2x

3 + x = 4x

Subtract x on both sides

3 + x - x = 4x - x

3 = 3x

Divide 3 on both sides

3 / 3 = 3x / 3

[tex]\boxed {x=1}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

13.6122

Step-by-step explanation:

(x-18.6)/15.3=-0.326

x-18.6=-0.326*15.3

x-18.6=-4.9878

x=-4.9878+18.6

x=13.6122