Four toy cars are moving at a constant speed until they experience an unbalanced force of 12 n each. Which toy car would have an acceleration of 3 m/s2 ?.

The period of oscillation is 0.5 second.

We need to know about period of oscillation to solve this problem. Period is how much time taken to do one oscillation. It can be determined as

T = t / n

where T is period, t is time and n is how many oscillations.

From the question above, we know that

n = 8

t = 4 s

By substituting the parameters, we get

T = t / n

T = 4 / 8

T = 0.5 second

Hence, the period of oscillation is 0.5 second.

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The frequency of orange light is 5 x 10¹⁴ Hz or 500 THz.

We need to know about photon frequency to solve this problem. The photon frequency can be determined as

f = c / λ

where f  is frequency, c is speed of light (3x10⁸ m/s) and λ is wavelength.

From the question above, we know that:

c = 3x10⁸ m/s

λ = 6 x 10¯⁷ m

By substituting parameters, we get

f = c / λ

f =  3 x 10⁸ /( 6 x 10¯⁷ )

f = 5 x 10¹⁴ Hz

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The kinetic energy of the proton is 1982.31 MeV.

We need to know about relativistic energy to solve this problem. The rest energy of the object can be determined by

Eo = m₀ . c²

where Eo is rest energy, m₀ is rest mass and c is the speed of light (3 x 10⁸ m/s).

The total energy of object can be described as

E = Eo / √(1 - v²/c²)

where E is total energy, v is the object speed.

Kinetic energy can be defined as energy change from rest energy until total energy. It can be determined as

KE = E - Eo

where KE is kinetic energy.

From the question above, we know that :

m₀ = 1.6 x 10¯²⁷ kg

c = 3 x 10⁸ m/s

v = 0.95c

Find the rest energy

Eo = m₀ . c²

Eo = 1.6 x 10¯²⁷ . (3 x 10⁸)²

Eo = 1.44 x 10¯¹⁰ joule

Eo = 1.44 x 10¯¹⁰ / (1.6 x 10¯¹⁹) eV

Eo = 900 x 10⁶ eV

Eo = 900 MeV

Determine the total energy

E = Eo / √(1 - v²/c²)

E = 900 / √(1 - (0.95c)²/c²)

E = 900 / 0.31

E = 2882.31 MeV

Calculate the kinetic energy

KE = E - Eo

KE = 2882.31 MeV - 900 MeV

KE = 1982.31 MeV

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The electric field at a midpoint is 1.425 x 10⁴ N/C.

We need to know about the electric fields to solve this problem. The electric field produced by a single-point positive charge is a radial field, whose strength is given by the equation

E = k.Q/r²

where E is the electric field, Q is the charge and r is the radius.

From the question above, we know that

k = 9 x 10⁹ Nm²/C²

Q1 =e = 1.6 x 10¯¹⁹ C

Q2 = e = 1.6 x 10¯¹⁹ C

x = 897 nm = 8.97 x 10¯⁷ m

from midpoint (r = 4.495 x 10¯⁷ m)

The electric field radially outward from proton to electron so that the total electric field between the charges will be added up.

Etotal = E1 + E2

Etotal = k.e/r² + k.e/r²

Etotal = 2. k.e/r²

Etotal = 2 x 9 x 10⁹ x 1.6 x 10¯¹⁹/(4.495 x 10¯⁷)²

Etotal = 1.425 x 10⁴ N/C

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Answer:

centripetal acceleration formula

a = v²/r

v velocity

r radius

a= .5²/7

a = .25/7

a= .03571

ans .o3571

Answer:

A

Explanation:

the change in kinetic energy of the car is None of these

perfectly inelastic collision - It is the physical process. Of one object which strike against another without conserving the kinetic energy of to object.

m₁ = 1,500 kg  (mass of car)

v₁ =  4.00m/s     (velocity of car)

m₂= 50000kg    (mass of truck)

v₂ = 1.80m/s       (velocity of truck)

for perfectly elastic collision

[tex]v_{f}[/tex]=?

[tex]m_{1} .v_{1,i} + m_{2} .v_{2,i} =( m_{1} + m_{2} ).v_{f}[/tex]

1500*4 + 50000*1.80

= (1500 + 50000) [tex]v_{f}[/tex]

[tex]v_{f}[/tex] = 1.864 m/s

Initial kinetic energy is

K.E (i) = [tex]\frac{1}{2} m_{1} .v_{1,i} ^{2} + \frac{1}{2} m_{2} .v_{2,i}^{2}[/tex]

[tex]\frac{1}{2}[/tex]× [(1500*4²) +(50000)*(1.8)²

= 93000J

Final kinetic energy is  

K.E = [tex]\frac{1}{2}(m_{1} +m_{2} )v_{f}^{2}[/tex]

[tex]\frac{1}{2}[/tex]× ((1500+50000)*(1.864 )²

= 89476 J

Change in kinetic Energy

K.E = K.E (f) -  K.E (i)  

 = 89476 -93000

= -3524 J

the change in kinetic energy of the car is None of these

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Answer: I don't know the right answer but it makes more sense for it to be balanced  

Explanation:

[tex]Given data : f01 = 560 hz f02 = 480 hz vs = 340 m/s ( velocity of sound ) vx = velocity of source ( police car )Condition 1 when source approach observer : f01 =[ vs /( vs - vx )].fs ...........(1)Condition 2 when source passes observer : f02 = [vs /( vs + vx) ].fs ............(2)eq(1) : eq (2) we get : f01 / f02 = ( vs + vx )/( vs - vx ) 7/6 = ( 340 + vx ) / ( 340 - vx )[/tex][tex]solve this equation get vx = 26.15 m/s[/tex]

The frequency of a repeated event is its number of instances per unit of time. In certain cases, it is also referred to as temporal frequency or ordinary frequency to underline differences with spatial and angular frequencies, respectively. One (event) per second is equal to one hertz (Hz), which is how frequency is stated. The period is the reciprocal of the frequency since it represents the length of time for one cycle in a recurring occurrence. For instance, the period, T—the space between beats—of a heart beating at a frequency of 120 beats per minute (2 hertz), is equal to 0.5 seconds (60 seconds divided by 120 beats).

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The weight of the car in kilogram is 4.04 kg.

The Mass of the substance in grams is 5,400 g.

The Distance of the marathoner in kilometers is 42.2 km.

The Volume of the Mountain dew in ounces is 33.8 oz.

The Capacity of the flash drive in centibytes is  8 x 10⁸ CB.

Unit conversion is used to convert the units of some measurement into other units.

The weight of the car in kilogram is calculated as follows;

1 pound = 0.453592 kg

8.9 pounds = ?

= (8.9 x 0.453592 kg)

= 4.04 kg

The mass of the substance in grams is calculated as follows;

1 kg = 1000 g

5.4 kg = ?

= (5.4 x 1000 g)

= 5,400 g

The distance of the marathoner in kilometers is calculated as follows;

1 mile = 1.609 km

26.2 miles = ?

= (26.2 x 1.609 km)

= 42.2 km

The volume of the Mountain dew in ounces is calculated as follows;

1 ml = 0.0338 oz

1000 ml = ?

= (1000 x 0.0338 oz)

= 33.8 oz

The capacity of the flash drive in centibytes is calculated as follows;

1 MB = 1 x 10⁸ CB

8 MB = ?

= (8 x 10⁸ CB)

= 8 x 10⁸ CB

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Answer:

The straight down arrow

Explanation:

Next time add a picture to also help those who would like to answer. :)

The time taken to diffuse 2.00 mm will be 20 seconds.

The velocity of diffusion(v) is given by the following formula:

v = Distance/Time

We are given that it takes a sample of molecules 10 seconds to diffuse 1.00 mm.

Thus, its velocity is

v = 1.0 mm/10 s = 0.1 mm/s

In the second case, the distance is given, so we can calculate the time required for diffusion by again applying the same formula

0.1 = 2.00 mm/Time

On rearranging above equation, we get

Time = 20 seconds

Thus, the time taken to diffuse 2.00 mm will be 20 seconds.

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When a wave encounters an obstacle or a slit that is comparable in size to its wavelength, it bends around it. This characteristic is called diffraction.

Diffraction refers to the phenomenon in which a propagating wave bends when it encounters an obstacle or a slit, especially when the obstacle or slit is similar in size to the wavelength of the wave.

The characteristic pattern produced from a diffracted wave is as a result of the interference of individual spherical wavelets, as described by the Huygens–Fresnel principle. Diffraction occurs in all waves, including water waves, sound waves, electromagnetic waves and even gravitational waves.

Sound waves can also diffract around objects. For example, a person is able to hear his name being called even though he is standing at the other side of an obstacle, as the sound waves bend around the obstacle.

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The time interval with respect to Ed is 4.88 ×10³ s.

A frame of reference is a set of reference points—geometric points whose positions are known mathematically and physically—that define the origin, orientation, and scale of an abstract coordinate system.

If a body does not continuously adjust its position in relation to its environment throughout the course of time, it is said to be at rest.

In the frame S', Dina and Owen are at rest.

The speed of the ball with respect to Owen, u =0.800c

The speed of the frame S' with respect to frame S,  v = 0.600c

Distance between Dina and Owen, L(p) = 1.8 × 10¹² m

Speed of light, c = 3 × 10⁸ m/s

Now, for time intervals using the Lorentz transformation equation:

Δt = 1 / [ √( 1 - (v²/c²)] ( Δt' + (vΔx'/c²))

Now, v = 0.6c as S' is moving with respect to frame S.

Hence, the time taken is:

Δt = 1 / [ √( 1 - ((0.6c)²/c²)] ( 7.5 ×10³ + [(-0.6c)(1.8 × 10¹²)/c²))

Δt = 1.25( 75000 - 3600)

Δt = 4.88 ×10³ s

The total time taken by the ball with respect to Ed is 4.88 ×10³ s.

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The current must be along +x axis.

A stream of charged particles, such electrons or ions, traveling through an electrical conductor or a vacuum is known as an electric current. It is calculated as the net rate of passage of electric charge through a surface or into a control volume. Charge carriers, which can be any one of a number of particle kinds depending on the conductor, are the moving particles. Electrons travelling through a wire are frequently the charge carriers in electric circuits. They may be electrons or holes in semiconductors. Ions are the charge carriers in an electrolyte, whereas ions and electrons make up plasma, an ionized gas.

Explanation:

Given,

Velocity of proton,V = [tex]V_{i} i[/tex]

Magnetic force,F = [tex]F_{i} j[/tex]

Magnetic Field= B

(a)

If proton (p+) is moving in ve x-direction.

So,current(I) must be along +x axis.

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The cheetah that can accelerate from rest to a speed of 30.0 m/s in 7.00s has an acceleration of: 4.285 m/s²

The formula and procedure we will use to solve this exercise is:

a = (vf - vi) /t

Where:

Information about the problem:

Applying the acceleration formula we have:

a = (vf - vi) /t

a = (30.0 m/s - 0 m/s) /7.00 s

a = (30.0 m/s m/s) /7.00 s

a = 4.285 m/s²

It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2

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Answer:

86.2 m  range

Explanation:

Vertical component of initial shot = 30 sin 55= 24.575 m/s

Now you can find out for how long it is in the air

     when it hits the ground , position = 0

            0 = 24.575 t  - 1/2 ( 9.81) t ^2

                         finds t = 5.01 seconds       (Using quadratic formula)

HORIZONTAL component = 30 cos 55 = 17.21 m/s

    it travels this speed for 5.01 seconds

               5.01 * 17.21 = 86.2 m

Answer:

480 meters

Explanation:

The charge per unit length on the inner surface of the cylinder is 3λL.

The electric flux across any closed surface is proportional to the net electric charge q enclosed by the surface, according to Gauss's law of electricity, which reads as = q/0, where 0 is the electric permittivity of free space, which has a value of 8.854 10-12 square coulombs per newton per square meter.

Here, q stands for charge.

Volt-metres (V m), the SI base unit of electric flux, is also equivalent to newton-meters squared per coulomb (N m2 C-1). On top of that, the fundamental units of electric flux are kgm3s-3A-1.

Q 1 = L as a result of the wire's induction of the cylinder's inner surface.

"q cylinder" is equal to "q in + q out" (cylinder).

L = L + q out

⇒q out =λL+(2λ)

L = q out =3λL

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The sound energy radiated through the windows and doors in 20 min is 332.6 J.

When a force, such as sound or pressure, causes an item or substance to vibrate, the result is sound energy. That energy moves through the substance in waves. Those sound waves are called kinetic mechanical energy. Sound waves are sometimes dubbed mechanical waves because sound waves require a physical medium to propagate. Liquids, gases, or solid materials transfer pressure variations, creating mechanical energy in waves. Like all waves, sound waves include peaks and valleys. The peaks are called compressions, while rarefaction is the term used for the lows. The oscillations between compression and rarefaction move through gaseous, liquid, or solid media to produce energy. The number of compression/rarefaction cycles in a given period determines the frequency of a sound wave.

Sound energy = E = power x time

energy = force x time / area

Given:

sound level, [tex]\beta=101 dB[/tex]

Area, A = [tex]22\;m^{2}[/tex]

Time, [tex]\triangle t=20\;min=1200\;s[/tex]

Intensity, [tex]I_{o}=1 \times 10^{-12}\;W/m^{2}[/tex]

We know that, Sound level is,

[tex]\beta=10 \times log\frac{I}{I_{o} }[/tex]

Solving the above equation for sound intensity,

[tex]I=I_{o}\times 10^{\frac{\beta}{10} }[/tex]

[tex]I=I \times 10^{-12} \times 10^{\frac{101}{10} }[/tex]

[tex]I=0.0126\;W/m^{2}[/tex]

Therefore, The sound energy is,

[tex]E = P \times \triangle t[/tex]

Substitute [tex]P=I \times A[/tex] in the above equation,

[tex]E = I \times A \times \triangle t[/tex]

[tex]E = 0.0126 \times 22 \times 1200[/tex]

[tex]E = 332.6\;J[/tex]

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A magnetic field, often known as a vector field, describes the magnetic influence on moving electric charges, electric currents, and magnetic materials. A force acting on a charge while it travels through a magnetic field is perpendicular to both the charge's motion and the magnetic field.

In a long, straight, vertical lightning stroke, downward-moving electrons and upward-moving positive ions produce a current of magnitude I = 20.0 kA.

At a location r = 50.0 m east of the stroke's center, a free electron is moving through the atmosphere at a speed of v = 300 m/s.

Let B represent the magnetic field and F represent the magnetic force. The vector sketch may then be represented as follows:

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At a depth of 10 m, the manatee's neutral buoyancy keeps it at the same level in water as if there were no air inside its lungs. However, because more air is now contained in the manatee's lungs than before it dove, its weight increases by 9.81 kg and therefore it accelerates downwards (due to momentum). This downward acceleration continues until equilibrium is reached and then ceases due to gravity pulling on both objects equally.

As a result, the manatee now becomes negatively buoyant and must rise to compensate.

When something has neutral buoyancy, it is not affected by the weight of anything above or below it.

This means that objects with neutral buoyancy will stay in place regardless of how high or low they are located in a liquid medium.

Examples of things with neutral buoyancy include air balloons and swimming caps.

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The velocity of Sam just before hitting the ground is 294 m/s.

The above situation represents a case of motion in one dimension.

This type of motion is governed by the following three equations of motion,

v = u + at

v² - u² = 2as

S = ut + 1/2 at²

As in the given case, the acceleration and time have been given and the final velocity is to be calculated, therefore the 1st equation can be used,

v = u+ at

As Sam jumped from the plane, his initial velocity is zero.

So,

v = 0 + 9.8(30)

v = 294 m/s.

Thus, Sam's velocity just before hitting the ground is 294 m/s.

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The velocity of the horse as it travels through the track is 20 m/s.

Velocity can be defined as the ratio of distance or displacement to time.

To calculate the velocity of the the horse, we use the  formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the velocity of the horse as it travels through the track is 20 m/s.

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Answer:

A. 2s

Explanation:

time = distance ÷ speed

T = .2 ÷.1

T= 2

Answer:

A parallel plate capacitor of capacitance C is charged using a battery. • Charge = Q, potential difference = V. • Battery is then disconnected.The electric field is a function of position, but does not depend on the test charge. It is a real entity, because we will show that it carries energy! Hope this helps!

The car given in the question is not traveling at a constant speed as the time interval in which it to cover the equal distance is not equal.

Speed is the physical quantity that measures the rate at which the position of a body is changing with respect to its surrounding. Its S.I. unit is meters per second. And its dimensional equation is [[tex]LT^{-1}[/tex]]

Given in the Question

Time to travel first meter =  5 seconds

Time to travel second meter =  8 seconds

The body is said to be moving with a constant speed if it travels an equal distance in equal intervals of time.

But in the above-given condition, the car travels 1m in 5 seconds but travels the next 1m in 8 seconds. Here the distance traveled is equal but the time interval in which both distances are covered is not equal.

Therefore, the car is not traveling at a constant speed.

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The man moves across the ice with a velocity of -1 m/s.

Formula:

To calculate the velocity we would be using the formula,

M₁U₁ + M₂U₂ = M₁V₁+ M₂V₂

Given:

After applying the law of linear momentum, we get the following value before the throw;

M₁ = Man's initial mass= 80kg,

U₁ = Initial velocity of Man = 0,

M₂= Initial mass of Book  = 4kg,

U₂= Initial velocity of Book = 0.

After the throw, the book's velocity will be

M₁ = Man final mass = 80kg,

V₁ = Man's final velocity = V.

M₂ = Final mass of Book = 4kg,

V₂ = Final velocity of Book = 20 m/s

After substituting the values in the formula, we get,

M₁U₁ + M₂U₂ = M₁V₁+ M₂V₂

Or, (80 x 0) + (4 x 0) = (80V) + (4 x 20)

Or, 0 = 80V + 80

Or, 80V = -80

Or, V = -80/80

V= -1m/s

[Note: The -ve sign shows the opposite direction]

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A metallic item becomes polarised when a charged insulator is brought close to it, as a result of the free charges in the metal moving about. The centre of charge for the type of charge opposite to that on the insulator will be positioned within the metallic item closer to the charged insulator .

When a negatively charged insulator is in contact with a positively charged conductor, the extra negatively charged electrons will migrate to the conductor until they would prefer not to move at all. We refer to this as the system having attained equilibrium when it occurs.

When an uncharged metal item and a charged insulator are positioned close to one another, the charged insulator will induce the opposite charge, and the two objects will be drawn to one another.

The insulator and a metallic item are therefore attracted to one another by the net electric force.

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The currents in the wires are in opposite directions.

If this flowing through the wire are in same direction then they the wire attract each other and if this flowing through the wire are opposite in direction then they the wire repel each other .

As it is given that a pair of wires repel each {other} which suggests that current inside the wires area unit in other means .

Hence current flowing through wires area unit opposite in direction.

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