Given the ion Al+3, what species would you expect to form with each of the following ions? OH- ___________ S2- ___________ PO43- _________

Answer:

Iron has four naturally-occurring stable isotopes, 54Fe, 56Fe, 57Fe and 58Fe. The relative abundances of the Fe isotopes in nature are approximately 54Fe (5.8%), 56Fe (91.7%), 57Fe (2.2%) and 58Fe (0.3%).

Answer:

Joule - J

Explanation:

As energy is defined via work, the SI unit of energy is the same as the unit of work – the joule (J).

Answer:

You are unable to lift an object. Which property makes the object difficult to lift?(1 point)

weight

Answer:

the answer is hydrogen which is B

The substance is an element that is considerably composed of molecules known as hydrogen (H2). Thus, the correct option for this question is C.

A chemical element may be defined as a species of an atom that remarkably bears a specific number of sub-atomic particles in its structure. These elements are not further decomposed into smaller components in a chemical reaction.

H2 is also known as molecular hydrogen. It forms when two hydrogen atoms are significantly bonded to one another in order to give rise to a molecule. Water is not an element, it is a molecule. While methane is a chemical compound that possesses a chemical formula CH4. Helium (He) is a chemical element only.

Therefore, hydrogen is an element that is composed of molecules. Thus, the correct option for this question is C.

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Pressure - Force per unit area

Hope it helped :)

Answer:

[tex]\boxed {\boxed {\sf37,467.72 \ Joules }}[/tex]

Explanation:

We are asked to find how much heat a sample of water absorbed. Since we are given the mass, temperature, and specific heat, we will use the following formula.

[tex]q=mc \Delta T[/tex]

The mass (m) of the sample is 112.5 grams. The specific heat capacity of water (c) is 4.184 Joules per gram degree Celsius. The difference in temperature (ΔT) is found by subtracting the initial temperature from the final temperature.

The water was heated from 12.5 degrees Celsius to 92.1 degrees Celsius.

Now we know three variables and can substitute them into the formula,

[tex]q= (112.5 \ g )(4.184 \ J/g \textdegree C)(79.6 \textdegree C)[/tex]

Multiply the first 2 numbers. Note the units of grams cancel.

[tex]q= (112.5 \ g *4.184 \ J/g \textdegree C)(79.6 \textdegree C)[/tex]

[tex]q= (112.5 *4.184 \ J/ \textdegree C)(79.6 \textdegree C)[/tex]

[tex]q= (470.7 \ J/ \textdegree C)(79.6 \textdegree C)[/tex]

Multiply again. This time the units of degrees Celsius cancel.

[tex]q= (470.7 \ J/ \textdegree C *79.6 \textdegree C)[/tex]

[tex]q= (470.7 \ J *79.6 )[/tex]

[tex]q= 37467.72 \ J[/tex]

37, 467.72 Joules of heat are absorbed by the sample fo water.

Answer:

22 options A cell wall

23 options A anabolism

24 options B 2sugar + 1phosphate group

Answer:

Displacement

Explanation:

OH- in the reactant side of the reaction has switched from Na+ to Al 3+ in the product side. Decomposition is where a compound from the reactant side of the reaction would dissolve into elements in the product side, but that's not the case in this example.

Answer:

Noble gases are stable as they have fully filled outermost orbital. Hence they do not participate in chemical reactions.

But Xenon reacts in some cases in favourable conditions

The option describes the molecule geometry of a molecule with one bond and three lone pairs. Thus, option B is correct.

A covalent bond is defined as  a chemical bond that includes the sharing of electron pair between atoms.The pair of electrons are know as bonding pairs and the stable balance of attractive and repulsive forces between atoms.

The properties of covalent bond are mentioned below:

The covalent compounds have low melting points and boiling points.The covalent compounds do not contain electricity.

The covalent compounds are  having lower enthalpies of vaporization and fusion.The covalent compounds are easily catches fire and are more flammable than ionic compounds.

The covalent compounds are very soft and flexible. The physical properties of covalent compounds are that they have lower melting points and electrical conductivity.

Therefore, The option describes the molecule geometry of a molecule with one bond and three lone pairs. Thus, option B is correct.

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Answer:

The vast majority of the volume in an atom consists of the electron orbitals with electrons that have too little mass to deflect the alpha particles.  So most pass right through the foil.  Only the ones hitting the nucleus are deflected.

Explanation:

The whole reason Rutherford and his students conducted this experiment was to test the then current hypothesis that an atom consists of a homogeneous blend of atomic particles, known as the "plum pudding" model.  If so, there should be no, or minimal, deflection of particles.  That's not what they found.  Since particles were found to be deflected, the group concluded that atoms must contain a large object, which became known as the nucleus.

Answer:

Step 1

1 of 2

V = m / D; V (nugget of gold) = 50 g / 5.0 g / cm 3 = 10 cm3; V (nugget of iron pyrite) = 50 g / 19 g / cm3 = 2.63 cm 3

Result

2 of 2

Due to these results you can conclude that nugget of gold which volume is 10 cm3 is bigger than volume of nugget of iron pyrite which is 2.63 cm3.

Explanation:

Answer:

b

Explanation:

Answer:

The answer is (400, 0.5)

The conversion of units in science is achieved by the use of conversion factors.

A conversion factor is a number used to change a quantity from one unit to another.

The given unit here is the micrometer and we are expected to convert the quantity (mass in this case) from micrometer to meter.

The conversion factor to use is:

1 μm = [tex]1 * 10^-6 m[/tex]

Hence;

0.16 μm = 0.16 μm * 1 * 10^-6 m/ 1 μm

= 1.60 * 10^-7 m

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The element is Magnesium

it has electronic configuration

[tex]\\ \sf\longmapsto 2,8,2[/tex]

or

[tex]\\ \sf\longmapsto 1s^22s^22p^63s^2[/tex]

In valence cell it has 2 electrons and therefore its valency is 2

Answer:

Science is related only to sense-experience, and reason based on the former. It is an accumulation of systematic and verifiable knowledge. The scientific method is one and the same in all branches of knowledge. The unity of science, according to him, consists in its method, not in its material alone.

Explanation:

Answer:

37.5 mL of HCl will be required for complete neutralization with magnesium hydroxide

Explanation:

[tex]{ \bf{2HCl _{(aq)} + Mg(OH)_{2(s)}→ MgCl_{2(s)} + 2H _{2} O_{(l)}}}[/tex]

we've to first get moles of magnesium hydroxide in 50.0 ml :

[tex]{ \sf{1 \: l \: of \: hydroxide \: contains \: 0.12 \: moles}} \\ { \sf{0.05 \: l \: of \: hydroxide \: contain \: (0.05 \times 0.12) \: moles}} \\ = { \underline{0.006 \: moles}}[/tex]

for complete neutralization:

[tex]{ \sf{1 \: moles \: of \: hydroxide\: react \: with \: 2 \: moles \: of \: acid}} \\ { \sf{0.006 \: moles \: react \: with \: \{0.006 \times 2 \}} \: moles} \\ = { \underline{0.012 \: moles \: of \: acid}}[/tex]

compare with acid molarity:

[tex]{ \sf{0.32 \: moles \: of \: acid \: occupy \: 1 \: litre}} \\ { \sf{0.012 \: moles \: of \: acid \: occupy \: ( \frac{0.012}{0.32}) \: litres }} \\ { \underline{ = 0.0375 \: litre \: \: = \: \: 37.5 \: ml}}[/tex]

Answer:

Vanadium (V) is the best conductor of thermal energy in this list

Answer:

A Type IV PFD is an approved device designed to be thrown to a person in the water. It is not designed to be worn. It is designed to have at least 16.5 pounds of buoyancy. The most com- mon Type IV PFD is a buoyant cushion.

Answer:

H2O is the formula of water

Answer:

H²O is formula of water

Explanation:

2 molecule of hydrogen and 1 molecule of oxygen

The property altered during a chemical change that is not altered during a physical change is composition of the matter.

A physical change is one in which no new substance is formed and it is easily reversible.

A chemical change is one that is not easily reversible and no new substance is formed. It may be accompanied by absorption or evolution of heat.

The composition of a substance changes during a chemical change  because bonds between atoms break and new bonds are formed. This does not occur during a physical change.

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Answer:

[tex]2.5\; \rm g[/tex] of [tex]\rm CaCO_{3}[/tex] would contain:

Explanation:

Look up the Avogadro constant: [tex]N_{\rm A} \approx 6.022 \times 10^{23}\; \rm mol^{-1}[/tex].

For example, "[tex]1\; \rm mol[/tex] of carbon atoms" would contain [tex]N_{\rm A}[/tex] carbon atoms (approximately [tex]6.022\times 10^{23}[/tex]) by definition.

Look up the relative atomic mass of carbon, calcium, and oxygen on a modern periodic table:

In other words, the mass of [tex]1\; \rm mol[/tex] of calcium atoms would be [tex]40.078\; \rm g[/tex]. The mass of [tex]1\; \rm mol\![/tex] of carbon atoms would be [tex]12.011\; \rm g[/tex], and the mass of [tex]1\; \rm mol \!\![/tex] of oxygen atoms would be [tex]15.999\; \rm g[/tex].

As the formula [tex]\rm CaCO_{3}[/tex] suggests, every formula unit of this ionic compound includes one calcium atom, one carbon atom, and three oxygen atoms. The formula mass of [tex]\rm CaCO_{3}\![/tex] would give the mass of every mole of [tex]\rm CaCO_{3}\!\![/tex] formula units.

Calculate the formula mass of [tex]\rm CaCO_{3}[/tex] from the relative atomic mass data:

[tex]\begin{aligned} & M({\rm CaCO_{3}}) \\ =\; & 40.078\; \rm g \cdot mol^{-1} \\ & + 12.011\; \rm g \cdot mol^{-1} \\ & + 3 \times (15.999\; \rm g \cdot mol^{-1}) \\ =\; & 100.086\; \rm g \cdot mol^{-1}\end{aligned}[/tex].

Calculate the number of [tex]\rm CaCO_{3}[/tex] formula units in that [tex]2.5\; \rm g[/tex] of this compound:

[tex]\begin{aligned}& n({\rm CaCO_{3}}) \\ =\; & \frac{m({\rm CaCO_{3}})}{M({\rm CaCO_{3}})} \\ =\; & \frac{2.5\; \rm g}{100.086\; \rm g \cdot mol^{-1}} \\ \approx\; & 0.025\; \rm mol\end{aligned}[/tex].

In other words, [tex]2.5\; \rm g[/tex] of [tex]\rm CaCO_{3}[/tex] would contain approximately [tex]0.025\; \rm mol[/tex] [tex]\rm CaCO_{3}\![/tex] formula units.

Again, there are one calcium atom, one carbon atom, and one oxygen atom in every [tex]\rm CaCO_{3}[/tex] formula unit. That approximately [tex]0.025\; \rm mol[/tex] [tex]\rm CaCO_{3}\![/tex] formula units would thus contain:

Make use of the Avogadro constant to convert the numbers.

For example, the number of calcium atoms in that approximately [tex]0.025\; \rm mol[/tex] of calcium atoms would be:

[tex]\begin{aligned} & N({\text{calcium}) \\ = \; & n({\text{calcium}) \cdot N_{\rm A} \\ \approx \; & 0.025\; \rm mol \times 6.022\times 10^{23} \cdot mol^{-1} \\ \approx \; & 1.5 \times 10^{22} \end{aligned}[/tex].

Likewise, the number of carbon atoms in that approximately [tex]0.025\; \rm mol[/tex] of carbon atoms would be:

[tex]\begin{aligned} & N({\text{carbon}) \\ = \; & n({\text{carbon}) \cdot N_{\rm A} \\ \approx \; & 0.025\; \rm mol \times 6.022\times 10^{23} \cdot mol^{-1} \\ \approx \; & 1.5 \times 10^{22} \end{aligned}[/tex].

The number of oxygen atoms in that approximately [tex]0.075\; \rm mol[/tex] of oxygen atoms would be:

[tex]\begin{aligned} & N({\text{oxygen}) \\ = \; & n({\text{oxygen}) \cdot N_{\rm A} \\ \approx \; & 0.075\; \rm mol \times 6.022\times 10^{23} \cdot mol^{-1} \\ \approx \; & 4.5 \times 10^{22} \end{aligned}[/tex].

Answer:

MECHANISM:

1) The lone pair on oxygen attacks the H-Br molecule forming a hydronium ion.

2) Formation of carbocation.

3) Attack of Nucleophile Br  −  .

Explanation:

Answer:

DISPLACEMENT REACTION

COMBINATION REACTION

DOUBLE DISPLACEMENT REACTION

DECOMPOSITION REACTION

Answer:

Density other dude is incorrect

Explanation:

Density is an intensive, rather than an extensive property of matter.

WHAT ARE INTENSIVE AND EXTENSIVE PROPERTIES?

Therefore, density is an intensive, rather than an extensive property of matter.

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Answer:

This Scientific notation;

[tex]4.25 \times {10}^{ - 3} [/tex]

This in standered notation ;

[tex]0.00425[/tex]

I hope I helped you^_^