A student puts a beaker of warm water next to a beaker of cold water so that they touch it. the two statements that are true are the thermal energy will move from warm water to cold water and the thermal energy will move from air to cold water, therefore option B and option D are the correct statements about the given problem statement.
What is the boiling point?It is a temperature at which the pressure exerted by the external atmosphere is equal to the vapor pressure of the substance.
The boiling point depends on atmospheric pressure, temperature, bond strength, and vapor pressure of the liquid.
As the water is boiling it means it has more thermal energy contained in it than the surrounding air and the ice is present at zero degrees.
As we know that heat is always transferred from the higher thermal potential to the lower thermal potential. The warm water has a higher thermal potential; than the cold water and the surrounding air has a higher thermal potential than the cold water.
As per the given problem statement, a student puts a beaker of warm water next to a beaker of cold water so that they touch it. the two statements that are true are the thermal energy will move from warm water to cold water and the thermal energy will move from air to cold water, therefore option B and option D are the correct statements about the given problem statement.
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3. Write any two differences between contact force and not contact force with examples.
Explanation:
Contact force includes applied force, the normal force, the tension and the frictional force. Non-contact force includes electro-magnetic force, the gravitational force and the electrostatic force. For Example, applied force is required to kick the ball else the ball would not move.
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When 4050 joules of heat were applied to 150g of aluminum, the final temperature was 50 degree Celsius. What was the initial temperature? Take specific heat capacity of aluminum as 900J/kg degree Celsius.
Answer:
[tex]\boxed {\boxed {\sf 20 \textdegree C}}[/tex]
Explanation:
We are asked to find the initial temperature of aluminum. We will use the following formula.
[tex]q= mc \Delta T[/tex]
Where q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature, which is also the difference between the final and initial temperature.
[tex]q= mc (T_f-T_i)[/tex]
We know the heat energy applied is 4050 Joules, the mass is 150 grams, the final temperature is 50 degrees Celsius and the specific heat is 900 Joules per kilogram degree Celsius.
We must convert the mass to kilograms because the specific heat is in kilograms. 1 kilogram contains 1000 grams.
[tex]\frac { 1 \ kg }{1000 g }[/tex][tex]150 \ g *\frac{ 1 \ kg }{1000 g } = 150 * \frac {1}{1000} \ kg = 0.150 \ kg[/tex]Substitute all the known values into the formula.
q= 4050 J m= 0.150 kg c = 900 J/g °C [tex]T_f[/tex]= 50°C[tex]4050 \ J = (0.150 \ kg )(900 \ J/kg \textdegree C)(50 \textdegree C -T_i)[/tex]
We are solving for the initial temperature, so we must isolate the variable [tex]T_i[/tex]It is being multiplied by 0.150 kilograms and 900 Joules per kilogram degree Celsius. The inverse operation of multiplication is division, so we divide by both values.
[tex]\frac {4050 \ J}{ (0.150 \ kg )(900 \ J/kg \textdegree C)}= \frac{(0.150 \ kg )(900 \ J/kg \textdegree C)(50 \textdegree C -T_i)}{(0.150 \ kg )(900 \ J/kg \textdegree C)}[/tex]
[tex]\frac {4050 \ J}{ (0.150 \ kg )(900 \ J/kg \textdegree C)}=(50 \textdegree C -T_i)}[/tex]
The units of Joules and kilograms cancel.
[tex]\frac {4050 }{ (0.150 )(900 \ \textdegree C)}=(50 \textdegree C -T_i)}[/tex]
[tex]\frac {4050}{135} \textdegree C = (50 \textdegree C -T_i)[/tex]
[tex]30 \textdegree C = (50 \textdegree C -T_i)[/tex]
50 degrees Celsius is being added to [tex]-T_i[/tex]. The inverse operation of addition is subtraction. Subtract 50 degrees Celsius from both sides.
[tex]30 \textdegree C - 50 \textdegree C= 50 \textdegree C - 50 \textdegree C - T_i[/tex]
[tex]-20 \textdegree C = -Ti[/tex]
[tex]T_i[/tex] is being multiplied by -1. The inverse operation of multiplication is division. Divide both sides by -1.
[tex]\frac {-20 \textdegree C}{-1}= \frac{-T_i}{-1}[/tex]
[tex]20 \textdegree C = T_i[/tex]
The initial temperature of the aluminum was 20 degrees Celsius.
Actividad
1: En general, la dificultad para arrancar electrones aumenta de izquierda a derecha en cada periodo de la tabla periódica. Busca en la tabla periódica potasio (K), calcio (Ca) y uranio (U) y basándote en sus posiciones indica cuál de ellos tendrá una función de trabajo más baja y cuál más alta:
Menor función de trabajo:
Mayor función de trabajo:
2.- La energía de un electrón emitido se mide en electrón-voltios(eV). Un electrón con una energía de 1 eV puede superar un campo eléctrico de 1 voltio. En el simulador, aumenta la tensión hasta que encuentres la tensión más alta que todavía permite a los electrones llegar al amperímetro.
Tensión =
El volaje que has encontrado es igual a la energía de los electrones emitidos en eV.
Class 10 cbse
Question: Draw the ray diagram in each case to show the position and nature of the image formed when the object is placed:
(i) at the centre of curvature of a concave mirror
(ii) between the pole P and focus F of a concave mirror
(iii) in front of a convex mirror
Explanation:
I hope it will help you. But I am in Grade nine .And sry too cuz I told the answer of Grade nine .
A tall pea plant (Tt) is crossbred with a short pea plant (tt). The following Punnett square shows the separated alleles for two pea plants.
Which of the following shows the correct match of the box numbers and the genotype of the offspring?
A. 1 = Tt; 2 = tt; 3 = Tt; 4 = tt
B. 1 = Tt; 2 = Tt; 3 = Tt; 4 = Tt
C.1 = Tt; 2 = Tt; 3 = tt; 4 = tt
D. 1 = Tt; 2 = tt; 3 = tt; 4 = tt
[tex]Hello[/tex] [tex]There![/tex]
The answer is...
A. 1 =Tt; 2 = tt; 3 = Tt; 4 = tt.
Hopefully, this helps you!!
[tex]AnimeVines[/tex]
If a ball is rolling at a velocity of 1.5 m/s and has a momentum of 10.0 kg times m/s, what is the mass of the ball?
Answer:
Mass of the ball, M = 6.667 kg
Explanation:
Given data:
Momentum, Mo = 10.0 kgm/s
Velocity of the rolling ball, V = 1.5 m/s
Mass of the body, M = ?
Momentum, Mo = Mass, M x Velocity, V
10.0 kgm/s = M x 1.5 m/s
Divide each side by 1.5 m/s
M = 10.0 kgm/s / 1.5 m/s
M = (6⅔) kg
:. Mass of the ball, M = 6.667 kg
4:36 PM
How high can a human throw a ball if he can throw it with initial velocity 90 kph
Answer:
90 km/hr= 90000/3600=25 m/s initial velocity
-25/ 2 (-4.9)= 2.551 secs
h(2.551)= -4.9 (2.551)² + 25(2.551)=-31.8872449+63.775 = 31.8m
The distance would be 31.8 meters, also that person will have sore arm.
which of the following are fundamental unit ?
I.candela
II.ampere
III.mole
IV.all of these
Answer:
all of these very easy questions
what is the relationship between high frequency and short wavelength? Low frequency and long wavelength?
Answer:
The frequency of a wave is inversely proportional to its wavelength. That means that waves with a high frequency have a short wavelength, while waves with a low frequency have a longer wavelength.
write si units of the following physical quantities volume , potential difference, temperature, electrical resistance
Answer:
cubic meter - Volume
Volt - potential difference
kelvin - temperature
ohm - electric resistance
Explanation:
hope it helps.
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Is ambition a good or bad thing?
Answer:
some amount of ambition is good for your motivation but excess ambition is dangerous.
Describe how you would measure the Volume of an irregular solid object.
You can include any apparatus and equations.
Answer:
Find a recipient that you can put the object completely inside, and fill this recipient with water. After, you put the irregular solid you want to measure the volume inside, and the water will spill out the recipient. So you take the water that spilled out and uses a graduated recipient to measure the volume of water. The volume of the solid will be exactly the same volume of water that spilled of the first recipient
13 The pressure of the atmosphere is 100 000 Pa
a Calculate the force with which the atmosphere presses on the outside of a large window 2.0m
high and 1.25m wide.
bExplain why this force does not break the window.
Question:-
(A) The pressure of the atmosphere is 100000 Pa Calculate the force with which the atmosphere presses on the outside of a large window 2.0m high and 1.25m wide.
(B) Explain why this force does not break the window.
Answer:-(A)
As we know
[tex]Formula -> pressure = {force} \times area[/tex]
Given->
Pressure-> 1atm
height-> 2 m
wide -> 1.25 m
Putting value in formula ->
[tex]100000 = force \times(h \times w) \\ 100000= force \times 2 \times 1.25 \\ force = \frac{100000}{2 \times 1.25}\\ force = {4×10000}\\ force = 40000\: newton \: (N)[/tex]
(B) Because atmosphere is present on both sides of the window pane so same force is applied from both sides of the window and as we know force is a vector quantity so according to the vector sum the force got cancelled out and net force becomes zero .
That's why even in presence of this amount of force window glass donot break
a) The force with which the atmosphere presses on the outside of the window be 3 × 10⁵ Newton.
b) As the atmosphere exerts thus much force on either side of the window, the opposing forces cancel one another out. The window is not broken by this force, therefore.
What is pressure?It is the ratio between the force being applied and the surface area being applied to. Pressure can be described as: the force applied perpendicularly to an object's surface divided by the surface area over which it is applied.
Given parameters:
The pressure of the atmosphere is 100000 Pa
Height of the large window: h = 2.0 m.
Width of the large window: d = 1.5 m.
surface area of the window = h×d = 2×1.5 m² = 3.0 m².
Hence, the force with which the atmosphere presses on the outside of the window = pressure × surface area
= 100000 Pa × 3.0 m².
= 3 × 10⁵ Newton.
b) As the atmosphere applies this amount of force in both side of the window, each two each an opposite force nullifies each other. So, this force does not break the window.
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A cyclist travels at 15 m/s during a sprint finish. What is this speed in km/h
Answer:
54km/hr
Explanation:
Since we have to complete m/s to km/h.
we can simply divide the m/s by (5/18)
so we get 54km/hr
Water does not run out of dropper unless the rubber-bulb is pressed. Why?
Answer:
The pressure inside the dropper is same as the atmospheric pressure when the rubber bulb is not pressed. ... But when we press the rubber bulb the pressure inside the dropper increases and hence the water flows out. Atmospheric pressure acting from outside the dropper balances the pressure exerted by water and water does not come out of a dropper. On pressing the dropper inside pressure of water becomes more than outside atmospheric pressure and water run out. When we press the bulb of a dropper with its nozzle kept in water, air in the dropper is seen to escape in the form of bubbles. Once we release the pressure on the bulb, water gets filled in the dropper.
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A brick is 32cm long and 10cm wide. It weighs 16N and is lying on the ground. Find the pressure exerted by the brick on the ground.
Answer:
Below
Explanation:
First, we need to convert the dimension from cm to m before plugging it into the equation:
32 / 100 = 0.32 m
10 / 100 = 0.1 m
You can use this equation to find the pressure exerted on the ground
Pressure = Force / Area
Plugging our values in.....
Pressure = 16 Newtons / (0.1)(0.32)
= 16 Newtons / 0.032
= 500 N/m^2
Hope this helps! Best of luck <3
what are each layer on an atom
Explanation:
Protons electrons and neutrons
b Write out the following in full:
103 2 x 106 6.92 x 104 1.34 x 102 10
Can somebody help?
Answer:
b
Explanation:
how is circuit used to make permanent magnet
Answer:
The touch in a circuit is by forming a circuit with the bars, and moving the horseshoe magnet backwards and forwards upon it. Between the two poles a strong current is excited, & on moving the magnet around we magnetize the bars to saturation i.e. to as a high degree as the bar is capable of retaining.
Explanation:
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What is the kinetic energy of a bicycle with a mass of 16 kg traveling at a velocity of 5 m/s
Answer:
200J
Explanation:
K.E=½mv²
K.E=½×16kg×5m/s²
K.E=8kg×25
K.E=200J
Abishek is a runner. He runs the 100 m sprint
in 10 x 6s. What speed did he travel at?
(in m/s)
Answer:
1.67m/s
Explanation:
Total Distance to be travelled by a Runner=100m
Time Taken=10*6s
Speed=Distance/Time
=100/10*6=10/6=1.67m/s
The answer you are looking for is approximately 1.67 m/s.
Solution/Explanation:
Distance Ran: 100 m.
Time ran: 10x6s, or 60s, or one minute.
Speed: Unknown?
Writing out the formula for speed, using distance and time,
S=D/T.
S=Speed.
D=Distance.
T=Time.
Substituting the given values of the variables,
S=100 m/10x6s, or S=100 m/one minute, or S=100 m/60s.
100÷60=1.6667≈1.67.
So, therefore, the final answer is approximately 1.67 m/s.
I hope that this has helped you. Enjoy your day, and take care.
A body of density 9.0cm appears to have mass 27.0g in a liquid of density 1.2gcm. What is the volume of the solid?
Answer:
v * 9.0 = 27.0 + (v * 1.2)
Question on picture please help
Answer:
the only one I know is physics is not absent in our lives so that's false
Jan is 1.32 meters tall. What is her height in inches?
Answer:
51.96 inches
Explanation:
Multiply 1.32 by 39.37
Answer:
52.0 inches
Explanation:
1.32 meters * 39.37 = 51.96 inches ~ 52.0 inches
What does v or vf stand for? What SI units are used to measure it?
Answer:
Below
Explanation:
In my experience, vf means final velocity, and v would be the average velocity!
You would write it as ΔV (delta V)
The SI units that are used to measure it are m/s
Hope that helped!
v and vf stand for velocity and final velocity respectively. its SI unit is to measure it is m/s.
What is velocity & Acceleration ?Velocity is "rate in change of displacement with respect to time".
i.e. v= dx/dt. It is denoted by v.
it is also defined as displacement divided time. i.e. v= Displacement÷Time.
Velocity shows how much distance can be covered in unit time. It's SI unit m/s.
Acceleration is rate in change of velocity with respect to time.
i.e. a = dv/dt
if an object changes its velocity in short time, we can say that it has greater acceleration.
a= dv/dt =Δv/Δt = [tex]\frac{v_{i} - v_{f} }{t_{i}-t_{f} }[/tex]
where [tex]v_{i}[/tex]= initial velocity of an object
[tex]v_{f}[/tex]= final velocity of an object
t₂= initial time of an object
t₁ = final time of an object
Hence v is stands for velocity and vf is stand for final velocity,
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A car starts from rest and accelerates uniformly at a rate of 8.0 meter per second squared for 1.0 meters. At the end of this time interval, the car's final velocity is ___ meters per second.
Answer:
The answer is [tex]v=4ms^{-1}[/tex]
Explanation:
Given,
[tex]u=0\,ms^{-1}\\a=8\,ms^{-2}\\s=1\,m\\\\v=?[/tex]
We know,
∴[tex]v^{2}=u^{2} +2as\\=>v^{2} =0^{2} +2*8*1\\=>v^{2}=16\\v=4\,ms^{-1}[/tex]
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what is the name of the chart that contain elements?
Answer:
Element Chart
Explanation:
It is a chart that provides many different elements.
Class 9 SCIENCE
ch 2 Is matter around us pure
Question -
what you mean by crystallization? Give example.
Answer:
Crystallization is defined as a process by which a chemical is converted from a liquid solution into a solid crystalline state.
Nikki has a momentum of 45 Kilogram meters per second and a mass of 30 Kilograms. What is her velocity?
Answer:
45/30
Explanation:
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Nikki has a momentum of 45 Kilogram meters per second and a mass of 30 Kilograms. then her velocity would be 1.5 meters per second
What is momentum?It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle, and the momentum of any particle is expressed in Kg m/s unit.
Mathematically the formula of the momentum is
P = mv
where P is the momentum of the particle
m is the mass of the particle
v is the velocity by which the particle is moving
As given in the problem Nikki has a momentum of 45 Kilogram meters per second and a mass of 30 Kilograms
P = 45 Kilogram meters per second
m = 30 Kilograms
By substituting the values of the momentum and the mass in the formula of the momentum
P = mv
45 = 30 ×v
v = 45/30 meters per seconds
v = 1.5 meters per seconds
Thus, Nikki weighs 30 kilograms and moves at a 45 kilogram per the second momentum. subsequently, her velocity would be 1.5 meters per second.
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the right-hand tube of the manometer is open to the atmosphere. The pump has been operated so that the mercury levels differ, as shown, by 250 mm. The density of mercury is 13 600 kg / m3. i) Calculate the pressure, in Pa, due to the 250 mm column of mercury.
Answer:
P(ressure) = d g h = density * gravity * height
P = 13600 * 9.8 * .25 = 33,300 Pa
Check: 1 atm = 76 cm = 760 mm height = 1.01 * 10E5 Pa
h = 1.01 * 10E5 / 9.8 * 13600 .758 m = 758 mm for 1 atm
250 / 758 = 1/3 atmosphere = 33,700 Pa close enough for estimates
(the pressure requested is 1/3 atmosphere where 1 atm = 760 mm Hg)