how many inches is in 140 feet?​

Answers

Answer 1

Hey there!

The formula for feet to inches is to simply multiply the length value by 12.

So, multiply 140 by 12.

I believe your answer would be 1680 inches.

Hope this helps!

Have a great day!

Answer 2

Answer:

140 feet is 1680 inches. Don't forget to put your units in; your teacher may dock off points for forgetting to put in the unit.

Step-by-step explanation:

A foot is 12 inches, so you must multiply 140 by 12.

[tex]140\times12=1680[/tex]


Related Questions

A mountain is 15,062 feet above sea level, and a valley is 350 feet below sea level, what is the difference in elevation between the mountain and the valley?

Answers

Answer:

14,712 ft difference

Step-by-step explanation:

15,062 - 350 = 14,712

Answer:

Step-by-step explanation:

Difference in elevation is 15,062-(-350)=15,062+350=15,412

What is the length of the ladder? It is 6 ft. from the house at the bottom and touches the wall 14 ft. up at the top. Simplify your answer

Answers

Answer:

15.2

[tex] {c }^{2} = {a}^{2} + {b}^{2} \: \\ {c}^{2} ={6}^{2} + {14}^{2} \\ {c}^{2} = 36 + 196 \\ {c}^{2} = 232 \\ \sqrt{c } = \sqrt{232} \\ c = 15.23154621[/tex]

4 2/3 - (1 4/5). PLEASE HELP MEEEEE

Answers

Answer: 2 13/ 15

Step-by-step explanation:

Kristen is creating a rectangular garden in her back yard. The length of the garden is 13 feet. The perimeter of the garden must be at least 54 feet and no more than 82 feet.

Answers

So what’s the question?

1) A spinner is divided into equal red, blue, green,
red, black, and yellow sections. What's the
probability of spinning green and then red.

Answers

Answer:

1/18

Step-by-step explanation:

Probability of spinning red=2/6=1/3

Probability of spinning green=1/6

probability of spinning green and then red=(1/6)*(1/3)=1/18

The perimeter of the square with side length y

Answers

Answer:

4y

Step-by-step explanation:

Answer:

perimeter=4y

Step-by-step explanation:

y+y+y+y=4y

..........

What is the range of exponential function g?

Answers

In general, the range is all the y-values used by the function. This function never gets to or goes below -6, so the range is all y-values greater than -6.

g(x) > -6

The range of the exponential function is: B. [tex]g(x)>-6[/tex]

Recall:

Range of any function includes all possible values of y (output)

Domain of any function includes all possible values of x (input).

Thus:

The values of y in the exponential function greater than -6 on the y-axis as shown in the graph given.

Therefore:

Range of the exponential function given in the graph is: B. [tex]g(x)>-6[/tex].

Learn more about exponential function here:

https://brainly.com/question/19554225

Solve M = 5rt^2- 2rv for v.

Can someone please help with this I’ll put it to 100 points

Answers

Answer:

(M-5rt^2)/(-2r) =v

Step-by-step explanation:

M = 5rt^2- 2rv

Subtract  5rt^2 from each side

M-5rt^2 = 5rt^2- 2rv -5rt^2

M-5rt^2 = - 2rv

Divide each side by -2r

(M-5rt^2)/(-2r) =- 2rv / (-2r)

(M-5rt^2)/(-2r) =v

Answer:

[tex]v = -\frac{M-5rt^2}{2r}[/tex]

Step-by-step explanation:

[tex]M = 5rt^2 - 2rv[/tex]

Switch sides

[tex]5rt^2-2rv=M[/tex]

Subtract [tex]5rt^2[/tex] from both sides

[tex]5rt^2 - 2rv-5rt^2= M -5rt^2[/tex]

Simplify

[tex]-2rv = M - 5rt^2[/tex]

Divide both sides by [tex]-2r[/tex]

[tex]\frac{-2rv}{-2r} =\frac{M}{-2r} -\frac{5rt^2}{-2r}[/tex]

Simplify

[tex]-\frac{M-5rt^2}{2r}[/tex]

100 yojan=how much km?​

Answers

Answer:

100 yojan=how much km

1287.48

please brainlist

how to calculate bearing​

Answers

Answer:

Step-by-step explanation:

You will have to interpret the question with the aid of a diagram and make out the relevant angles and either make use of cosine rule,sine rule etc....Your knowledge on angles should be sound

Find the LCM of 315,420,525 using prime factorisation method with slove it​

Answers

[tex]\boxed{\sf \:\begin{cases}\\\begin{gathered} {\underline{{ \sf {\blue{\Large\bf \underbrace{ {\rm {\purple{\begin{array}{r | l}\large\rm{\red{ 5}}&\underline{315,420,525}\\\large\rm{\red{ 3}}& \underline{63,84,105}\\\large\rm{\red{3}}&\underline{21,28,35}\\\large\rm{\red{ 7}}&\underline{7,28,35}\\\large\rm{\red{2}}&\underline{1,4,5}\\\large\rm{\red{2}}&\underline{1,2,5}\\\large\rm{\red{5}}&\underline{1,1,5}\\&1,1,1\end{array}}}}} }}}}}\end{gathered}\\\end{cases}}[/tex]

LCM = 5 × 3 × 3 × 7 × 2 × 2 × 5

LCM = 6300

Hence, the LCM of 315 , 420 , 525 is 6300

Answer:

6300

Step-by-step explanation:

Prime factors of given numbers:

315 = 3*3*5*7420 = 2*2*3*5*7525 = 3*5*5*7

The LCM is:

LCM(315, 420, 525) = 2*2*3*3*5*5*7 = 6300

Choose the best description of the commutative property of addition,
O A. When zero is added to a number, the sum is that number.
OB. If two numbers are added in opposite orders, their sum is 0.
O C. The order in which numbers are added does not affect the sum.
D. Numbers should be added in order from smallest to largest.

Answers

9514 1404 393

Answer:

  C. The order in which numbers are added does not affect the sum.

Step-by-step explanation:

In symbols, the commutative property of addition is ...

  a +b = b +a

The order in which numbers are added does not affect the sum.

A wall is 1200 sq ft.
A gallon of paint covers 200 sq ft.
Complete the conversion factor: 1 gallon / ? sq ft

Answers

200 because a gallon of paint covers 200 square feet

what is the distance between the points (7, 8) and (9, 10).

Answers

Answer:

√8 or 2√2

Step-by-step explanation:

√[(x₂ - x₁)² + (y₂ - y₁)²]

√[(9 - 7)² + (10 - 8)²]

√[2² + 2²]

√[4 + 4]

√8 or 2√2

6. The unit circle with center at the origin is a relation but not a function.
Find the two functions which are semicircles of the unit circle, and determin
e
their domains and ranges?
b. Are these functions onto functions? Justify.
c. Find the two functions which are lie in one of the semicircle in part a, and
determine their domains and ranges?
d. Are these functions one to one correspondence functions? Justify.
Whi​

Answers

Answer:

Step-by-step explanation:

A product is introduced into the market. Suppose a products sales quantity per month q(t) is a function of time t in months is given by q(t) = 5000t-120t^2. And suppose the price in dollars of that product. p(t). is also a function of time t in months and is given by p(t) = 120-t^2.

Required:
a. Find, R'(t). the rate of change of revenue as a function of time t
b. What is the the rate of change of revenue with respect to time 3 months after the introduction?

Answers

Answer:

Part A)

[tex]\displaystyle R'(t) = (5000-240t)(120-t^2)+(5000t-120t^2)(-2t)[/tex]

Part B)

After three months, the revenue is increasing at a rate of $391,560 per month.

Step-by-step explanation:

A product is introduced into the market. The quantity per month q sold is given by the function:

[tex]q(t) = 5000t - 120t^2[/tex]

And the price p (in dollars) of the product is given by the function:

[tex]p(t) = 120-t^2[/tex]

Part A)

R(t), or the revenue, will be the product of the quantity sold and its respective price during the month. Hence:

[tex]\displaystyle R(t) = q(t)\cdot p(t)[/tex]

Substitute:

[tex]\displaystyle R(t) = \left(5000t-120t^2\right)\left(120-t^2\right)[/tex]

To find R'(t), take the derivative of both sides with respect to t:

[tex]\displaystyle R'(t) = \frac{d}{dt}\left[ \left(5000t-120t^2\right)\left(120-t^2\right)\right][/tex]

Since the function is a product of two expressions, we can consider using the Product Rule:

[tex]\displaystyle \frac{d}{dx} \left[uv\right] = u'v+uv'[/tex]

Hence:

[tex]\displaystyle R'(t) = \frac{d}{dt}\left[5000t-120t^2\right]\left(120-t^2\right) + \left(5000t-120t^2\right)\frac{d}{dt}\left[120-t^2\right][/tex]

Differentiate. Therefore:

[tex]\displaystyle R'(t) = (5000-240t)(120-t^2)+(5000t-120t^2)(-2t)[/tex]

(We may simplify if we desire, but this is not required by the problem.)

Part B)

To find the rate of change of revenue with respect to time three months after the introduction, we can evaluate R'(t) at t = 3. Hence:

[tex]\displaystyle R'(3) = (5000-240(3))(120-(3)^2)+(5000(3)-120(3)^2)(-2(3))[/tex]

Evaluate:

[tex]R'(3) = 391560\text{ dollars/month}[/tex]

In conclusion, after three months, the revenue is increasing at a rate of $391,560 per month.

(Note: it is increasing because the final value is positive.)

Rewrite as a product of the GCF and another sum 36 + 48

Answers

Answer:

72+12

Step-by-step explanation:

3 kom 2.7 Eve carves a shape out of wood. What is the volume of the shap 3 cm 1 cm 2 cm 3 cm 4 cm ​

Answers

Answer:

50cm

Step-by-step explanation:

oh apdiya I just wanted to let you

2. Which group of numbers is in size order?

A. 3.10 - 3.20 - 3.09 - 3.55
B. 3.09 - 3.10 - 3.2 - 3.5
C. 3.10 - 3.20 - 3.09 - 3.55
D. 3.1 - 3.55 - 3.2 - 3.09

Answers

Answer:

B. 3.09-3.10-3.2-3.5 is the answer

8 thousands + 4 thousands
What is the answer in standard form?

Answers

Answer:

12000

Step-by-step explanation:

8000+4000=12000

8000
4000

8,000+4,000= 12,000

2. STEM A circuit board manufacturer rejects a 100-ohm resistor if its measured resistance is 0.15 ohm more than or less than 100 ohms. Resistors A and B are rejected. Resistor A's resistance differs from 100 ohms by 0.15 ohm. Resistor B's resistance differs from 100 ohms by -0.78 ohm. How do the resistances of these two resistors compare? Explain.​

Answers

The comparison of both resistors is defined by an inequality. Resistor A has a higher resistance than resistor B because [tex]100.15\Omega > 99.22\Omega[/tex]

Given that:

[tex]R = 100 \Omega[/tex] ---- the reference resistor

First, we calculate the resistance of both resistors

Resistor A differs by [tex]0.15\Omega[/tex] means that:

[tex]R_A = 100\Omega + 0.15\Omega[/tex]

[tex]R_A = 100.15\Omega[/tex]

Resistor A has a resistance of [tex]100.15\Omega[/tex]

Resistor B differs by [tex]-0.78\Omega[/tex] means that:

[tex]R_B = 100\Omega -0.78\Omega[/tex]

[tex]R_B = 99.22\Omega[/tex]

Resistor B has a resistance of [tex]99.22\Omega[/tex]

By comparing the calculated values, we can conclude that:

Resistor A has a higher resistance than resistor B because [tex]100.15\Omega > 99.22\Omega[/tex]

Read more about inequality comparison at:

https://brainly.com/question/11772136

Use the order of operations to evaluate the expression below.
3 + 5 x 5 - 50 ÷ 2 + 3 - 4

Answer here

Answers

Answer:

2

Step-by-step explanation:

=3+5×5-25+3-4

=3+25-25+3-4

=28-22-4

=28-26

=2

Answer:

2

Step-by-step explanation:

3 + 5 * 5 - 50 / 2 + 3 - 4

3 + (5 * 5) - 50 / 2 + 3 - 4  => Multiplication what ever comes first

3 + 25     (-50 / 2) + 3 - 4  => Division left to right

(3 + 25)     - 25  +( 3 - 4)  => Addition what ever comes first

28  - 25 - 1 => Substraction  left to right

2

Leave comment if you're curious.

Let A={1,2,3,4,5,6,7,8}A={1,2,3,4,5,6,7,8}. Define a relation ∼∼ on AA by a∼ba∼b if and only if 33 divides a−ba−b for all a,b∈Aa,b∈A.  1. Find all the pairs (a,b)∈A×A(a,b)∈A×A such that a∼ba∼b. 2. Show that ∼∼ is an equivalence relation on AA. 3.  Find the equivalence classes [2][2] and [3][3].​

Answers

Define relation.

Let A and B are only two non-empty set,then A*B is cartesian product of A*B.Then any subset of A*B is known as the relation fromA to B.

On the first day of December, 34,789 people went to the mall. On the second day 63,587 people went to the mall. How many people went to the mall over the two days

Answers

Answer:

98376

Step-by-step explanation:

I need help, NO LINKS

Answers

If you distribute each side of the equation, you’d get 12g+18 = 12g+18
This statement is always true, no matter what you put in place of g.
That means any and every real number will be a solution.
Therefore there are infinitely many solutions.

If the equation had worked out to be 12g+18 = 12g+7 or something else where the variable terms were identical, but the numbers weren’t, then there’d be no solution, since there’s no way to make 18=7.

HELP!! TRUTH TABLE

I would really appreciate it, if someone could walk me through how they did it! Thanks.

Answers

pq (i.e. "p and q") is true only if both p and q are true. This is the case for the first two rows, but not the third.

Similarly, (pq) ∧ r is true only if both pq and r are true. We know when pq is true, so (pq) ∧ r is true only when all three of p, q, and r are true. This happens only in the first row.

All other cases are false.

The table should look like this:

[tex]\begin{array}{c|c|c|c|c}p&q&r&p\land q&(p\land q)\land r) \\---&---&---&---&--- \\T&T&T&\boxed T&\boxed T\\&&&&\\T&T&F&\boxed T&\boxed F\\&&&&\\T&F&T&\boxed F&\boxed F\end{array}[/tex]

graph the sequence 2, 4, 6, 8, 10

Answers

Answer:

going up in even numbers

Step-by-step explanation:

its like the two times table, and it goes up in even numbers

Answer:

any number you can take

Step-by-step explanation:

like 4'6'8''12

Show that 5x^2 + 2x - 3 < 0 can be written in the form | x + 1/5 | < 4/5

if possible with the explanation as well ​

Answers

Step-by-step explanation:

First let solve the inequality

[tex]5 {x}^{2} + 2x - 3 < 0[/tex]

Factor by grouping

[tex]5 {x}^{2} + 5x - 3x - 3 < 0[/tex]

[tex]5x(x + 1) - 3(x + 1)[/tex]

So the factor are

[tex](5x - 3)(x + 1)[/tex]

So the factor are

[tex]x = \frac{3}{5} [/tex]

and

[tex]x = - 1[/tex]

Solutions to a quadratic can be represented by a absolute value equation because remeber quadratics

creates 2 roots and/or double roots.

The inequality

[tex] |x - b| < c[/tex]

works as

b is the midpoint between 2 roots. And c is the

[tex] |x + b| = c[/tex]

We know that the midpoint between both roots is-1/5.

so

[tex] |x - ( - \frac{1}{5} )| < c[/tex]

[tex] |x + \frac{1}{5} | < c[/tex]

Let use roots 3/5

[tex] | \frac{3}{5} + \frac{1}{5} | = \frac{4}{5} [/tex]

-1 works as well.

[tex] | - 1 + \frac{1}{5} | = | - \frac{4}{5} | = \frac{4}{5} [/tex]

So the absolute value equation is

[tex] |x + \frac{1}{5} | < \frac{4}{5} [/tex]

Write the number in expanded form 99,763

Answers

Answer:

90,000+9,000+700+60+3

Answer:

90,000 + 9,000 + 700 + 60 + 3 I hope this helped

Answer this question.

Answers

Answer:

B) Both functions have a y-intercept of -2.

Step-by-step explanation:

Hi there!

A) Both functions are always increasing.

⇒ False

Let's first take a look at the given equation, [tex]y=3x-2[/tex]. This is a linear equation, and it is organized in slope-intercept form: [tex]y=mx+b[/tex]. m is the slope and b is the y-intercept. When m is positive, it is always increasing.

In [tex]y=3x-2[/tex], 3 is m, and because it's positive, this line is always increasing on a graph.

However, when we take a look at the given graph, this isn't the case. It is decreasing for values of x below 0 (on the left side of the y-axis).

B) Both functions have a y-intercept of -2.

⇒ True

In the given equation [tex]y=3x-2[/tex], this is true. -2 is the y-intercept.

On the given graph, we can see that the graph intercepts the y-axis at -2, so this is also true for the graph.

C) Both functions are symmetric about the y-axis.

⇒ False

The given graph is symmetric about the y-axis, but the line is not. Any line that would be symmetric about the y-axis would be in the form [tex]y=b[/tex], which isn't the case here with [tex]y=3x-2[/tex]. [tex]y=3x-2[/tex] has a slope.

D) Both functions are linear relationships.

⇒ False

Sure, [tex]y=3x-2[/tex] is a linear equation, making it a line, but not the given graph. The graph does not resemble a straight line, so it is not a linear relationship.

I hope this helps!

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