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The sign of v(O) is positive.

Recurrence is the quantity of events of a rehashing occasion for each unit of time. It is additionally once in a while alluded to as fleeting recurrence to underscore the difference to spatial recurrence, and customary recurrence to stress the differentiation to precise recurrence. Recurrence is communicated in units of hertz (Hz) which is comparable to one (occasion) each second. The comparing time frame is the time term of one cycle in a rehashing occasion, so the period is the corresponding of the recurrence. Recurrence is estimated in units called hertz (Hz). At the point when one wave passes in a single second its recurrence is 1 wave each second or 1 Hertz. Recurrence and period are really alternate extremes. While period is estimated in seconds per cycle, recurrence is estimated in cycles each second. Think about our wave with a time of 2 seconds.

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Answer:

Drinks are cooled more effectively by ice pieces at 00C and not by water at 00C. This is because ice takes away more heat from the drink while melting as a result of high specific latent heat capacity of ice.

Explanation:

Answer:

the study of Earth's magnetic field is known as isochronism

Explanation:

isochronism is having a period that is independent of oscillator amplitude in an oscillator. Like, a pendulum or balance.

The physics problem to find the unknown has applied physics principles will be the following:

The simplified expression for coefficient of kinetic friction is 0.097.

The given parameters:

g = 9.8 m/s²

a = 3.6 m/s²

θ=27.0∘

The simplified expression for coefficient of kinetic friction is calculated as follows;

μkmgcosθ = mgsinθ − ma

m(μkgcosθ) = m(gsinθ − a)

μkgcosθ = gsinθ − a

The practise of using physics as a science to assist people and address their issues is known as applied physics.

Engineering is distinct from it since engineers deal with clearly defined problems. Applying physics to the development of new technologies or the resolution of engineering issues is the work of applied physicists.

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If the distance d is much greater than the length of the wire, then intuitively, the magnitude of the electric field at point p should be very large. This is because a strong electric field will cause an increase in current flow through any metal conductor. In this case, due to how greater d is compared to l, there would likely be a significant amount of electricity flowing through both wire and ground.

It will happen as a result of a stronger field and more room between charges. In order to determine this magnitude, one method is to apply Coulomb's Law, which stipulates that:

E=q×C where,

E is the electric field.

q is charge per unit area.

C is the amount of charge held by a object.

Coulomb's law can be derived from the principle of electrostatics. This states that an electrical force is equal and opposite to the electric field at any point in space. In other words, if you charge a capacitor up with electricity, the voltages on each terminal will oppose one another and cause a Force between them (Coulomb's Law).

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The tension in the cord is 4.6 N

According to Newton's second law, an object's acceleration is determined by two factors: the net force acting on the object and the mass of the object.

So, if we chose the positive +x uphill for the FedEx box of mass m2= 1.0 kg and +ve axis for m1 = 3.0 kg such that their accelerations have the same magnitude.

As we apply Newton's second law to each box, we discover that:

[tex]\mathbf{F - T -m_2gsin\theta = m_2a}[/tex]

where;

Thus, the first equation can be rewritten as:

[tex]\mathbf{F-m_2gsin\theta = (m_1+m_2)a}[/tex]

Now, the acceleration moving in the same direction can be computed as:

[tex]\mathbf{a=\dfrac{12N (1.0 kg)(9.8 \ m/s^2)sin 37^0}{(1.0+3.0)kg}}[/tex]

a = 1.53 m/s²

Finally, the tension [tex]\mathbf{T=m_1a}[/tex] = (3.0 kg) (1.53 m/s²)

= 4.6 N

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The rate of increase of the current in the given circuit is determined as 6.67 A/s.

The rate at which the current increases is calculated as follows;

E = L(di/dt)

where;

The rate of increase of the current is calculated as follows;

di/dt = E/L

di/dt = 100 / 15

di/dt = 6.67 A/s

Thus, the rate of increase of the current in the given circuit is determined as 6.67 A/s.

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20855 turns of wire are on the coil.

A substance or thing that creates a magnetic field is called a magnet. The most noteworthy characteristic of a magnet—a force that pulls on other ferromagnetic elements, such as iron, steel, nickel, cobalt, etc.—as well as the ability to attract or repel other magnets—is caused by this invisible magnetic field. An object made of a substance that has been magnetized and produces its own persistent magnetic field is referred to as a permanent magnet. A common example is a refrigerator magnet used to keep notes on the door of the refrigerator. Ferromagnetic materials are those that can be magnetized and are also those that are powerfully drawn to a magnet (or ferrimagnetic).

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The scientific experiments are performed under controlled conditions, which can be considered characteristic of science, therefore the correct answer is option C.

The deliberate, empirically supported pursuit and application of knowledge and understanding of the natural and social worlds are what is known as science.

Science is characterized by the controlled environments in which experiments and observations are made.

Thus, option C is the proper response.

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The Pressure of gas in the syringe when at an initial pressure of 60 kPa and when the volume decreased from 45 cm³ to 40 cm³ is 67.5 kPa.

Pressure can be defined as the force acting perperdicular per unit area to the surface of an object.

To calculate the pressure in the gas, we use the formula below

Formula:

Where:

Make P' the subject of the equation

From the question,

Given:

Substitute these values into equation 2

Hence, the pressure of the gas is 67.5 kPa.

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The magnitude of the force is  295.54 x 10⁻³ N

Attraction betweem nucleus and electron is by electric force. Now, a positive or negative charge generates a field in the void surrounding it. We refer to this void as the electric field.

We know that , force can be found out by given formula

F = q × E where,

F = Force

q = Charge

E = Electric field

Here, the direction of Force is the same as that of the Electric field

Substituting the values, we get

F = 1.4 x 10⁻³ x 211.1

=295.54 x 10⁻³ N

Thus, the magnitude of force is 295.54 x 10⁻³ N

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The electric field is 5.39 × 10^3 N/C.

R(radius of the metal rod) = (10cm)( 1m/100cm) = 0.1m

[tex]\lambda\;(\text{charge per unit length})=(30\;\mathrm{nC/m})\left(\dfrac{1\;\mathrm{C}}{10^9\;\mathrm{nC}} \right)=\textcolor{#ff9c8c}{30\times 10^{-9}\;\mathrm{C/m}}[/tex]

Since the rod is long L≫l, we model it as a long filament of infinite length and constant charge per unit length for which the electric field is found from Equation (*):

[tex]E=\dfrac{\lambda}{2\pi \epsilon_0 r} \\[/tex]

Substitute numerical values:

[tex]E&=\dfrac{30\times 10^{-9}}{2\pi (8.8542\times 10^{-12})(0.1)}\\ &={5.39\times 10^{3}\;\mathrm{N/C}}}[/tex]

electric field, an electric property associated with each point in space when the charge is present in any form. The magnitude and direction of the electric field are expressed by the value of E, called electric field strength or electric field intensity or simply the electric field.

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Because according to Rutherford's atomic model electrons revolve around the nucleus and are not embedded in it just like plum in pudding. Therefore, it was J.J Thomson's model was rejected.

Rutherford disapproved the previous atomic model of J.J Thomson which suggested that electron are embedded in a positively charged nucleus like the plums in a pudding also known as plum pudding model.

He performed gold foil experiment to determine the atomic model.

However, after conducting the experiment he found that many electrons went starting without changing path.

Only few changed their path showing that atom has a dense massive structure called nucleus.

Thus, Rutherford model shows that electron are not embedded in the nucleus instead they revolve around it.

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0.125 mm . is the thickness of the sample.

The Hall effect is the creation of a voltage difference (the Hall voltage) across an electrical conductor, which is transverse to an applied magnetic field perpendicular to the current and an electric current in the conductor. Edwin Hall made the discovery in 1879.

We need to know the material's current, magnetic field, length, number of charge carriers, and area in order to calculate the Hall voltage. The Hall voltage is computed using the formula: v=IBlneA=(100A)(1.5T)(1.0102m)(5.91028/m3)(1.61019C)(2.0105m2)=7.9106V.

lof4

First we have to plot those point Then we can use some computer program to fit those point linearly to get slope

of that graph a and interception b. We already know, from theory, that Hall's voltage AVH and magnitude of

magnetic field B are connected as

Δ[tex]V_{H} =\frac{I}{nqt} B[/tex]

where I is current trough probe, n is concentration of charge carriers, q = 1.6 • 10¯19 C is charge of charge

carries and t is thickness of the material. We have put the data from the problem on a graph and fitted linearly and

got

a = 100 μ[tex]\frac{V}{T}[/tex]

b = —0.02  μV.

As we can see, our result are in agreement with theoretical assumptions because interception b is almost O, and a

is asked relation between Hall's voltage A VH and magnitude of magnetic field B. Then we can write

ΔVH =[tex]100X10^{-6}[/tex] V/TB

(4) Then we can use result (4) and numbers from the textbook to calculate the thickness of the sample as

[tex]a=\frac{I}{nqt} \\t=\frac{I}{anq} \\t=\frac{.200A}{100X10^{-6}X 1.6 X10^{-19}X10^{26} } \\t=0.125mm[/tex]

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No, we cannot conclude that the photoelectric effect will also occur for different metals under the same conditions.

Mathematically , we can define the photoelectric effect as:

[tex]K.E_m_a_x=E-\phi[/tex]

where  [tex]K.E_m_a_x[/tex] is the kinetic energy of the free electron, E is the energy of the incident photon, and Ф is the work function, the energy needed to release the electron from its parent atom.

For example if we take a light of  2eV that is incident on cesium, which has a work function of 1.26 eV. In this case, since the photon energy is greater than the work function, an electron can be emitted.

but if we hit this light of 2eV on the platinum which has a work function of 3.65eV . Apparently, this time the light doesn't have enough energy to free loosely bound electrons from their parent atoms.

Thus ,the emission of photoelectrons and the kinetic energy of the emitted photoelectrons depend on the frequency of light  incident on the metal surface.

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The wavelength of the initial note is 2.34m

The distance between two successive crests or troughs of a wave is known as its wavelength. It is measured in the wave's direction. The distance a wave travels between its crests or troughs is known as its wavelength (which may be an electromagnetic wave, a sound wave, or any other wave). The wave's crest is its highest point, while its dip is its lowest. Because a wavelength represents a distance or length, it is expressed in length units like meters, centimeters, millimeters, nanometers, etc. Light's wavelength changes with color, or it differs for each hue. While violet has the shortest wavelength, red has the longest.

wavelength = v/f

Given:

Initial frequency, [tex]f_{initial} = 146.8 Hz[/tex]

Final frequency, [tex]f_{final} = 880\;Hz[/tex]

Sound Level, [tex]\beta = 79\;dB[/tex]

We know that,

Speed of the sound, [tex]v=343\;m/s[/tex]

Density of air, [tex]\rho=1.2\;kg/m^{3}[/tex]

Wavelength, [tex]\lambda = \frac{v}{f}[/tex]

Wavelength of initial note is,

[tex]\lambda = \frac{v}{f_{initial} }[/tex]

Substitute the known values in the above equation,

[tex]\lambda = \frac{343}{146.8}[/tex]

[tex]\lambda = 2.34\;m[/tex]

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The  force vector that has a magnitude of 12.0 N. and is oriented 60° to the left of the (y) has the followings components:

To solve this exercise the formulas and procedures we will use are:

Where:

Information about the problem:

Applying the formula of the component of the vector in the (x) axis we have:

v(x) = v * cosine (angle).

v(x) = 12.0 N * cosine (60º)

v(x) =6 N

Applying the formula of the component of the vector in the (y) axis we have:

v(y) = v * sine (angle)

v(y) = 12.0 N * sine (60º)

v(y) = 10.39 N

It can be said to be a straight line described by a point (a) and (b) that has direction and sense.

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Robert uses a spring scale to measure force. The unit of his measurement is newtons.

In material science, a power is an impact that can change the movement of an item. A power can make an item with mass change its speed, i.e., to speed up. Power can likewise be portrayed naturally as a push or a force. Logicians in classical times involved the idea of power in the investigation of fixed and moving articles and basic machines, yet scholars, for example, Aristotle and Archimedes held crucial mistakes in grasping power. To a limited extent this was because of a deficient comprehension of the occasionally non-clear power of erosion, and a thusly lacking perspective on the idea of normal movement.

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The height the atmosphere would extend is 16,218.5 m.

The standard atmospheric pressure at sea level has a magnitude of 101,325 N/m².

Pa = ρgh

where;

when the density of air is half, ρ = 0.5ρ

Pa = (0.5ρ)gh

h = Pa/(0.5ρg)

h = (101,325) / (0.5 x 1.275 x 9.8)

h = 16,218.5 m

Thus, the height the atmosphere would extend is 16,218.5 m.

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Fundamental frequency will be [tex]\frac{1}{\sqrt{2} }[/tex] times that of original frequency on doubling the mass per unit length.

From equation (1) , it can be seen clearly that  fundamental frequency is inversely proportional to the square root of the mass per unit length of the string.

On putting double the mass per unit length in equation (1) keeping the all factor same , we get

               [tex]f'=\frac{1}{2l} \sqrt{\frac{T}{2u} }\\\\f'=\frac{1}{\sqrt{2} } f[/tex]

Where f ' is the new frequency and f is the original frequency .

Thus, on doubling the mass per unit length, with all other factors held constant then the fundamental frequency will be [tex]\frac{1}{\sqrt{2} }[/tex] times that of original frequency.

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An object which has a mass of 70 kg is sitting on a cliff 10 m high. the object's potential energy is 7,000 J

Given: m = 70 kg in mass Height h = 10 m and acceleration g = 10 m/s2

Required. Potential Energy of Gravitation, or P.E

Equation: P.E = mgh

= (70 Kg)(10 m/s²) ( 10 m)

P.E. equals 7,000 kg/m2 or

P.E = 7,000 J

Scottish physicist William Rankine initially used the word "potential energy" in the 19th century, and it has since become a cornerstone of the science. Because of their location, which makes them position relative, items that have this energy stored in them have the capacity to unleash it.

Our knowledge of the cosmos and how we fit into it depends on potential energy. In fact, potential energy and the labour necessary to move an item are determined by the position of the object in the universe.

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If a wave has a wavelength of 2.5 m and a frequency of 150 Hz, then the speed of the wave would be

It can be understood in terms of the distance between any two similar successive points across any wave for example wavelength can be calculated by measuring the distance between any two successive crests.

As given in the problem If a wave has a wavelength of 2.5 m and a frequency of 150 Hz, then we have to find the speed of the wave,

The speed of the wave = frequency of the wave ×  wavelength

                                       = 150 × 2.5

                                       =375 meters / seconds

Thus, the speed of the wave would be 375 meters / seconds.

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Achieving a speed of 112.25 km/h is impossible for a human.

The frequency of an event is its repetitions per unit of time. In a contrast to spatial frequency, it is also sometimes referred to as temporal frequency. Hertz (Hz), which equals one (event) per second, is the unit of frequency. The reciprocal of frequency is period, which is defined as the length of time for one cycle of a repeating occurrence.

According to the question:

Emitted frequency, f₀

Frequency heard when athlete approaches horn, f₁

Frequency heard when the athlete passes horn, f₂

Speed of the athlete (observer), v₁

Speed of sound in air = 343m/s

When an athlete approaches the horn, the frequency observed is given by,

f₁=( (v+v₁)/(v-v₂) ) ₓ f₀

f₂=( (v-v₁)/(v-v₂) ) ₓ f₀

From question,

f₂/f₁ = 5/6

5/6 = v-v₁/v+v₁

hence, v₁ = 112.25 km/h

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The study 'characterizing vibration-assisted atomic force based nanomachining' aims to elucidate nanomachine properties for heterogeneous materials.

The expression nanomachining makes reference to the study of nanometric machines (nanomachines) and related materials, which can be achieved by different approaches including sensor-based strategies related to acoustic auditive phenomena.

In conclusion, the study 'characterizing vibration-assisted atomic force based nanomachining' aims to elucidate nanomachine properties for heterogeneous materials.

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A physical field called an electric field surrounds electrically charged particles and attracts or repels all other charged particles nearby. The physical field of a system of charged particles can also be referred to as the electric field.

In a uniform electric field E, a particle with electric charge q moves in a straight line. The speed of the particle is u.

The electric force exerted in the charge is qE.

The electric field and the velocity of the particle are both in the x direction.

For a small speed u when compared to the speed of light c, the relativistic equation reduces to the classical acceleration:

a = qE / m

Now, as u approaches c, the acceleration will tend to zero, so that the object can or will never reach the speed of light.

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Answer:

Do you have the fomular send please so I can work on it

The amount of heat the cup absorb is 1003200 J.

Given,

Mass of coffee cup = 4.00 × 100 g or 4 kg

Room temperature = 20°C

Hot water temperature = 80°C

We have to find the amount of heat the cup absorbed.

Now, by using the specific heat formula, we have

Q = mCΔT

Where m is the mass of the substance, c is the specific heat, ΔT is the change in temperature, and Q is the amount of heat received or lost.

Putting the values, we get

Q = 4 × 4180 × (80°- 20°)

Q = 1003200 J/kg K

Hence, the amount of heat absorbed by the cup is 1003200 J/kg K.

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