Identify the charges that are negative. mentum. . ​

Dynamics sound helps differentiate between the sound of a fire truck, an ambulance and an 18-wheeler.

Elements allude to the din or delicateness of music. Elements offer a method for showing articulation in printed music. They help to drive the profound substance of music through volume and force. Elements can likewise be shown at the large-scale level for a piece of music in general. This may be just a single time toward the beginning, or a few times all through in the event that the din changes during various segments. Static elements are melodic directions that advise us to play the music at a specific volume that doesn't change. As such, don't get stronger or calmer, play each note at a similar volume as the final remaining one.

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The volume of the 4.00 cm length of the, 1.85 mm thick cylinder pump, that comes to thermal equilibrium with the air is approximately 6.24 cm³.

Parameters of the question found in a similar question found online are as follows;

Thickness of the steel cylinder, t = 1.85 mm

Length of steel cylinder that comes to thermal equilibrium with the air, l = 4.00 cm

Given parameters;

Inner diameter of the cylinder, d = 2.50–cm

Length of the cylinder = 50.0–cm

Required; Volume of the steel in the 4.00–cm length

Solution;

1.85 mm = 0.185 cm

Volume of the cylinder, V, is found as follows;

V = π•(D² - d²)/4 × l

Where;

D = The outer diameter of the cylindrical pump

d = The inner diameter

l = Length of the cylinder

Therefore;

D = d + 2•t

Which gives;

D = 2.5 + 2 × 0.185 = 2.87

V = (π•(2.87² - 2.5²)/4) × 4 ≈ 6.24

Therefore;

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the frequency at which gain is maximized for the forced damped harmonic oscillator is ωr .when 0<b<2mω

ωr is the frequency at which gain is maximum.

oscillator is a device that work on the principle of oscillation.

harmonic oscillator - It is a periodic rotation about the main position. That shifts to and fro.

Damped harmonic oscillator - It is a vibrating system for amplitude of vibration decreases over a time.

equation of damped harmonic oscillator.

[tex]\frac{d^{2}x}{dt^{2}} +2k\frac{dx}{dt} + \omega^{2} x = 0[/tex]

ω is the angular frequency

k is resistance coefficient

when 0<b<2mω

ωr is the frequency at which gain is maximum.

the frequency at which gain is maximized for the forced damped harmonic oscillator is ωr

The question is incomplete.

ind the frequency at which gain is maximized for the forced damped harmonic oscillator with equation

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Answer:

Explanation:

it should be 3.2 m/s^2

The acceleration is 3.2 m/ s2. Acceleration is change in velocity per time.

Any procedure where the velocity varies is referred to as acceleration. There are only two ways to accelerate: changing your speed or changing your direction, or changing both. This is because velocity is both a speed and a direction.

A moving object can occasionally alter its velocity by the same amount every second. The data table above depicts an item altering its velocity by 10 m/s every second, as was described in the paragraph above. Since the velocity is changing by a fixed amount every second, this is known as a constant acceleration.

Therefore, The acceleration is 3.2 m/ s2. Acceleration is change in velocity per time.

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At a point 2 cm horizontally east of the wire's center, the magnetic field generated by the vertical wire is pointing south. As a result, option B south is the correct answer.

There are north and south poles on every magnet. The same poles repel one another whereas opposite poles are attracted to each other. The north-seeking poles of the iron's atoms pairing in the same direction when it is touched against a magnet. A magnetic field is produced by the force that the aligned atoms produce. The iron object has changed into a magnet. An electric current has the ability to magnetize specific materials. A magnetic field results from the flow of electricity through a coil of wire. But as quickly as the electric current is cut off, the field around the coil will disappear.

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If the table says that the atomic number of the element is 12 and the mass number of the element is 40, then the element has 12 protons and 28 neutrons, therefore the correct answer is option C.

It is the sum of the mass of all the protons as well as the neutrons that are present inside the nucleus.

The addition of protons and neutrons represents the mass number of any element.

The mass number of any element is the sum of the number of protons and the number of neutrons, therefore the correct answer is option C.

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The ion rocket engine give an acceleration to the space probe of: 0.001 m/s²

To solve this exercise, the formula and procedure to be applied is:

F = m * a

Where:

Information about the problem:

Applying the force formula and isolating the acceleration, we get:

F = m * a

a = F/m

a = 1 N /1000kg

a =  1 kg * m/s² / 1000kg

a = 0.001 m/s²

It is the physical magnitude that expresses the effort necessary to move the mass of one kilogram with an acceleration of one meter per second squared, this is expressed in units of the international system in Newton.

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The initial velocity with which the rock was launched is 41.16 m/s and the maximum height achieved by the rock is 86.4 m.

The three equations of motion are -

v = u + at

S = ut + 1/2 at²

v² - u² = 2aS

Given is a rock launched from ground vertically upwards reaching its highest point after 4.2 s of being launched. Therefore, we can write -

Time taken to achieve maximum height [t] = 4.2 sec

Acceleration [a] = - 9.8 m/s²

Assume that the initial velocity is u.

Therefore - at maximum height S[max],  t = 4.2 s

Now, at maximum height, final velocity (v) will be zero.

From the first equation of motion -

v = u + at

0 = u - gt

u = gt

u = 9.8 x 4.2

u = 41.16 m/s

The initial velocity of rock was 41.16 m/s.

The maximum height achieved by the rock -

S[max] = ut + 1/2 at²

S[max] = 41.16 x 4.2 - 0.5 x 9.8 x 4.2 x 4.2 = 172.87 - 86.44 = 86.4 m

Therefore, the initial velocity with which the rock was launched is 41.16 m/s and the maximum height achieved by the rock is 86.4 m.

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When a moving thing slows down, gravity action must be taking place on the object.

Every item is subject to the gravitational pull of the earth, which pulls everything in the atmosphere toward the planet's surface.

Since there is no gravity nor a vacuum in space, the only reason the item is traveling is due to the attraction of the earth's gravitational field.

Therefore, when an item slows down while in motion, gravitational force must be at work. The moon's gravitational pull causes ocean tides, and on Earth, gravity gives weight to physical objects. Additionally, gravity is a key factor in a variety of biological processes, such as gravitropism, which controls plant development, and the fluid movement in multicellular organisms.

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Magnitude of the magnetic fields from largest to smallest is,

[tex]B_{e}\; > \;B_{c}\; > \;B_{b}\; > \;B_{a}\; > \;B_{d}[/tex]

We know that,

[tex]Permeability\;of\;free\;space,\;\mu_{0} = 4 \times \pi \times 10^{-7}\;H/m\\[/tex]

[tex]l=length[/tex]

[tex]I=current[/tex]

(a)

[tex]Radial\;distance,\;r = 2\;cm=0.02\;m[/tex]

[tex]Current,\;I = 3\;A[/tex]

We know that, Magnetic equation,

[tex]B_{a} =\frac{\mu_{0} \times I}{2\times \pi\times r}[/tex]

Substitute the known values in the above magnetic field equation,

[tex]B_{a}=\frac{4 \times \pi \times 10^{-7} \times 3}{2\times \pi\times 0.02}[/tex]

By solving the equation, we get

[tex]B_{a}=3 \times 10^{-5}\;T[/tex]

(b)

[tex]Radius\;of\;the\;coil,\;r = 0.02\;m[/tex]

[tex]Number\;of\;turns,\;N = 10[/tex]

[tex]Current,\;I = 0.3\;A[/tex]

We know that, Magnetic equation,

[tex]B_{b} =\frac{\mu_{0} \times N \times I}{2\times r}[/tex]

Substitute the known values in the above magnetic field equation,

[tex]B_{b}=\frac{4 \times \pi \times 10^{-7} \times 10 \times 0.3}{2 \times 0.02}[/tex]

By solving the equation, we get

[tex]B_{b}=9.425 \times 10^{-5}\;T[/tex]

(C)

[tex]Length\;of\;the\;solenoid,\;l = 2\;m[/tex]

[tex]Number\;of\;turns,\;N = 1000[/tex]

[tex]Current,\;I = 0.3\;A[/tex]

We know that, Magnetic equation,

[tex]B_{c} =\frac{\mu_{0} \times N \times I}{l}[/tex]

Substitute the known values in the above magnetic field equation,

[tex]B_{c}=\frac{4 \times \pi \times 10^{-7} \times 1000 \times 0.3}{2}[/tex]

By solving the equation, we get

[tex]B_{c}=18.85 \times 10^{-5}\;T[/tex]

(d)

[tex]Current\;through\;the\;bar,\;I = 300\;A[/tex]

At the center of the conductor if we consider an Amperian loop of zero radius, no current will be enclosed by this loop.

Hence, At the center of the conductor magnetic field will be zero

[tex]B_{d}=0[/tex]

(e)

[tex]1 mT=1 \times 10^{-3}[/tex]

Therefore,

[tex]B_{e}=1 \times 10^{-3}\;T[/tex]

Therefore, Magnitude of the magnetic fields from largest to smallest is,

[tex]B_{e}\; > \;B_{c}\; > \;B_{b}\; > \;B_{a}\; > \;B_{d}[/tex]

When placed inside a magnetic field, a material's permeability—which is defined as the number of magnetic lines of force that may pass through a specific surface—allows magnetic flux to pass through it.

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Answer:

standard

Explanation:

we sometimes use weights of known mass to balance with an object of unknown mass to determine that objects weight.

Answer:

10

Explanation:

2*3^2-8

2*9-8

18-8

10

The magnitude is 167.6cm and the angle (relative to the floor) of the displacement of p is 32.5 degree.

A displacement is a vector in geometry and mechanics that has a length equal to the shortest distance between a point P's initial and final positions. It calculates the length and angle of the net motion, or total motion, in a straight line from the starting point to the destination of the point trajectory. The translation that links the starting point and the ending point can be used to spot a displacement.

A point's ultimate location in relation to its original position, or a displacement, can also be defined as a relative position. The instantaneous velocity of an object is the rate at which the displacement changes as a function of time when studying motions of objects throughout time.

Explanation:

a)

height = 2*r =2*45 cm = 90 cm

y = 1/2 * circumference

   =1/2 * 2*pi*r

   = pi*r

  = pi*45

  = 141.4 cm

displacement  =sqrt ( height^2 + y^2)

   = sqrt (90^2 + 141.4^2)

   = 167.6 cm

Answer: 167.6 cm

b)

angle ,x = atan (height/y)

               = atan (90/141.4)

                = 32.5 degree

Answer: 32.5 degree

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Answer: Given -

To find -

Solution -

[tex]A=\frac{v-u}{t}\\A=\frac{12-0}{36} \\A=\frac{12}{36} \\A=0.33m/s^2[/tex]

Therefore, the acceleration of the ball is 0.33 m/s².

I hope this helps.

(c) The fundamental frequency of one of the organ pipes will go up or increase.

When pressured air is forced into an organ pipe, it echoes at a particular pitch, generating the sound of the pipe organ. Each pipe has been adjusted to a particular pitch on the musical scale.

An outdoor pipe organ is a type of musical instrument used to perform music. It sounds quite serene and produces some calming tones.

The organ pipe produces the sound of the outdoor organ. The wavelength of the sound is also dependent on the length of the pipe. The fundamental frequency of one of the organ pipes will grow as the speed of the sound increases as the ambient air temperature rises.

The correct option is (c).

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The frequency that the driver detects after the police car passes him is 2.08 kHz.

The quantity of waves that pass a set location in a predetermined period of time is known as frequency. Therefore, if a wave passes through in half a second, the frequency is 2 per second. The frequency is 100 per hour if it takes 1/100 of an hour. Frequency is typically expressed in hertz units, which were created in honor of German physicist Heinrich Rudolf Hertz in the 19th century. The frequency, abbreviated as Hz, refers to the number of waves that move across a space in a second. An "A" note on a violin string, for instance, vibrates at roughly 440 Hz (440 vibrations per second).

frequency = 1/T

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The molecule in the air that is moving at a speed 459 m/s during a time of 7.00 ms (milliseconds) if it didn’t collide with any other molecules would move a distance of: 3.213 m

The formula and procedure we will use to solve this exercise is:

x = v * t

Where:

Information about the problem:

By converting the time units from (ms) to (s) we have:

t = 7.00 ms * 1 s/1000 ms

t = 0.007 s

Applying the distance formula we have that:

x = v * t

x= 459 m/s * 0.007 s

x = 3.213 m

It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).

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The average acceleration of the ball while it is in contact with the wall is 1634.48 m/s²

Speed of the ball, v = 23.7 m/s

Contact timing of the ball with the wall, t = 0.0145 s

Since,  average acceleration of the ball while it is in contact with the wall is being asked, so we can neglect the rebound speed.

So according to the First Equation of Motion which relates the velocity, acceleration and time i.e.

v = u +at

u = 0 as the initial velocity of the ball is zero

v = at

a = [tex]\frac{v}{t}[/tex]

a = [tex]\frac{23.7}{0.0145}[/tex]

a = 1634.48 m/s²

The average acceleration of the ball while it is in contact with the wall will be 1634.48 m/s²

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Tech B is correct. The brake pedal pressure is transmitted to the brakes hydraulically.

The energy of the pads clamping against the rotors and brake shoes pushing against drums generates friction and heat.

This heat-friction, along with friction generated between the tire and road surface, slows rotor and axle rotation and ultimately brings the car to a stop.

Thus, Tech B is correct. The brake pedal pressure is transmitted to the brakes hydraulically.

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The acceleration lasts 0.0077 seconds and is equivalent to 8450 m/s².

The rate at which an object's position changes with respect to time is defined as velocity.

Because it consist of both magnitude and direction, it is a vector quantity. Speed is a scalar quantity that represents the magnitude of velocity. The SI unit of velocity and speed is m/s.

Acceleration is the measure of how quickly a velocity varies over time. It is also a vector quantity. A negative sign of acceleration indicates that the velocity of the body is decreasing with time.  

Given in the question

Initial speed = u = 0 m/s ( as the firework starts from rest)

Final velocity = v = 65 m/s

Distance traveled = 0.25 m

B) Acceleration

Using the third equation of motion,

[tex]v^{2} -u^{2} =2as[/tex]

Put in the value, we get

(65)² - (0)² = 2a(0.250)

0.5a = 4225

a = 8450 m/s²

As a result, fireworks accelerate at 8450 m/s².

A) Time the acceleration lasts

Acceleration is calculated as (Final Velocity - Initial Velocity)/Time.

Put in the values, we get

8450 = 65/time

Time = 65/8450

Time = 0.0077 seconds

Hence, the acceleration lasts for 0.0077 seconds and is 8450 m/s².

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If a certain piece of metal is cooled, it will conduct electricity better, this statement is theory whereas, the amount of electric current that passes through a conductor is directly proportional to the voltage is known as law.

A hypothesis is a statement that may be true or false. A theory is a well-supported explanation of observations or data. A scientific law is a statement that explains the relationship between variables. Hypothesis is a statement that is given before performing an experiment. It can be true or false after we perform an experiment. When a number of experiments can be performed and the hypothesis comes out true then theory is evolved. When the statement is verified after performing large number of experiments, it becomes a law.

So we can conclude that if a certain piece of metal is cooled, it will conduct electricity better, this statement is theory whereas, the amount of electric current that passes through a conductor is directly proportional to the voltage is known as law.

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By the velocity, they will travel 6.875 m and the dog catches the man at 2.08s.

We need to know about velocity to solve this problem. Velocity can be determined as the distance traveled divided by time interval. It can be written as

v = s / t

where v is velocity, s is distance and t is the time interval.

From the question above, we know that.

v man = 1.5 m/s

v dog = 3.3 m/s

to = 2.5s

Determine the distance traveled by man when the dog waits

so = vman . to

so = 1.5 x 2.5 = 3.75 m

Find the man's total distance

total distance = distance after dog run + distance when the dog waits

total distance = vman . t + 3.75

We know that the total distance by man's will be caught by the dog, Thus

total distance = vman . t + 3.75

v dog . t = 1.5t + 3.75

3.3t = 1.5t + 3.75

1.8t = 3.75

t = 2.08 s

Find total distance

total distance = vdog . t

total distance = 3.3 x 2.08

total distance = 6.875 m

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To find the masses of both stars in a binary system, you must find the velocity of each star, the period of the orbit, and the average distance between the stars.

The displacement covered by an object in the unit of time is called velocity.

The formula of velocity is v = d/t and its dimensions are LT-1.

A unit of time in which a particle or object passes through a point to complete its one cycle is called a period. It is related to time.

The time-period is denoted by T and the formula is T = 2 π√ l / g.

In physics, distance is a vector quantity without any direction. It can be calculated as distance = speed x time i.e. d = v.t

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Net electric field in middle of two charge is equal to 7,318.4 NC⁻.

Electric field at a point by an point electric charge is given by:

E=KQ/r²

where,

E is electric field

K is an constant with value 9×10⁹

Q is point electric charge

r is the distance at which E is desired

for 10.8 nC

electric field at +0.25 m is as

E=+155.2NC⁻

for 51.9nC

electric field at -0.25 m is as

E= - 7473.6NC⁻

therefore net electric field in middle of two charge

=(+155.2- 7473.6)

= -7318.4NC⁻

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Magnetic field due to current in wire is 0.1308 Tesla.

The friction coefficient is the ratio of the normal force pressing two surfaces together to the frictional force preventing those surfaces from moving. Typically, it is represented by the Greek letter mu.

Given:

[tex]Mass\;per\;unit\;length(\frac{m}{l})=1.0\;g/cm=0.1\;kg/m\\[/tex]

[tex]Coefficient\;of\;friction,\;(\mu)=0.2[/tex]

[tex]Current,\;(I)=1.5\;A[/tex]

[tex]According\;to\;the\;question,\;wire\;is\;moving\;on\;a\;surface\;with\;\mu\;and\;force\;that\;is[/tex][tex]moving\;the\;wire\;is\;magnetic\;force\;f_{m} , then,[/tex]

[tex]f_{m}=\mu f_{N} (f_{N}=normal\;reaction\;of\;wire)[/tex]

[tex]Also, f_{m}=B\;L\;I\;sin\propto[/tex]

Therefore,

[tex]B_{b}=\frac{\mu\;m\;g}{L\;I\;sin\propto}[/tex]

[tex]B=magnetic\;field[/tex]

[tex]f_{N}=mass \times accelaration\;due\;to\;gravity[/tex]

Therefore,

[tex]B_{b}=\frac{0.2\times0.1\times10}{1.5\times sin\propto}[/tex]

[tex]sin \propto = angle\;magnetic\;field\;and\;the\;current\;in\;the\;wire=sin\;90^{\circ}=1[/tex]

Therefore,

[tex]B_{b}=0.1308\;T[/tex]

Now, from the figure shown and using Fleming's Right Hand rule in which the fore finger indicates current that is in east direction and the thumb indicates force that is in north direction and then direction, shown by your middle finger shows the direction of induced magnetic field.

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The level of sound intensity at the late-night is β₂ = 67.0dB

Acoustic measurements are made with a sound level metre, often known as a sound pressure level metre (SPL). A hand-held device with a microphone is the most typical type. The condenser microphone is the best kind of microphone for sound level metres because it combines accuracy with stability and dependability. Sound waves generate changes in air pressure, which the microphone's diaphragm reacts to. The device is sometimes referred to as a sound pressure level metre because of this (SPL).

We are given:

The level of sound intensity in the afternoon is  β₁ = 80dB

No. of cars per min in the afternoon = 100

No. of cars per min in late night = 5

The level of sound intensity in the late night β₂ =?

The level of sound intensity in the late night I² =?

Reference sound intensity, I₀ = 10⁻¹²W/m²

The sound intensity level is given by: β = 10Log(I/I₀)

Numerically evaluating,

β₂ = 10 log (5X10⁻⁶/10⁻¹²)

β₂ = 67.0dB

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An elevator is being lifted up an elevator shaft at a constant speed by a steel cable. All frictional effects are negligible. In this situation, forces on the elevator are such that the upward force of the cable is equal to the downward force of gravity.

As per Newton's 2nd regulation F = ma, acceleration needs a force proportional to mass. So when the elevator is accelerating upwards, it has to not handiest oppose gravity however provides greater pressure for the upward acceleration. This calls for an expanded ordinary force

Friction is the pressure resisting the relative motion of strong surfaces, fluid layers, and cloth factors sliding against each other. There are several types of friction: Dry friction is a pressure that opposes the relative lateral movement of two solid surfaces in touch.

The gravitational force is a pressure that draws any gadgets with mass. We call the gravitational pressure attractive as it usually attempts to pull masses collectively, it in no way pushes them apart. In fact, each item, which includes you, is pulling on each other object in the entire universe.

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Answer:

X is frictional force

Explanation:

when X is greater than pushing force,the object won't move

The correct answer for the nature of force at "X" is frictional force.

What is friction force?

Friction or frictional force is the force that acts when two surface comes in contact with each other. When a body A is resting upon a body B, The force that helps the body to maintain the equilibrium position is static friction.

Kinetic friction slows down a moving object, when their is relative   motion between two objects. It always acts in apposite direction to the force applied.

It is denoted by [tex]F[/tex].

The formula to calculate static friction is [tex]F = \mu N[/tex]

[tex]\mu_s =[/tex] Co-efficient of static friction

[tex]\mu_k =[/tex] Co-efficient of Kinematic friction.

The Force indicated at "X" is "Kinetic friction", It will slow down the moving object.

When "X" is greater than the moving object, the object will stop moving and will remain at rest.

The Force Indicated at "X" is Frictional force.

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The gravitational force on the box is 580N.

It should be noted that the gravitational force acts perpendicularly downwards and the normal force of the box  is perpendicular to the slanting ramp. This force we are given 538 N.

The gravitational force is the component of this 538 N.

In this case, Cos22° = 538/Y  

Where

y = the gravitational force.

 Cos22° = 538/Y

 Y× Cos22° = 538

 Y = 538/Cos22°

   = 580.25

Therefore, the gravitational force on the box is 580N.

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