If the length of the pendulum in pendulum clock increases by 0.1 % , then the error in time per day is
a) 86.4s
b) 4.32s
c) 43.2s
d) 8.64s

JEE Mains 2022​

Answer:

See below

Explanation:

F = ma       net force is 300 N upward

300 = 306  * a         a = .980 m/s^2

Answer:

The ground we walk on is flat, not round. Gravity doesn't exist. Objects don't fall down, the flat earth(disk) goes up with a force called dark energy. There is a 45 ft tall ice wall to prevent people from falling off the Earth.

Explanation:

The attractive force of Earth on the moon will be said to be double when there is a doubling of the mass of the moon.

Since the moon has an attracting force, it is one that will remain the same on Earth. In gravitational forces, the two concerned objects always feel the same force.

The explanation of how this would affect the gravity between earth and the moon is that this can result to the earth tilt a little bit harder to change, which could imply that there will be a more stable climate and  ice ages may not occur as often.

Therefore, The attractive force of Earth on the moon will be said to be double when there is a doubling of the mass of the moon. Since the moon has an attracting force, it is one that will remain the same on Earth. In gravitational forces, the two concerned objects always feel the same force.

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You throw a rock from the upper edge of a 75.0 -m vertical dam with a speed of 25.0 m/s at 65.0∘ above the horizon.

The horizon is the line that, when seen from a position on or near the surface of a celestial body, appears to separate the surface from the sky of that body. All viewing directions are split according to whether it crosses the surface of the relevant body or not.

Since the true horizon is an imaginary line, it can only be seen with any degree of accuracy when it is situated along a generally flat surface, such as the oceans of the Earth. On Earth, the geography may also cause biological objects like trees and/or man-made objects like buildings to obstruct this line in some locations. The location where these obstructions overlap the sky is known as the visible horizon.

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Answer:

Solution in Photo

Explanation:

To solve this question, draw the Free Body Diagram (FBD) for the whole system such that

theta < 90, it will be more clearer that way.

The impulse the gravity imparts on the stone from the instant it was dropped until it hits the ground is 72.66 Ns

This is defined as the change in momentum of an object.

Impulse = change in momentum

Impulse = final moment – Initial momentum

Impulse = force × time

h = ½gt²

6.02 = ½ × 9.8 × t²

6.02 = 4.9 × t²

Divide both side by 4.9

t² = 6.02 / 4.9

Take the square root of both side

t = √(6.02 / 4.9)

t = 1.1 s

Impulse = Force × time

Impulse = 66.052 × 1.1

Impulse = 72.66 Ns

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The magnitude of the minimum deceleration needed to avoid the accident is –0.89 m/s²

The solution of the question can be obtained by first approaching the relation between Speed, Distance and Time which is given by:

Speed = Distance/Time

Now according to question;

Speed = 18 m/s

Time = 0.54 s

Therefore, Distance = Speed×Time

Distance = 18 × 0.54

Distance = 9.72 m

Thus, the engineer travelled a distance of 9.72 m during the reaction time.

Now, there is a need to find distance between the engineer and the car. This can be obtained by:

Distance between the engineer and the car = Total distance - Distance during the reaction time

Distance between the engineer and the car = 190 – 9.72

Distance between the engineer and the car = 180.28 m

Finally, we need to determine the magnitude of the deceleration needed to avoid the accident. This can be obtained by using newton's third equation of motion, which is represented as:

v² = u² + 2as; where u is the initial velocity, v is the final velocity, a is the acceleration/deceleration and S is the distance.

According to the question;

Initial velocity (u) = 18 m/s

Final velocity (v) = 0 m/s

Distance (s) = 180.28 m

Deceleration (a) =?

Thus, using Newton's third equation of motion

0² = 18² + (2 × a × 180.28)

0 = 324 + 360.56a

=> –324 = 360.56a

=> a = –324 / 360.56

=> a = –0.89 m/s²

Therefore, the magnitude of the deceleration needed to avoid the accident is –0.89 m/s.

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Explanation:

it dosent depend on the weights of the items. I'll reach the ground at same time taking as no air friction or restrictions.

i.e

v = u + gt

whte v is final velocity of the object

u is initial velocity of the object

g is acceleration due to gravity and

t is time. thanks

please if found helpful rate brainliest

Assuming there is little air resistance, the acceleration felt by both objects when one drops a 20-ton object and a 10-ton object at the same time will be the same.

Even though both objects accelerate at the same rate, the forces acting on them will be different because of their different masses. Newton's second law of motion states that an object's force is inversely proportional to its mass (F = ma). The 20-ton object will therefore encounter twice as much force as the 10-ton object, but their rates of acceleration will remain constant.

In conclusion, both the 20-ton and 10-ton objects will accelerate to about 9.8 meters per second squared when dropped simultaneously with little air resistance.

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Answer: I don't really see the answer choices.

Explanation:

The angular momentum can be indicated by formula mvr. The correct option is A.

The property of any rotating object given by moment of inertia times angular velocity is defined as angular momentum.

It is the property of a rotating body determined by the product of the rotating object's moment of inertia and angular velocity.

The rotational equivalent of linear momentum is the angular momentum formula. Both concepts are concerned with the rate at which anything moves.

It can be represented by symbol L.

L = mvr.

Thus, the correct option is A.

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When the temperature of the ocean is 80°F what is likely to develop is Hurricane. That is option D.

Hurricane is a natural disaster that occurs over the tropical large water bodie such as the oceans which is characterized by low-pressure storm.

The factors that can cause the occurrence of hurricane include the following;

Therefore, when the temperature of the ocean is 80°F what is likely to develop is Hurricane.

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Answer: thunderstorm

Explanation:

When the sea surface is at least 80° Fahrenheit (27° Celsius), it can supercharge a thunderstorm. The storm sucks up that heat and water, which make the storm bigger. As it grows, air pressure at the center of the storm continues to drop, which causes the vacuum in the middle to grow stronger.

A bowling ball results in kinetic friction compared to a sliding bowling ball.

According to Conservation of momentum, if a bowling ball hits some pins, the momentum that lost by the bowling ball is known to be equal to the momentum obtained by the pins.

The friction that is used in bowling is kinetic friction because the more oil that is placed down, the lower the friction that is found between the ball and that of the lane surface. The  little friction, the stronger it is for the bowler to be able to send the ball in a curved path and thus the formula to find the kinetic friction is know to be : µk=F k/mg.

Therefore, A bowling ball results in kinetic friction compared to a sliding bowling ball.

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Answer:

13.33 mA s

Explanation:

400 mA * 1/30 s = 13.33 mA s

Link walks 5 miles east, then 7 miles north then 2 miles south

If you draw a simple diagram you’ll see that your displacement from the start is 5 miles East and 7 miles North and then 2 miles south

These distances are the sides of a right-angled triangle. The displacement you are looking for is the hypotenuse of the triangle. Use the Pythagorean theorem to calculate it.

Displacement

= √ (5+2)^2 + 7^2)

= 9.899 miles

Distance

= 5+7+2

= 14 miles

Time to complete his whole journey = 4 hours

Average Speed= Distance travelled / Time

= 14÷4

= 3.5 miles/hour

Average velocity= Displacement / Time

= 9.899÷4

= 2.47475 miles/hour

The distance is 14 miles and the displacement is 9.899 miles, the Average Speed is 3.5 miles/hour and the Average Velocity is 2.47475 miles/hour

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Answer:

Explanation:

temperature is a scalar quantity

A car traveling 83.0 km/h on a straight road is 1900 m behind a truck traveling at 61.0 km/h. The required voltage is 10 Volts.

Electric current is defined as the rate at which charge passes a fixed unit cross sectional area.

Voltage is defined as the physical quantity required to move charge from one end to other.

Resistance is defined as the the factor which opposed the electric current.

It states that voltage is directly proportional to electric current

V=IR

Given:

current (I) = 0.1 A

resistance (R) = 100 Ω

Now from definition of voltage we have:

V = I × R

V = 100 × 0.1

V = 10 volts

Thus from the above conclusion we can say that therefore the required voltage is 10 volts.

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The correct answer is 16.

The conventional way to express function is F(x).

You may alternatively describe it as a machine that has input, output, and some other ways they are connected.

You must first evaluate the first function in order to get the value of a composite function like this one. We placed the value for x in parentheses first in that equation because f is on the right side.

f (x) = 2x - 8

f (5) = 2 × 5 - 8

f (5) = 10 - 8

f (5) = 2

Once the first portion of a composite function has an answer, we insert that response into the second part. We insert our response (2) into g because it is on the left side.

g(x) = x^4

g(2) = 2^4

g(2) = 16

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First, see that in the time interval 3.44 to 9.49, the average velocity is [tex]2.9\text{m} / (9.49\text{s} - 3.44\text{s})=2.9\text{m}/6.05\text{s} \approx 0.479\text{m/s}[/tex]. So, as we have uniform acceleration, the velocity must be linearly increasing over this entire interval, so for the average to be 0.479 m/s over this interval, the velocity must be 0.479 m/s in the exact middle of this interval, or at 5.465s.

We now note that the object starts from rest, which means that at 0s, the velocity is 0 m/s.  So, in 5.465 seconds, the velocity increases by 0.479 m/s.  We again have that the object undergoes uniform acceleration, meaning that the acceleration over this interval is a constant [tex]\frac{0.479\text{m/s}}{5.465\text{s}} \approx 0.0876 \text{m/s}^2[/tex].

Finally, note again that as we are looking at uniform acceleration, by the same principle at the beginning, the average velocity of the object during the time interval from 18.6s to 22.92s is the same as the velocity at the exact middle of this interval, or at 20.76s.  We have that acceleration is constant and 0.0876 m/s^2, and initial velocity is 0 at 0s. So, in 20.76 seconds, the object will have accelerated [tex]0.0876\text{m/s}^2 \cdot 20.76\text{s} \approx 1.82 \text{m/s}[/tex].

So, average velocity will be 1.82 m/s over the time interval 18.6s to 22.92s.

It will take the fugitive 4.83 s to catch the empty box car

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

The time taken for the fugitive to catch the car if he maintains his maximum speed can be obtained as follow:

a = (v – u) / t

Thus,

t = (v – u) / a

t = (5.8 – 0) / 1.2

t = 5.8 / 1.2

t = 4.83 s

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(a) The acceleration is 0.2 m /s²

(b) The acceleration is  - 0.2 m /s²

(c) The acceleration is  - 0.3 m /s²

(d) The acceleration is 0.4 m /s²

(a)  Putting  v₁ₓ = 0.8 m/s , v₂ₓ = 1.2 m/s ,  t₁ = 2 s and t₂ = 4s  in equation (1)

, we get   a = 1.2 - 0.8 / 4 -2

              a = 0.4 / 2

               a = 0.2 m /s²

(b) Putting v₁ₓ = 1.6 m/s, v₂ₓ = 1.2 m/s , t₁ = 2 s and t₂ = 4s  in equation (1) , we get   a = 1.2 - 1.6 / 4 -2

              a = - 0.4 / 2

               a = - 0.2 m /s²

(c) Putting  v₁ₓ = - 0.4 m/s, v₂ₓ = - 1.0 m/s,  t₁ = 2 s and t₂ = 4s  in equation (1) , we get   a = -1.0 - (-0.4) / 4 -2

              a = - 0.6 / 2

               a = - 0.3 m /s²

(d) Putting  v₁ₓ = -1.6 m/s, v₂ₓ = -0.8 m/s,  t₁ = 2 s and t₂ = 4s  in equation (1) , we get   a = -0.8 - (-1.6) / 4 -2

              a = 0.8 / 2

               a = 0.4 m /s²

The traveller races in cases (a) and (c) and slows down in (b) and (d), however the common acceleration is positive in (a) and (d) and negative in (b) and (c). In alternative words, negative acceleration doesn't essentially indicate a deceleration down.

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The complete question is given below :

An astronaut has left the space shuttle on a tether to test a new personal maneuvering device. She moves along a straight line directly away from the shuttle. Her onboard partner measures her velocity before and after certain maneuvers, and obtains the following results:

(a) v₁ₓ = 0.8 m/s, v₂ₓ = 1.2 m/s; (speeding up)

(b)v₁ₓ = 1.6 m/s, v₂ₓ = 1.2 m/s; (slowing down)

(c) v₁ₓ = - 0.4 m/s, v₂ₓ = - 1.0 m/s; (speeding up)

(d) v₁ₓ = -1.6 m/s, v₂ₓ = -0.8 m/s; (slowing down)

If t₁ = 2 s and t₂ = 4s in each case, find the average acceleration for each set of data.

The statement that best explains why this helps protect orange trees and fruit from freezing is that the transfer of thermal energy in water as it freezes protects the orange trees by transferring heat energy from the orange trees and fruit. That is option A.

Freezing is the phase transition that involves the change of a liquid substance into a solid form as it's temperature becomes lower.

During winter seasons which is a weather that can freez the orange fruits, the orange grower sprays water on their orange trees to prevent it from freezing.

The mechanism that prevents the orange from freezing is the transfer of the thermal energy between the water and the orange fruits.

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The speed over the ground is 0 m/s.

The speed of an object or body is the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.

As it is given that the mosquito is flying at 2 m/s relatives to the air caught in a 2 m/s right angle crosswind.

As we know that speed over the ground is the difference between the flight speed and resistance speed.

So, the general equation for the speed over the ground is :

v = Flight Speed of the mosquito - Resistance Speed of the crosswind

This implies, [tex]v= 2 {~}m / s - 2{~} m / s[/tex]

[tex]v = 0 {~}m / s[/tex]

Hence, the speed over the ground is 0 m/s.

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The required voltage is 10 Volt for 100 ohms of resistance and 0.1 ampere of current.

electric current is defined as the rate at which charge passes a fixed unit cross sectional area.

voltage is defined as the physical quantity required to move charge from one end to other.

Resistance is defined as the the factor opposing electric current.

Ohms law states that voltage is directly proportional to electric current

V=IR

given:

current (I) = 0.1 A

resistance (R)=100 ohms

now from definition of voltage we have:

V=I.R

V=100×0.1

V=10volts

therefore the required voltage is 10 volts.

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The kinds of materials can be involved in static electric effects is All types of materials, both metals and non metals.

The static electric effects can be described as the effect that bring about the  changes to the  body  as a result of the changes in the distribution that is been imposed on the electric charges  that is found on the surface of the body.

It should be noted that sufficiently large surface charge density  could be discovered as a result of the effect, however in the case above option A is correct.

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Answer:

35

Explanation:

The upward applied force will be 579.249 lbf.

Mass of the rocket, m = 4.5 lb

Acceleration, a = 3g

as we know g = 32.2 ft/s²

therefore acceleration, a = 3 * 32.174 = 96.522  ft/s²

According to the Newton's second law of motion, which states that the magnitude of the force acting on an object is equal to the product of the object's mass and the acceleration with which it is moving.

Mathematically, it is F =  [tex]\frac{mass}{acceleration}[/tex] ;

Upward force (F₀) for the rocket will be the sum of Force applied by the weight (Fₓ) and the force by the acceleration(Fₐ).

i.e. gₙ *F₀ = Fₓ + Fₐ

Fₓ = mg

Fₐ = ma

F₀ = ma + mg

F₀ = m (a + g)

F₀ = 4.5 (96.522 + 32.2)

F₀ = 4.5 * 128.722

F₀ = 579.249 lbf.

The upward applied force, required to accelerate a 4.5-lb model rocket vertically upward will be 579.249 lbf.

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