in a class of 80 students in Debre Berhan university,45 good in mathematics,15 are good in both Mathematics and English,13 are good in both Mathematics and Psychology, 16 are good in both in English and psychology,20 are good in Psychology and 9 are good in both of the three courses A,how many students are good in mathematics only? B,how many students are not good in any of three courses?

Hi ;-)

[tex]x=2\\\\4x+8=4\cdot2+8=8+8=\boxed{16}[/tex]

Step-by-step explanation:

4x + 8

4 × 2 + 8

8 + 8

16

Therefore its 16.

Answer:

60/125 which can be reduced to 12/25

Step-by-step explanation:

Gina wins

2/5 * 2/5 = 4/25

3/5 * 2*5 * 2/5 = 12 /125

2/5 * 3/5 * 2/5 = 12/125

Fred Wins

3/5 * 3/5 = 9/25

2/5 * 3/5 * 3/5 = 18/125

3/5 * 2/5 * 3/5 = 18/125

P(3 sets) = (18 + 18 + 12 + 12)/125 = 60/125

P(2 sets) = (20 + 45)/125 = 65/125

I found the probability of 2 sets so I could add the results together to see if the probability totals 1. It does. This question is done correctly.

Answer:

(a)

sin²A×cos²A+sin⁴A

we will take sin²A as an common factor

so it become

sin²A×(cos²A+sin²A)

sin²A+cos²A=1

sin²A×1=sin²A

(c)

sinA×cotA

cotA= cosA/sinA

sinA×cosA/sinA=cosA

(e)

(1+sinA)²-(1-sinA)²

(a+b)²=a²+b²+2×a×b

(a-b)²=a²+b²-2×a×b

1²+sin²A+2×1×sinA-(1²+sin²A-2×1×sinA)

1+sin²A+2sinA-1-sin²A+2sinA=4sinA

(g)

(cosec²A-1)/cosec²A

cosecA=1/sinA

1/sin²A-1/1/sin²A

(1/sin²A-1)×sin²A

1-sin²A

1=sin²A+cos²A

sin²A+cos²A-sin²A=cos²A

(i)

sqrt(1+tan²A)×sqrt(1-cos²A)

1+tan²A=

1+sin²A/cos²A=

sin²A+cos²A/cos²A

sin²A+cos²A=1

=1/cos²A

1-cos²A

1=sin²A+cos²A

sin²A+cos²A-cos²=sin²A

sqrt(1/cos²A)×sqrt(sin²A)

1/cosA×sinA=sinA/cosA=tanA

have a great day

Answer:

y = 78

Step-by-step explanation:

66 + 4 = 70 + 4 = 74 + 4 = 78

-12 + 3 = -9 + 3 = -6 + 3 = -3

x = -3

y = 78

Bi weekly means you get paid every 2 weeks so you would get two paychecks per month.

Monthly net pay = 489.00 x 2 = $968.00

Multiply monthly by 15%

968 x 0.15 = $146.70

Answer: $146.70

If Your average bi-weekly net pay is $489.00. Your average monthly net pay is:$146.70.

First step

Monthly net pay=$489.00×2

Monthly net pay=$968

Second step

Average monthly net pay:

Average monthly net pay=$968×15%

Average monthly net pay=$146.70

Therefore your average monthly net pay is:$146.70.

Learn more about average monthly net pay here:https://brainly.com/question/25273589

Answer:

0.09

Step-by-step explanation:

hope it helps!!!!!!

Answer:

Here is your answer. Hope this helps you!

Answer:

Rate(R)= 11%

Times(T)=11/2

Principle(P)= 9000

We know that,

SI = P×T×R÷100

= 9000×11/2×11÷100

=9000×5.5×11÷100

= 544500÷100

=5445

Hence, the required simple interest is 5445.

Ans

Answer:

wut are the statements?

Step-by-step explanation:

Answer:

3 to the fourth power and 81 to the first power.

Step-by-step explanation:

i took he quiz

The equivalent expressions are 3^4 and -9^2

To determine the equivalent expressions, we simply solve the options.

So, we have:

3^9 = 19683

3^4 = 81

-9^2 = 81

9^9 = 387420489

From the above computation, we have:

3^4 = 81 and -9^2 = 81

Hence, the equivalent expressions are 3^4 and -9^2

Read more about equivalent expressions at:

https://brainly.com/question/2972832

Answer:

3³  = 27

Step-by-step explanation:

I'm guessing you need answer E

Answer:

b)68

Step-by-step explanation:

i think helping you...say correct or no...

Answer:

2,3,5,7,11,13,17,19,23 and 29

Step-by-step explanation:

hope this helps

Answer:

[tex]thank \: you[/tex]

Answer:

Take 2x- 3y= 6 as equation 1

And

x+ 3y= 3 as equation 2

Now add both equation

2x - 3y = 6

x + 3y = 3

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

3x 0 = 9

We can also write 3x 0= 9 as 3x = 9

Now we have to solve 3x =9

3x = 9

x = 9/3

x= 3

I hope this will help you

Answer:

c = (2 - ad) / b

Step-by-step explanation:

Subtract both sides by ad

bc = 2 - ad

Divide both sides by b

c = (2 - ad) / b

Answer:

L = length of arc , R = radius

radian angle = L / R

L = R* radian angle

L = R * 1/3

L = R/3 #1

Area of sector = 1/2 L*R

By substitution using #1

Area of sector = 1/2 * R/3 * R

9 = R^2 /6

R^2= 6*9

R^2= 36

R =✓36

R = 6

Answer:

[4  -2  -19]

[-1   1     8]

Step-by-step explanation:

[ 2 5]    *   [a b c]    =   [3 1 2]

[ 1  3]         ld e f]          [1 1 5]

[2a+5d 2b+5e 2c+ 5f]   =   [3 1 2]

[a+3d    b + 3e   c + 3f]       [1 1 5]

Solving systems of equations:

2a + 5d = 3

a + 3d    = 1

2a + 6d = 2

Subtract -d = 1 so d = -1

and a = 1 - 3d = 1 - 3(-1) = 4

So d = -1 and a = -4.

In the same way we find that b = -2, e = 1, c = -19, f = 8.

Read each number from top to bottom. Each digit is in base 20, and as I pointed out in another question of yours, 1 bar = 5, 1 dot = 1, and disk = 0.

(47) Only 1 digit here, with 2 bars and 4 dots. So this is 14.

(49) 3 digits, in order from top to bottom: 19, 0, 6. So this number is

[19]06₂₀ = 19×20² + 0×20¹ + 6×20⁰ = 7606

(51) 3 digits: 8, 8, 8.

888₂₀ = 8×20² + 8×20¹ + 8×20⁰ = 3368

(53) 4 digits: 2, 0, 0, 11.

200[11]₂₀ = 2×20³ + 0×20² + 0×20¹ + 11×20⁰ = 16011

(55) 4 digits: 10, 10, 0, 10.

[10][10]0[10]₂₀ = 10×20³ + 10×20² + 0×20¹ + 10×20⁰ = 84010

(57) 6 digits: 5, 10, 0, 6, 2, 3.

5[10]0623₂₀ = 5×20⁵ + 10×20⁴ + 0×20³ + 6×20² + 2×20¹ + 3×20⁰ = 17602443

(59) 6 digits: 10, 5, 0, 0, 11, 4.

[10]500[11]4₂₀ = 10×20⁵ + 5×20⁴ + 0×20³ + 0×20² + 11×20¹ + 4×20⁰ = 32800224

9514 1404 393

Answer:

  x = -1.4

Step-by-step explanation:

  3(x-6) -8x = -2 + 5(2x + 1)

  3x -18 -8x = -2 +10x +5 . . . . . . . eliminate parentheses

  -21 = 15x . . . . . . . . . . . . . . add 5x -3 and collect terms

  x = -21/15 = -7/5

  x = -1.4

__

Check

  3(-1.4 -6) -8(-1.4) = -2 +5(2(-1.4) +1) . . . substitute for x

  3(-7.4) +11.2 = -2 +5(-2.8 +1)

  -22.2 +11.2 = -2 +5(-1.8)

  -11 = -2 -9 . . . . . true

Answer:

5539

Step-by-step explanation:

You should conclude that the number in the thousands place and the one in the 100s place are the same.

x * 1000 + x * 100 + y + x + 4

So you could sum the digits as

3x + y + 4 = 19   Subtract 4 from both sides

3x +  y = 15

x can be six           That means y = 1 which is OK

x can be five          That means y = 3 which is OK

Now we run into a little grief. Can x be 4? No

x cannot be 4          that would mean that y = 19 - 12 = 7 The tens digit is too big.

Come to think of it, x cannot be 6 because then the units digit will be 10 -- not possible.

So the answer is

1000*5 + 100*5 + 10*3 + 9

5539 is the answer.

Thanks for posting.

We want to find a 4-digit number that meets some given conditions. We will find two, which are:

4438 and 5509

A general 4-digit number can be written as:

a*1000 + b*100 + c*10 + d

Where a, b, c, and d are single-digit numbers.

a is the thousands digit

b is the hundreds digit

c is the tens digit

d is the units digit.

Here we know that:

"the value of the digit in the thousands place is 10 times greater than the value of the digit in the hundreds place."

So the first term is 10 times the second term, this means that:

(a*1000) = 10*(b*100)

a*1000 = b*1000

a = b

-the least (the smaller one) digit is in the tens place.

so:

c < a, b, d

- The sun of the digits is 19.

So:

a + b + c+ d = 19

-The digit in the ones place is 4 more than the digit in the hundreds place.

so:

d = b + 4

Now we can rewrite all of these conditions as:

Using the first one, we can replace all the b's by a's in the other conditions, so we have:

Now we can use the third equation and replace it in the second one to get:

2a + c + d = 19

2a + c + (a + 4) = 19

3a + c + 4 = 19

3a + c = 19 - 4

3a + c = 15

Now we need to remember that:

c < a.

So we can try with different values of a.

For example, if a = 3, then:

3*3 + c = 15

9 + c = 15

c = 15 - 9 = 6

here we have c > a, so we can discard this.

If a = 4, then:

3*4 + c = 15

12 + c = 15

c = 15 - 12 = 3

c < a

From this we can construct our number:

a = b = 4

c = 3

d = b + 4 = 4 + 4 = 8

Then the number is:

4438

If a = 5, then:

3*5 + c = 15

15 + c = 15

c = 15 - 15 = 0

c < a

So we also can have:

a = b = 5

c = 0

d = b + 4 = 9

Such that the number is:

5509

And if a is equal to or larger than 6 we have problems, because

3*6 + c = 15

18 + c =15

c = 15 -18 = -3

And c can't be a be a negative number.

So we can conclude that we found two 4-digit numbers that meet all the conditions, and these are:

4438 and 5509

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https://brainly.com/question/19902993

Answer:

70; The following graph is simply a horizontal line at the value 70.

Step-by-step explanation:

Answer:

Graph A. On a coordinate plane, a curve approaches y = 0 in quadrant 1 and curves up into quadrant 2. It goes through (2, 49) and (0, 100).

Step-by-step explanation:

Edge

Answer:

can you please type that question

Answer:

the area of square is

the area of square is side*side

therefore ,area= 11*11= 121 feet square

9514 1404 393

Answer:

  14xv^3

Step-by-step explanation:

Coefficients are 28 and 14, which have a GCF of 14.

x exponents are 1 and 6, so the GCF is x^1 = x

y exponents are 8 and 0, so the GCF is y^0 = 1

v exponents are 7 and 3, so the GCF is v^3

The GCF of the two terms is the product of the factors just found:

  14xv^3

Answer: Choice A

Explanation:

If you use a calculator or long division, you should find that

5/6 = 0.8333333...

where the '3's go on forever. We shorten this down to [tex]0.8\overline{3}[/tex], the horizontal bar tells us which item goes on forever (just the 3 only).

The answer is A. I don't know how to explain.

Step-by-step explanation:

your answer

We want to find the number of students that are not good in any of the courses.

There are 80 students.

45 are good in mathematics

15 are good in both, mathematics and in English

13 are good in both, mathematics and psychology

16 are good in both English and psychology

20 are good in psychology

9 are good in all of the courses.

First, we know that we have:

45 good in math + 20 good in psychology = 65 students good in something.

But we know that:

13 are good in both, mathematics and psychology

This means that there are 13 students that are being counted twice, so we need to subtract 13.

45 + 20 - 13  = 52 students good in something.

Now we know that:

15 are good in both, mathematics and in English

16 are good in both English and psychology

9 are good in all of the courses.

So one would want to also count these students, but notice that these are already good in mathematics or in psychology, so these are already counted.

And we can't see the number of students that are only good with English, so we can conclude that

52 students are good in something.

then 28 students are not good at any of the 3 courses.

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