The magnitude of the magnetic moment due to the electron's motion is [tex]87.87 * 10^{-37}[/tex].
What is magnetic moment?The magnetic pull and direction of a magnet or other object that produces a magnetic field are referred to as the magnetic moment in electromagnetism. Things that have magnetic moments include electromagnets, permanent magnets, various compounds, elementary particles like electrons, and a number of celestial objects (such as many planets, some moons, stars, etc).
The term "magnetic moment" really refers to the magnetic dipole moment of a system, which is the portion of the magnetic moment that can be represented by an equivalent magnetic dipole or a pair of magnetic north and south poles that are only very slightly apart. The magnetic dipole component is adequate for sufficiently small magnets or over sufficiently large distances.
Calculations:
radius= [tex]5.29 * 10^{-11} m\\[/tex]
velocity=[tex]2.9* 10^{6} m/s[/tex]
Working formula, M=N/A
[tex]I=\frac{charge flow }{time taken} =\frac{e}{time taken\\}[/tex]
[tex]T= \frac{2xr}{v} =\frac{2xx * 5.29 * 10^{-11} }{2.9* 10^{6} }[/tex]
=[tex]15.16 * 10^{-5} s[/tex]
[tex]I= \frac{1.6 * 10^{-19} }{15.16 * 10^{-5} }[/tex][tex]= 0.10 * 10^{-14}[/tex]
=[tex]1 * 10^{-15} C[/tex]
M=[tex]1x (1* 10^{-15} * (5.29 * 10^{-11} )^{2}[/tex]
=[tex]87.87 * 10^{-37}[/tex]
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list 5 example where pivot is present
The five examples where pivot can be seen include the following: 1. Nut Cracker · 2. Seesaw · 3. Scissors · 4. Plier · 5. Stapler
What is a pivot?A pivot is the fulcrum of a simple machine that serves as a point in the machine that allows for easy movement when force of load or effort is being applied at either ends.
The pivot can eithe be located at the either ends of the simple machine or at the middle of the simple machine.
Typical examples of machines that has pivot include the following:
Nut Cracker,Seesaw,Scissors,Plier, and Stapler.From the examples listed above, the pivot of nutcracker and stapler are located at its end while the pivot of seesaw, scissors and pliers are located at the middle.
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How much kinetic energy does a 3.50kg block with a speed of 4.00m/s have?
Taking into account the definition of kinetic energy, the kinetic energy of a 3.50kg block with a speed of 4.00 m/s is 28 J.
Definition of kinetic energyKinetic energy is defined as the energy associated with bodies that are in motion and this energy depends on the mass and speed of the body.
In other words, kinetic energy is defined as the amount of work necessary to accelerate a body of a certain mass and in a position of rest, until it reaches a certain speed.
Kinetic energy is represented by the following expression:
Ec = 1/2×m×v²
where:
Ec is kinetic energy, which is measured in Joules (J). m is mass measured in kilograms (kg).v is velocity measured in meters over seconds (m/s).Kinetic energy in this caseIn this case, you know:
m= 3.50 kgv= 4 m/sReplacing in the definition of kinetic energy:
Ec = 1/2× 3.50 kg× (4 m/s)²
Solving:
Ec= 28 J
Finally, the kinetic energy of a 3.50kg block with a speed of 4.00 m/s is 28 J.
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Using 6. 0×1024 kg for the mass of the earth, what is the acceleration of the earth toward her as she accelerates toward the earth with an acceleration of 9. 8 m/s2 ? assume that the net force on the earth is the force of gravity she exerts on it.
The value of the acceleration of the earth toward it when it accelerates toward the earth with 9.8m/s² is a = 7.35×10-²³m/s².
What is acceleration?Acceleration is defined as the second derivative of displacement or the derivative of velocity:
a = d/dt(dS/dt) = dV/st.
It is the rate of change of velocity, it generates a constant change over time.
What are forces?Forces are the definition of Newton's second law, which is stated under the relation:
∑ Force = mass × acceleration.
In other words, force is the origin of motion since it generates acceleration in a system.
In this case we must complete the statement:
"A student with mass 45 kg jumps off a high diving board. Using 6. 0×1024 kg for the mass of the earth, what is the acceleration of the earth toward her as she accelerates toward the earth with an acceleration of 9. 8 m/s2 ? assume that the net force on the earth is the force of gravity she exerts on it."
We determine the Force of the student:
F = ma
F = 45kg * 9.8m/s².
F = 441N
Now we go to the acceleration of the earth:
a = F/m
a = 441N / 6×10²⁴ Kg
a = 7.35×10-²³m/s².
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Q|C A large set of unoccupied football bleachers has solid seats and risers. You stand on the field in front of the bleachers and sharply clap two wooden boards together once. The sound pulse you produce has no definite frequency and no wavelength. The sound you hear reflected from the bleachers has an identifiable frequency and may remind you of a short toot on a trumpet, buzzer, or kazoo.(d) the duration of the sound on the basis of data you specify.
As a result, it is a noise without a pitch or wavelength. When the time comes, part of it is incidental and radiates away from you in all directions.
Following that, there is a temporal delay of 60 cm, or 0.6 m divided by 340 m/s, or 0.002 seconds. This is the amount of time it takes for the sound impulse to travel from one riser to the next. Any material will now reflect a significant portion of the sound that reaches it, and the reflected wave will sound substantially different from the shop. first sound. If there are 20 rows of seats and you hear a tone with 20 crests coming from the stands,
What is sound pulse?We are informed about this sound wave problem that a loud, sharp sound is produced in the middle of a field in an empty stadium. We hear an echo with a distinct pitch but no frequency or Waveland in the pulse.
Now that the sound has been accounted for, we need to estimate its frequency, wavelength, and duration in terms of orders of magnitude. We will now graph the air pressure versus time and model the Lord Sharp sound impulse as a single narrow peak.
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Copmared with a sound of 60 decibles a sound of 80 decibles has an intesity what times greater
According to sound power level, 80 decibel sound has greater intensity.
We need to know about sound power levels to solve this problem. The sound power level can be defined by a decibel unit. The decibel unit is proportional to the logarithm intensity ratio. It can be written as
dB = 10 log(I1 / I0)
where dB is sound power level, I1 is sound intensity and I0 is reference sound intensity (10¯¹² W/m²)
From the question we know that
Ia = 60 dB
Ib = 80 dB
Because the decibel unit is proportional to the logarithm intensity ratio, the sound with greater decibel will have greater intensity.
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The rest energy of an electron is 0.511MeV. The rest energy of a proton is 938MeV. Assume both particles have kinetic energies of 2.00MeV. Find the speed of(d) Repeat the calculations in parts (a) through (c) assuming both particles have kinetic energies of 2000MeV
Answer:
The speed of the electron is 0.98c, given that the rest energy of an electron is 0.511MeV and the rest energy of a proton is 938MeV, with both particles having kinetic energies of 2.00MeV.
Explanation:
A particle's total energy and the rest energy follow the laws of physics and the theory of relativity. The energy of any particle is equal to mass times the speed of the light-squared relatively.
Where; E=γ.〖mc〗^2
γ is the ratio of total energy to rest energy of the particle.
m_0 is known as the rest mass of the particle.
Rest energy can be written as: E_0=〖m_0 c〗^2
γ=K/E_0 +1 (1)
γ=1/(√1-v^2/c^2) (2)
Putting the values of the electron energy into equation (1):
γ=2.00MeV/0.511MeV+1
γ= 3.91 + 1
γ=4.91
From equation (2),
γ=1/(√1-v^2/c^2)
Squaring both sides of the equation,
γ^2=1/(1-v^2/c^2)
1/γ^2 =1-v^2/c^2
v^2/c^2 =1-1/γ^2
v/c=√1-1/γ^2
Making v subject of the formula,
v=√1-1/γ^2 ×c (3)
Inserting the values into Equation 3,
v=√1-1/〖4.91〗^2 ×c
v=√1-1/24.11×c
v=√0.959×c
v=0.98×c
v=0.98c
Therefore, the speed of the electron is 0.98c.
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Answer please with working out
Answer:
(1) a) S=D/T
b)5m/s
c)3.33s
(2) a) 1.104m
Explanation:
(1) b) S=D/T
S=1500/300
S=5m/s
c) T= V-U/a
v=10
u= 2
a= 2.4
10-2=8/2.4=3.33s
(2) a) d=s×t
0.46×2.4=1.104m
A 2 kg block of cheese is in an elevator accelerating down at a rate of 1.5 m/s².
What is the normal force on the cheese?
What is inertia and how does it relate to Newton's first law of motion?
Answer:
inertia is basically the fact that something will continue moving until something else stops it. take friction for example. If you roll a ball on the ground, it will eventually stop because of friction, you can kind of think of it like a gear wheel. and i guess it relates to newtons first law of motion because it is his first law?? i don't know how to answer that
Explanation:
Using 6. 0×1024 kg for the mass of the earth, what is the acceleration of the earth toward her as she accelerates toward the earth with an acceleration of 9. 8 m/s2 ? assume that the net force on the earth is the force of gravity she exerts on it.
The value of the acceleration of the earth toward it when it accelerates toward the earth with 9.8m/s² is a = 7.35×10-²³m/s².
What is acceleration?Acceleration in theoretical terms refers to the derivative of the velocity function, it is the rate of change of this variable, and the physical magnitude of the motion that gives rise to the change of position.
What are forces?Forces are the definition of Newton's second law, which is stated under the relation:
∑ Force = mass × acceleration.
In other words, force is the origin of motion since it generates acceleration in a system.
In this case we must complete the statement:
"A student with mass 45 kg jumps off a high diving board. Using 6. 0×1024 kg for the mass of the earth, what is the acceleration of the earth toward her as she accelerates toward the earth with an acceleration of 9. 8 m/s2 ? assume that the net force on the earth is the force of gravity she exerts on it."
We determine the Force of the student:
F = ma
F = 45kg * 9.8m/s².
F = 441N
Now we go to the acceleration of the earth:
a = F/m
a = 441N / 6×10²⁴ Kg
a = 7.35×10-²³m/s².
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The subatomic particles that are least massive and most massive respectively are the.
The subatomic particles that are least massive and most massive are the electron and neutron respectively.
Subatomic particles are defined as the elementary particles which make the fundamental constituents of all matter. The subatomic particles constitute the negatively charged electrons, the positively charged protons, and the neutral neutrons which do not have any charge on them.
Protons and neutrons on the other hand are made up of other elementary particles namely quarks. Subatomic particles have emerged a lot in the coming days with the construction of particle accelerators.
The electron is the least massive subatomic particle. It carries a negative charge of 1.602176634 × 10^−19 coulomb which is about 0.000548 amu.
Neutron is the heaviest subatomic particle having a mass of about 1.008 amu.
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13. Two identical metallic spheres A and B, each carry- ing a charge q, repel each other with a force F. A third metallic sphere C of the same size, but un- charged, is successively made to touch the spheres A and B, and then removed away. What is the force of repulsion between A and B? (Ans. 3F/8) 4.
Answer:
Who knows the answer please I need the answer
Acceleration (m/s²)
1. Complete the following table:
Starting speed
(m/s)
2
10
8
b
2
5
4
5
Final speed (m/s) Time taken (s)
25
8
2
2
10
2
Answer:
Acceleration= 2 m/s²
Time= 10 s
Final Speed= 24 m/s
Final Speed= 85 m/s
Starting Speed= 0 m/s
Explanation:
By using, v = u + at
Acceleration= 2 m/s²
Time= 10 s
Final Speed= 24 m/s
Final Speed= 85 m/s
Starting Speed= 0 m/s
the coefficient of performance of a residential heat pump is 1.6. calculate the heating effect in kj/s this heat pump will produce when it consumes 2 kw of electrical power.
The heating effect in with the residential heat pump will be 3.2 KJ/s
Heat pump - mechanical device which convert heat from low temperature to high temperature reservoir with the use of external work.
Heating effect - it is the change of electrical energy which passes through the conductor into heat energy.
The rate of heat produced. [tex]Q_{H}[/tex] is calculated by
The coefficient of residential heat pump = 1.6
The consume of electric power = 2kw
The rate of heat produced.( [tex]Q_{H}[/tex]) =
The coefficient of performance × consume of electric power
[tex]Q_{H}[/tex] = 1.6 × 2
= 3.2 KJ/s
The heating effect in with the residential heat pump will be 3.2 KJ/s
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A single-turn square loop of wire, 2.00 cm on each edge, carries a clockwise current of 0.200 A . The loop is inside a solenoid, with the plane of the loop perpendicular to the magnetic field of the solenoid. The solenoid has 30.0 turns/cm and carries a clockwise current of 15.0A . Find (a) the force on each side of the loop
The force on each side of the loop is [tex]2.26\times10^{-4}N[/tex] away from the centre .
Magnetic field at the centre of a solenoid of length 'L' having 'N' number of turns with a current 'I' is given by [tex]B=\frac{u_0NI}{L}[/tex] ...(1) where [tex]u_0[/tex] is the permittivity of free space whose value is [tex]4\pi \times10^{-7}Tm/A[/tex] .Force due to current carrying wire 'I' in a magnetic 'B' having length 'L' is given by [tex]F=BILsin\theta[/tex] ...(2) where θ is the angle between current and length of the wire .It is given that solenoid has 30.0 turns/cM which means we have given number of turns per unit length [tex]n=\frac{N}{L} =30\times10^{2}m[/tex] and carries a clockwise current of 15.0A .
Putting above values in equation (1) , we get
[tex]B=4\pi \times10^{-7}\times 30\times10^{2} \times15.0\\B=0.0565T[/tex]
The magnetic force exerted due to their magnetic field on the sides of the loop will be away from the center of loop and is given by equation (2) .
It is given that current in the loop is 0.200 A and length of the each side of the loop is 2.00 cm [tex]=2\times10^{_2}m[/tex] and plane of the loop perpendicular to the magnetic field of the solenoid.
Putting above values in equation (2) , we get
[tex]F=0.0565\times0.2\times2\times10^{-2}\times sin90\\F=2.26\times10^{-4}N[/tex]
Direction of force is found by Fleming' Left Hand rule which states that when the thumb, index finger and middle finger of the left hand are placed perpendicular to each other, the thumb points in the direction of the magnetic force, the index finger points in the direction of the magnetic field, and the middle finger points in the direction of the flow.
According to Fleming's left hand rule, the magnetic force exerted due to their magnetic field on the sides of the loop will be away from the center of loop and is given by equation (2) .
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What is the mass of a rocket 5,000m above the Moon’s surface if 84kJ
of gravitational potential energy is stored? Assume g on the Moon =
1.63N/kg.
Considering the definition of potential energy, the mass of a rocket 5,000 m above the Moon’s surface is 10.31 kg.
Potential energyPotential energy is the energy that measures the ability of a system to do work based on its position. In other words, this is the energy that a body located at a certain height above the ground has.
Gravitational potential energy is the energy associated with the gravitational force. This will depend on the relative height of an object to some reference point, the mass, and the strength of gravity. Then, the expression applied to the gravitational energy of the object is:
Ep= m×g×h
Where:
Ep is the potential energy in joules (J).m is the mass in kilograms (kg). h is the height in meters (m).g is the acceleration of the fall in m/s².Mass of the rocketIn this case, you know:
Ep= 84 kJ= 84,000 J (being 1 kJ= 1,000 J)m= ?h= 5,000 mg= 1.63 N/kg= 1.63 m/s²Replacing in the definition of gravitational potential energy:
84,000 J= m×1.63 m/s²×5,000 m
Solving:
84,000 J= m× 8,150 m/s²×m
84,000 J÷ (8,150 m/s²×m)= m
10.31 kg= m
Finally, the mass of a rocket 5,000 m above the Moon’s surface is 10.31 kg.
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velocity changes from 2m/s to 12m/s time taken is 5 seconds (with the guess method pleasee)
Answer:
a = 2 m/c²
Explanation:
Given:
V₁ = 2 m/s
V₂ = `12 m/s
t = 5 c
______________
a -?
Acceleration:
a = ( V₂ - V₁) / t
a = ( 12 - 2 ) / 5 = 10 / 5 = 2 m/c²
who is Isacc.Newton??
Answer:
Sir Isaac Newton contributed significantly to the field of science over his lifetime. He invented calculus (opens in new tab) and provided a clear understanding of optics. But his most significant work had to do with forces, and specifically with the development of a universal law of gravitation and his laws of motion
Explanation:
A genius with dark secrets. Isaac Newton changed the way we understand the Universe. Revered in his own lifetime, he discovered the laws of gravity and motion and invented calculus. He helped to shape our rational world view.
a model house that runs completely on renewable energy uses 2 windmills and 3 solar panels. each windmill generates mmm kilowatt-hours (kwh) of energy per year, and each solar panel generates sss kwh per year. which expressions can we use to describe how many kwh of energy the model house will output in 10 years? choose 2 answers: choose 2 answers:
The model house on remote renewable energy will generate (20mmm + 30sss) kilowatt-hours of energy in 10 years.
Given:
Remote Renewable House= 2 windmills + 3 turbines
1 windmill generate mmm kilowatts-hours in a year
Therefore,
2 windmills will generate,
2×mmm=2mmm kwh in a year
In 10 years, 2 windmills will generate
10×2mmm=20mmm
1 solar panel generate sss kilowatt-hour each in 1 year
3 solar panels will generate yearly
3×sss=3sss
In 10 years, 3 solar panels will generate
10×3sss=30sss
Therefore, the total energy generated in the renewable model house is in 10 years
(20mmm+30sss) kwhr
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Help me to answer this..
Click the picture to see the full question.
Explanation:
Newton second law of motion
Please someone help me.
is the block of wood at rest or in motion?
refer to the figure below draw the forces acting on the block of wood use the gas as the origin of the forces.
thank you very much for answering this.
Answer:
1) The block of wood is at rest.
2) Weight and Normal Reaction (see attached diagram).
Explanation:
Assumptions
The block of wood is a particle (a body whose mass acts at a point, so its dimensions don't matter).There are no other external forces involved.Question 1
"At rest" or "resting" means that the object isn't moving.
Therefore, the block of wood is at rest.
Question 2
Forces that are acting on the block of wood:
Weight (W): Due to the particle's mass, m, and the acceleration due to gravity, g: W = mgSee attached diagram.
a red car and a green car, identical except for the color, move toward each other in adjacent lanes and parallel to an x axis. at time t
The constant acceleration of the green car is -2m/s2
Given,at t= 0
d=220m(distance between the cars)
let v0 be the final velocity of the green car
And,a be the green car acceleration
Then,for the red car with V1= 20km/h=5.56m/s the passing point
X1=44.5m
t1=X1/V1 =8.01s
then,X1-d=Vot1+1/2at2.......... equation (1)
And,for the red car with V2=40km/h=11.11m/s,the passing point
X1=76.6m
t2=X2/V2= 6.894s
then,X2-d= V0 t2+1/2at2.......equation (2)
on solving equation (1) & (2),
We obtain the following results;
The initial velocity of the green car is = -2m/S2 (the negative sign means that it's along the -X direction)
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Disclaimer: The question was given incomplete on the portal.Here is the complete question.
Question:a red car and a green car, identical except for the colour, move toward each other in adjacent lanes and parallel to the x−axis. At time t=0, the red car is at x r =0, and the green car is at x g =220m. If the red car has a constant velocity of 20km/h, the cars pass each other at x=44.5m, and if it has a constant velocity of 40km/h, they pass each other at x=76.6m. What is the constant acceleration of the green car?
which of these statements about density is true? group of answer choices the density of an object depends on the force of gravity. density does not depend on temperature. density is a physical property. larger objects are more dense.
The statement about density that is true is: density is a physical property
The density of an object is the relation that exist between the mass and the space that the object occupies. The general formula of the density is:
ρ = m/v
Where:
v= volumeρ= densitym= massFor example if we want to know which is the density of a body that has a mass of 100g and a volume of 150 cm³, applying the density formula we get:
ρ = 100 g/150 cm³
ρ = 0.666 g/cm³
What is density?It is a physical quantity that expresses the ratio of the body mass to the volume it occupies.
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questiona balloon is a sphere with a radius of 5.0 m. the force of air against the walls of the balloon is 45 n.what is the air pressure inside the balloon?surface area
Air pressure inside the balloon is 0.143 N/m²
PRESSURE : force applied perpendicular to the surface of object per unit area.
GIVEN -
Radius = 5.0m
Force = 45N
Air pressure inside the balloon is given by
[tex]P = \frac{F}{A}[/tex]
Where
P = Pressure
F = Force
A = Area
Surface area of the sphere = 4πr²
r is the radius of sphere
A = 4 ×3.14×(5)²
A = 314 m²
P = F/A
P = 45/314
P = 0.143 N/m²
Air pressure inside the balloon is 0.143 N/m²
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What is the purpose of a free body diagram?
to show the velocity of an object
to show the acceleration of an object
to show the forces acting on an object
to show the direction of motion vectors of an object
Answer:
c: to show forces acting on an object
a spring is compressed by 1 cm when a force of 5.0N is applied. what is the potential energy stored in the spring when it is compressed by 10.cm
The potential energy stored in the spring is 0.025 J.
What is potential energy stored in a spring?This is the energy stored in a spring when its is stretched or compressed through a certain length.
To calculate the potential energy stored in a spring, we use the formula below.
Formula:
E = Fe/2............... Equation 1Where:
E = Potential energy of the springF = Force applied to the springe = Extension or CompressionFrom the question,
Given:
F = 5 Ne = 1 cm = 0.01 mSubstitute these values into equation 1
E = 5×0.01/2E = 0.025 JHence, the potential energy stored in the spring is 0.025 J.
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A parallel-plate capacitor is disconnected from a battery, and the plates are pulled a small distance further apart. Do the following quantities increase, decrease, or stay the same?.
When the parallel-plate capacitors are disconnected from a battery and plates are pulled a small distance farther apart then Q remains the same, C decreases, Change in potential increases, Energy stored increases and E stays the same.
Solution:
Let's take C as the capacitance of parallel plates and Q as the Charge stored and 'd' is the distance between a plate of capacitors.
In the case of disconnection between plate capacitors, the capacitance of a parallel-plate capacitor becomes equal.
Then, charge Q remains the same i.e.
Q = εA / d = Q / Ed = Q/V
Here Q refers to the charge stored in a capacitor, E is the Electric field, V is the potential difference, and 'd' is the separation between plates.
There is an inverse relationship between potential difference and distance against the capacitance between a plate of the capacitor.
Similarly, the potential difference will increase when capacitance decreases.
E = V/d
While the values of V and d show a gradual decrease, E remains constant, therefore energy stored in the capacitor will be E = 1/2CV^2
The decrease in C causes an increase in V, as a result of which energy stored in the capacitor increases.
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A plane moves with a velocity of 63.5 m/s at 32 degrees South of East. Calculate the plane's horizontal and vertical velocity components.
The plane's horizontal and vertical velocity components are 33.65 m/s and 53.85 m/s respectively.
What is velocity ?
velocity is defined as rate of change of displacement d of the object with respect to rate of change in time t. In mathematics It is written as :
v = d/t
it should be noted that, velocity is nothing but speed in particular direction. That is velocity is vector quality having both magnitude and direction where as speed is just the magnitude of velocity.
It is given that :
A plane moves with a velocity v of 63.5 m/s at 32 degrees South of East with the horizontal.
Therefore, the planes horizontal velocity components will be :
v₁ = vsinθ
v₁ = 63.5 x sin 32⁰
v₁ = 33.65 m/s
the planes vertical velocity components will be :
v₂ = vsinθ
v₂ = 63.5 x cos 32⁰
v₂ = 53.85 m/s
Therefore, the plane's horizontal and vertical velocity components are 33.65 m/s and 53.85 m/s respectively.
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Owen and Dina are at rest in frame S' , which is moving at 0.600 c with respect to frame S . They play a game of catch while Ed , at rest in frame S , watches the action (Fig. P39.75). Owen throws the ball to Dina at 0.800 c (according to Owen), and their separation (measured in S' ) is equal to 1.80 × 10¹²m .(a) According to Dina, how fast is the ball moving?
The speed of the ball with respect to Dina is 0.800c.
A frame of reference is a set of reference points—geometric points whose positions are known mathematically and physically—that define the origin, orientation, and scale of an abstract coordinate system.
If a body does not continuously adjust its position in relation to its environment throughout the course of time, it is said to be at rest.
In frame S', Dina and Owen are at rest.
The speed of the ball with respect to Owen, u =0.800c
The speed of the frame S' with respect to frame S, v = 0.600c
Distance between Dina and Owen, L(p) = 1.8 × 10¹² m
Speed of light, c = 3 × 10⁸ m/s
Therefore, the speed of the ball according to Dina is 0.800c. As Dina and Owen are in the same frame.
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when driving downhill, gravity will cause you to go slower and decrease your stopping distance. a. true b. false
False.While driving downhill, the gravity will cause you to go faster and increase your stopping distance.
What is stopping distance?Brakes are suddenly applied while the body is travelling at a given speed. You would have observed that after travelling a given distance, the body stops entirely. The stopping distance is that distance.
The distance travelled between the moment the body decides to stop a moving vehicle and the moment the vehicle comes to a complete stop is known as the stopping distance. The stopping distance, indicated by the letter d, is dependent on a number of variables, including as the road's surface and the driver's reflexes.
Stopping Distance formula is given by,
[tex]d=\frac{v^{2} }{2ug}[/tex]
Where,
d = stopping distance (m)
v = velocity (m/s)
μ = friction coefficient
g = the gravitational acceleration
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