in rhombus $abcd$, points $e,f,g,$ and $h$ are the midpoints of $\overline{ab},\overline{bc},\overline{cd},$ and $\overline{da},$ respectively. quadrilateral $efgh$ has area 14 and perimeter 16. find the side length for rhombus $abcd$.

The accuracy of a survey estimate refers to the closeness of the estimate to the true population value. Where there is a discrepancy between the value of the survey estimate and the true population value, the difference between the two is referred to as the error of the survey estimate.

The total error of the survey estimate results from the two types of error:

sampling error, which arises when only a part of the population is used to represent the whole population; and

the non-sampling error which can occur at any stage of a sample survey and can also occur with censuses. Sampling error can be measured mathematically whereas measuring non-sampling error can be difficult.

Sampling error is affected by a number of factors including sample size, sample design, the sampling fraction, and the variability within the population. In general, larger sample sizes decrease the sampling error, however, this decrease is not directly proportional.

The most commonly used measure of sampling error is called the standard error (SE). The standard error is a measure of the spread of estimates around the "true value". In practice, only one estimate is available, so the standard error can not be calculated directly.

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Answer:

I think the answer is -7 1/5, -7.1 repeating, 23/3, square root of 50

The solution for the system of equation is 4534 and the graphical representation is attached below.

A system of equation or simultaneous equations are a pair of linear equation is 2 variables such that they represent a pair of straight line sin the cartesian plane.

The point of intersection of these two line on the cartesian plane is given by the solution of the two equation that are given.

A system of equations can be solved algebraically  by matrix method , elimination method or by substitution.

Now let us solve the given equation algebraically by elimination method.

5x - y = 35

3x + y = -3

Adding the equation we get:

or, 8 x = 32

or,  x  = 4

putting the value of x in the first equation we get:

5 × 4 - y = 35

or, -y = 35 - 20

or, y = -15

Hence the point of intersection is ( 4 , -15 )

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Answer: B

I took the quiz

Answer:

(−3, 2); 2 ≤ y < ∞

Step-by-step explanation:

I literally took the test hours ago

Answer:

93

Step-by-step explanation:

first you add 30 and 57

where you will get 87

then subtract 87 from 180 and get 93

a) for given functions f(x) = 8x and g(x) = 12x + 3,

(f g)(x) = 96x² + 24x

b) for functions f(x)= 14 and g(x)= 3 - 12x,

f(x) • g(x) = 42 - 168x

In this question, we have been given two functions.

We need to find the given function.

a) f(x) = 8x and g(x) = 12x + 3

To find (f g)(x)

We know that, the product of functions f(x) and g(x) is:

(f g)(x) = f(x) . g(x)

(f g)(x) = (8x) (12x + 3)

(f g)(x) = 96x² + 24x

So, for given functions f(x) = 8x and g(x) = 12x + 3,

(f g)(x) = 96x² + 24x

b) f(x)= 14 and g(x)= 3 - 12x

To find f(x) • g(x)

f(x) • g(x) = (14) . (3 - 12x)

f(x) • g(x) = 42 - 168x

So, for functions f(x)= 14 and g(x)= 3 - 12x,

f(x) • g(x) = 42 - 168x

Therefore, a) for given functions f(x) = 8x and g(x) = 12x + 3,

(f g)(x) = 96x² + 24x

b) for functions f(x)= 14 and g(x)= 3 - 12x,

f(x) • g(x) = 42 - 168x

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The statements that are true about the graph of the system of linear inequalities include:

The graph of y > 3x − 4 has shading above a dashed line.

The graphs of the inequalities will intersect.

y means the shading will be above the corresponding line.

y means the shading will be below the corresponding line.

Together, the two graphs intersect the entire y-axis. Jointly, they only intersect the y-axis on the interval -4 < y < 1.

Therefore, the graph of y > 3x − 4 has shading above a dashed line and thee graphs of the inequalities will intersect.

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Answer:

A, C

Step-by-step explanation:

Which statements are true about the graph of the system of linear inequalities? Select two options.

y > 3x – 4

y < One-halfx + 1

The graph of y > 3x − 4 has shading above a dashed line.

The graph of y < One-halfx + 1 has shading below a dashed line.

The graphs of the inequalities will intersect.

There are no solutions to the system.

The graphs of the two inequalities intersect the y-axis at (0, 1) and (0, 4).

Edge 2022

Answer:

$317.55

Step-by-step explanation:

There are 365 days in a year and the subscription is 0.87 cents per day.

365 * 0.87 = 317.55

Answer: 6 words per minute

Step-by-step explanation:

54 words / 9 minutes =

54/9=6 words per minute

Answer:

6 words/min

Step-by-step explanation:

9 min --- 54 words

÷9 ( )÷9

1 min --- 6 words

Malia that uses 51 yards of ribbon to make 17 bows will have to use 204 yards of ribbon to make 68 bows

To solve this problem we will use a rule of three with the problem information:

17 bows-------- 51 yards of ribbon

68 bows-------- x

Applying the rule of three we get:

x = (68 bows * 51 yards of ribbon) /17 bows

x = 204 yards of ribbon

It describes the proportionality of 3 known data and an unknown data. When you have more than 3 known facts that are involved in the proportionality, it is known as a compound rule. The rule of three is also known as a direct proportions.

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The inequality for the graph is given by   y > | x - 5 | + 1 .

An inequality in mathematics is a relation that compares two numbers or other mathematical expressions in an unequal way.

A graphical representation of an inequality in 2 dimension refers to as the region above or below the graph.

Given the graph of an inequality we write the required inequality using translation properties of a graph.

The parent function of the graph can be written as y > | x |.

the graph of y > | x | is attached below.

The following steps are used to write the inequality:

Hence the required inequality for the graph is given by y > | x - 5 | + 1

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Answer:

False! as long as the the Scale Factor is 1, there is still a possibility that the figure will be congruent or greater! GOOD LUCK!

Answer: True

Step-by-step explanation: This is the difference between using transformations to create similar figures vs using transformations to create congruent figures. Similar figures are figures with the same shape. Congruent figures are figures with the same shape and size. If the scale factor is not equal to 1, then the figures are similar. If the scale factor is equal to 1, then the figures are congruent.

There are five whole numbers between 1 and 150 that have exactly 3 different factors. Whole numbers between 1 and 150 with exactly 3 different factors must be the square numbers whose square roots are prime.

To find the complete list begin counting...

skip 1, not prime;

2 is prime and 2 squared is 4;

3 is prime and 3 squared is 9;

skip 4 b/c it is not prime;

5 is prime and 5 squared is 25;

6 not prime;

7 prime and 7 squared is 49;

8 not prime;

10 not prime;

11 prime and squared is 121;

12 is not prime;

13 prime, but squared it is greater than 150.

The complete list is 4, 9, 25, 49, and 121. 4 has 1, 2, 4;

9 has 1, 3, 9;

25 has 1, 5, 25 ;

49 has 1, 7, 49 ;

121 has 1, 11, 121.

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Answer:

(k + 4) (7k + 3)

k(7k + 3) + 4(7k + 3)

7k² + 3k + 4(7k + 3)

7k² + 3k + 28k + 12

7k²  + 3k + 28k + 12

7k² + 31k + 12

7k² + 31k + 12

The condition  [tex]f^{\prime}(2)[/tex] = 0 to form a subspace of  [tex]\mathbb{R}^{(0,3)}[/tex] is that f ∈ S is that otherwise, S wouldn't be closed under addition and thus would not be a subspace of  [tex]\mathbb{R}^{(0,3)}[/tex].

An identity element (like 0 in the collective of whole numbers under operation of addition) that leaves unaffected any element that it is added in a provided mathematical system.

Now, for the given question.

I'd just like to comment on the paragraph about intuition as well as the additive identity: That instinct is incorrect.

First, we could perhaps define a object that we need to confirm is a subspace of [tex]\mathbb{R}^{(0,3)}[/tex] in a more precise manner than the translation in which it is initially presented. We want to look at a set, S.

Where,

[tex]S=\left\{x, f \mid 0 < x < 3, f \in \mathbb{R}^{(0,3)} \wedge f^{\prime}(x)=0\right\}[/tex]

We are specifically tasked with having to prove the restriction just on derivative of f, which is best accomplished in the manner made reference.

The fact that S, as described above, describes a functional space explains why my initial intuition about problem is ultimately incorrect. I was hindering myself by viewing it solely as a geometric space.

As a result, I missed the fact that zero function (the additive identity in such a functional space) is indeed a natural member of S.

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The complete question is-

I'm working my way through Axler's "Linear Algebra Done Right", and I've run into a proposition that I don't understand. Namely:

The set of differentiable real-valued functions f on the interval (0, 3) such that [tex]f^{\prime}(2)[/tex] = b is a subspace of [tex]\mathbb{R}^{(0,3)}[/tex]  if and only if b = 0.

My intution is that this has something to do with the fact that a subspace requires an additive identity, but that because the domain of the differentiable functions is open and exludes 0, we have to make some concessions (i.e.  [tex]f^{\prime}(2)[/tex] = 0), though I'm unsure of how to work up a proof that backs this.

Why must   [tex]f^{\prime}(2)[/tex] = 0 to form a subspace of  [tex]\mathbb{R}^{(0,3)}[/tex]?

Answer:

5 m/s

Step-by-step explanation:

The equation for speed is distance/time. The distance given is 50 meters. The time given is 10 minutes. 50/10 is 5. 5 meters per second is your speed.

Answer:

2⁹

Step-by-step explanation:

Repeatedly dividing 512 by 2 which is a prime number gives:

512 = 2 x 2 x 2 x 2 x 2 x 2 x 2x 2 x 2 = 2⁹ in index notation

Answer:

1,2,4,8,16,32,64,128,256,and 512

We need to know about the concept of compound interest to solve the given problem. The minimum interest rate that Harry needs to meet his need is 11.4%

Compound interest can be described as the interest that you earn on both the principal amount and the interest earned. In this question it is said that the bank offers annual interest compounded monthly, we will be using a formula to solve this problem. Since Harry has 21350 EUR we will take that as the principal amount and the minimum amount that he needs is 30000 EUR we will consider this to be the final amount at the end of 3 years. We need to find out the rate of interest that the bank offers.

A=P[tex](1+\frac{r}{12} )^{12t}[/tex] where A is amount, P is principal, r is the rate of interest and t is time period.

P=21350 EUR

A=30000 EUR

t=3

30000=21350[tex](1+\frac{r}{12}) ^{36}[/tex]

[tex]\frac{600}{427} =(1+\frac{r}{12}) ^{36}[/tex]

1+[tex]\frac{r}{12}[/tex]=1.00949

r/12=0.00949

r=0.1139

r=11.4%

Therefore we found that the minimum rate of interest Harry requires to meet his needs is 11.4%

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Answer:

y = - x³ - 3x² - 3x - 4

Step-by-step explanation:

!!!!!!

The function represented in the graph is -

[tex]y\ =\ -\left(x+0.9\right)^{3}-3.3[/tex]

In mathematics, if -

xⁿ = k

then -

[n] is called exponent

[x] is called base.

Logarithm is the inverse function to exponentiation. That means the logarithm of a number [x] to the base [b] is the exponent to which [b] must be raised, to produce [x]. We can write -

[tex]y = log_{e}x[/tex]

We have the function as -

f(x) = x³

Refer to the graph of the function in the modified form. The function after being translated is same as the one given in the question. The function after translation is -

[tex]y\ =\ -\left(x+0.9\right)^{3}-3.3[/tex]

Therefore, the function represented in the graph is -

[tex]y\ =\ -\left(x+0.9\right)^{3}-3.3[/tex]

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The fact that the sum of the interior angles of a triangle add up to 180 is equivalent to the parallel postulate. Therefore, the sum of the interior angles of a triangle in this type of geometry be different from those of triangle in Euclidean geometry.

There is only one parallel to the given line in Riemannian geometry. A straight line of finite length that can be continued endlessly is the second postulate of Euclid.

One of the non-Euclidean geometries that entirely rejects the validity of Euclid's fifth postulate and alters his second postulate is Riemannian geometry, commonly known as elliptic geometry. The fifth postulate of Euclid states that there is only one line that passes through a point that is not on a particular line and is parallel to that line.

In this case, the angles won't change as it's always equal

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Answer:

i don't know the answer!!

An AABA form can be repeated to create a larger form; when b and a are repeated after the first AABA, it is called a "partial reprise". The BA or ABA sections of the AABA structure are repeated in the majority of partial reprises.

The term "reprise" is derived from the French word "repris," which means "act of taking back." The word is also derived from the Latin word "reprendre," which means "taken up again." The term is typically used in music, but it can refer to any continuation of an action.

Various uses of reprise in musics are given below-

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Answer:

Step-by-step explanation:

Complete the following statement. Use the integers that are closest to the number in the middle.

< –80

The function of domain is X∈R and the range is [tex]\[\left\{ {f \in \mathbb{R}:f \le \frac{1}{4}(1 + 4\sqrt 2 )} \right\}\].[/tex]

The given function is  [tex]\[f\left( x \right) = \sqrt {2 - x - {x^2}} \][/tex]

Domain: The domain of a function is the set of input or argument values for which the function is real.

Use commutative properties to reorder the terms

[tex]\[f(x) = \sqrt { - x + 2} - {x^2}\][/tex]

Separate the function into parts to determine the domain of each part

[tex]\[f\left( x \right) = \sqrt { - x + 2} \]=-x+2= x^{2}[/tex]

Domain is XR (all real numbers)

The function has no undefined points nor domain constraints. Therefore, the domain is X∈R.

Range: The set of values of the dependent variable for which a function is defined

Range of [tex]\[\left\{ {f \in \mathbb{R}:f \le \frac{1}{4}(1 + 4\sqrt 2 )} \right\}\][/tex]

Combine the ranges of all domain intervals to obtain the function range.

Hence, the domain and the range of the function [tex]\[f\left( x \right) = \sqrt {2 - x - {x^2}} \][/tex] are

Domain = X∈R

Range [tex]=\[\left\{ {f \in \mathbb{R}:f \le \frac{1}{4}(1 + 4\sqrt 2 )} \right\}\][/tex].

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The point which is located on the ray PQ as required in the task content given that the points M, N, O, P, Q, R, S are collinear is; point R.

It follows from the task content that the point which is located on the ray PQ is to be identified among the given answer choices.

Since all points given are said to be contained on a line, it can therefore be inferred that the points are collinear.

Also, by the definition of a ray; it follows that the ray PQ is one which starts from P and goes through Q and continues in the direction of Q.

Ultimately, the point which is located on such ray as described above among the answer choices is the point R.

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Answer:

Point R

Step-by-step explanation:

The zeroes of the expression are 5 and -3.5.

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

The zeroes of the expression can be found by equating the factors of the given expression with 0. Therefore, the zeroes of the expression are,

x - 5 = 0

x = 5

2x + 7 = 0

2x = -7

x = -7/2

x = -3.5

Hence, the zeroes of the expression are 5 and -3.5.

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Answer:

The least common multiple of 8 and 6

burgers: 6, 12, 18, 24

buns: 8, 16, 24

You make 24 burgers which is 4 packages

of meat patties and 3 packs of buns.

Answer: a.{2, 4, 5, 7, 15}    b.{2, 3, 5, 6.5, 9}

Step-by-step explanation: for (a.) you find the median and both extremes, lower and highest value, and for (b.) you just have to re-find the median and the new upper and lower quartiles.

Hope this helps c:

Answer: 16. f(1)=-2

17. f(-3)=1

18. x=0

19. x=-1 and x=1

Step-by-step explanation:

16. f(1)=-2

17. f(-3)=1

18. f(x)=-3

x=0 ==> f(0)=-3

19. f(x)=-2

x=-1 and x=1 ==> f(-1)=-2, f(1)=-2