m∠DBC=(12x-18) and m∠ABD=(8x+30) what is the value for x ?

Answer:

The 1st option is correct.

We are not clear that WX = XY.

3rd is is not correct.

4th option is also incorrect.

......................

Answer:

21

Step-by-step explanation:

14 - (-20) + (-13) =

= 14 + 20 - 13

= 34 - 13

= 21

For the given question options C, D and E are correct answers.

Given that, ∠2, ∠3, and ∠5 are interior angles of the triangle and ∠1, ∠4, and ∠6 are exterior angles of the triangle.

When any side of a triangle is extended, the angle that is formed with this side and its adjacent side is called the exterior angle of a triangle. There are three exterior angles in a triangle. It should be noted that each exterior angle forms a linear pair with its corresponding interior angle.

Now, m∠5 + m∠6=180° (Adjacent angles are added up to 180°)

m∠2 + m∠3 = m∠6 (Exterior angle is equal to the sum of opposite interior angles)

m∠2 + m∠3 + m∠5 = 180° (Sum of all the interior angles of a triangle is equal to 180°)

Therefore, options C, D and E are correct answers.

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Answer:

Step-by-step explanation: it will be having 10 kg each

Answer:

C i think

Step-by-step explanation:

Answer:

C.

Step-by-step explanation:

Answer A is the definition of literal language, while C is the definition of figurative. So, C is correct.

Answer:

12+2=14odokxjxnxnxnxnjskaowoowsjd

Step-by-step explanation:

Across

1.26

2.59

3.19

5.38

6.82

7.62

8.48

9.72

11.40

12.64

Down

1.24

2.59

3.18

4 42

5.32

6.88

7.65

8.42

9.70

10.34

the net pay (weekly) is $359.87

First, we know that the employee wins $11.50 per hour. The employee works 38 hours per week, then the weekly pay is:

38*$11.50  = $437

Now we need to discount the taxes:

There are 10% from federal tax, 6.2% from social services and 1.45% from medicare.

The total is:

10% + 6.2% + 1.45% = 17.65%

Then we need to discount a 17.65% of the weekly pay, we will get:

$437*(1 - 17.65%/100%) = $437*(1 - 0.1765) = $359.87

We conclude that the net pay (weekly) is $359.87

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The required number of people that contribute 34 pays in the goal of 2414 is 71.

According to the assertions, it deals with a number of operations in mathematics. Addition, subtraction, multiplication, and division are the four main arithmetic operators.

Here,
as given in the question,
Total contribution = 2414
Contribution by each person = 34
Applying arithmetic operations
number of people = 2414 / 34
Number of people= 71

Thus, the required number of people that contribute 34 pays in the goal of 2414 is 71.

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Answer:

see explanation

Step-by-step explanation:

to determine if the values of y are a solution to the equation, substitute the values of y into the left side and if equal to the right side then they are a solution.

y = 70

[tex]\frac{70}{7}[/tex] - 1 = 10 - 1 = 9 ≠ - 2 → NO

y = 56

[tex]\frac{56}{7}[/tex] - 1 = 8 - 1 = 7 ≠ - 2 → NO

y = - 7

[tex]\frac{-7}{7}[/tex] - 1 = - 1 - 1 = - 2 → YES

y = 0

[tex]\frac{0}{7}[/tex] - 1 = 0 - 1 = - 1 ≠ - 2 → NO

Answer:

Yes. I think that is a pre algebre question.

Hence , the coordinate of point B is (7 , -3) .

We have given two coordinate A (-3,3) and M (2,0) .

Let the coordinate of B (x, y) .

Using midpoint formula , we get

[tex](2,0) = ( \frac{-3+x}{2} ,\frac{3+y}{2} )[/tex]

On comparing , we get

[tex]\frac{-3+x}{2} =2\\\ \\-3+x = 4\\x = 7[/tex]

[tex]\frac{3+y}{2} =0\\3+y=0\\y=-3[/tex]

We get coordinate (7 , -3) .

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Answer: k=[tex]{4\sqrt{2}[/tex]

Step-by-step explanation:

√128 = 2k

k=[tex]\frac{\sqrt{128}}{2}[/tex]

k=[tex]\frac{\sqrt{64*2}}{2}[/tex]

k=[tex]\frac{8\sqrt{2}}{2}[/tex]

k=[tex]{4\sqrt{2}[/tex]

The number of zeros of the polynomial expression given as y(x)=-4x^5 - 4x^4 - 3x^3 + 11x^2 - x + 2 is 5

Polynomial expressions are mathematical statements that are represented by variables, coefficients and operators

The polynomial expression is given as

f(x)=-4x^5 - 4x^4 - 3x^3 + 11x^2 - x + 2

The degree of the above polynomial expression is

degree = 5

The degree of a polynomial expression is the number of zeros of the polynomial

This means that

Zeros = 5

Hence, the number of zeros of the polynomial expression given as y(x)=-4x^5 - 4x^4 - 3x^3 + 11x^2 - x + 2 is 5

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If out of 7 squares, 4 squares are in grey colour then if there are 15 white squares there will be 20 grey squares by solving through ratios.

Given that out of 7 squares, 4 squares are in grey colour.

We are required to find the number of grey colour squares if there are 15 white squares by using equivalent ratios.

Equivalent ratios are basically the ratios that are the same when we compare them. Two or more ratios can be compared with each other to find whether they are equivalent or not.

Ratio of white squares in 7 total squares=3:4

Total number of squares if there are 15 white squares=15*7/3=35

Number of grey squares=35-15=20

Hence if out of 7 squares, 4 squares are in grey colour then if there are 15 white squares there will be 20 grey squares by solving through ratios.

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Answer:

Step-by-step explanation:

if solved for x the answer is x=−4

step wise step

3x+7= 5x+15

3x-5x=15-7

-2x=8

x=8÷2

×=4

Answer:

Step-by-step explanation:

First plug in the values for x and y:

y=-2
x=2

-2=2k+4

Then just simplify to get k:
-2=2k+4
Minus 4 from both sides
-6=2k
Divide each side by 2
k=-3



I hope this helps!

( -8 , -8) are the coordinate of the other endpoint B .

What is coordinate ?

the coordinates of the second endpoint are  ( x₂, y₂ )

 x = x₁ + x₂/2      

  0 = 4 + 0/2

   x₂  = -8

y = y₁  + y₂/2

-2 = 2 + y₂/2

-2 -2 = y₂/2

- 8  = y₂

( -8 , -8) are the coordinate of the other endpoint B .

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The answers to both the questions are as follows:

The quantity of specific hair dye produced by given ingredients are:

As a result, the amount of specific hair dye produced by given ingredients = 5/2qz

The amount of red tone required to make 1 oz of a specific dye:

= 3/8 × 2/5 = 3/20 oz

Now, multiply each by 20.

The amount of red tone required to make 20 oz of a specific dye:

3/20 × 20 = 3 oz

To find each dye needed to make 100 ounces of dye, multiply the above amounts by 5.

The amount of red tone required to make 20 oz of specific dye: 15oz

Therefore, the answers to both the questions are as follows:

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The correct question is given below:
To make a specific hair dye, a hair stylist uses a ratio of 1 1/8 ounces of red tone, 3/4 ounces of a gray tone, and 5/8 ounces of brown tone. If the stylist needs to make 20 ounces of dye, how much of each dye color is needed? If the stylist needs to make 100 ounces of dye, how much of each dye color is needed?

The vertex of f(x)=x²+10x+1 is found to be  (-5,-24).

The Vertex of the quadratic equation f(x)=ax²+bx+c is (h,k) where

h=-b/2a  and k=f(h).

In the given question

f(x)=x²+10x+1

On comparing with ax²+bx+c

we get a=1 , b=10 , c=1

So , h=-b/2a

h=-10/2(1)

h=-5     ...(i)

k=f(h)

Substituting the value of x=h in f(x) we get

k=(-5)²+10(-5)+1

k=25-50+1

k=-25+1

k=-24

Therefore , the vertex of f(x)=x²+10x+1 is (-5,-24).

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The ambient temperature, aka the outside air temperature, isn't 0 degrees Fahrenheit. This is the reason why the oven isn't at 0 degrees Fahrenheit when the oven is off. For example, if it is 68 degrees Fahrenheit outside, then the oven's temperature is likely around this figure when it is off.

------------------------------

The way the oven works is that it heats the air using a gas or electric source. Once reaching 350 or slightly higher, the oven burner will turn off for a set period of time. This is so the temperature doesn't go too far over 350.

After the burner is turned off, the air inside the oven is still really hot and will stay around 350 for a while. But the temperature will slowly decrease. Once dipping slightly below 350, the oven will turn back on to heat back up to 350 again. This process repeats over and over.

This explains why you see the oscillating bouncing curve like this. It also explains why ovens seem to go on or off in the middle of a baking session.

Answer:

  (1/3)log(5) +(4/3)log(x) +log(y)

Step-by-step explanation:

You want the expanded form of the expression log(∛5·x^4·y^3).

The applicable rules of logarithms are ...

  log(ab) = log(a) + log(b)

  log(a^b) = b·log(a)

In addition to these, you need to know that a root is a fractional power: the cube root is the 1/3 power. Of course, the rules of powers tell you ...

  (a^b)^c = a^(bc)

You can express the root as a fractional power before or after taking logs. Either way, you get the same result.

Before

  [tex]\log\left(\sqrt[3]{5\cdot x^4y^3}\right)=\log\left(5^{\frac{1}{3}}\cdot x^{\frac{4}{3}}y^{\frac{3}{3}}\right)=\boxed{\dfrac{1}{3}\log(5)+\dfrac{4}{3}\log(x)+\log(y)}[/tex]

After

  [tex]\log\left(\sqrt[3]{5\cdot x^4y^3}\right)=\dfrac{1}{3}\log\left(5}\cdot x^{4}y^{3}}\right)=\dfrac{1}{3}\left(\log(5)+4\log(x)+3\log(y)\right)\\\\=\boxed{\dfrac{1}{3}\log(5)+\dfrac{4}{3}\log(x)+\log(y)}[/tex]

__

Additional comment

Working a more complex problem is like working a simple problem, except it has more parts and may require the use of the rules more times. It may be tedious to keep track of all the parts, but it is not difficult.

Answer:

gg

Step-by-step explanation:

Answer:

Three consecutive integers are 43, 44, 45

Step-by-step explanation:

Let three consecutive integers be x, (x + 1), (x + 2)

According to the question, if the third of three consecutive integers is subtracted from 132, the result is the sum of the first and second.

[tex] \therefore [/tex]

[tex] \implies \rm 132 - (x + 2) = x + (x + 1) \\ \\ \implies \rm 132 - x - 2 = x + x + 1 \\ \\ \implies \rm 130 - x = 2x + 1 \\ \\ \implies \rm 130 - 1 = 2x + x \\ \\ \implies \rm 129 = 3x \\ \\ \implies \rm 3x = 129 \\ \\ \implies \rm x = \frac{129}{3} \\ \\ \implies \rm x = 43[/tex]

So,

The integers are as follows:

x = 43

x + 1 = 44

x + 2 = 45

Answer:

46

Step-by-step explanation:

13a+4b

Substitute

13(2)+4(5)

Multiply

26+20

Add

46

Answer:

True, When the clock transitions from 11:59am to 12:00pm, it is the first hour of noon.

Step-by-step explanation:

The exact side length of the rug is √35.

What is the area of parallelogram

Let take the area of length as =a

As per the given question

A square rug has an area=35 sq ft

Area is the quantity that measures the number of unit square

As we know

area of square= a^2

Square area formula: A = a²

As already given a^2=35

So a=√35

The exact side length of the rug is √35.

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Answer:

For Ai - P = 4 , Q = 4 , R = 4

For Aii - P = 3 , Q = 4 , R = 5

For Aiii - b^13 × b^-2 / b^1 = b^10

Step-by-step explanation:

I hope this is correct answer.

Based on the time that it took Kenny and his family to reach the campsite and set it up, the time when they finished setting up the campsite was 8:22 pm

First, find the time that Kenny and his family reached their campsite:
= 3:48 pm + 2 hours 59 minutes

= 6:47 pm

After getting to the campsite at 6:47 pm, Kenny and his family took 1 hour 35 minutes to finish setting up their campsite:

= 6:47 pm + 1 hour 35 minutes

= 8:22 pm

In conclusion, Kenny and his family finished setting up at 8:22 pm.

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As per the question statement, we are given a mathematical expression [tex]|a+5| -1[/tex] is [tex]$\left[\begin{array}{cc}\text { Solution: } & -\infty < a < \infty \\ \text { Interval Notation: } & (-\infty, \infty)\end{array}\right]$[/tex]

As this question involves a modulus function therefore let us suppose that [tex]b=|a+5|-1[/tex]

Find the absolute value vertex. In this case, the vertex for [tex]b=|a+5|-1[/tex] is [tex](-5,-1)[/tex]

Function range definition

The set of values of the dependent variable for which a function is defined

Domain of [tex]$|a-5|-1: \quad-\infty < a < \infty$[/tex]

Extreme Points of [tex]$|a-5|-1: \quad$[/tex] Minimum [tex]$(5,-1)$[/tex]

Find the range for the interval [tex]$-\infty < a < \infty: \quad-1 \leq f(x) < \infty$[/tex]

Combine the ranges of all domain intervals to obtain the function range [tex]$f(x) \geq-1$[/tex]

Axis interception points of [tex]$|a-5|-1: \quad X$[/tex]Intercepts: [tex]$(4,0),(6,0), Y$[/tex]Intercepts:[tex]$(0,4)$[/tex]

x - axis interception points of[tex]$|a-5|-1: \quad(4,0),(6,0)$[/tex]

y - axis interception point of [tex]$|a-5|-1: \quad(0,4)$[/tex]

X Intercepts: [tex]$(4,0),(6,0), Y$[/tex] Intercepts: [tex]$(0,4)$[/tex]

Asymptotes of [tex]$|a-5|-1$[/tex] : None

Vertical asymptotes of [tex]$|a-5|-1$[/tex] : None

Horizontal Asymptotes of [tex]$|a-5|-1$[/tex] : None

Extreme Points of[tex]$|a-5|-1$[/tex] : Minimum [tex]$(5,-1)$[/tex]

First Derivative Test definition

Suppose that [tex]$x=c$[/tex] is a critical point of [tex]$f(x)$[/tex] then,

If [tex]$f^{\prime}(x) > 0$[/tex] to the left of [tex]$x=c$[/tex]and [tex]$f^{\prime}(x) < 0$[/tex] to the right of [tex]$x=c$[/tex] then $x=c$ is a local maximum.

If [tex]$f^{\prime}(x) < 0$[/tex] to the left of [tex]$x=c$[/tex] and [tex]$f^{\prime}(x) > 0$[/tex] to the right of[tex]$x=c$[/tex] then $x=c$ is a local minimum.

If [tex]$f^{\prime}(x)$[/tex] is the same sign on both sides of [tex]$x=c$[/tex] then [tex]$x=c$[/tex]

is neither a local maximum nor a local minimum.

[tex]f^{\prime}(a)=\frac{a-5}{a-5}$$[/tex]

Plug [tex]$a=5$[/tex] into [tex]$|a-5|-1: \quad-1$[/tex]

Minimum [tex]$(5,-1)$[/tex]

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