Programming challenge description: In this challenge, you're given a string containing jumbled letters from several concatenated words. Each word is a numeral from zero to nine. Each numeral may be used multiple times in the jumbled string. Write a program that returns integers corresponding to the numerals used to form the jumbled string. Integers must be sorted in ascending order. For example, reuonnoinfe are shuffled letters of the strings one four nine. Your program's output should be 149. Input: A string formed from jumbled letters of numerals. For example:

Following are the Java program to the given question:

import java.util.*;//import package

public class Jumbledletters //defining Jumbledletters class  

{

public static void main (String[] axv)//defining main method

{

String num[] = {"zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};//defining an arrayof string

int i,j;

Scanner xc = new Scanner(System.in);//creating Scanner class object to input value

System.out.print("Enter value: ");//print message

String v= xc.next();//defining a String variable that input String value

for(i=0; i<num.length; i++)//defining a loop to count input String length

{

String s = num[i];//defining a string variable to hold array value

boolean f = true;//defining a boolean variable

for(j=0; j<s.length(); j++)//defining a for loop that convets value into integer

{

char c = s.charAt(j);//defining char variable that hold value

if(v.indexOf(c)==-1)//defining if block to check indexOf value

{

f = false;//use boolean variable that hold boolean value

break;//using break keyword

}

}

if(f) //use if to check boolean value

System.out.print (i);//use print method that print i value

}

System.out.println();//use print method for beak line

}

}

Output:  

Enter value: onefournine

149

Explanation of code:

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01 public static void mergesort (char[] a, int i, int r){
02
03 if (1 >= r) {
04 return;
05 }
06 int middle = (1+r)/2;
07 mergesort(a, l, middle);
08 mergesort(a, middle+1, r);
09 merge(a, l, middle, r);
10 }
11
12 public static void merge (char[] a, int i, int m, int r){
13
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17 b[i] = a (1+i);
18 }
19
20 int i = 0, j m+1, k = 1;
21 while (i <= m-1 && j <= r ) {
22 if (a[j] < b[i]) {
23 a[j];
24 k += 1;
25 j += 1;
26 } else {
27 a[k] b[i];
28 k += 1;
29 i += 1;
30 }
31 }
32 while (i <= m-1) {
33 a[k] b[i];
34 k += 1;
35 i += 1;
36 }
37 while ( j <= r ) {
38 a[k] a[j];
39 k += 1;
40 j += 1;
41 }
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Run the program and observe the output to be: 55 4 250 19. Modify the numsInsert function to insert each item in sorted order. The new program should output: 4 19 55 250.
#include
#include
using namespace std;
void numsInsert(vector& numsList, int newNum) {
unsigned int i;
for (i = 0; i < numsList.size(); ++i) {
if (newNum < numsList.at(i)) {
// FIXME: insert newNum at element i
break; // Exits the for loop
}
}
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if (true) { // No higher number was found, so append to end
numsList.push_back(newNum);
}
}
void numsPrint(const vector& numsList) {
unsigned int i;
for (i = 0; i < numsList.size(); ++i) {
cout << " " << numsList.at(i) << endl;
}
}

int main() {
vector numsList;
numsInsert(numsList, 55);
numsInsert(numsList, 4);
numsInsert(numsList, 250);
numsInsert(numsList, 19);
numsPrint (numsList);

return 0;
}

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