Solomon says the number 0 belongs only the set of rational numbers. Explain his error.

Answer:

The least common multiple of 8 and 6

burgers: 6, 12, 18, 24

buns: 8, 16, 24

You make 24 burgers which is 4 packages

of meat patties and 3 packs of buns.

It is found that the intercepts can be found from vertex form, if the graph is hovering above the x axis (k<0).

The intersection of the graph of the function with the y-axis gives y-intercept of that function. The y-intercept is the value of y on the y-axis at which the considered function intersects it.

Assume that we've got: y = f(x) At y-axis, we've got x = 0, so putting it will give us the y-intercept. Thus, y-intercept of y = f(x) is y = f(0)

If a quadratic equation is written in the form y=a(x-h)² + k

therefore it is called to be in vertex form. It is called so because when you plot this equation's graph, we will see vertex point(peak point) is on (h,k)

To convert the given equation to vertex form, We will take out coefficient of x squared, and then inside the bracket, we try to make perfect square like situation.

To find the intercepts, if the graph is hovering above the x axis (k<0) then there will be no real solutions for the x intercept.

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Answer:

3y = 5x - 24

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

given

3y = 5x + 2 ( divide through by 3 )

y = [tex]\frac{5}{3}[/tex] x + [tex]\frac{2}{3}[/tex] ← in slope- intercept form

with slope m = [tex]\frac{5}{3}[/tex]

• Parallel lines have equal slopes , then

y = [tex]\frac{5}{3}[/tex] x + c ← is the partial equation of the parallel line

to find c substitute (6, 2 ) into the partial equation

2 = 10 + c ⇒ c = 2 - 10 = - 8

y = [tex]\frac{5}{3}[/tex] x - 8 ← equation in slope- intercept form

multiply through by 3 to clear the fraction

3y = 5x - 24 ← equation of parallel line

[tex]~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ C(\stackrel{x_1}{x}~,~\stackrel{y_1}{y})\qquad T(\stackrel{x_2}{1}~,~\stackrel{y_2}{2}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ 1 +x}{2}~~~ ,~~~ \cfrac{ 2 +y}{2} \right) ~~ = ~~ \stackrel{\textit{\LARGE A}}{(-1~~,~~0)} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{1+x}{2}=-1\implies 1+x=-2\implies \boxed{x=-3} \\\\\\ \cfrac{2+y}{2}=0\implies 2+y=0\implies \boxed{y=-2}[/tex]

Answer:

93

Step-by-step explanation:

first you add 30 and 57

where you will get 87

then subtract 87 from 180 and get 93

Answer:

Mass is the property of a body that measure its inertia. It is taken as the measure of the amount of material it contains and have weight in gravitational field

Mass is also refers as the weight of an object. It is measured in grams (g) and kilograms (kg)

Radius of an object is defined as a straight line from the centre of a circular object to the circumference of the circular object

According to the data given of five planets  

(a) The planet which has greatest mass is Mars that is 6.42 x 1023 kg

Radius of a given object can be calculated by dividing the diameter of the given object by 2.

(b) Radius of the mercury = Diameter given in kilometers / 2

                                          = 4.88 × 10³ / 2

                                          = 2.44 x 103 km

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Answer:

[tex]\frac{3}{x-1}+\frac{2}{x+1}=\frac{5}{x}[/tex]

Answer: 16. f(1)=-2

17. f(-3)=1

18. x=0

19. x=-1 and x=1

Step-by-step explanation:

16. f(1)=-2

17. f(-3)=1

18. f(x)=-3

x=0 ==> f(0)=-3

19. f(x)=-2

x=-1 and x=1 ==> f(-1)=-2, f(1)=-2

The integers are 14 and 16.

Let the integers be represented by x and x+2.

It was stated that the consecutive even integers such that 6 times the smaller integer is 36 more than 3 times the larger integer.

This will be:

6(x) = 3(x + 2) + 36

6x = 3x + 6 + 36

6x = 3x + 42

6x - 3x = 32

3x = 42

Divide

3x/3 = 42/3

x = 14.

The larger number will be:

= x + 2

= 14 + 2

= 16

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Answer:

39

Step-by-step explanation:

[tex]{ \blue{ \mathfrak{39}}}[/tex]

Step-by-step explanation:

[tex]{ \red{ \tt{ \frac{12}{3} }}} \times ({ \green{ \tt{15 - 6}}}) + { \red{ \tt{3}}}[/tex]

[tex]{ \red{ \tt{4}}} \times { \green{ \tt{9}}} \: + \: { \red{ \tt{3}}}[/tex]

[tex]{ \red{ \tt{36}}} + { \red{ \tt{3}}}[/tex]

[tex] = { \purple{ \mathfrak{39}}}[/tex]

When Mr. Johnson earns $5.40 an hour. One week, he worked 40 hours and 2 hours overtime, If he is paid time and one-half for overtime then the total amount he earned is $232.2

Given,

The amount he earns in an hour = $5.40

Total number of hours he worked =40 hours

The amount he earns = 5.40×40 = $216

Overtime hours = 2 hours

Overtime payment per hour= 5.40×1.5= $8.1

The amount he earns for overtime = 2×8.1= $16.2

The total amount he earned = 216+16.2= $232.2

Hence, when Mr. Johnson earns $5.40 an hour. One week, he worked 40 hours and 2 hours overtime, If he is paid time and one-half for overtime then the total amount he earned is $232.2

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Answer: a=1/2=0.5

Step-by-step explanation:

7(a)=a+3

Subtract a from both sides.

7a−a=3

Combine 7a and −a to get 6a.

6a=3

Divide both sides by 6.

a= 63

​Reduce the fraction  

63

​to lowest terms by extracting and canceling out 3.

a= 21

12% of  students are enrolled in less than three courses and taking a math course

For given question,

50% of students are enrolled in less than three courses and 33% of students are taking a math class.

The probability that the students are enrolled in less than three courses is 0.5

P(A) = 0.5

The probability that the students are taking a math class is 0.33

P(B) = 0.33

if 71% of students are either enrolled in less than three courses or taking a math course.

P(A ∪ B) = 0.71

We need to find the percentage of students that are enrolled in less than three courses and taking a math course.

i.e., we need to find P(A ∩ B)

We know that, P(A ∪ B) = P(A) + P(B) - P(A ∩ B)

P(A ∩ B) = 0.5 + 0.33 - 0.71

P(A ∩ B) = 0.12

So, 12% of  students are enrolled in less than three courses and taking a math course.

Therefore, 12% of students are enrolled in less than three courses and taking a math course.

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Maria's capital gain is 55.2%.

Here, we are given that Maria purchased 1,000 shares of stock for $35.50 per share in 2003.

Thus, the total cost price of these shares = 1000 × 35.5

= $35500

In 2007, she sold all of the stocks for $55.10 per share

Thus, the total selling price of these shares = 1000 × 55.1

= $55100

Now, absolute gain = selling price - cost price

Here, Maria's absolute gain will be-

= 55100 - 35500

= 19600

Now, her percentage gain will be given by-

Gain % = absolute gain/ initial value × 100

= 19600/35500 × 100

= 55.2

Thus, Maria's capital gain is 55.2%.

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Answer:

so it goes 11,22,33,44,55,66,77,88,99!

Step-by-step explanation:

Not that hard you're welcome kings and queens have a nice day

Answer:

a) EF

c) DF

a) DG

a) DE EF

Step-by-step explanation:

Answer:

the length of one side of square is 3

Juan multiplied the bases together, and added the power together, therefore, his solution is wrong.

Power is the result of multiplying same number for n number of times. Power is typically expressed by a base number and an exponent. The base number indicates the number being multiplied. The exponent, which is a little number printed above and to the right of the base number, indicates the number of times the base number is multiplied.

The correct solution,

3² ∙ 9⁴

= 3² ∙ (3²)⁴

= 3²  ∙ 3⁸

= 3¹⁰

Hence, Juan multiplied the bases together, and added the power together, therefore, his solution is wrong.

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Answer:

i don't know the answer!!

Answer:

The area will decrease by 9%.

Step-by-step explanation:

The area of a rectange is given by the formula below.

[tex]\boxed{\text{Area of rectangle}= \text{length}×\text{width}}[/tex]

Let the original length and width of the rectangle be L and W respectively.

Start by finding the original area:

Original dimensions

Length= L= 100%L

Width= W= 100%W

Original area= LW

Let's find the dimensions of the new rectangle in terms of L and W.

New dimensions

Length= (100% +30%)L= 130%L

Width= (100%-30%)W= 70%W

New area

[tex] = \frac{130}{100} L \times \frac{70}{100} W[/tex]

[tex] = \frac{91}{100} LW[/tex]

= 91% LW

Comparing the new area with the original area:

100% LW- 91% LW= 9% LW

∴ The area will decrease by 9%.

*Note that percentage is equivalent to dividing a number by 100.

rise: 1 run: 2

slope: 1/2

you can start from any point on the slope. if i picked point (-5,0) i go up 1 square and right 2 squares to get to point (-3, 0). thats basically the rise and run, and the slope is always rise over run

Answer:

(k + 4) (7k + 3)

k(7k + 3) + 4(7k + 3)

7k² + 3k + 4(7k + 3)

7k² + 3k + 28k + 12

7k²  + 3k + 28k + 12

7k² + 31k + 12

7k² + 31k + 12

The statements that are true about the graph of the system of linear inequalities include:

The graph of y > 3x − 4 has shading above a dashed line.

The graphs of the inequalities will intersect.

y means the shading will be above the corresponding line.

y means the shading will be below the corresponding line.

Together, the two graphs intersect the entire y-axis. Jointly, they only intersect the y-axis on the interval -4 < y < 1.

Therefore, the graph of y > 3x − 4 has shading above a dashed line and thee graphs of the inequalities will intersect.

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Answer:

A, C

Step-by-step explanation:

Which statements are true about the graph of the system of linear inequalities? Select two options.

y > 3x – 4

y < One-halfx + 1

The graph of y > 3x − 4 has shading above a dashed line.

The graph of y < One-halfx + 1 has shading below a dashed line.

The graphs of the inequalities will intersect.

There are no solutions to the system.

The graphs of the two inequalities intersect the y-axis at (0, 1) and (0, 4).

Edge 2022

Answer:

18000

Step-by-step explanation:

18 000, тому що якщо ви заробляєте 6 000 і маєте 2% дефектних деталей, помножте на 3, щоб отримати 6% дефектних деталей, які дають вам 18 000

The required information is (B), (C), (D), and (I).

So,

A. Who paid for the survey? It is not required.

B. Who made up the population from which the sample was drawn? Needed.

We need to know if the sample is representative of the "college students" population, on which we are basing our conclusions.

C. What sampling strategy was used? Needed.

We want to know if the sample was chosen at random.

D. How large was the sample size? Needed.

This information is required to determine the accuracy of the results.

E. What are the colleges represented in the sample?

It's not necessary if we already know "B."

F. How many survey questions were there? It is not required.

G. How many people participated in the survey? It is not required.

H. What were the questions? It is not required.

I. Is the language in the questions clear, accurate, unbiased, and valid? Needed.

We want to know if the answer was unbiased and clear so that we can determine if the conclusions are also unbiased.

J. What day of the week was the survey held? It is not required.

Therefore, the required information is B, C, D, and I.

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The correct question is given below:

A survey indicates that the vast majority of college students own their own personal computers. What information would you want to know before you accepted the results of this​ survey? Select all that apply. A. Who funded the​ survey? B. What was the population from which the sample was​ selected? C. What sampling design was​ used? D. What was the sample​ size? E. What are the names of the colleges included in the​ sample? F. How many questions were asked in the​ survey? G. How many people conducted the​ survey? H. What questions were​ asked? I. Were the questions​ clear, accurate,​ unbiased, and​ valid? J. On what day of the week was the survey​ conducted? g