Solve using any method. All work must be shown and handwritten.
3x-y=-10
x+y=-2
show how it is solved please <3

Hi there!

[tex]f(x)+f(x+1)=4f(x)[/tex]

There are 3 parts to this equation:

f(x)

f(x+1)

4f(x)

We must first determine these three parts separately.

1) f(x)

We're given that  [tex]f(x)=3^x[/tex]:

⇒ [tex]f(x)=3^x[/tex]:

2) f(x+1)

Now, we must find f(x+1). To do so, add 1 to x in the original function [tex]f(x)=3^x[/tex]:

⇒ [tex]f(x+1)=3^x^+^1[/tex]

3) 4f(x)

To find 4f(x), multiply the original function [tex]f(x)=3^x[/tex] by 4:

[tex]4f(x)=4*3^x[/tex]:

4) Put it all together

Now, plug each of the three parts into the equation [tex]f(x)+f(x+1)=4f(x)[/tex]:

[tex]f(x)+f(x+1)=4f(x)[/tex]

[tex]3^x+3^x^+^1=4*3^x\\3^x+3^x*3=4*3^x[/tex]

Factor the left side

[tex]3^x*(1+3)=4*3^x[/tex]

Divide both sides by 3^x

[tex]1+3=4\\4=4[/tex]

Because this equation is true, [tex]f(x)+f(x+1)=4f(x)[/tex] is therefore true.

I hope this helps!

Answer:

2^7

Step-by-step explanation:

2 * 2^3 *8

Rewriting 8

8 = 2^3

2 * 2^3 * 2^3

We know that a^b * a^c = a^(b+c)

2^1 * 2^3*2^3

2^(1+3+3)

2^7

Answer:

four lines axes of symmetry does a square have

Hope this helps you. Thank you....

Using the reflection concept, it is found that the function g is given by:

[tex]g(x) = |6x| - 2[/tex]

-------------------

-------------------

Reflecting over the x-axis:

[tex]g(x) = f(-x)[/tex]

[tex]g(x) = |6(-x)| - 2[/tex]

[tex]g(x) = |-6x| - 2[/tex]

Modulus is an even function, thus [tex]|-6x| = |6x|[/tex], and:

[tex]g(x) = |6x| - 2[/tex]

For more on reflections over the y-axis, you can check https://brainly.com/question/17686579

Answer:

Neither

Step-by-step explanation:

Answer:

1/3

a dice has 6 sides and the probability of getting 4 or 5 is just 2/6 which simplifies to 1/3

Answer:

38

Step-by-step explanation:

nAuB=nA+nB-nA∩B. take nA as x

now substitute

59=x+33-12

59=x+21

x=59-21

x=38

Answer:

Step-by-step explanation:

0.919191....It can be represented as a fraction. You can always make repeating decimals into fractions.

It does not terminate. 91 will go on forever. It's a repeating decimal

We don't know what the second one does. You are likely not supposed to say it repeats; it certainly does not terminate. It cannot be made into a fraction.

0.555 This terminates. It can be written as a fraction.

It can be written as a fraction. It repeats. It contains a repeating decimal which can always be written as a fraction.

Answer:

Cost = $1 + $0.41x

Step-by-step explanation

Angle B is 90 degrees so angle A and c when added also equal 90:

7x + 8 + 3x + 2 = 90

Simplify:

10x + 10 = 90

Subtract 10 from both sides

10x = 80

Divide both sides by 10

X = 8

Now you have x calculate angle A:

7x + 8 = 7(8) + 8 = 56 + 8 = 64

Answer: C. 64

Answer:

C

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180° , so

7x + 8 + 3x + 2 + 90 = 180 , that is

10x + 100 = 180 ( subtract 100 from both sides )

10x = 80 ( divide both sides by 10 )

x = 8

Then

∠ A = 7x + 8 = 7(8) + 8 = 56 + 8 = 64° → C

A negative value is when money is taken out ( withdrawal). A positive value is when money is added to the account(deposit)

-10.40 is a withdrawal

8.50 is a deposit

Answer:

Hint :- Withdrawal is denoted as the -ve sign and deposit are denoted by the +ve sign. This is because if we deposit money then the money increase and if we withdraw then the money decreases.

-10.40

See there is a negative sign. This means it is a withdrawal

8.50

See there is a positive sign. This means it is a deposit

Answer:

-2, 2

Step-by-step explanation:

Answer:

42.395

Step-by-step explanation:

The Sequence:

1 , 1+2 , 1+2+3 , 1+2+3+4, ...

here, every term is an AP. finding the general formula for the sum of the elements of each term is:

Sₙ = [tex]\frac{x}{2}(2a + (x-1)d)[/tex]        [where x = number of term, a = first term and d = common difference]

here, the first term is always 1 and so is the common difference.

Sₙ = [tex]\frac{x}{2}(2 +x-1)[/tex]

Sₙ = [tex]\frac{x}{2}(1 +x)[/tex] = [tex]\frac{1}{2}(x + x^{2})[/tex]

which is the formula for a general term in our series

now, we need to find the sum of the first n terms of this series

[tex]\displaystyle\sum_{x=1}^{n} [\frac{1}{2}(x + x^{2})][/tex]

[tex]\displaystyle\frac{1}{2} [\sum_{x=1}^{n} (x) + \sum_{x=1}^{n}(x^{2})][/tex]

in this formula, for the first term, it's just an AP from x = 1 to x = n

for the second term, we have a general formula [tex]\frac{n(n+1)(2n+1)}{6}[/tex]

[tex]\frac{1}{2}[\frac{n}{2}(2a + (n-1)d)+ \frac{n(n+1)(2n+1)}{6} ][/tex]

in this AP (first term), the first term and the common difference is 1 as well

[tex]\frac{1}{2}[\frac{n}{2}(2 + n-1)+ \frac{n(n+1)(2n+1)}{6} ][/tex]

[tex]\frac{1}{2}[\frac{n}{2}(n+1)+ \frac{n(n+1)(2n+1)}{6} ][/tex]

[tex][\frac{n}{4}(n+1)+ \frac{n(n+1)(2n+1)}{12} ][/tex]

[tex]\frac{n}{4}(n+1) [1+\frac{(2n+1)}{3} ][/tex]

[tex]\frac{n}{4}(n+1) [\frac{(3+2n+1)}{3} ][/tex]

[tex]\frac{n}{4}(n+1) [\frac{(2n+4)}{3} ][/tex]

[tex]\frac{n}{2}(n+1) [\frac{(n+2)}{3} ][/tex]

[tex]\frac{n(n+1)(n+2)}{6}[/tex]

which is the sum of n terms of the given sequence

USE (m a t h w a y) its real easy to use

Step-by-step explanation:

Answer:

21x4 + 8x3 - 40x2 + 15

Step-by-step explanation:

expand using distributive property.

Answer:

-5

Step-by-step explanation:

− 11 − ( − 6)

= -11 + 6

= -5

Answer:

-5

Step-by-step explanation:

-11-(-6)

-11--6

NB: --=+

-11+6

-5

Therefore, the answer is -5.

Answer:

vdffdersewsesdfdresweseseseeerswesdsfd

Step-by-step explanation:

reterersesdvbvfdderereerereeeewwqwewereddddscdcvvbvfddewww

9514 1404 393

Answer:

Step-by-step explanation:

The given expression says ...

  [tex]t_n+1=3\\\\t_n=2\qquad\text{for any value of n}\\\\t_2=2\\\\t_3=2[/tex]

Answer:

[tex]here \: tn + 1 = 3 \\ tn = 2 \\ put \: n = 1 \\ t1 = 2 \\ n = 2 \\ t2 = 2 \\ n = 3 \\ t3 = 2 \\ for \: all \: n \: values \: = 2 \\ thank \: you[/tex]

Hi! I'm happy to help!

To solve this problem, we need to find out what part isn't already listed.

We know that The entire line (SQ) is 80, and the part of the line that isn't RS (QR) is 33.4. The rest of the line must be the difference between 80, and 33.4. To find the difference we use subtraction:

80-33.4

44.6

So, RS is 44.6

I hope this was helpful, keep learning! :D

The calculated length of the segment RS is 46.6

From the question, we have the following parameters that can be used in our computation:

R is between Q and S.

QR = 33.4 and SQ = 80

using the above as a guide, we have the following:

QR + RS = QS

substitute the known values in the above equation, so, we have the following representation

33.4 + RS = 80

So, we have

RS = 80- 33.4

Evaluate

RS = 46.6

Hence. the length of the segment RS is 46.6

Read more about side lengths at

https://brainly.com/question/29135476

#SPJ3

[tex]thank \: you[/tex]

Answer:

64 ivy stems

Step-by-step explanation:

72 ivy stems / 18 centerpieces = 4 ivy stems / 1 centerpiece

Create an equation with x being the amount of ivy stems needed.

x / 16 = 4

x = 64

Answer:

The proof of Pythagorean Theorem in mathematics is very important. In a right angle, the square of the hypotenuse is equal to the sum of the squares of the other two sides. States that in a right triangle that, the square of a (a²) plus the square of b (b²) is equal to the square of c (c²).

Step-by-step explanation:

[tex]thank \: you[/tex]

Answer:

[tex] \frac{3}{4} x + \frac{4}{7} y = \frac{5}{4} x - 1 \\ \frac{4}{7} y = \frac{5}{4} x - 1 - \frac{3}{4} x \\ \\ \frac{4}{7} y = \frac{5x - 4 - 3x}{4} \\ \frac{4}{7} y = \frac{2x - 4}{4} \\ \\ y = \frac{2x - 4}{4} \div \frac{4}{7} \\ y = \frac{2x - 4}{4} \times \frac{7}{4} \\ \\ y = \frac{14x - 28}{16} \\ \\ y = \frac{14x}{16} - \frac{28}{16} [/tex]

I hope I helped you^_^

Answer:

Answer is $4145.6

Step-by-step explanation:

formular for compound interest:

[tex]{ \bf{A = P( \frac{r}{100} + 1) {}^{n} }}[/tex]

P is the principle, P = $4000

r is rate, r = 1.2%

n is period, n = 3 years

A is the accumulative amount.

substitute:

[tex]{ \sf{A = 4000( \frac{1.2}{100} + 1) {}^{3} }} \\ \\ { \sf{A = 4000 \times 1.0364}} \\ { \sf{A = 4145.6 \: dollars}}[/tex]