The composite bar chart Messages received shows the number of messages Tim received each day for five days.
a) How many texts did Tim receive on Monday?
b) How many emails did Tim receive on Thursday?
c) In total, what fraction of the messages were emails?
Give your answer in its simplest form.

The Composite Bar Chart Messages Received Shows The Number Of Messages Tim Received Each Day For Five

Answers

Answer 1

We need to know about a composite bar chart to solve the question. The answer for (a) is Tim received 8 texts on Monday, (b) Tim received 4 emails on Thursday and (c) 0.52 of the messages were emails.

A composite bar chart is used when there are two sets of data that are connected and their frequencies are combined.In this question there are two sets of data emails and texts but both of them belong to the same category which is messages. For question (a) we can easily say from the diagram that the number of texts Tim received on Monday is 8.

For question (b) we need to find out the number of emails Tim received on Thursday, for this we have to look at the bar for Thursday and subtract the number of texts received from total number of messages to get the number of emails received that means, 15-11=4, so Tim received 4 emails on Thursday.

For question (c) we need to find the total number of messages received by Tim for five days, total number of emails received and then calculate the fraction of emails out of messages.

Total number of messages=14+16+14+15+14=73

Total number of emails=6+10+10+4+8=38

Fraction of emails over messages=[tex]\frac{38}{73}[/tex]=0.52

Thus 0.52 of the messages were emails.

We analysed the composite bar chart to find out the answers of the three questions, Tim received 8 texts on Monday,4 emails on Thursday and 0.52 of the messages were emails.

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Answer 2

Answer:

a= 5

b= 7

c=

Step-by-step explanation:


Related Questions

Multiple Choice
11) The intersection of 2 line segments can be
I.
a point
II. a line segment
a ray
IV.
a line
III.
A. I only
C. I and IV
12) The intersection of 2 distinct rays can be
I. a point
II. a line segment
III. a ray
IV. a line
A. I only
C. I, II and III
B. I and II
D. all of the above
I. a point
III. a ray
13) The intersection of 2 distinct lines can be
II. a line segment
IV. a line
A. I only
C. I, III and IV
B. IV only
D. all of the above
B. IV only
D. all of the above

Answers

Step-by-step explanation:

[tex](3 \sqrt{3 - 2 \sqrt{2)(3 \sqrt{3 - 2 \sqrt{2)} } } } [/tex]

6c3c² +d³ for c = 5 and d = 3

Answers

Answer:

6(5)3(5)² + (3)³

Step-by-step explanation:

Put this into your calculator just like this

Hector earns $12 an hour plus a daily per diem of $15. This week he worked 4 days and earned a total of $444. Write an equation to find how many hours Hector worked this week.

Answers

The number of hours Hector worked this week is 32 hours.

Equation to find how many hours Hector worked this week.Amount Hector earned per hour = $12Additional amount earned daily = $15Number of days Hector worked this week = 4 Total amount Hector earned = $444Number of hours worked = x

444 = 15(4) + 12(x)

open parenthesis

444 = 60 + 12x

substract 60 from both sides

444 - 60 = 12x

384 = 12x

divide both sides by 12

x = 384/12

x = 32 hours

check:

444 = 60 + 12x

444 = 60 + 12(32)

444 = 60 + 384

444 = 444

Therefore, the number of hours Hector worked this week is 32 hours.

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3
Un camión está cargado con 10 pies cúbicos de pajote. El chofer entrega 25
C
3
pies cúbicos de pajote en la primera parada y 3 pies cúbicos de pajote en la
segunda parada. En la tercera parada recoge 11½ pies cúbicos de pajote que no
quiere el cliente. ¿Cuánto pajote queda en el camión después de la tercera
parada?

Answers

Answer is 140

According to the question,

Given that,

111 + 10 + 25 - 2 × 3

calculate the term

121 + 25 - 6

121 + 19

140

Una solicitud de licencia de manejar comercial

(DL 44C). Al firmar este formulario significa

que usted se compromete a hacerse un análisis

químico para determinar el contenido de alcohol

o drogas en su sangre. Si se niega a firmarlo, el

Departmento de Vehículos Motorizados (DMV)

no expedirá o renovará su licencia de manejar.

• Su nombre verdadero y completo.

• Un reporte de examen médico aprobado Medical Examination Report (MER). El formulario

federal válido (orginal o copia) del reporte del

examen médico Medical Examination Report

(MER) (MCSA-5875) y el formulario del certificado del examinador médico Medical Examiner’s Certificate Form (MEC) MCSA-5876

al solicitar la licencia de manejar o el permiso;

tal reporte debe ser expedido por un doctor en

los Estados Unidos que esté licenciado en medicina (M.D.), un doctor licenciado en osteopatía

(D.O.), un médico asistente con licencia (P.A.),

un enfermero practicante avanzado y registrado

(APN) o un doctor quiropráctico autorizado. Los

conductores que tengan certificados para manejar autobuses escolares, autobuses de actividades

estudiantiles School Pupil Activity Bus Certificate (SPAB), autobuses de jóvenes, vehículos

paratránsito para el público en general General

Public Paratransit Vehicle (GPPV) o co certificados para manejar vehículos de labores agrícolas

deben tener un examen médico expedido por

un doctor en medicina, un médico asistente con

licencia, un enfermero practicante avanzado y

registrado o un quiropráctico que esté autorizado en el registro nacional de examinadores médicos certificados National Registry of Certified

Medical Examiners (§12517.2 del CVC).

Se requiere un reporte médico fechado en los 2

últimos años para cualquier tipo de solicitud de

licencia CDL y luego cada 2 años.

Nota: No envíe por correo su reporte médico

a la patrulla de caminos California Highway

Patrol (CHP). El formulario MER y el formulario

del certificado MEC pueden presentarse en una

oficina del DMV o ser enviados por correo directamente al DMV para actualizarlos. Envíe por

correo sus formularios MER y MEC a la siguientedirección por lo menos 4 semanas antes que se

venza su reporte médico anterior o su privilegio

para manejar vehículos CMV puede invalidarse.

Envíe el reporte médico a:

Department of Motor Vehicles

CDL/PDPS Unit, MS G204

PO Box 942890

Sacramento, CA 94290-0001

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Square root 3 x square root 2 x square root 5

Answers

Answer:

=sqrt of 30

Step-by-step explanation:

=sqrt of 3×2×5

=sqrt 30

A sequence starting with 0 but each number is two times three less than the previous number

Answers

The sequence starting with 0 but each number is two times three less than the previous number is as follows:

0, -6, -12, -18, -22

How to find sequence?

A sequence is defined as an arrangement of numbers in a particular order.

The most common sequence are the arithmetic and the geometric sequence.

The sequence starts with 0 but each number is two times three less than the previous number.

This means the first term of the sequence is 3.

Hence,

2 times 3 less than the previous number means:

Aₙ = Aₙ₋₁ - 2(3)

where,

n = number of terms

Let's use the formula to find the other numbers in the sequence,

A₂ = A₂₋₁ - 2(3) = 0 - 6 = -6

A₃ = A₃₋₁ - 2(3) = -6 - 6 = -12

A₄ = A₄₋₁ - 2(3) = -12 - 6 = - 18

A₅ = A₅₋₁ - 2(3) = -18 - 6 = - 22

Therefore, the sequence starting with 0 but each number is two times three less than the previous number is as follows:

0, -6, -12, -18, -22

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XZ is the perpendicular bisector of segment WY. WY = 64. Solve for k. Enter a NUMBER only.

Answers

2(6k+2)=64

12k+4=64

12k=60

k=5

Two ships A and B take off at the same time from the same spot at a harbour. Ship A travels west with a speed of 40 km/h, while ship B travels north at a speed of 50 km/h. Determine, to the nearest integer, how fast the distance between the ships is increasing when they are 0.5 hours away from the harbour. Use the units as given in the question but write down only the numerical value of your answer without the unit.

Answers

Using the Pythagorean Theorem and implicit differentiation, it is found that the distance between them is increasing at a rate of 2050 km/h when they are 0.5 hours away from the harbor.

What is the Pythagorean Theorem?

The Pythagorean Theorem relates the length of the legs [tex]l_1[/tex] and [tex]l_2[/tex] of a right triangle with the length of the hypotenuse h, according to the following equation:

[tex]h^2 = l_1^2 + l_2^2[/tex]

For this problem, we have that since the ships are moving west and north, the distance between them as a function of the time will be given by the hypotenuse of a right triangle, as follows:

d² = x² + y².

In which;

x is the position of Ship A(moving horizontally).y is the position of Ship B(moving vertically).

Applying implicit differentiation, the rate of change of the position is given as follows:

[tex]2\frac{dd}{dt} = 2x\frac{dx}{dt} + 2y\frac{dy}{dt}[/tex]

[tex]\frac{dd}{dt} = x\frac{dx}{dt} + y\frac{dy}{dt}[/tex]

From the velocities, we have that:

[tex]\frac{dx}{dt} = 40, \frac{dy}{dt} = 50[/tex]

From the velocities, and the time of half an hour, the positions are given as follows:

x = 0.5 x 40 = 20, y = 0.5 x 50 = 25.

Hence:

[tex]\frac{dd}{dt} = x\frac{dx}{dt} + y\frac{dy}{dt}[/tex]

[tex]\frac{dd}{dt} = 20(40) + 25(50)[/tex]

dd/dt = 2050.

The distance between them is increasing at a rate of 2050 km/h when they are 0.5 hours away from the harbor.

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Abby knows that 1 mile is about 1.61 kilometers. She wants to write an equation she can use to convert
any given distance in miles (m) to kilometers (k).
How should Abby write her equation?

Answers

Abby should write her equation as k = 1.61m.

The correct option is B.

What is an equation?

A pair of algebraic equations with the equal symbol (=) in the center and the same value are referred to as an equation.

Given:

Abby knows that 1 mile is about 1.61 kilometers.

To write an equation, which she can use to convert any given distance in miles (m) to kilometers (k):

Let m be the total number of miles and k be the kilometers.

So, the equation is,

k = 1.61m

Where 1.61 is multiplied by m.

Therefore, the equation is k = 1.61m.

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The numbers of students in the 8 schools in a district are given below.
(Note that these are already ordered from least to greatest.)
185, 235, 255, 266, 269, 303, 370, 381
Send data to calculator
Suppose that the number 381 from this list changes to 237. Answer the following.
(a) What happens to the median?
(b) What happens to the mean?
O It decreases by 0
O It increases by 0
O It stays the same.
O It decreases by 0
O It increases by 0
O It stays the same.

Answers

Part (a)

The middle values were nitially 266 and 269, but now they are 255 and 266. Thus, the median changes from 267.5 to 260.5, meaning it decreases by 7.

Part (b)

The sum before the change is 2264, but after, it is 2120. This means the sum decreased by 144, and thus the mean decreased by 16.

Please help me with 1-4. I will give an Brainly and a bunch of extra points.

Answers

Answer: 1. {a, b, c, d, e}

2. {a, b, d}

3. {c, f, g, h}

4. {a, c}

Step-by-step explanation:

1. AUC ==> Means take all parameters from A and C.

A+C=

{a, b, c, d}+{a, e}={a, b, c, d, e}

2. B∩A ==> Means take the common parameters from B and A

B: {b, e, a, d}

A: {a, b, c, d}

Both B and A have a, b, and d.

So answer is {a, b, d}.

3. B' is every parameter that isn't in B

Reminder: B={b, e, a, d}.

All parameters: {a, b, c, d, e, f, g, h}

Remaining Parameters(B'): {c, f, g, h}

4. A-B∩C'

First, let's find C'.

C' is every parameter that isn't in C.

Reminder: C={a, e}

All parameters: {a, b, c, d, e, f, g, h}

Remaining Parameters(C'): {b, c, d, f, g, h}

Then lets find B∩C'

B: {b, e, a, d}

C': {b, c, d, f, g, h}

Both B and C' have b and d, so B∩C' is {b, d}

A-{b, d}=

{a, b, c, d}-{b, d}={a, c} ==> Answer for 4

Answer:

[tex]\sf 1) \quad \sf A \cup C = \{a, b, c, d, e\}[/tex]

[tex]\sf 2) \quad B \cap A = \{a, b, d\}[/tex]

[tex]\sf 3) \quad B' = \{c, f, g, h \}[/tex]

[tex]\sf 4) \quad A -(B \cap C') = \{a, c \}[/tex]

Step-by-step explanation:

Set Notation

[tex]\begin{array}{|c|c|l|} \cline{1-3} \sf Symbol & \sf N\:\!ame & \sf Meaning \\\cline{1-3} \{ \: \} & \sf Set & \sf A\:collection\:of\:elements\\\cline{1-3} \cup & \sf Union & \sf A \cup B=elements\:in\:A\:or\:B\:(or\:both)}\\\cline{1-3} \cap & \sf Intersection & \sf A \cap B=elements\: in \:both\: A \:and \:B} \\\cline{1-3} \sf ' \:or\: ^c & \sf Complement & \sf A'=elements\: not\: in\: A \\\cline{1-3} \sf - & \sf Difference & \sf A-B=elements \:in \:A \:but\: not\: in \:B}\\\cline{1-3} \end{array}[/tex]

Given sets:

U = {a, b, c, d, e, f, g, h}A = {a, b, c, d}B = {b, e, a, d}C = {a, e}

Therefore:

Universal set = {a, b, c, d, e, f, g, h}B' = not in B = {c, f, g, h}C' = not in C = {b, c, d, f, g, h}

Question 1

[tex]\begin{aligned}\sf A \cup C & = \sf \{a, b, c, d\} \cup \{a,e\}\\& = \sf \{a, b, c, d, e\}\end{aligned}[/tex]

Question 2

[tex]\begin{aligned}\sf B \cap A & = \sf \{b, e, a, d\} \cap \{a, b, c, d\}\\& = \sf \{a, b, d\}\end{aligned}[/tex]

Question 3

[tex]\begin{aligned}\sf B' & = \rm U - \sf B\\& = \sf \{a, b, c, d, e, f, g, h \}-\{b, e, a, d\}\\& = \sf \{c, f, g, h \}\end{aligned}[/tex]

Question 4

[tex]\begin{aligned}\sf A -(B \cap C') & = \sf \{a, b, c, d \}- \left( \{b, e, a, d \} \cap \{b, c, d, f, g, h \} \right)\\& = \sf \{a, b, c, d \}- \{b, d \} \\& = \sf \{a, c \}\end{aligned}[/tex]

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what are all values of x such that 1-2/3x<=-3 is satisfied

Answers

The possible values of x will belong to the set A = [9, ∞).

We have the following inequality -

1 - 2x/3 ≤ -3

We have to determine all values of x.

What is Inequality ?

An inequality is a relation which makes a non-equal comparison between two numbers or other mathematical expressions.

According to the question, we have the following inequality -

1 - 2x/3 ≤ -3

Subtract 1 from both sides -

-2x/3 ≤ -4

Multiply by -1 on both sides -

2x/3 ≥ 4

Multiply by 3/2 on both sides -

x ≥ 9

Hence, the possible values of x will belong to the set A = [9, ∞).

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By rounding to 1 significant figure, estimate the answers to these questions: 476 × 2354

Answers

answer:

1,120,504

Step-by-step explanation:

I don't really have one but I'm sure

To get to 1, divide 60 by
From 1, multiply by
OR, in a single step, multiply 60 by
to get to 25.
to get to 25. Submit Answer

Answers

To get to 1 we have to divide 60 by 60, and to get 25 we have to multiply 60 with 5/12 or 0.41.

Given that we have to get 1 by dividing 60 by something and multiply 60 by something to get 25.

We are required to find those numbers.

Take first result:

Suppose the number which divides 60 be x.

So,

60/x=1

x=60

Number will be 60.

Take second result:

Suppose the number which multiplied with 60 to get 25 be y.

So,

60*y=25

y=25/60

y=0.41

Number will be 0.41.

Hence to get to 1 we have to divide 60 by 60, and to get 25 we have to multiply 60 with 5/12 or 0.41.

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What inequality represents all the values of x for y <

-5(x - 8) - 2 when y = 7?

Answers

Answer:

(−∞, 31/5) or x <31/5 (the graph will start a little bit past 6 and will be a open circle and head to the left)

Answer:

x< 6[tex]\frac{1}{5}[/tex]

Step-by-step explanation:

7<-5(x -8) - 2  Distribute the 5

7<-5x + 40 - 2

7<-5x +38  Subtract 38 from both sides

-31<-5x  Divide both sides by -5

[tex]\frac{31}{5}[/tex] >x  When you divide both sides by a negative number, you must flip the sign.

or

x < 6 [tex]\frac{1}{5}[/tex]

Find the slope-intercept form of the line through (−1,3) and (7,−8)

Answers

Answer:

[tex]\sf y =\dfrac{-11}{8}x +\dfrac{13}{8}[/tex]

Step-by-step explanation:

Slope-intercept form:  y = mx + b

Here, m is the slope and b is the y-intercept.

( -1, 3) ;  x₁ = -1  & y₁ = 3

(7, -8) ; x₂ = 7 & y₂ = -8

Slope can be obtained by the formula:

    [tex]\sf \boxed{\bf Slope = \dfrac{y_2-y_1}{x_2-x_1}}[/tex]

                [tex]\sf =\dfrac{-8-3}{7-[-1]}\\\\\\=\dfrac{-8-3}{7+1}\\\\\\=\dfrac{-11}{8}[/tex]

Now, we can find the y-intercept,

[tex]\sf y = \dfrac{-11}{8}x + b\\\\Substitute \ any \ one \ of \ the \ point \ in \ the \ above \ equation.\\\\\text{Here, we are substituting (-1 ,3)}\\\\3 = \dfrac{-11}{8}*(-1) + b\\\\3 = \dfrac{11}{8}+b\\\\b = 3 - \dfrac{11}{8}\\\\b = \dfrac{3*8}{1*8}-\dfrac{11}{8}\\\\b= \dfrac{24-11}{8}\\\\b= \dfrac{13}{8}[/tex]

Slope-intercept form:

          [tex]\sf y =\dfrac{-11}{8}x +\dfrac{13}{8}[/tex]

                   

     

You decide you need a new computer. The cost of the computer is $864. However, the store also offers a rent to own option which will cost $41 per week for 24 weeksHow much more will the rent to own option cost after you have made all of the payments?

Answers

Answer:

120

Step-by-step explanation:

the difference = 24×41-864=120

If DE = 4x + 10, EF = 2x-1, and DF = 9x-15, find DF

Answers

The measure of segment DF from the given question is 21

Addition postulate

In line geometry, a line is the distance between two points while an angle is the point where two lines intersect.

Given the following parameters

DE = 4x + 10, EF = 2x-1, and DF = 9x-15,

Required

DF

Using the addition postulate

DE + EF = DF

Substitute

4x+10 + 2x -1= 9x - 15

6x + 11 = 9x - 1

6x - 9x =  -1 - 1

-3x = -12

x = 12/3

x = 4

For DF

DF =  9(4) - 15

DF = 21

Hence the measure of segment DF from the given question is 21

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You have 8 times as many dimes as nickles. You have 18 dimes and nickles altogether. How much money do you have in all?

Answers

Answer:

$1

Step-by-step explanation:

If you have x dimes, you have 8x nickels.

So, this means x + 8x = 18.

9x = 18 (combine like terms)x = 2 (divide both sides by 2)

This means you have 2 dimes and 16 nickels, which have a combined value of 2(0.10)+16(0.05)=$1.

the ice rink sold 95 tickets for a total of 828.00. general admission tickets are $10.00 each and youth tickets are $8.00 each. how many of each did they sell

Answers

Answer:

GA =34

Y = 61

Step-by-step explanation:

GA= GENERAL ADMISSION =$10

Y= YOUTH =$8

GA+Y= 95

GA=95-Y

10GA+8Y=828

10(95-Y)+8Y=828

950-10Y+8Y=828

-2Y= 122 MULTIPLY BY (-1)

2Y= 122

Y= 61

GA= 34

There were 61 youth tickets sold and 34 general admission tickets



After an accident, police can use the formula v=2/5L to estimate the speed, v, in miles per hour, that a car was traveling by measuring the length of the skid marks, L in feet. Estimate the speed of a car that left skid marks 69 ft long. If the posted speed limit is 35 mi/h, was the car speeding?

Answers

Answer: The car was not speeding. It went 27.6 mi/h.

Step-by-step explanation: The equation v=2/5L is given where v is measured in mi/h. L is measured in ft. Since we have the value 69 for L, we sub it into the equation. We end up getting 27.6 mi/h after evaluating.

Electric utility poles in the form of right cylinders are made out of wood that costs $13.72 per cubic foot. Calculate the cost of a utility pole with a radius of 0.75 ft and a height of 40 ft. Round your answer to the nearest cent.

Answers

Answer:

So what you have to do is go back to you lesson and read till you find an answer just like this one and read how to do it when u do that go back and to the quick check and find an answer that is similar. the reason why I'm telling you this is cause I cant calculate it right. or what you can do is calculate it right on here.

Step-by-step explanation:

https://www.inchcalculator.com/cubic-footage-calculator/

Write 0.45 kg in g, mg and ng

Answers

Answer:

450g

450,000mg

450,000,000,000ng

Explaination:

Kg to g (x1,000)

Kg to mg (x1,000,000)

kg to ng (x1,000,000,000,000)

In G is
450 g
I think that in mg it’s the same


The sum of two numbers is 4. Three times the larger number plus two times the smaller number is 26. Find the numbers.
The larger number is and the smaller number is

Answers

The larger integer number is 18 and the smaller integer number is -14.

Integers are the subset of Rational numbers which contains all numbers except fraction and decimals

Numbers are the building blocks of mathematics. Numbers are used to count ,measure or label quantities.

The different types of numbers are:

Real numbers: 89.26 , -847 , 4/5irrational numbers √2 ,√3 imaginary numbers (5 + 9i) Integers -89 , 65 , 45

Let the smaller number be x. The sum of the numbers is 4 .

So the larger number is 4 - x

Again given that sum of three times the larger number and 2 times the smaller number is 26.

∴3 ( 4-x )+ 2x = 26

or, 12 -3x +2 x = 26

or, -x = 26-12

or, x = -14

Therefore the larger number is 4-(-14)= 18

Hence the larger integer number is 18 and the smaller number is -14 .

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here are four lengths of wood ​

Answers

How am I supposed to answer

(3x-3)
(4y+4)°/60°
Solve for x and y. Explain.

Answers

The value of x and y is y=29, X=21.

180-60=120

4y+4=120 get y by itself and remember that what ever you do to one side you do to the other.

Alternate interior angles are congruent so 3x-3=60

What is an angle ?

Angle is the figure formed by two rays, called the sides of the angle, sharing a common endpoint, called the vertex of the angle. Angles formed by two rays lie in the plane that contains the rays. Angles are also formed by the intersection of two planes. These are called dihedral angles.

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Answer the following questions

WILL GIVE BRAINLIEST

Answers

yes to the first question, no to the bottom two.
1). Yes 2). No
Hope this helps

Points S, T, and P lie on a number line. Their coordinates
are 0, 1, and x, respectively. Given SP = PT, what is the value of x?

Answers

The value of x associated with the point P on a number line is 0.5.

How to find the locations of a point on a number line

In accordance with the statement, the condition SP = PT means that the locations of points S, T and P on the number line are 0, 1, x, so that S < P < T and that point P is equidistant of points S and T. Then, the location of the missing point is determined by the midpoint formula:

P = 0.5 · S + 0.5 · T

P = 0.5 · 0 + 0.5 · 1

P = x = 0.5

The value of x associated with the point P on a number line is 0.5.

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Question 5 of 10
This circle is centered at the origin, and the length of its radius is 10. What is
the circle's equation?
5+ 10.
O A ²+²=10
OB. +²2=100
O c. x10+10=100
O D. x+y=10

Answers

The equation of circle is [tex]x^2+y^2=100[/tex]

The standard equation of a circle with center (h, k) and radius r is given by:

[tex](x-h)^2+(y-k)^2=r^2[/tex] ........(1)

This is the equation needed for the circle with a center at A(h, k) and a radius equal to r since it describes the relationship between the coordinates of any point on the circumference.

Now according to the question, it is given that the circle has the center at origin and length of its radius is 10.

Center = (h, k)=(0, 0)

Radius(r) = 10 units

Now, substituting the given values in (1) we get;

⇒[tex]x^2+y^2=100[/tex]

Therefore, the equation of circle centered at origin with radius 10 is [tex]x^2+y^2=100[/tex]

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To make a sand sculpture Arthur used 2 cm³ of red sand with a density of 4 g/cm³ 7 cm³ of yellow sand with a density of 5 g centimeter and 5 cm³ of brown sand with a density of 6 g cubiccm³ what is the average density of the sculpture in grams per cubic centimeter express your answer as decimal to the nearest 10th.

Answers

Answer:

  5.2 g/cm³

Step-by-step explanation:

Given a sculpture consisting of 2 cm³ at 4 g/cm³, 7 cm³ at 5 g/cm³, and 5 cm³ at 6 g/cm³, you want its average density.

Mass

The total mass of the sculpture is the sum of the masses of the components. Each of those is the product of its volume and density.

  red sand: (2 cm³)(4 g/cm³) = 8 g

  yellow sand: (7 cm³)(5 g/cm³) = 35 g

  brown sand: (5 cm³)(6 g/cm³) = 30 g

The total mass of the sculpture is ...

  total mass = 8 g + 35 g + 30 g = 73 g

Volume

The total volume of the sculpture is the sum of the volumes of its parts:

  total volume = 2 cm³ +7 cm³ +5 cm³ = 14 cm³

Average density

The density is the ratio of mass to volume:

  ρ = (total mass)/(total volume) = (73 g)/(14 cm³) = 73/14 g/cm³

  = 5 3/14 g/cm³ ≈ 5.2 g/cm³

The average density of the sculpture is about 5.2 g/cm³.

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