The number 87 is NOT
an element of
which set?

Answer:

2/3

Step-by-step explanation:

1/6 + 3/6 = 4/6

4/6 = 2/3

Answer:

Step-by-step explanation:

I think it’s translation because your just sliding the figure

Answer:

$624,000

Step-by-step explanation:

100-4 = 96

96/100 = 0.96

650,000 x 0.96 = 624,000

= $624,000

Answer:

6. was Narbada alienated ...?

7. did Pratima make ...?

8. did Zayasha wander ...?

9. Did Sachin behave as if...?

10. did susan look ...?

12. do sarina and sazina jump ...? (plural noun)

13. Were ... and ... aghast to...?

Step-by-step explanation:

yes/ no question:

Past simple: Did + S + V-bare...?

Passive voice (Past simple): Was/ Were + S + V3/ed (past participle)

Answer:

675 ÷ 3 - ( 225 - 144)

675 ÷ 3 - (81)

225 - 81

144

I hope it's helps you

Answer:

[tex]675 \div 3 - (15 - 12) {}^{2} \\ \\ 675 \div 3 - (225 - 144) \\ \\ 675 \div 3 - 81 \\ \\ 225 - 81 \\ \\ = 144[/tex]

Answer:

[tex]\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}[/tex]

Answer:

Step-by-step explanation:

option a

Answer:

1. D

2.B

3.0.1081 (the one with a line over it)

Answer:

34 - 13k

Step-by-step explanation:

Answer:

the solution is 34 - 13k

Step-by-step explanation:

Answer:

is it $21.75

Step-by-step explanation:

add it together

Answer:

$21.75

Step-by-step explanation:

$12.75+$9=$21.75.

Answer:

42.25/6.5=6.5 per hour

Step-by-step explanation:

Hi! I'm happy to help!

To solve this, we need to divide the amount of money by the number of hours.

You earned $42.25, over the course of 6.5 hours.

42.25/6.5

6.5

So, you earned $6.50 per hour cleaning a community park.

I hope this was helpful, keep learning! :D

Answer:

k=13

Step-by-step explanation:

3k+6+4k-7+90=180

7k+89=180

k=180-89/7

k=13

4 no. one i guess 10

not sure

Answer:

12/99

Step-by-step explanation:

x=0.121212

100x=12.121212

100x-x=12.1212-0.1212

99x=12

x= 12/99

Answer:

6/50 is simplified to 3/25

Step-by-step explanation:

step 1 Address input parameters & values.

Input parameters & values: The decimal number = 0.12

parameters & values: The decimal number = 0.12step 2 Write it as a fraction

parameters & values: The decimal number = 0.12step 2 Write it as a fraction0.12/1

parameters & values: The decimal number = 0.12step 2 Write it as a fraction0.12/1step 3 Multiply 100 to both numerator & denominator

parameters & values: The decimal number = 0.12step 2 Write it as a fraction0.12/1step 3 Multiply 100 to both numerator & denominator(0.12 x 100)/(1 x 100) = 12/100

parameters & values: The decimal number = 0.12step 2 Write it as a fraction0.12/1step 3 Multiply 100 to both numerator & denominator(0.12 x 100)/(1 x 100) = 12/100It can be written as 12% = 12/100 or 12/100

parameters & values: The decimal number = 0.12step 2 Write it as a fraction0.12/1step 3 Multiply 100 to both numerator & denominator(0.12 x 100)/(1 x 100) = 12/100It can be written as 12% = 12/100 or 12/100step 4 To simplify 12/100 to its lowest terms, find LCM (Least Common Multiple) for 12 & 100.

parameters & values: The decimal number = 0.12step 2 Write it as a fraction0.12/1step 3 Multiply 100 to both numerator & denominator(0.12 x 100)/(1 x 100) = 12/100It can be written as 12% = 12/100 or 12/100step 4 To simplify 12/100 to its lowest terms, find LCM (Least Common Multiple) for 12 & 100.4 is the LCM for 12 & 100

parameters & values: The decimal number = 0.12step 2 Write it as a fraction0.12/1step 3 Multiply 100 to both numerator & denominator(0.12 x 100)/(1 x 100) = 12/100It can be written as 12% = 12/100 or 12/100step 4 To simplify 12/100 to its lowest terms, find LCM (Least Common Multiple) for 12 & 100.4 is the LCM for 12 & 100step 5 divide numerator & denominator by 4

parameters & values: The decimal number = 0.12step 2 Write it as a fraction0.12/1step 3 Multiply 100 to both numerator & denominator(0.12 x 100)/(1 x 100) = 12/100It can be written as 12% = 12/100 or 12/100step 4 To simplify 12/100 to its lowest terms, find LCM (Least Common Multiple) for 12 & 100.4 is the LCM for 12 & 100step 5 divide numerator & denominator by 412/100 = (12 / 4) / (100 / 4)

parameters & values: The decimal number = 0.12step 2 Write it as a fraction0.12/1step 3 Multiply 100 to both numerator & denominator(0.12 x 100)/(1 x 100) = 12/100It can be written as 12% = 12/100 or 12/100step 4 To simplify 12/100 to its lowest terms, find LCM (Least Common Multiple) for 12 & 100.4 is the LCM for 12 & 100step 5 divide numerator & denominator by 412/100 = (12 / 4) / (100 / 4)= 3/25

parameters & values: The decimal number = 0.12step 2 Write it as a fraction0.12/1step 3 Multiply 100 to both numerator & denominator(0.12 x 100)/(1 x 100) = 12/100It can be written as 12% = 12/100 or 12/100step 4 To simplify 12/100 to its lowest terms, find LCM (Least Common Multiple) for 12 & 100.4 is the LCM for 12 & 100step 5 divide numerator & denominator by 412/100 = (12 / 4) / (100 / 4)= 3/253/25 is a simplest fraction for the decimal point number 0.12

Identify which number??

Answer:

5 pizzas; 1/2 of a slice

Step-by-step explanation:

18/4=

4.5; the .5 is the leftover as the pizza so Mary needs 5 pizzas to be ordered.

The decimal value 0.1 converts to the fraction 1/10

This is because the 1 in 0.1 represents "one tenth", as its in the tenths place.

So this means 2/0.1 is the same as 2/(1/10) or [tex]2 \div \frac{1}{10}[/tex]

Then we can follow these steps:

[tex]2 \div \frac{1}{10} = \frac{2}{1} \div \frac{1}{10}\\\\\\2 \div \frac{1}{10} = \frac{2}{1} \times \frac{10}{1}\\\\\\2 \div \frac{1}{10} = \frac{2*10}{1*1}\\\\\\2 \div \frac{1}{10} = \frac{20}{1}\\\\\\2 \div \frac{1}{10} = 20\\\\\\[/tex]

Note in the second step, we flip the second fraction to go from a division problem to a multiplication problem. The general rule is [tex]\frac{A}{B} \div \frac{C}{D} = \frac{A}{B} \times \frac{D}{C}[/tex]. The first fraction does not flip.

Answer:

1, 4, 9

Step-by-step explanation:

1 x 3 = 3

9 x 5 = 45

total = 48

median = 4

twice median = 4×2

= 8

sum = 8 + 40 = 48

48=48

Answer:

The 1st term is -67

Step-by-step explanation:

I. When Sn = [tex]\frac{n}{2}[/tex]([tex]a_{1} + a_{n}[/tex])

   If  Sn = 124, n = 8 and [tex]a_{n}[/tex] = 98

                124 = 8/2(a + 98)

                124 = 4(a + 98)

                124 = 4a + 392

                124 - 392 = 4a

                -268/4 = a

                -67 = [tex]a_{1}[/tex]

Hope that help :D

Answer:

4+7(11)

Step-by-step explanation:

the square root of 121 is 11 so it would be 4+7(11)

Answer:

4 + 7 × 11

Step-by-step explanation:

[tex]4 + 7 \sqrt{ {5}^{3} - 4} [/tex]

[tex] = 4 + 7 \sqrt{125 - 4} [/tex]

[tex] = 4 + 7 \sqrt{121} [/tex]

simplify the square root of 121

[tex] \boxed{\green{\boxed{\bold{= 4 + 7 \times 11}}}}[/tex]

[tex] = 4 + 77[/tex]

[tex] = 81[/tex]

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★ . ꜝꜞ ᳝ ࣪ hope that helped!  ʬʬ

Answer:

2000 J

Step-by-step explanation:

We know that

KE = ½ mv²

KE = ½ × 10 × (20)²

KE = 5 × 400

KE = 2000 J

Now we have to,

find the required kinetic energy.

The formula we use,

→ KE = 1/2 mv²

The given information is,

→ Mass (m) = 10 kg

→ Velocity (v) = 20 m/s

Let's find the kinetic energy,

→ 1/2 mv²

→ 1/2 × 10 × (20)²

→ 5 x 400

→ [2000 J]

Thus, kinetic energy is 2000 J.

Answer:

Step-by-step explanation:

Given,

Area of a triangle = 40

Therefore,

Side of the square

[tex] = \sqrt{40} [/tex]

= 6.3245553203

= 6.3 (estimated) (Ans)

Answer:

B (Base surface area) = 16 [tex]m^{2}[/tex]

P (Perimeter of the base) = 16 m

H (Height) = 6 m

L (Not sure what L means. I assume it's the slant height??) =  6.32 m

LA (I assume lateral surface area) = [tex]50.59 m^{2}[/tex]

SA (I assume total surface area) = [tex]66.59 m^{2}[/tex]

V (volume) = [tex]32 m^{3}[/tex]

Step-by-step explanation:

Sorry if anything is wrong. It would be more helpful to put the names, instead of acronyms.

Perimeter of base=4(4)=16m

Area of base=4²=16m²

Height=6m

Slant height=6.3m

Lateral surface area=4(1/2(4)(6.3))=8(6.3)=50.54m²

Total surface area=50.54+16=66.54m²

Volume=a²h/3=4²/(6)/3=16(2)=32m³

Step-by-step explanation:

1. ∠STQ

2. ∠BCD

3. ∠ORS and ∠QPO both are alternate angles of ∠POR

4. ∠EFG

5. ∠DCF and ∠CFH

6. ∠DEB

7. ∠YUT

8. 180° (because they are co-interior angles)

The simplified form of the expression is 2(31x-20).

Given the expression is -2(x-4)-8(6-8x).

Expressions in mathematics are mathematical statements containing at least two terms containing numbers or variables or both connected by an intermediate operator.

The given expression is solved by using the distributive property a(b+c)=ab+bc, we get

-2(x-4)-8(6-8x)=-2x-4(-2)-8(6)-8(-8x)

-2(x-4)-8(6-8x)=-2x+8-48+64x

Now, we will simplify the above expression by adding or subtracting like terms, we get

-2(x-4)-8(6-8x)=62x-40

-2(x-4)-8(6-8x)=2(31x-20)

Hence, the simplified form of the given expression -2(x-4)-8(6-8x) is 2(31x-20).

Learn more about distributive property from here brainly.com/question/8329981

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Answer:

It's 87.

Step-by-step explanation:

See the picture upside down.

Answer:

b= x

Step-by-step explanation:

[tex]\boxed{ {x}^{m} \times {x}^{n} = {x}^{m + n} }[/tex]

Applying the law of indices above:

[tex]b = {x}^{ \frac{1}{4} } \times {x}^{ \frac{3}{4} } [/tex]

[tex]b = {x}^{ \frac{1}{4} + \frac{3}{4} } [/tex]

[tex]b = {x}^{ \frac{4}{4} } [/tex]

[tex]b = {x}^{1} [/tex]

∴b= x

Answer:

It is b = x

Step-by-step explanation:

From law of indices:

[tex] {a}^{b} \times {a}^{c} = {a}^{(b + c)} [/tex]

for, multiplication: same coefficients, we sum up the powers.

[tex]b = {x}^{ \frac{1}{4} } \times {x}^{ \frac{3}{4} } \\ b = {x}^{( \frac{1}{4} + \frac{3}{4} ) } \\ b = {x}^{ \frac{4}{4} } \\ b = {x}^{1} \\ b = x[/tex]

Answer:

13 inches

Step-by-step explanation:

in an equilateral triangle all sides had we the same length.

so, the perimeter is simply 3×one triangle side.

and the perimeter of the square is 4×one square side.

x = triangle side length

y = square side length

3x = 4y + 15

x = y + 7

we use the second equation as substitution in the first equation.

3(y + 7) = 4y + 15

3y +21 = 4y + 15

6 = y

x = y + 7 = 6 + 7 = 13 inches

Answer:

[tex]-x^2+24x-70[/tex]

Step-by-step explanation:

[tex](x-1)^2+(2-x)^2-3(x-5)*(x-5)\\=> (x - 1)^2 + (2 - x)^2 - 3(x - 5)^2\\=> x^2 - 2x + 1 + 4 - 4x + x^2 - 3(x - 5)^2\\=> x^2 - 2x + 5 - 4x + x^2 - 3(x - 5)^2\\=> x^2 - 6x + 5 + x^2 - 3(x - 5)^2\\=> 2x^2 - 6x+5 - 3(x - 5)^2\\=> 2x^2 - 6x+5 - 3(x^2 - 10x + 25)\\=> 2x^2 - 6x+5 - 3x^2+30x-75\\=> -x^2 - 6x + 5 + 30x - 75\\=> -x^2 + 24x + 5-75\\=> -x^2+24x-70[/tex]

Formula used =

[tex](a-b)^2 = a^2+ 2ab + b^2[/tex]