The picture shows a basic diagram of an electric motor. At top left a piece of magnet labeled N and at top right a piece labeled S. Between these a square coil of wire X sits attached to a metal rod, which runs between the 2 pieces of magnet. 2 semicircular pieces Z of metal surround the rod at its opposite end from the pieces of magnet. Wires connect to each semicircular piece at terminals Y to one pole of a battery. Blue arrows superimposed on the end of the coil away from the magnets point toward S and away from N. Which labels best complete the diagram? X: Brush Y: Armature Z: Commutator X: Commutator Y: Brush Z: Armature X: Armature Y: Commutator Z: Brush X: Armature Y: Brush Z: Commutator Mark this and return

Answer:

T = 708.81 N

Explanation:

Given that,

Length of a steel wire in a piano, l =0.54 m

Mass, [tex]m=4.8\times 10^{-3}\ kg[/tex]

We need to find the tension must this wire be stretched so that the fundamental vibration corresponds to middle C, fc = 261.6 Hz

The equation for fundamental frequency is given by :

[tex]f=\dfrac{1}{2l}\times \sqrt{\dfrac{T}{\mu}} \\\\f=\dfrac{1}{2l}\times \sqrt{\dfrac{T}{\dfrac{m}{l}}} \\\\261.6=\dfrac{1}{2\times 0.54}\times \sqrt{\dfrac{T}{\dfrac{4.8\times 10^{-3}}{0.54}}} \\\\261.6\times 2\times 0.54=\sqrt{\dfrac{T}{\dfrac{4.8\times 10^{-3}}{0.54}}}\\\\282.528=\sqrt{\dfrac{T}{0.00888}} \\\\(282.528)^2=\dfrac{T}{0.00888}\\\\T=708.81\ N[/tex]

So, the required tension in the wire is 708.81 N.

Answer:

a) 400.4Joules

b) 262.69Joules

Explanation:

Work is said to be done if the force applied to an object cause the object to move through a distance

Workdone = Force × Distance

Given

Force = 76N

Distance= 5.2m

Work done = 77 × 5.2

Work done = 400.4Joules

b) If the force is exerted at an angle of 41°

Work done = Fdsin theta

Work done = 77(5.2)sin41

Work done = 400.4sin41

Work done = 262.69Joules

Answer:

Fr = 48 [N] forward.

Explanation:

Suppose the movement is on the X axis, in this way we have the force of the engine that produces the movement to the right, while the force produced by the brake causes the vehicle to decrease its speed in this way the sign must be negative.

∑F = Fr

[tex]F_{engine}-F_{brake} =F_{r}\\F_{r}=79-31\\F_{r}=48[N][/tex]

The movement remains forward, since the force produced by the movement is greater than the braking force.

Answer:

Afternoons are much warmer than the mornings or evenings is explained below in complete detail.

Explanation:

Because in the afternoon the sun is on the head and the beams of sunshine arrive straight to the earth so we exhibit warmer and in daylight and evening the sun is sparse to the earth so we observe colder than an afternoon. However, in the evening, when the sun is weak, I don't sense or experienced loads of heat and sunburn on body parts that are viewing the sun directly.

Answer:

(a) The acceleration is 7.85 m/s²

(b) It takes the car to change speed from 10.0 m / s to 20 m / s in a time of 1.27 seconds.

(c) Doubling the time will double the change in velocity if the acceleration is kept constant.

Explanation:

(a)  Acceleration is the physical quantity that measures the rate of change of velocity with time. That is, acceleration relates changes in speed with the time in which they occur, that is, it measures how fast the changes in speed are.

The average acceleration is calculated using the following expression:

[tex]a=\frac{vf-vi}{t}[/tex]

where a is the acceleration, vf is the final velocity, vi is the initial velocity and t is the time.

In this case:

Replacing:

[tex]a=\frac{20.4 \frac{m}{s} - 0\frac{m}{s} }{2.60 s}[/tex]

a= 7.85 m/s²

The acceleration is 7.85 m/s²

(b) In this case you know:

Replacing:

[tex]7.85 \frac{m}{s^{2} } =\frac{20 \frac{m}{s} - 10\frac{m}{s} }{t}[/tex]

and solving you get:

[tex]t=\frac{20 \frac{m}{s} - 10\frac{m}{s} }{7.85 \frac{m}{s^{2} } }[/tex]

t=1.27 s

It takes the car to change speed from 10.0 m / s to 20 m / s in a time of 1.27 seconds.

(c)  Being:

[tex]a=\frac{vf-vi}{t}[/tex]

Then:

a*t= vf - vi

vf - vi represents the change in velocity. You can see that, if a (acceleration) is constant, then (vf - vi) is directly proportional to the time t: therefore, if t doubles, the change in velocity doubles as well.

In other words, doubling the time will double the change in velocity if the acceleration is kept constant.

Answer:

a)  t = 3.027 10⁻⁹ s ,  b)   y = 2.25 10⁻² m

Explanation:

We can solve this problem using the kinematic relations

a) as on the x-axis there is no relationship

          vₓ = x / t

          t = x / vₓ

We reduce the magnitudes to the SI system

          x = 5.6 cm (1m / 100 vm) = 0.056 m

we calculate

          t = 0.056 / 1.85 10⁷

          t = 3.027 10⁻⁹ s

b) the time is the same for the two movements, on the y axis

         y = v₀t + ½ a t²

as the beam leaves horizontal there is no initial vertical velocity

         y = ½ a t²

let's calculate

         y = ½  5.45 10¹⁵ (3.027 10⁻⁹)²

         y = 2.25 10⁻² m

Answer:

1) directly

2) increase or double

Explanation:

Momentum is directly proportional to an objects mass and its velocity, meaning that if either the mass or the velocity increases, the momentum will double/increase.

We know, acceleration is given by :

a = F/m

a = 16.6/3.1 m/s²

a = 5.35 m/s²

Now, we need to find the speed after it has moved 3.8 m.

By equation of motion :

[tex]v^2 -u^2 = 2as\\\\v=\sqrt{2as}\\\\v = \sqrt{2\times 5.35 \times 3.8 }\ m/s\\\\v = 6.38\ m/s[/tex]

Therefore, the speed after it has moved 3.8 m is 6.38 m/s.

Answer: the answer is 6kg.

Explanation:

Mass= force divided by acceleration, which would be 12 divided by 2.

Answer:

Horizontal acceleration is 0 in a projectile motion

Explanation:

first we have to find the horizontal velocity

15cos40 = 11.49ms^-1

and then use the following equation to find the distance

[tex]s = ut + \frac{1}{2} a {t}^{2} \\ s = 11.49 \times 2 \\s = 22.98m[/tex]

Given:

According to the question,

→ [tex]15 \ Cos 40^{\circ} = 11.49 \ m/s^{-1}[/tex]

By using the relation, we get

→ [tex]s = ut +\frac{1}{2}at^2[/tex]

By substituting the values, we get

     [tex]= 11.49\times 2[/tex]

     [tex]= 22.98 \ m[/tex]

Thus the response above is correct.

Learn more about distance here:

https://brainly.com/question/23397620

Answer:

a) The initial elastic potential energy of the block-spring system is 28.113 joules.

b) The final speed of the block is approximately 4.192 meters per second.

Explanation:

a) By applying Hooke's law and definition of work, we define the elastic potential energy ([tex]U_{g}[/tex]), measured in joules, by the following formula:

[tex]U_{g} = \frac{1}{2}\cdot k\cdot x^{2}[/tex] (1)

Where:

[tex]k[/tex] - Spring constant, measured in newtons per meter.

[tex]x[/tex] - Deformation of the spring, measured in meters.

If we know that [tex]k = 865\,\frac{N}{m}[/tex] and [tex]x = 0.065\,m[/tex], then the elastic potential energy is:

[tex]U_{g} = \frac{1}{2}\cdot \left(865\,\frac{N}{m} \right) \cdot (0.065\,m)[/tex]

[tex]U_{g} = 28.113\,J[/tex]

The initial elastic potential energy of the block-spring system is 28.113 joules.

b) According to the Principle of Energy Conservation, the initial elastic potential energy of the block-spring system becomes into translational kinetic energy, that is:

[tex]U_{g} = \frac{1}{2}\cdot m\cdot v^{2}[/tex] (2)

Where:

[tex]m[/tex] - Mass, measured in kilograms.

[tex]v[/tex] - Final speed, measured in meters per second.

Then, the final speed is cleared:

[tex]v = \sqrt{\frac{2\cdot U_{g}}{m} }[/tex]

If we know that [tex]U_{g} = 28.113\,J[/tex] and [tex]m = 3.20\,kg[/tex], then the final speed of the block is:

[tex]v = \sqrt{\frac{2\cdot (28.113\,J)}{3.20\,kg} }[/tex]

[tex]v \approx 4.192\,\frac{m}{s}[/tex]

The final speed of the block is approximately 4.192 meters per second.

Answer:

(d) not enough info

Explanation:

because it doesn't specify where the strings are attached

if it was the two ends of the rod then T1 would be equal to T2

Answer:

I think it is Location.

Explanation:

If im wrong im sorry

Answer:

Money

Explanation:

______ is the limiting factor that can keep some people from exercising if they (can’t afford) to purchase certain types of exercise equipment or pay for activities.

Says they cant afford it, therefore it would obviously be money

Answer:

T₂ = 469.73 K = 196.73 °C

Explanation:

First we will find the surface area of rubber stop:

[tex]Area = A= \frac{Volume}{Length} \\\\A = \frac{100\ cm^3}{15\ cm}\\\\A = 6.67\ cm^2 = 6.67 \ x\ 10^{-4}\ m^2[/tex]

Now, we will find the final pressure required to remove the rubber stop:

[tex]Final\ Pressure\ = P_{2} = \frac{Force}{Area}+Atmospheric Pressure \\\\P_{2} = \frac{40\ N}{6.67\ x\ 10^{-4}\ m^2} + 101.3 KPa\\\\ P_{2} = 60000\ Pa + 101.3 KPa = 60\ KPa + 101.3 KPa\\\\P_{2} = 161.3\ KPa[/tex]

Now, we use equation of state:

[tex]\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}[/tex]

for constant volume due to rigid cylinder:

[tex]\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}\\\\T_{2} = \frac{P_{2} T_{1}}{P_{1}}[/tex]

where,

P₁ = initial pressure = 101.3 KPa

P₂ = final pressure = 161.3 KPa

T₁ = Initial Temperature = 22°C = 295 K

T₂ = Final Temperature = ?

Therefore,

[tex]T_{2} = \frac{(161.3\ KPa)(295\ K)}{101.3\ KPa}[/tex]

T₂ = 469.73 K = 196.73 °C

Correct question is;

An object exerts a pressure of 2 pa on the ground if another object of the same weight is kept above it then the net pressure will become _____

Answer:

4 pa

Explanation:

We know that formula for pressure is;

P = Force/area

Where formula for force is;

F = mg

Thus;

P = mg/A

We are told P = 2 pa

Thus;

mg/A = 2

Now, when we add the same weight, our new Force is;

F_new = mg + mg = 2mg

Area remains the same A.

Thus, net pressure = F_new/A = 2mg/A

From earlier, we saw that mg/A = 2.

Thus;

net pressure = 2mg/A = 2 × 2 = 4 pa

Answer:

A particle moves in the +x direction and then reverses the direction of its velocity

Explanation:

This is illustrated in that when a particle moves in a straight route with no alterations in direction, this will lead to displacement and distance being equal at any point in time during the movement. Thereby the quantity of average speed and average velocity will equal.

On the other hand, should the particle reverses direction, the distance traveled will be greater than it's displacement, thereby, the average speed will be greater than the average velocity.

Answer:

When the reflecting surface is instead curved, we call it a curved mirror. There are two types of curved mirrors; concave and convex mirror. Curved mirrors whose reflecting surfaces curve inwards are called concave mirrors while those whose reflecting surfaces bulge outwards are called convex mirrors.

Explanation:

Answer:

a) W=0  b) force of gravity and friction force

Explanation:

a) When the kicker touches the soccer ball, his foot exerts a force on the ball in the same direction of its movement, but the ball is stationary, therefore the displacement of the ball during the very short contact is zero and as the work is the product of force and distance, we conclude that there is no work

   W = F. d

   d = 0

    W = 0

b) When the ball is in flight there is mainly the force of gravity that has a vertical direction and the friction force that opposes the movement at all times

a.He does not do any work on the ball after it loses contact with his toe

b.The force of gravity and friction force doing work on the ball while it is in flight.

Work is defined as the product of applied force and the distance through which the body is displaced on which the force is applied.

Work may be zero, positive and negative.it depend on the diection of body displaced . if the body is displaced in the same direction of force it will be positive.

While if the displacement is in the opposite direction of force applied the work will be negative work . if their is no displacement of the body the work done will be zero.

a.He does not do any work on the ball after it loses contact with his toe.

When the kicker makes contact with the soccer ball, his foot exerts a force on the ball in the same direction as its movement, but the ball is stationary,

So the displacement of the ball during the very short contact is zero, and since work is the product of force and distance, we conclude that there is no work.

[tex]\rm W= F \times d \\\\ \rm W= F \times 0 \\\\ \rm W=0[/tex]

Hence he does not do any work on the ball after it loses contact with his toe.

b.The force of gravity and friction force doing work on the ball while it is in flight.

When the ball is in flight, there is primarily a vertical force of gravity and a friction force that resists movement at all times.]

Hence the force of gravity and friction force doing work on the ball while it is in flight.

To learn more about the work refer to the link ;

https://brainly.com/question/3902440

Answer:

The value is  [tex]V_{os} = 0.001 \ V[/tex]

Explanation:

From the question we are told that

     The circuit resistance is  [tex]R_1 = 10 \ k \Omega[/tex]

     The feedback resistance  is  [tex]R_f = 220 \ k \Omega[/tex]

      The offset current is  [tex]I_{os } = 100 \ nA = 100 * 1)^{-9} \ A[/tex]

Generally the offset voltage is mathematically reparented as

           [tex]V_{os} = R_f * I_{os}[/tex]

=>        [tex]V_{os} = 10 *10^{3}* 100 *10^{-9}[/tex]

=>        [tex]V_{os} = 0.001 \ V[/tex]

Explanation:

Given that,

Mass of a soccer ball, m = 0.427 kg

Initial speed, u = 16 m/s

Final speed, v = -21.7 m/s (negative as it is in opposite direction)

(a) Impulse = change in momentum

J = 0.427 × (-21.7 -16)

J = -16.097 kg-m/s

(b) Impulse delivered to the ball by the player is in opposite direction.

(c) Time of contant, t = 0.0600 s

Average force,

J = force×time

[tex]F=\dfrac{J}{t}\\\\F=\dfrac{16.097}{0.0600 }\\\\=268.28\ N[/tex]

Hence, this is the required solution.

Explanation:

Gravitational potential energy

= mgh

= (85kg)(9.81N/kg)(8848m)

= 7,377,904.8J.

Answer:

Liter

Explanation:

Answer:

443.8 nm

Explanation:

mλ = yd/D = d(y/D)

m = 1

d = 6.42 x 10-5 m

θ = 0.396°

y/D = tanθ = tan(0.396°) ≅ 6.912 x 10-3

λ = (6.42 x 10-5 m) tan(0.396°) = (6.42 x 10-5 m)(6.912 x 10-3) ≅ 4.438 x 10-7 m = 443.8 nm

I JUST WANT TO MAKE CLEAR THAT  d=6.42*10^-5 NOT d = 6.42x10-5 right?

Answer:

O chemical energy into thermal energy

Hope this helped!!

Answer:

chemical energy into thermal energy

Explanation:

Answer:

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sysydyydydysysysysyxhxyt56fys7w727ueudu

Answer:

D

Explanation:

The direction that positive charge would move

Answer:

All points to the left of zero are negative

Explanation:

Answer:

C

Explanation:

on edge

Answer:

[tex]T_f=18.641^{\circ} C[/tex]

Explanation:

Given that,

Heat raised, Q = 9400 J

Mass, m = 3.5 kg

Initial temperature of water, [tex]T_i=18^{\circ} C[/tex]

The specific heat of water, [tex]c=4186\ J/kg^{\circ} C[/tex]

We need to find the final temperature of water. The heat required to raise the temperature is given by :

[tex]Q=mc\Delta T\\\\Q=mc(T_f-T_i)\\\\\dfrac{Q}{mc}=(T_f-T_i)\\\\T_f=\dfrac{Q}{mc}+T_i\\\\T_f=\dfrac{9400}{3.5\times 4186}+18\\\\=18.641^{\circ} C[/tex]

So, the final temperature is [tex]18.641^{\circ} C[/tex].