The pressure at the top of Mount Everest is 0.31×105N/m2, and the temperature is −30∘C. The pressure at sea level is 1.0×105N/m2, and the temperature is 20∘C.

Determine how much more frequently you need to breathe on top of Mount Everest to inhale the same amount of oxygen as you do at sea level.

________ times more frequently.

Answer:

•Renewable energy, often referred to as clean energy, comes from natural sources or processes that are constantly replenished. For example, sunlight or wind keep shining and blowing, even if their availability depends on time and weather.

• Renewable sources of energy are better than nonrenewable sources because they refill themselves over a short period of time.

Answer:

W = 15 N

Explanation:

The moments from the center mus be equal for balance to occur

 center is at 25 cm  ( for a 1/2 meter stick)

moment one :   15 cm * 20 N

moment two :   20 cm * W         these must be equal

   15 * 20 = 20 * W        W = 15 N

Answer:

See below

Explanation:

The forces are equal but opposite directions

the velocities of the two differ because of the different masses of the two objects....the bullet is light compared to the rifle/shooter.

I would not want to fire a heavy projectile...the 'kick' or 'recoil' of the rifle would be quite large.....and painful!

Answer:

Solution in Photo

Explanation:

To solve this question, draw the Free Body Diagram (FBD) for the whole system such that

theta < 90, it will be more clearer that way.

a)average force was exerted on the 10kg ball= -120 N

b)average force was exerted on the 5kg ball= 60N

c)What is the final momentum of the 5kg ball= 2.5 kg m/s

d) the initial momentum of the 10kg ball=60 kg m/s

The average force can be calculated by formula F=m(vf–vi)/ Δt so, 10 (0-6)/0.5 = -120 N the minus is representing opposite direction

the average force on the 5 kg ball = 5(6-0)/0.5= 60 N

The final momentum of 5 kg ball is 5 X 0.5 =2.5 kg m/s and initial momentum of 10 kg ball = 10 X 6 = 60 Kg m/s.

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The correct responses are;

1) No the density of an object is not always the same as its mass

2) The density of an object is calculated from mass/volume

3) After completing the liquids portion of the lab, oil has the lest density

4) It is a false statement that the density of the liquids depends on the order in which they are added to the column.

5) The golf ball has a greater density than the ping pong ball

The term density refers to the mass per unit volume of an object. This implies that if measure the mass of the object and divide this value by the volume of the object then we obtain the density of the object. The density is an empirical property hence it does not change.

Let us now answer the questions individually;

1) No the density of an object is not always the same as its mass

2) The density of an object is calculated from mass/volume

3) After completing the liquids portion of the lab, oil has the lest density

4) It is a false statement that the density of the liquids depends on the order in which they are added to the column.

5) The golf ball has a greater density than the ping pong ball

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The acceleration of the runner 10 sec later will be 0.08 meters per second square (m/s²).

Average acceleration is defined as the average rate of change of velocity with time. Mathematically -

a = Δv/Δt

Given is a runner sprinting at 3 m/s and after 10 s the same runner is sprinting at 3.8 m/s. Therefore, we can write -

Initial velocity [u] = 3 m/s

Final velocity [v] = 3.8 m/s

time taken [Δt] = 10 s

The average acceleration of the sprinter can be calculated as follows -

a = Δv/Δt

Δv = v - u

Δv = 3.8 - 3 = 0.8 m/s

Δt = 10 s

Therefore -

a = 0.8/10 = 0.08 m/s².

Therefore, the acceleration of the runner 10 sec later will be 0.08 meters per second square (m/s²).

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The orbital speed of the proton is 4.7 x 10⁶ m/s.

The orbital speed of the proton is calculated by applying the following equations as shown below.

Centripetal force of the proton = magnetic force of the proton

Fc = qVB

mv²/r = qvB

mv² = qvBr

v² = qvBr/m

v = qBr/m

where;

The orbital speed of the proton is calculated as follows;

v = (1.6 x 10⁻¹⁹ x 0.35 x 0.14) / (1.67 x 10⁻²⁷)

v = 4.7 x 10⁶ m/s

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Answer:

108 km/hr = 1.8 km/min

90 km/hr = 1.5 km/min

V1 = (-39.6, 0)

V2 = (-10.6, -10.6)         (10.6^2 + 10.6^2)^1/2 = 15    1.5 km/min * 10 min

V = (-50.2, -10.6)       final displacement vector

Total time = 22 + 10 = 32 min

S = (50.2^2 + 10.6^2)^1/2 = 51.3 km

Average speed = (1.8 * 22 + 1.5 * 10) / 32 = 1.71 km / min

Displacement = 51.3 km

Average velocity = 51.3 / 32 = 1.60 km/min

Direction = 10.6 / 50.2 = .211 or 11.9 deg S of W

Answer:

Explanation:

temperature is a scalar quantity

The correct answer is 16.

The conventional way to express function is F(x).

You may alternatively describe it as a machine that has input, output, and some other ways they are connected.

You must first evaluate the first function in order to get the value of a composite function like this one. We placed the value for x in parentheses first in that equation because f is on the right side.

f (x) = 2x - 8

f (5) = 2 × 5 - 8

f (5) = 10 - 8

f (5) = 2

Once the first portion of a composite function has an answer, we insert that response into the second part. We insert our response (2) into g because it is on the left side.

g(x) = x^4

g(2) = 2^4

g(2) = 16

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The Independent variable here in this sentence is the type of drink each group was subjected to intake.

Independent variable in a experiment is the one which stands independent and acts as a control which influences the experiment's outcome. Independent variables are employed in a experiment to test whether the dependent variable changes accordingly.

Here, in this experiment the dependent variable, i.e., the theory to be tested is the memory of the patients. The independent variable here is the type of juice given to the patients, which acts as a control of the experiment's outcome. Any variable which alters the final result of the experiment and which can be controlled through out the experiment is termed as Independent variable.

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Answer:

22m/s

Explanation:

This is a vector addition problem. First identify the two vectors: 20m/s in the -x direction and 9m/s in the -y direction. Since neither vector shares an axis component you can use the formula [tex]\sqrt{20^2+9^2\\[/tex] =21.93 (This is the Pythagorean Theorem where your non-hypotenuse sides are your velocity vectors). Round to 2 significant figures and you'll get 22m/s.

The property that the wire must have to be used in the game is high conductivity.

A wire is a material that is used to carry electric current from one point to another. Thus, we know that when we connect wire to a source, there is a movement of electrons. We can thus see that the wire is able to conduct electricity.

Having said that, the game as shown in the image attached has to do with the formation of a circuit and the flow of electricity in that circuit that is formed.

We can see that the property that the wire must have to be used in the game is high conductivity.

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A car traveling 83.0 km/h on a straight road is 1900 m behind a truck traveling at 61.0 km/h. The required voltage is 10 Volts.

Electric current is defined as the rate at which charge passes a fixed unit cross sectional area.

Voltage is defined as the physical quantity required to move charge from one end to other.

Resistance is defined as the the factor which opposed the electric current.

It states that voltage is directly proportional to electric current

V=IR

Given:

current (I) = 0.1 A

resistance (R) = 100 Ω

Now from definition of voltage we have:

V = I × R

V = 100 × 0.1

V = 10 volts

Thus from the above conclusion we can say that therefore the required voltage is 10 volts.

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Answer:

15

Explanation:

Explanation:

stones a and b will hit the ground at the same time because they are of identical weight I think your right

Sound cannot travel through a vacuum because there are no particles to carry the vibrations.

Explanation:

When travelling through air, the speed of sound is about 330 metres per second (m/s).

Answer:

The ground we walk on is flat, not round. Gravity doesn't exist. Objects don't fall down, the flat earth(disk) goes up with a force called dark energy. There is a 45 ft tall ice wall to prevent people from falling off the Earth.

Explanation:

Answer:

200N in Player 1's direction

Player 2 is knocked back

Explanation:

Let's start by working out the force exerted by each player by using the equation F=ma, Force = Mass x Acceleration.

Player 1 has an acceleration of 4m/s2 and a mass of 150kg, therefore their force will be: [tex]F = (150)(4)[/tex], [tex]F=600N[/tex]

Player 2 has an acceleration of 2m/s2 and a mass of 200kg, therefore their force will be: [tex]F = (200)(2)[/tex], [tex]F=400N[/tex]

They are both coming from different directions so we can find the net force by subtracting one from the other: [tex]600-400=200N[/tex]

Player 1 has the higher force so the net force will be 200N in the direction Player 1 is travelling in and Player 2 will be the one knocked back.

Hope this helped!

The upward applied force will be 579.249 lbf.

Mass of the rocket, m = 4.5 lb

Acceleration, a = 3g

as we know g = 32.2 ft/s²

therefore acceleration, a = 3 * 32.174 = 96.522  ft/s²

According to the Newton's second law of motion, which states that the magnitude of the force acting on an object is equal to the product of the object's mass and the acceleration with which it is moving.

Mathematically, it is F =  [tex]\frac{mass}{acceleration}[/tex] ;

Upward force (F₀) for the rocket will be the sum of Force applied by the weight (Fₓ) and the force by the acceleration(Fₐ).

i.e. gₙ *F₀ = Fₓ + Fₐ

Fₓ = mg

Fₐ = ma

F₀ = ma + mg

F₀ = m (a + g)

F₀ = 4.5 (96.522 + 32.2)

F₀ = 4.5 * 128.722

F₀ = 579.249 lbf.

The upward applied force, required to accelerate a 4.5-lb model rocket vertically upward will be 579.249 lbf.

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Answer:

(i) A body has a uniform acceleration if its velocity changes by equal amounts in equal intervals of time. The motion of a freely falling body is an example of uniform acceleraion.

(ii) A body has a non-uniform acceleration if its velocity changes by unequal intervals of time. The motion of a car on a crowded city road is an example of non-uniform acceleration.

Answer: I don't really see the answer choices.

Explanation:

Explanation:

it dosent depend on the weights of the items. I'll reach the ground at same time taking as no air friction or restrictions.

i.e

v = u + gt

whte v is final velocity of the object

u is initial velocity of the object

g is acceleration due to gravity and

t is time. thanks

please if found helpful rate brainliest

Assuming there is little air resistance, the acceleration felt by both objects when one drops a 20-ton object and a 10-ton object at the same time will be the same.

Even though both objects accelerate at the same rate, the forces acting on them will be different because of their different masses. Newton's second law of motion states that an object's force is inversely proportional to its mass (F = ma). The 20-ton object will therefore encounter twice as much force as the 10-ton object, but their rates of acceleration will remain constant.

In conclusion, both the 20-ton and 10-ton objects will accelerate to about 9.8 meters per second squared when dropped simultaneously with little air resistance.

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Answer:

[tex]1:1[/tex]

Explanation:

Given:-

To find:-

Answer:-

The nuclear densities for all atoms is same and it doesn't depends on mass number.

So the ratio of the nuclear densities will be 1:1 .

[tex]\implies \underline{\underline{\green{ \rm Ratio= 1:1}}}[/tex]

_________________________________________

Additional information:-

Here I would be providing you the proof for the same .

Firstly we know that the volume of nucleus is directly proportional to its mass number ( Why ? because as the mass number increases , nucleons increases so volume increases) . Therefore;

[tex]\implies V = \dfrac{4}{3}\pi r^3 \\[/tex]

And ,

[tex]\implies V \propto A \\[/tex]

So ,

[tex]\implies \dfrac{4}{3}\pi r^3 \propto A \\[/tex]

[tex]\implies r^3 \propto A \\[/tex]

[tex]\implies r\propto A^{\dfrac{1}{3}} \\[/tex]

[tex]\implies r = r_0 A^{\dfrac{1}{3}} \dots\rm{(1)} \\[/tex]

where,

Now in order to find out the nuclear density , say [tex]\rho[/tex] ; we have ;

[tex]\implies \rho =\dfrac{Mass_{\rm nucleus}}{Volume_{\rm nucleus}} \\[/tex]

Now let's assume that there are m nucleons and their average mass number is A . So the average mass of m nucleons would be mA .

[tex]\implies \rho = \dfrac{mA}{ \dfrac{4}{3}\pi r^3}\\[/tex]

From equation (1) , we have ;

[tex]\implies \rho = \dfrac{mA}{\dfrac{4}{3}\pi (r_0 A^{\dfrac{1}{3}})^3} \\[/tex]

[tex]\implies \rho = \dfrac{mA}{\dfrac{4}{3}\pi r_0^3 A} \\[/tex]

[tex]\implies \underline{\underline{\green{\rho = \dfrac{3m}{4\pi r_0^3}}}} \\[/tex]

Now we can see that all the terms in the RHS of the equation are constants. This implies that nuclear density is also constant for all atoms independent of their mass numbers .

And we are done!

The tension of the rope is 750 N.

According to Newton's second law of motion, the mass of a rock climber, m = 50 kg, while lifting a thing upwards with an acceleration, the upward force must be larger than the weight of the object in order to have a net force in upward direction to induce acceleration in upward direction.

accelerating a rock climber upward with a rope,

a= 5 m/s

determining the rope's tension (T)

The following two forces are at work on the rock climber as it is raised:

Rope tension acting upward. The rock climber's weight acting downward. Using Newton's second rule of motion, we may now:

Mass times climber's acceleration equals net upward force.

T−m×g=m×aT

=m×(g+a)T

=50× (10+5) T

=750 N

The complete question is -A rescue helicopter lifts a 50 kg rock climber by a rope from a cliff face. The rock climber is accelerated vertically a 5m/s−² What is the tension in the rope?

a) 350N

b) 500N

c) 750N

d) 1500 N

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