Answer:
8
Step-by-step explanation:
-5 is 5 units left of zero.
3 is 3 units right of zero.
The difference is 8.
Answer the following questions
WILL GIVE BRAINLIEST
After an accident, police can use the formula v=2/5L to estimate the speed, v, in miles per hour, that a car was traveling by measuring the length of the skid marks, L in feet. Estimate the speed of a car that left skid marks 69 ft long. If the posted speed limit is 35 mi/h, was the car speeding?
Answer: The car was not speeding. It went 27.6 mi/h.
Step-by-step explanation: The equation v=2/5L is given where v is measured in mi/h. L is measured in ft. Since we have the value 69 for L, we sub it into the equation. We end up getting 27.6 mi/h after evaluating.
Please help me with 1-4. I will give an Brainly and a bunch of extra points.
Answer: 1. {a, b, c, d, e}
2. {a, b, d}
3. {c, f, g, h}
4. {a, c}
Step-by-step explanation:
1. AUC ==> Means take all parameters from A and C.
A+C=
{a, b, c, d}+{a, e}={a, b, c, d, e}
2. B∩A ==> Means take the common parameters from B and A
B: {b, e, a, d}
A: {a, b, c, d}
Both B and A have a, b, and d.
So answer is {a, b, d}.
3. B' is every parameter that isn't in B
Reminder: B={b, e, a, d}.
All parameters: {a, b, c, d, e, f, g, h}
Remaining Parameters(B'): {c, f, g, h}
4. A-B∩C'
First, let's find C'.
C' is every parameter that isn't in C.
Reminder: C={a, e}
All parameters: {a, b, c, d, e, f, g, h}
Remaining Parameters(C'): {b, c, d, f, g, h}
Then lets find B∩C'
B: {b, e, a, d}
C': {b, c, d, f, g, h}
Both B and C' have b and d, so B∩C' is {b, d}
A-{b, d}=
{a, b, c, d}-{b, d}={a, c} ==> Answer for 4
Answer:
[tex]\sf 1) \quad \sf A \cup C = \{a, b, c, d, e\}[/tex]
[tex]\sf 2) \quad B \cap A = \{a, b, d\}[/tex]
[tex]\sf 3) \quad B' = \{c, f, g, h \}[/tex]
[tex]\sf 4) \quad A -(B \cap C') = \{a, c \}[/tex]
Step-by-step explanation:
Set Notation
[tex]\begin{array}{|c|c|l|} \cline{1-3} \sf Symbol & \sf N\:\!ame & \sf Meaning \\\cline{1-3} \{ \: \} & \sf Set & \sf A\:collection\:of\:elements\\\cline{1-3} \cup & \sf Union & \sf A \cup B=elements\:in\:A\:or\:B\:(or\:both)}\\\cline{1-3} \cap & \sf Intersection & \sf A \cap B=elements\: in \:both\: A \:and \:B} \\\cline{1-3} \sf ' \:or\: ^c & \sf Complement & \sf A'=elements\: not\: in\: A \\\cline{1-3} \sf - & \sf Difference & \sf A-B=elements \:in \:A \:but\: not\: in \:B}\\\cline{1-3} \end{array}[/tex]
Given sets:
U = {a, b, c, d, e, f, g, h}A = {a, b, c, d}B = {b, e, a, d}C = {a, e}Therefore:
Universal set = {a, b, c, d, e, f, g, h}B' = not in B = {c, f, g, h}C' = not in C = {b, c, d, f, g, h}Question 1
[tex]\begin{aligned}\sf A \cup C & = \sf \{a, b, c, d\} \cup \{a,e\}\\& = \sf \{a, b, c, d, e\}\end{aligned}[/tex]
Question 2
[tex]\begin{aligned}\sf B \cap A & = \sf \{b, e, a, d\} \cap \{a, b, c, d\}\\& = \sf \{a, b, d\}\end{aligned}[/tex]
Question 3
[tex]\begin{aligned}\sf B' & = \rm U - \sf B\\& = \sf \{a, b, c, d, e, f, g, h \}-\{b, e, a, d\}\\& = \sf \{c, f, g, h \}\end{aligned}[/tex]
Question 4
[tex]\begin{aligned}\sf A -(B \cap C') & = \sf \{a, b, c, d \}- \left( \{b, e, a, d \} \cap \{b, c, d, f, g, h \} \right)\\& = \sf \{a, b, c, d \}- \{b, d \} \\& = \sf \{a, c \}\end{aligned}[/tex]
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What is the opposite of the number located at point d.
Answer:
-7
Step-by-step explanation:
The number located at point D is 7, And the opposite of 7 is -7.
Points S, T, and P lie on a number line. Their coordinates
are 0, 1, and x, respectively. Given SP = PT, what is the value of x?
The value of x associated with the point P on a number line is 0.5.
How to find the locations of a point on a number line
In accordance with the statement, the condition SP = PT means that the locations of points S, T and P on the number line are 0, 1, x, so that S < P < T and that point P is equidistant of points S and T. Then, the location of the missing point is determined by the midpoint formula:
P = 0.5 · S + 0.5 · T
P = 0.5 · 0 + 0.5 · 1
P = x = 0.5
The value of x associated with the point P on a number line is 0.5.
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Two ships A and B take off at the same time from the same spot at a harbour. Ship A travels west with a speed of 40 km/h, while ship B travels north at a speed of 50 km/h. Determine, to the nearest integer, how fast the distance between the ships is increasing when they are 0.5 hours away from the harbour. Use the units as given in the question but write down only the numerical value of your answer without the unit.
Using the Pythagorean Theorem and implicit differentiation, it is found that the distance between them is increasing at a rate of 2050 km/h when they are 0.5 hours away from the harbor.
What is the Pythagorean Theorem?The Pythagorean Theorem relates the length of the legs [tex]l_1[/tex] and [tex]l_2[/tex] of a right triangle with the length of the hypotenuse h, according to the following equation:
[tex]h^2 = l_1^2 + l_2^2[/tex]
For this problem, we have that since the ships are moving west and north, the distance between them as a function of the time will be given by the hypotenuse of a right triangle, as follows:
d² = x² + y².
In which;
x is the position of Ship A(moving horizontally).y is the position of Ship B(moving vertically).Applying implicit differentiation, the rate of change of the position is given as follows:
[tex]2\frac{dd}{dt} = 2x\frac{dx}{dt} + 2y\frac{dy}{dt}[/tex]
[tex]\frac{dd}{dt} = x\frac{dx}{dt} + y\frac{dy}{dt}[/tex]
From the velocities, we have that:
[tex]\frac{dx}{dt} = 40, \frac{dy}{dt} = 50[/tex]
From the velocities, and the time of half an hour, the positions are given as follows:
x = 0.5 x 40 = 20, y = 0.5 x 50 = 25.
Hence:
[tex]\frac{dd}{dt} = x\frac{dx}{dt} + y\frac{dy}{dt}[/tex]
[tex]\frac{dd}{dt} = 20(40) + 25(50)[/tex]
dd/dt = 2050.
The distance between them is increasing at a rate of 2050 km/h when they are 0.5 hours away from the harbor.
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6c3c² +d³ for c = 5 and d = 3
Answer:
6(5)3(5)² + (3)³
Step-by-step explanation:
Put this into your calculator just like this
Electric utility poles in the form of right cylinders are made out of wood that costs $13.72 per cubic foot. Calculate the cost of a utility pole with a radius of 0.75 ft and a height of 40 ft. Round your answer to the nearest cent.
Answer:
So what you have to do is go back to you lesson and read till you find an answer just like this one and read how to do it when u do that go back and to the quick check and find an answer that is similar. the reason why I'm telling you this is cause I cant calculate it right. or what you can do is calculate it right on here.
Step-by-step explanation:
https://www.inchcalculator.com/cubic-footage-calculator/
The numbers of students in the 8 schools in a district are given below.
(Note that these are already ordered from least to greatest.)
185, 235, 255, 266, 269, 303, 370, 381
Send data to calculator
Suppose that the number 381 from this list changes to 237. Answer the following.
(a) What happens to the median?
(b) What happens to the mean?
O It decreases by 0
O It increases by 0
O It stays the same.
O It decreases by 0
O It increases by 0
O It stays the same.
Part (a)
The middle values were nitially 266 and 269, but now they are 255 and 266. Thus, the median changes from 267.5 to 260.5, meaning it decreases by 7.
Part (b)
The sum before the change is 2264, but after, it is 2120. This means the sum decreased by 144, and thus the mean decreased by 16.
the ice rink sold 95 tickets for a total of 828.00. general admission tickets are $10.00 each and youth tickets are $8.00 each. how many of each did they sell
Answer:
GA =34
Y = 61
Step-by-step explanation:
GA= GENERAL ADMISSION =$10
Y= YOUTH =$8
GA+Y= 95
GA=95-Y
10GA+8Y=828
10(95-Y)+8Y=828
950-10Y+8Y=828
-2Y= 122 MULTIPLY BY (-1)
2Y= 122
Y= 61
GA= 34
There were 61 youth tickets sold and 34 general admission tickets
Question 5 of 10
This circle is centered at the origin, and the length of its radius is 10. What is
the circle's equation?
5+ 10.
O A ²+²=10
OB. +²2=100
O c. x10+10=100
O D. x+y=10
The equation of circle is [tex]x^2+y^2=100[/tex]
The standard equation of a circle with center (h, k) and radius r is given by:
[tex](x-h)^2+(y-k)^2=r^2[/tex] ........(1)
This is the equation needed for the circle with a center at A(h, k) and a radius equal to r since it describes the relationship between the coordinates of any point on the circumference.
Now according to the question, it is given that the circle has the center at origin and length of its radius is 10.
Center = (h, k)=(0, 0)
Radius(r) = 10 units
Now, substituting the given values in (1) we get;
⇒[tex]x^2+y^2=100[/tex]
Therefore, the equation of circle centered at origin with radius 10 is [tex]x^2+y^2=100[/tex]
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Find the slope-intercept form of the line through (−1,3) and (7,−8)
Answer:
[tex]\sf y =\dfrac{-11}{8}x +\dfrac{13}{8}[/tex]
Step-by-step explanation:
Slope-intercept form: y = mx + bHere, m is the slope and b is the y-intercept.
( -1, 3) ; x₁ = -1 & y₁ = 3
(7, -8) ; x₂ = 7 & y₂ = -8
Slope can be obtained by the formula:
[tex]\sf \boxed{\bf Slope = \dfrac{y_2-y_1}{x_2-x_1}}[/tex]
[tex]\sf =\dfrac{-8-3}{7-[-1]}\\\\\\=\dfrac{-8-3}{7+1}\\\\\\=\dfrac{-11}{8}[/tex]
Now, we can find the y-intercept,
[tex]\sf y = \dfrac{-11}{8}x + b\\\\Substitute \ any \ one \ of \ the \ point \ in \ the \ above \ equation.\\\\\text{Here, we are substituting (-1 ,3)}\\\\3 = \dfrac{-11}{8}*(-1) + b\\\\3 = \dfrac{11}{8}+b\\\\b = 3 - \dfrac{11}{8}\\\\b = \dfrac{3*8}{1*8}-\dfrac{11}{8}\\\\b= \dfrac{24-11}{8}\\\\b= \dfrac{13}{8}[/tex]
Slope-intercept form:
[tex]\sf y =\dfrac{-11}{8}x +\dfrac{13}{8}[/tex]
Hector earns $12 an hour plus a daily per diem of $15. This week he worked 4 days and earned a total of $444. Write an equation to find how many hours Hector worked this week.
The number of hours Hector worked this week is 32 hours.
Equation to find how many hours Hector worked this week.Amount Hector earned per hour = $12Additional amount earned daily = $15Number of days Hector worked this week = 4 Total amount Hector earned = $444Number of hours worked = x444 = 15(4) + 12(x)
open parenthesis444 = 60 + 12x
substract 60 from both sides444 - 60 = 12x
384 = 12x
divide both sides by 12x = 384/12
x = 32 hours
check:
444 = 60 + 12x
444 = 60 + 12(32)
444 = 60 + 384
444 = 444
Therefore, the number of hours Hector worked this week is 32 hours.
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Which number sentence is not true?
A.|-20|<20
B.|9|=9
C.|-20|>|9|
D.|9|<|20|
Answer:
A
Step-by-step explanation:
that should be an equal sign
You decide you need a new computer. The cost of the computer is $864. However, the store also offers a rent to own option which will cost $41 per week for 24 weeksHow much more will the rent to own option cost after you have made all of the payments?
Answer:
120
Step-by-step explanation:
the difference = 24×41-864=120
what are all values of x such that 1-2/3x<=-3 is satisfied
The possible values of x will belong to the set A = [9, ∞).
We have the following inequality -
1 - 2x/3 ≤ -3
We have to determine all values of x.
What is Inequality ?An inequality is a relation which makes a non-equal comparison between two numbers or other mathematical expressions.
According to the question, we have the following inequality -
1 - 2x/3 ≤ -3
Subtract 1 from both sides -
-2x/3 ≤ -4
Multiply by -1 on both sides -
2x/3 ≥ 4
Multiply by 3/2 on both sides -
x ≥ 9
Hence, the possible values of x will belong to the set A = [9, ∞).
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A sequence starting with 0 but each number is two times three less than the previous number
The sequence starting with 0 but each number is two times three less than the previous number is as follows:
0, -6, -12, -18, -22
How to find sequence?A sequence is defined as an arrangement of numbers in a particular order.
The most common sequence are the arithmetic and the geometric sequence.
The sequence starts with 0 but each number is two times three less than the previous number.
This means the first term of the sequence is 3.
Hence,
2 times 3 less than the previous number means:
Aₙ = Aₙ₋₁ - 2(3)
where,
n = number of termsLet's use the formula to find the other numbers in the sequence,
A₂ = A₂₋₁ - 2(3) = 0 - 6 = -6
A₃ = A₃₋₁ - 2(3) = -6 - 6 = -12
A₄ = A₄₋₁ - 2(3) = -12 - 6 = - 18
A₅ = A₅₋₁ - 2(3) = -18 - 6 = - 22
Therefore, the sequence starting with 0 but each number is two times three less than the previous number is as follows:
0, -6, -12, -18, -22
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Square root 3 x square root 2 x square root 5
Answer:
=sqrt of 30
Step-by-step explanation:
=sqrt of 3×2×5
=sqrt 30
Question
Graph the line passing through (3, 4) whose slope is m = -1.
Answer: See attached
Step-by-step explanation:
See attached
Multiple Choice
11) The intersection of 2 line segments can be
I.
a point
II. a line segment
a ray
IV.
a line
III.
A. I only
C. I and IV
12) The intersection of 2 distinct rays can be
I. a point
II. a line segment
III. a ray
IV. a line
A. I only
C. I, II and III
B. I and II
D. all of the above
I. a point
III. a ray
13) The intersection of 2 distinct lines can be
II. a line segment
IV. a line
A. I only
C. I, III and IV
B. IV only
D. all of the above
B. IV only
D. all of the above
Step-by-step explanation:
[tex](3 \sqrt{3 - 2 \sqrt{2)(3 \sqrt{3 - 2 \sqrt{2)} } } } [/tex]
here are four lengths of wood
Write and solve an equation to answer the question.
How many people must attend the third show so that the average attendance per show is 3000?
Write an equation.
Write an equation
write one
Equation:_ =3000
An equation to answer the question of how many people must attend the third show to have an average attendance of 3,000 when the other show attendance numbers are 2580, and 2920 is 9,000 = 2,580 + 2,920 + x.
What is an equation?An equation is a mathematical expression or statement that shows that two values are equal.
An equation uses the equation mark (=).
Data and Calculation:To have an average attendance per show of 3,000 for three shows, a total of 9,000 people must attend the three shows (3,000 x 3).
Attendance for the first show = 2,580
Attendance for the second show = 2,920
Total attendance for the two shows = 5,500
Required attendance for the third show, x = 9,000 = 2,580 + 2,920 + x
x = 9,000 - 5,500
x - 3,500
Thus, the equation for the third show attendance is 9,000 = 2,580 + 2,920 + x where x = 3,500.
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Question Completion:And the other show attendance numbers are 2580 and 2920.
What inequality represents all the values of x for y <
-5(x - 8) - 2 when y = 7?
Answer:
(−∞, 31/5) or x <31/5 (the graph will start a little bit past 6 and will be a open circle and head to the left)
Answer:
x< 6[tex]\frac{1}{5}[/tex]
Step-by-step explanation:
7<-5(x -8) - 2 Distribute the 5
7<-5x + 40 - 2
7<-5x +38 Subtract 38 from both sides
-31<-5x Divide both sides by -5
[tex]\frac{31}{5}[/tex] >x When you divide both sides by a negative number, you must flip the sign.
or
x < 6 [tex]\frac{1}{5}[/tex]
You have 8 times as many dimes as nickles. You have 18 dimes and nickles altogether. How much money do you have in all?
Answer:
$1
Step-by-step explanation:
If you have x dimes, you have 8x nickels.
So, this means x + 8x = 18.
9x = 18 (combine like terms)x = 2 (divide both sides by 2)This means you have 2 dimes and 16 nickels, which have a combined value of 2(0.10)+16(0.05)=$1.
(3x-3)
(4y+4)°/60°
Solve for x and y. Explain.
The value of x and y is y=29, X=21.
180-60=120
4y+4=120 get y by itself and remember that what ever you do to one side you do to the other.
Alternate interior angles are congruent so 3x-3=60
What is an angle ?
Angle is the figure formed by two rays, called the sides of the angle, sharing a common endpoint, called the vertex of the angle. Angles formed by two rays lie in the plane that contains the rays. Angles are also formed by the intersection of two planes. These are called dihedral angles.
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3
Un camión está cargado con 10 pies cúbicos de pajote. El chofer entrega 25
C
3
pies cúbicos de pajote en la primera parada y 3 pies cúbicos de pajote en la
segunda parada. En la tercera parada recoge 11½ pies cúbicos de pajote que no
quiere el cliente. ¿Cuánto pajote queda en el camión después de la tercera
parada?
Answer is 140
According to the question,
Given that,
111 + 10 + 25 - 2 × 3
calculate the term
121 + 25 - 6
121 + 19
140
Una solicitud de licencia de manejar comercial
(DL 44C). Al firmar este formulario significa
que usted se compromete a hacerse un análisis
químico para determinar el contenido de alcohol
o drogas en su sangre. Si se niega a firmarlo, el
Departmento de Vehículos Motorizados (DMV)
no expedirá o renovará su licencia de manejar.
• Su nombre verdadero y completo.
• Un reporte de examen médico aprobado Medical Examination Report (MER). El formulario
federal válido (orginal o copia) del reporte del
examen médico Medical Examination Report
(MER) (MCSA-5875) y el formulario del certificado del examinador médico Medical Examiner’s Certificate Form (MEC) MCSA-5876
al solicitar la licencia de manejar o el permiso;
tal reporte debe ser expedido por un doctor en
los Estados Unidos que esté licenciado en medicina (M.D.), un doctor licenciado en osteopatía
(D.O.), un médico asistente con licencia (P.A.),
un enfermero practicante avanzado y registrado
(APN) o un doctor quiropráctico autorizado. Los
conductores que tengan certificados para manejar autobuses escolares, autobuses de actividades
estudiantiles School Pupil Activity Bus Certificate (SPAB), autobuses de jóvenes, vehículos
paratránsito para el público en general General
Public Paratransit Vehicle (GPPV) o co certificados para manejar vehículos de labores agrícolas
deben tener un examen médico expedido por
un doctor en medicina, un médico asistente con
licencia, un enfermero practicante avanzado y
registrado o un quiropráctico que esté autorizado en el registro nacional de examinadores médicos certificados National Registry of Certified
Medical Examiners (§12517.2 del CVC).
Se requiere un reporte médico fechado en los 2
últimos años para cualquier tipo de solicitud de
licencia CDL y luego cada 2 años.
Nota: No envíe por correo su reporte médico
a la patrulla de caminos California Highway
Patrol (CHP). El formulario MER y el formulario
del certificado MEC pueden presentarse en una
oficina del DMV o ser enviados por correo directamente al DMV para actualizarlos. Envíe por
correo sus formularios MER y MEC a la siguientedirección por lo menos 4 semanas antes que se
venza su reporte médico anterior o su privilegio
para manejar vehículos CMV puede invalidarse.
Envíe el reporte médico a:
Department of Motor Vehicles
CDL/PDPS Unit, MS G204
PO Box 942890
Sacramento, CA 94290-0001
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PLEASE HELP SIMPLIFY 4(m + ( -2) + 15
Answer:
[tex] \sf \large \: 4m+52[/tex]
Step-by-step explanation:
4(m−2+15)
=(4)(m+−2+15)
=(4)(m)+(4)(−2)+(4)(15)
=4m−8+60
=4m+52
Answer:
4m+52
Step-by-step explanation:
To get to 1, divide 60 by
From 1, multiply by
OR, in a single step, multiply 60 by
to get to 25.
to get to 25. Submit Answer
To get to 1 we have to divide 60 by 60, and to get 25 we have to multiply 60 with 5/12 or 0.41.
Given that we have to get 1 by dividing 60 by something and multiply 60 by something to get 25.
We are required to find those numbers.
Take first result:
Suppose the number which divides 60 be x.
So,
60/x=1
x=60
Number will be 60.
Take second result:
Suppose the number which multiplied with 60 to get 25 be y.
So,
60*y=25
y=25/60
y=0.41
Number will be 0.41.
Hence to get to 1 we have to divide 60 by 60, and to get 25 we have to multiply 60 with 5/12 or 0.41.
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To make a sand sculpture Arthur used 2 cm³ of red sand with a density of 4 g/cm³ 7 cm³ of yellow sand with a density of 5 g centimeter and 5 cm³ of brown sand with a density of 6 g cubiccm³ what is the average density of the sculpture in grams per cubic centimeter express your answer as decimal to the nearest 10th.
Answer:
5.2 g/cm³
Step-by-step explanation:
Given a sculpture consisting of 2 cm³ at 4 g/cm³, 7 cm³ at 5 g/cm³, and 5 cm³ at 6 g/cm³, you want its average density.
MassThe total mass of the sculpture is the sum of the masses of the components. Each of those is the product of its volume and density.
red sand: (2 cm³)(4 g/cm³) = 8 g
yellow sand: (7 cm³)(5 g/cm³) = 35 g
brown sand: (5 cm³)(6 g/cm³) = 30 g
The total mass of the sculpture is ...
total mass = 8 g + 35 g + 30 g = 73 g
VolumeThe total volume of the sculpture is the sum of the volumes of its parts:
total volume = 2 cm³ +7 cm³ +5 cm³ = 14 cm³
Average densityThe density is the ratio of mass to volume:
ρ = (total mass)/(total volume) = (73 g)/(14 cm³) = 73/14 g/cm³
= 5 3/14 g/cm³ ≈ 5.2 g/cm³
The average density of the sculpture is about 5.2 g/cm³.
Write 0.45 kg in g, mg and ng
Answer:
450g
450,000mg
450,000,000,000ng
Explaination:
Kg to g (x1,000)
Kg to mg (x1,000,000)
kg to ng (x1,000,000,000,000)