Answer:
12
Step-by-step explanation:
To find the greatest common factor if 72 and 84 first we need to find factors of them separately
72 : 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72
84 : 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 84
there are 6 common factors that are 1, 2, 3, 4, 6, and 12
Therefore, the highest common factor of 72 and 84 is 12.
we can find highest common factor by other method called prime factorization for the you need to factorize them separately
prime factorization of
72 : 2 × 2 × 2 × 3 × 3
84: 2 × 2 × 3 × 7
now we have to find common prime factors
those are 2 × 2 × 3
now multiply them
= 12
The greatest common factor of 72 and 84 is 12
What is HCF?The HCF (Highest Common Factor) of two or more numbers is the highest number among all the common factors of the given numbers.
Given is to find the greatest common factor or HCF of 72 and 84.
We will first find the factors of each of the numbers given.
The factors of 72 are as follows : 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72.
The factors of 84 are as follows : 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 84.
Check the bolded numbers. It can be seen that it is both common and largest of the other common numbers. From the definition of HCF, we can write that the HCF of 72 and 84 would be 12. So, the greatest common factor or HCF is 12.
Therefore, the greatest common factor of 72 and 84 is 12.
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Casey went to the store and purchased 12 pairs of socks, and 3 pairs of shoes for $18.20 each. She spent a total of $81.60. How much did she pay for each pair of socks?
Which equation represents a population of 490 animals that increases at an annual rate of 20% ?
Answer:
Step-by-step explanation:
The standard form of this exponential function is
[tex]y=a(b)^x[/tex] where a is the initial value and b is the growth rate. Our initial value is 490 and our growth rate is .2 so the equation is
[tex]y=490(.2)^x[/tex]
Mr. Mathman had a square frame with an area of 175.6 ft². Which measurement is the closest to the side length of Mr. Mathman’s frame?
A) 88 feet
B) 15 feet
C) 44 feet
D) 13 feet
Answer:
Fifteen feet is the closest to the side length of the frame, have a good day
Jayla and her mom are making a cake.
They add % c flour and 3/2 c sugar.
:)
If the total amount of batter is 4 lc,
how many cups of other ingredients
are included?
The text in the bottom of the v=10 is what I’m confused in
Answer:
Other ingredients is 2
v =10 is the answer of 5th question (-40)/-4 = 10
Step-by-step explanation:
I. Find sum of flour and sugar
when c is cup, flour = 3/4 and sugar is 3/2
[tex]\frac{3}{4} +\frac{3}{2} = \frac{9}{4}[/tex] or [tex]2\frac{1}{4}[/tex]
II. If total is [tex]4\frac{1}{4}[/tex]
so [tex]4\frac{1}{4} - 2\frac{1}{4}[/tex] = 2
Hope that help :D
solve 4m plus 2n equals 5n for m.
Answer:
m = (3/4) n
Step-by-step explanation:
4m + 2n = 5n
The subtraction property of equality states that we can subtract 2n from both sides to isolate the m and its coefficient to get
4m = 3n
The division property of equality states that we can divide 4 from both sides to isolate only the m (we divide by 4 because anything divided by itself equals 1) to get
m = (3/4) n
Which of the following are rational numbers?
Step-by-step explanation:
square cube 214
I think this was your answer
So like for integers when it’s only 28 - 19 do you change the negative to a positive like 28 - 19?
Answer:
Sorry I don't really understand your question, but 28-19 is 9 therefore 9 is more than 0
9 >0
Are a total of 127 Cars And trucks on a lot. If there. For more than twice the number of trucks, then cars, how many cars and trucks are on the lot?
Answer:
41 cars and 86 trucks
Step-by-step explanation:
C+T=127
2C+4=T
C+(2C+4)=127
3C+4=127
3C=123
C=41When C=41,
41+T=127
T=127-41
T=86
Can you please show all your work plus the equation.
Answer:
25°
Step-by-step explanation:
20°--5°=
20°+5°=
25°
Answer: fell 25 degrees
Step-by-step explanation: 20-25= -5
//Give thanks(and or Brainliest) if helpful (≧▽≦)//
The length of a sandbox is three feet longer than its width. What expression would represent the area of the sandbox
Expression represent the area of the sandbox is a² + 3a
GIven that;
Length of sandbox is three feet longer than its width
Find:
Expression represent the area of the sandbox
Computation:
Assume;
Width of sandbox = a feet
So,
Length of sandbox = (a + 3) feet
[tex]Area\ of\ rectangle = Length \times Width[/tex]
So,
Area of the sandbox = Length of sandbox × Width of sandbox
Area of the sandbox = (a + 3) × a
Area of the sandbox = a² + 3a
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What is the
range of the function graphed below? I am in desperate need of answer
Answer:
B
Step-by-step explanation:
look at where the line reaches on the y-axis
-6k+1=-2+7k
Help plz !
Answer:
k=3/13
Step-by-step explanation:
Rearrange terms
Subtract
from both sides of the equation
Simplify
Subtract
from both sides of the equation
Simplify
Divide both sides of the equation by the same term
Simplify
Answer:
[tex]k=\frac{3}{13}[/tex]
Step-by-step explanation:
[tex]-6k+1=-2+7k[/tex]
Subtract 1 from both sides:-
[tex]-6k=7k-3[/tex]
Now, Subtract 7k from both sides:-
[tex]-6k-7k=7k-3-7k[/tex]
[tex]-13k=-3[/tex]
Divide both sides by -13:-
[tex]\frac{-13k}{-13}=\frac{-3}{-13}[/tex]
[tex]x=3/13[/tex]
OAmalOHopeO
The angle,2Θ, lies in the third quadrant such that cos2Θ=-2/5. Determine an exact value for tanΘ . Show your work including any diagrams if you plan to use them. (3 marks)
Answer:
[tex]tan(\theta)=\frac{\sqrt{21}}{3}[/tex]
Step-by-step explanation:
1. Approach
One is given the following information:
[tex]cos(2\theta)=-\frac{2}{5}[/tex]
One can rewrite this as:
[tex]cos(2\theta)=-0.4[/tex]
Also note, the problem says that the angle ([tex]2\theta[/tex]) is found in the third quadrant.
Using the trigonometric identities ([tex]cos(2\theta)=2(cos^2(\theta))-1[/tex]) and ([tex]cos(2\theta)=1-2(sin^2(\theta))[/tex]) one can solve for the values of ([tex]cos(\theta)[/tex]) and ([tex]sin(\theta)[/tex]). After doing so one can use another trigonometric identity ([tex]tan(\theta)=\frac{sin(\theta)}{cos(\theta)}[/tex]). Substitute the given information into the ratio and simplify.
2. Solve for [tex](cos(\theta))[/tex]
Use the following identity to solve for ([tex]cos(\theta)[/tex]) when given the value ([tex]cos(2\theta)[/tex]).
[tex]cos(2\theta)=2(cos^2(\theta))-1[/tex]
Substitute the given information in and solve for ([tex]cos(\theta)[/tex]).
[tex]cos(2\theta)=2(cos^2(\theta))-1[/tex]
[tex]-0.4=2(cos^2(\theta))-1[/tex]
Inverse operations,
[tex]-0.4=2(cos^2(\theta))-1[/tex]
[tex]0.6=2(cos^2(\theta))[/tex]
[tex]0.3=cos^2(\theta)[/tex]
[tex]\sqrt{0.3}=cos(\theta)[/tex]
Since this angle is found in the third quadrant its value is actually:
[tex]cos(\theta)=-\sqrt{0.3}[/tex]
3. Solve for [tex](sin(\theta))[/tex]
Use the other identity to solve for the value of ([tex]sin(\theta)[/tex]) when given the value of ([tex]cos(2\theta)[/tex]).
[tex]cos(2\theta)=1-2(sin^2(\theta))[/tex]
Substitute the given information in and solve for ([tex]sin(\theta)[/tex]).
[tex]cos(2\theta)=1-2(sin^2(\theta))[/tex]
[tex]-0.4=1-2(sin^2(\theta))[/tex]
Inverse operations,
[tex]-0.4=1-2(sin^2(\theta))[/tex]
[tex]-1.4=-2(sin^2(\theta))[/tex]
[tex]0.7=sin^2(\theta)[/tex]
[tex]\sqrt{0.7}=sin(\theta)[/tex]
Since this angle is found in the third quadrant, its value is actually:
[tex]sin(\theta)=-\sqrt{0.7}[/tex]
4. Solve for [tex](tan(\theta))[/tex]
One can use the following identity to solve for [tex](tan(\theta))[/tex];
[tex]tan(\theta)=\frac{sin(\theta)}{cos(\theta)}[/tex]
Substitute the values on just solved for and simplify,
[tex]tan(\theta)=\frac{sin(\theta)}{cos(\theta)}[/tex]
[tex]tan(\theta)=\frac{-\sqrt{0.7}}{-\sqrt{0.3}}[/tex]
[tex]tan(\theta)=\frac{\sqrt{0.7}}{\sqrt{0.3}}[/tex]
[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}}}{\sqrt{\frac{3}{10}}}[/tex]
Rationalize the denominator,
[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}}}{\sqrt{\frac{3}{10}}}[/tex]
[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}}}{\sqrt{\frac{3}{10}}}*\frac{\sqrt{\frac{3}{`0}}}{\sqrt{\frac{3}{10}}}[/tex]
[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}*\frac{3}{10}}}{\sqrt{\frac{3}{10}*\frac{3}{10}}}[/tex]
[tex]tan(\theta)=\frac{\sqrt{\frac{21}{100}}}{\frac{3}{10}}[/tex]
[tex]tan(\theta)=\frac{\frac{\sqrt{21}}{10}}{\frac{3}{10}}[/tex]
[tex]tan(\theta)=\frac{\sqrt{21}}{10}*\frac{10}{3}[/tex]
[tex]tan(\theta)=\frac{\sqrt{21}}{3}[/tex]
Problem 2: Vector v has initial point (4, 3) and terminal point (-7, 9). Write v as a linear combination of the standard unit vectors i and j.
We have
v = (-7, 9) - (4, 3) = (-7 - 4, 9 - 3) = (-11, 6)
which as a linear combination of the i and j unit vectors is
v = -11i + 6j
Answer:
Step-by-step explanation:
ok how do you add pictures
problem #1 help please
Given the following triangle. Find c
A.18v17
B.6v17
C.3v34
D.12
Answer:
The choose C.3√34
Step-by-step explanation:
15²+9²=c²
225+81=c²
306=c²
C= 3√34
I hope I helped you^_^
Please help its due in 30 minutes will mark braniliest
Answer:
a point
Step-by-step explanation:
because it really seems like a point I dunno
you buy 4 video tapes for 14.99 each and 3 dvds for 19.99 each find the total cost of the movies
Answer:
119.93
Step-by-step explanation:
I will assume the total of the cost of the movies will be the total.
the total = 4*14.99 + 3*19.99
total = 119.93
{x:x is a natural number and x is greater than 70} write the set in listed form.
Answer:
{71,72,73,74,75,76,77,78,79,80}Step-by-step explanation:
natural numbers start from one but it says greater than 70 so it will start from 71 but to any number as long as it is greater than 70
Can Someone help me!
Answer:50 degree
Step-by-step explanation:
It is an isosceles triangle so two sides and angles are equal. The first line is facing the first angle so the second angle ( m<DEF) = 65 degrees because both angles are equal.
This implies that m<FED =
65 + 65+ <FED= 180( sum of angle in a triangle)
130 + <FED=180
<FED= 180- 130
<FED= 50 degree
Perform the indicated operations. Write the answer in standard form, a+bi.
-4+4i / -3-6i
Answer:
[tex] \frac{ - 4 + 4i}{ - 3 - 6i} \\ multiply \: and \: divide \: by \: - 3 + 6i \\ \frac{ - 4 + 4i}{ - 3 - 6i} \times \frac{ - 3 + 6i}{ - 3 + 6i} \\ = \frac{ ( - 4 + 4i)( - 3 + 6i)}{ ( - 3 - 6i)( - 3 + 6i)} \\ = \frac{12 - 24i - 12i + 24 {i}^{2} }{ {( - 3)}^{2} - {(6i)}^{2} } \\ = \frac{12 - 24 - 36i}{9 + 36} \\ = \frac{ - 12 - 36i}{45} \\ \frac{ - 36i}{45} + \frac{ - 12}{45} \\ thank \: you[/tex]
what is line PR called
Answer:
A radius is a line segment with one endpoint at the center of the circle and the ... is called the midpoint, and arc PQ ≅ arc PR if and only if PQ ≅ PR.
Step-by-step explanation:
brainliest please
Answer:
A radius is a line segment with
help please I need help
[tex]40x = 60x(x - 1) \\ \\ 7 \times \frac{7x}{2} - 29x = - 9 [/tex]
Answer:
[tex]40x = 60(x - 1) \\ \\ 2x = 3x - 3 \\ \\ x = 3 \\ \\ \\ 7 \times \frac{7x}{2} - 29x = - 9 \\ \\ 49x - 58x = - 18 \\ \\ - 9x = - 18 \\ \\ x = 2[/tex]
Answer:
#140x = 60x(x - 1)40x = 60x² - 60x60x² - 100x = 03x² - 5x = 0x(3x - 5) = 0x = 0 or3x = 5 ⇒ x = 5/3#27×7x/2 - 29x = - 949x/2 - 29x = - 949x - 58x = - 18-9x = -18x = -18/-9x = 2Please answer ASAP please and thank and also please draw it on the modle
Answer:
5/12
Step-by-step explanation:
1x5/2x6
Two numbers are in the ratio 1:2. If 7 is to be added to both, then ratio changes to 3:5, find the numbers
Let numbers be x and 2x
ATQ
[tex]\\ \rm\longmapsto \dfrac{x+7}{2x+7}=\dfrac{3}{5}[/tex]
[tex]\\ \rm\longmapsto 5(x+7)=3(2x+7)[/tex]
[tex]\\ \rm\longmapsto 5x+35=6x+21[/tex]
[tex]\\ \rm\longmapsto 6x-5x=35-21[/tex]
[tex]\\ \rm\longmapsto x=14[/tex]
2x=2(14)=28yearsn order to better manage his money, Joe kept track of his monthly grocery bills for the past six months to see how much he had spent. These amounts appear in the table.
Round each number in the table to the nearest hundred and estimate the total amount of money Joe should budget for groceries for the next 6 months.
Answer:
1,100
Step-by-step explanation:
200 + 200 + 200 + 200 + 100 + 200
Total amount after rounding off will be : 900
What is Rounding of numbers to nearest hundred ?
Rounding off a number to the nearest hundred means that you have to look or find the hundred which is closest to the given number and then write that as the rounded-off number .
Rounding off each number in the table to the nearest hundred :
1) 223 ( since , we have 223 and 223 < 250 . Since, 223 is closest to 200 as compared to 300 , after rounding it off we will get 200 instead of choosing 300) = 200
2) 189 =200
3) 210 = 200
4) 164 = 200
5) 148 = 100
6) 206 = 200
Total amount after rounding of numbers will be = 200 + 200 + 200 + 100 + 200
= 900
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Which is an
appropriate estimate
for this addition
problem?
462
543
844
+ 921
The lifeguard on duty gets 10 minutes a break for every two hours how much break time does the lifeguard get during a six hour shift
Answer:
The lifeguard would get a 30 minute break.
Step-by-step explanation:
6 hours ÷ 2 hours = 3
3 x 10 = 30 minutes
EFGH is a rectangle. EA is 12 in. Find the length of the diagonal EH
26 in.
12 in.
24 in.
6 in.
Answer:
your answer is 24 in
I hope it's helps you
The length of the diagonal is 24 inches
From the given diagram, the length of the diagonal is twice the length EA
Mathematically;
EH = 2EA
Given the parameter:
EA = 12in
EH = 2(12)
EH = 24 in
Hence the length of the diagonal is 24 inches
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