why is an inflated balloon likely to burst if you leave it near a window with the sun streaming in it?

Answers

Answer 1

Answer:

Because the plastic of the balloon will eventually get to such I heat the radiation from the sun would cause it to pop

Explanation:

that is my answer

Answer 2

Answer:

because the heat melts  the rubber and when it does it pops when it gets to hot

Explanation:


Related Questions

Increasing the number of turns on the generator coil....? 1 point Increases the voltage output. Does not alter the output voltage. Reduces the output voltage.

Answers

Answer:

increases the voltage output

Explanation:

By Increasing the number of turns on the generator coil , the output volatge of a generator increases. However, there are various other methods availbble to increase the output voltage of a generator. Some of these can be

1. By increasing the rpm of generator coil.

2. By using stronger magnets

What exercise will strengthen your legs?

Biking
Stretching
Lifting a box
Playing catch

Answers

Biking will strengthen your legs

Answer:

biking

Explanation:

To make the Bike move you peddle with your legs.

A -0.6 C charge that moves downward is in a uniform electric field with a strength of 200 N/C what is the magnitude and direction of the force on the charge

Answers

Answer:

The magnitude and direction of the force on the charge is 120 N in the direction of the charge.

Explanation:

Given;

magnitude of the charge, q = 0.6 C

electric field strength, E = 200 N/C

The magnitude of the electric force is calculated as;

F = Eq

where;

F is the magnitude of the force

Substitute the given values and solve for F;

F = (200)(0.6)

F = 120 N in the direction of the charge.

Therefore, the magnitude and direction of the force on the charge is 120 N in the direction of the charge.

traveling at about 30 mph, how many feet will the average driver cover from the time they see the danger until they hit the brakes

Answers

Answer: 75 ft

Explanation:

Breaking distance = Speed²/ 20

= 30²/20

= 45 feet

Stopping distance = Speed + braking distance

= 30 + 45

= 75 ft

Sudhir walks 0.40 km in a direction 60.0° west of north, then goes 0.50 km due west. What is his displacement?

Answers

Answer:

The displacement of Sudhir is 0.781 km.

Explanation:

Given;

initial distance, d₁ = 0.4 km = 400 m, N60.0°W

final distance, d₂ = 0.5 km

Make a sketch of Sudhir motion to form a right angled triangle;

(Check image uploaded).

Apply cosine rule to determine d "displacement"

d² = 500² + 400² - (2 x 500 x 400 x cos 120)

d² = 410,000 - (400,000 x -0.5)

d² = 410,000 - (-200,000)

d² = 410,000  + 200,000

d² = 610,000

d = √610000

d = 781.03 m

d = 0.781 km

Therefore, the displacement of Sudhir is 0.781 km.

HELP ME ASAP PLEASE!!Which natural phenomenon can trigger a landslide?
O intense rain or an earthquake
O light breezes or a flowing stream
O heavy snow or continuous sunlight
O icy conditions or ground surface melting

Answers

Answer:

O Intense rain or an earthquake

Explanation:

Landslides can be initiated in slopes already on the verge of movement by rainfall, snowmelt, changes in water level, stream erosion, changes in ground water, earthquakes, volcanic activity, disturbance by human activities, or any combination of these factors.

Intense rain or an earthquake can trigger a landslide.

Landslide is a natural phenomenon in which a mass of rock and/or earth moves down a slope.

An earthquake is a major geologic hazard that shakes the Earth and thus can induce a landslide.

Intense rain can also induce a landslide because humidity on the ground also leads to disturbances in the natural stability of the slope.

In conclusion, intense rain or an earthquake can trigger a landslide.

Learn more about landslides here:

https://brainly.com/question/7555672

A boy throws rocks with an initial velocity of 12m/s [down] from a 20 m bridge into a river. Consider the river to be at a height of 0 m. Draw a velocity-time and position-time graph. Use up as position and ignore air resistance.

Answers

Answer:

Please find attached the Velocity-Time graph, the Displacement-Time graph and the combined Velocity/Displacement-Time graph, created with Microsoft Excel

Explanation:

The given parameters are;

The initial velocity with which the boy throws the rock, u = 12 m/s

The direction in which he throws the rock = Down

The height from which the rock was thrown, h = 20 m

The height at which the river is located = 0 m

The kinematic equation of motion, of the rock can be given as follows;

h = u·t + 1/2·g·t²

Where;

t = The time of motion of the rock

g = The acceleration due to gravity = 9.8 m/s²

h = The height from which the rock is thrown = 20 m

Substituting the known values into given equation, we get;

20 = 12·t + 1/2·9.8·t² = 12·t + 4.9·t²

4.9·t² + 12·t - 20 = 0

t = (-12 ± √(12² - 4×4.9×(-20)))/(2 × 4.9) = (-12 ± √(242))/(9.8)

t ≈ -3.587 seconds or t ≈ 1.138 seconds

Attached please find the Velocity-Time graph, the Displacement-Time graph and the combined Velocity/Displacement-Time graph, created with Microsoft Excel.

a horizental force of 310n exerted on 2.0kg ball as it rotates ( at arm's length) uniformly in horizental circle of radius 0.0.90m calculate the speed of the ball ​

Answers

Answer:

v=11.8m/s

Explanation:

speed of the ball

Force=mass*centripetal acceleration

Centripetal acceleration= V2/r

F=M*V2/r

Data

F=310N

M=2.0kg

r=0.90m

v=?

310N=(2.0kg)*V2/0.90m

cross multiply

279Nm=(2.0kg)V2

V2= 279Nm/2.0kg

V2=139.5Nm/kg

apply square root both sides

√V2=√139.5

V=11.8m/s

A projectile is shot a cliff of 20m high, at an angle of 60o with respect to the horizontal, and it lands on the ground 8 seconds later. Find: a) the initial speed ? b) the speed of the projectile after 4 s c) the horizontal range d)the maximum height it reached e) what was the speed of the projectile when it landed on the ground?

Answers

Answer:

a) The initial speed of the projectile is approximately 42.410 meters per second.

b) The speed of the projectile after 4 seconds is approximately 21.352 meters per second.

c) The horizontal range of the projectile is 169.64 meters.

d) The maximum height of the projectile is 68.775 meters.

e) The speed of the projectile when it landed on the ground is approximately 46.807 meters per second.

Explanation:

According to the statement, the projects shows a parabolic motion, which consists in the combination of horizontal uniform motion and vertical uniformly accelerated motion due to gravity. This motion is represented by the following equations of motion:

[tex]x = x_{o} + v_{o}\cdot t\cdot \cos \theta[/tex] (1)

[tex]y = y_{o} + v_{o}\cdot t\cdot \sin \theta + \frac{1}{2}\cdot g\cdot t^{2}[/tex] (2)

Where:

[tex]x_{o}[/tex], [tex]x[/tex] - Initial and current horizontal position, measured in meters.

[tex]y_{o}[/tex], [tex]y[/tex] - Initial and current vertical position, measured in meters.

[tex]\theta[/tex] - Launch angle, measured in sexagesimal angle.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]t[/tex] - Time, measured in second.

a) By using (2) and knowing that [tex]y_{o} = 20\,m[/tex], [tex]y = 0\,m[/tex], [tex]t = 8\,s[/tex], [tex]\theta = 60^{\circ}[/tex] and [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], then initial speed of the projectile is:

[tex]v_{o}\cdot t \cdot \sin \theta = y-y_{o}-\frac{1}{2}\cdot g\cdot t^{2}[/tex]

[tex]v_{o} = \frac{y-y_{o}-\frac{1}{2}\cdot g\cdot t^{2} }{t\cdot \sin \theta}[/tex]

[tex]v_{o} = \frac{0\,m-20\,m-\frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right)\cdot (8\,s)^{2} }{(8\,s)\cdot \sin 60^{\circ}}[/tex]

[tex]v_{o} \approx 42.410\,\frac{m}{s}[/tex]

The initial speed of the projectile is approximately 42.410 meters per second.

b) The vertical component of the velocity of the projectile is determine by differentiating (2) in time and substitute all known values:

[tex]v_{y} = v_{o}\cdot \sin \theta +g\cdot t[/tex] (3)

([tex]v_{o} \approx 42.410\,\frac{m}{s}[/tex], [tex]\theta = 60^{\circ}[/tex], [tex]g = -9.807\,\frac{m}{s^{2}}[/tex] and [tex]t = 4\,s[/tex])

[tex]v_{y} = -2.5\,\frac{m}{s}[/tex]

The horizontal component of the velocity of the projectile is:

[tex]v_{x} = v_{o}\cdot \cos \theta[/tex]

[tex]v_{x} = 21.205\,\frac{m}{s}[/tex]

And the speed of the projectile is determined by Pythagorean Theorem:

[tex]v = \sqrt{v_{x}^{2}+v_{y}^{2}}[/tex]

[tex]v = \sqrt{\left(21.205\,\frac{m}{s} \right)^{2}+\left(-2.5\,\frac{m}{s} \right)^{2}}[/tex]

[tex]v \approx 21.352\,\frac{m}{s}[/tex]

The speed of the projectile after 4 seconds is approximately 21.352 meters per second.

c) By (1) we find the horizontal range of the projectile:

([tex]x_{o} = 0\,m[/tex], [tex]v_{o} \approx 42.410\,\frac{m}{s}[/tex], [tex]\theta = 60^{\circ}[/tex], [tex]g = -9.807\,\frac{m}{s^{2}}[/tex] and [tex]t = 8\,s[/tex])

[tex]x = 0\,m + \left(42.410\,\frac{m}{s} \right)\cdot (8\,s)\cdot \cos 60^{\circ}[/tex]

[tex]x = 169.64\,m[/tex]

The horizontal range of the projectile is 169.64 meters.

d) The projectile reaches its maximum height when velocity is zero. By (3) and knowing that [tex]v_{y} = 0\,\frac{m}{s}[/tex], [tex]v_{o} \approx 42.410\,\frac{m}{s}[/tex] and [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], the time associated with maximum height is:

[tex]0\,\frac{m}{s} = \left(42.410\,\frac{m}{s}\right)\cdot \sin 60^{\circ}+\left(-9.807\,\frac{m}{s^{2}} \right) \cdot t[/tex]

[tex]t = 3.745\,s[/tex]

And by (2) and knowing that [tex]y_{o} = 20\,m[/tex], [tex]v_{o} \approx 42.410\,\frac{m}{s}[/tex], [tex]t = 3.745\,s[/tex], [tex]\theta = 60^{\circ}[/tex] and [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], the maximum height reached by the projectile is:

[tex]y = 20\,m + \left(42.410\,\frac{m}{s} \right)\cdot (3.745\,s)\cdot \sin 60^{\circ}+\frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right)\cdot (3.745\,s)^{2}[/tex]

[tex]y = 68.775\,m[/tex]

The maximum height of the projectile is 68.775 meters.

e) If we know that [tex]y_{o} = 20\,m[/tex], [tex]v_{o} \approx 42.410\,\frac{m}{s}[/tex], [tex]t = 8\,s[/tex], [tex]\theta = 60^{\circ}[/tex] and [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], the components of the speed are, respectively:

[tex]v_{y} = \left(42.410\,\frac{m}{s}\right)\cdot \sin 60^{\circ} + \left(-9.807\,\frac{m}{s^{2}} \right)\cdot (8\,s)[/tex]

[tex]v_{y} = -41.728\,\frac{m}{s}[/tex]

[tex]v_{x} = v_{o}\cdot \cos \theta[/tex]

[tex]v_{x} = 21.205\,\frac{m}{s}[/tex]

And the speed of the projectile is determined by Pythagorean Theorem:

[tex]v = \sqrt{v_{x}^{2}+v_{y}^{2}}[/tex]

[tex]v = \sqrt{\left(21.205\,\frac{m}{s} \right)^{2}+\left(-41.728\,\frac{m}{s} \right)^{2}}[/tex]

[tex]v \approx 46.807\,\frac{m}{s}[/tex]

The speed of the projectile when it landed on the ground is approximately 46.807 meters per second.

State Ohms law o derive relation between
Vel and R Draw the graph between
vanda​

Answers

Answer:

Explanation:

V = I*R

V/R = I

Rank this objects in order of their acceleration small to larger

Answers

Answer:

The answer is "DACB".

Explanation:

The missing data of the question is defined in the attached file please find it.

Using formula:

[tex]\to F= m \cdot a\\\\ \to m= 5 \ kg[/tex]

In object A:

[tex]F= 15 \\\\a =\frac{F}{m} = \frac{15}{5} = 3[/tex]

In object B:

[tex]F= 30 \\\\a =\frac{F}{m} = \frac{30}{5} = 6[/tex]

In object C:

[tex]F= 20 \\\\a =\frac{F}{m} = \frac{20}{5} = 4[/tex]

In object D:

[tex]F= 0 \\\\a =\frac{F}{m} = \frac{0}{5} = 30[/tex]

That's why the answer is "DACB" .

An electric heater is rated at 1500 W. If the heater is rated as 80% efficient, calculate the output
rate of energy​

Answers

Answer:

Power = 1200 [W].

Explanation:

The efficiency of an electrical equipment is defined as the relationship between the power realized, over the power that is consumed. For this case, they give us the data of consumed power and efficiency in this way we can calculate the power that the equipment performs.

[tex]Efficency=\frac{Power_{done}}{P_{consumed}}\\0.8 = \frac{Power_{done}}{1500} \\Power_{done}=1500*0.8\\Power_{done} = 1200 [W][/tex]

This means that of the 1500 [W], 1200 [W] are actually used to get the job done. This is established by means of the first law of thermodynamics.

1.What is the influence of Greek Philosophy on the understanding of human-environment? What is the implication of this on the relationship of human beings and the human environment?

Answers

Explanation:

The theory which is linked to person and climate is more concerned with Mother Nature and human's position within it. It is a misconception that humans are the most important species on this planet and they are relying on other species for their life. Conservation ethics also revolve around making human societies and habitats healthier, preserving vital resources for the present and future. This philosophical approach values the human/nonhuman interaction of nature, understanding how humans and the world have a continuing causal association with one another.

Derive 3:
v2=u2 + 2as​

Answers

I HAVE ATTACHED A FILE..

Please find the attached photograph for your answer

help pls physics problem

Answers

Answer:

0.4329 seconds

Explanation:

We are given;

Distance; d = 0.635 m

Velocity; v = 3.22 m/s

Angle; θ = 62.9°

To find the time, we have to find the horizontal component of the velocity.

Thus, Vx = 3.22 × cos 62.9

Formula for time is;

t = d/Vx

t = 0.635/(3.22 × cos 62.9)

t = 0.4329 sec

Thus the time he will take to clear the hurdle is 0.4329 sec

Why do clownfish rarely go far from their home

Answers

Answer:

In the wild, clownfish rarely leave their anemone home. In fact, part of its purpose is to defend the anemone from other fish. However, clownfish bred in aquariums (without an anemone home) may still have this instinct, but it’s much calmer than wild harvested species.

Explanation:

Clownfish have no defense mechanism of their own, which is one reason they never stray to far away from their anemone.

Strong magnetic fields created by high currents can result in:910 A. Arc flash B. Arc blast C. Large mechanical stresses that may cause conductors to move D. Shock

Answers

Answer:

B. Arc blast

Explanation:

Arc blast are as a result of rapid injection of electrical energy into an arc. These shock waves and arc blast pressure wave at low level can lead to damage of eardrums at lower levels and cardiac arrest at high levels.

Strong magnetic fields created by high currents (> 100 kA) can result to equipment destruction. These arc blast hazards are mostly found in high-energy power circuits and large capacitor banks.

What are the units of Mass and Weight in the English System? Explain.

Answers

Answer:

I tried...

Explanation:

Assuming the English system of mass and weight is the same as the Imperial system, the measurements are:

• 1 pound (lb) = 16 ounces (oz)

• 2,000 pounds (lbs) = 1 ton (T)

I think that's everything?

In the English system, mass is measured in pounds and weight is also measured in pounds. However, it is important to understand the difference between mass and weight.

Mass is a measure of the amount of matter in an object and is a scalar quantity. It does not change with location or gravitational force. In the English system, mass is typically measured using a scale or balance, which compares the object's mass to a standard mass. The pound (lb.) is the unit of mass in the English system.

Weight, on the other hand, is a measure of the force exerted on an object due to gravity and is a vector quantity. It depends on the object's mass and the gravitational force acting on it. In the English system, weight is typically measured using a spring scale or a balance that incorporates a spring. The pound (lb.) is also used as the unit of weight in the English system.

Weight = Mass x Acceleration due to gravity

Mass is measured in pounds (lb.) and weight is also measured in pounds (lb.).It is important to note that weight can vary depending on the gravitational force acting on an object.

Learn more about weight here:

https://brainly.com/question/28221042

#SPJ2

Total Internal Reflection
Each critical angle of the prisms is 42°.How the direction of light to reflect ?​

Answers

Answer: The light beam will not diffract out of the prism.

Explanation: The angle the light is entering the prism is greater than the critical angle therefore total internal reflection will occur. Hope this helps :)


Linear momentum is conserved is a system when the net force is equal to

Answers

Answer:

zero

Explanation:

The linear momentum is conserved when the system is closed. Therefore, the net force is zero.

Which of the following statements would be best described as an expression of an attitude that is low in accessibility and high in ambivalence?
A.
Frank: “I eat a banana for breakfast everyday. I’ve loved them since I was little.”
B.
Judy: “I really dislike bananas. I don’t know why. I just always have.”
C.
Ralph: “I’m not sure about bananas. I’d have to think about it.”
D.
Fiona: “I am a huge banana fan. I don’t know why. I just like them.”

Answers

Answer:

The answer is C. Ralph: “I’m not sure about bananas. I’d have to think about it.”

Explanation:

I did the practice.

Answer:

C.) Ralph: "I'm not sure about bananas. I'd have to think about it."

Explanation:

Just took the practice

A race car was is moving at a constant speed of 35 m/s. A security car was
moving at a speed of 5 m/s as the race car passes by it and was accelerating at
constant rate of 5 m/s2. what was the speed of the security car when it took
over the race car?
65 m/s
60 m/s
35 m/s
5 m/s

Answers

Answer:

Final speed of security car v = 65 m/s

Explanation:

Given:

Speed of race car u1 = 35m/s

Speed of security car u2 = 5 m/s

Acceleration = 5 m/s²

Find:

Final speed of security car v

Computation:

Assume, they chase S meter

So

S = u1t + [1/2]at²

S = 35t

S = u2t + [1/2]at²

so,

35t = 5t +  [1/2](5)t²

t = 12 s

So

v = u + at

v = 5 + 5(12)

Final speed of security car v = 65 m/s

PLEASE HELP! I know the answer to this, but I need an explanation.

Answers

Let r be the distance between the man and point Q. He applies a torque of

(r i ) × ((-800 N) j ) = ((-800 N) r ) k

pointing "into the page" with magnitude (800 N) r.

Meanwhile, the rope applies a torque of

((3.0 m) i ) × ((500 N) j ) = (1500 N•m) k

pointing out of the "page" with mag. 1500 N•m

The beam is held in place in a horizontal position, so the torques cancel and

(800 N) r = 1500 N•m

r = (1500 N•m)/(800 N) = 1.875 m ≈ 1.9 m

A bicyclist travels 4.5 km west, then travels 6.7 km at an angle 27.0 degrees South of West. What is the magnitude of the bicyclist's total displacement?

Answers

Answer:

10.90km

Explanation:

Magnitude of the total displacement is expressed using the equation

d = √dx²+dy²

dx is the horizontal component of the displacement

dy is the vertical component of the displacement

dy = -6.7sin27°

dy = -6.7(0.4539)

dy = -3.042

For the  horizontal component of the displacement

dx = -4.5 - 6.7cos27

dx = -4.5 -5.9697

dx = -10.4697

Get the magnitude of the bicyclist's total displacement

Recall that: d = √dx²+dy²

d = √(-3.042)²+(-10.4697)²

d = √9.2538+109.6146

d = √118.8684

d = 10.90km

Hence the magnitude of the bicyclist's total displacement is 10.90km

The bicyclist magnitude of displacement is equal to 9.62m

Resolution of Vectors

To find the resultant magnitude of the bicyclist total displacement, we have to find the x and y component.

For the first direction, the components are

[tex]x_1 = -4.5i[/tex]

sine we don't have any vertical displacement, the y-component is equal to zero.

for the second direction,

[tex]x_2 = -6.7sin27i\\y_2= 6.7cos27j[/tex]

The resultant x and y component are;

[tex]R_x = -4.5i + (-6.7sin27i)\\R_x = -7.54i[/tex][tex]R_y = 0 + 6.7cos27= 5.97j[/tex]

Let's find the magnitude of displacement

[tex]R = \sqrt{R_x^2 + R_x^2}\\R = \sqrt{(-7.54)^2 + (5.97)^2 }\\\\R = 9.62m[/tex]

The bicyclist magnitude of displacement is equal to 9.62m

Learn more on resolution of vectors here;

https://brainly.in/question/3543542

a horizontal force of 50 Newtons acts on a body of mass 3kg placed on a rough horizontal surface, giving it an acceleration of 8m/s2​

Answers

Explanation:

Fnet = ma = (3kg)(8m/s²) = 24N.

50N - 24N = 26N.

Hence the frictional force is 26N.

PLEASE ANSWER WILL MARK BRAINLIEST















Im doing it for free just say something to make meh smile and u get brainliest :3

Answers

Answer:

your pretty no matter what others say

Explanation:

Answer:

two bros chillin in a hot tub five feet apart cuz there not gay

Explanation:

do you remember this vine

A 40 kg boy is moving upwards in a lift with an acceleration of 2 m /s ^2 what would be the weight felt by him if measuured in a scale

Answers

Answer:

40×(9.8+2)=432n

Explanation:

9.8m/s^2 is acceleration of gravity

when required to be returned to the issuing activity upon the individual's transfer, clothing loaned to an individual by a navy activity is referred to by what term?

Answers

Answer:

Organizational clothing.

Explanation:

An organizational clothing can be defined as the standard field uniform of the U.S Navy that is being loaned to a person (officer) by a naval activity and as such must be returned to the naval activity as soon as the person is transferred.

Basically, an organizational clothing is generally considered to be the property of the U.S Navy and should be sent to the regional or area naval coordinator.

Hence, when required to be returned to the issuing activity upon the individual's transfer, clothing loaned to an individual by a navy activity is referred to as organizational clothing.

The level of mercury falls in a barometer
while taking it to a mountain.​

Answers

Answer:

This is due to a relative decrease in atmospheric pressure in high places.

Explanation:

Given that atmospheric pressure decreases at the higher point or ground, this reduced atmospheric pressure, however, will be unable to contain the Mercury in the barometer tube.

Therefore, at the top of the mountain where the air pressure is low, the barometer reading ultimately goes down.

Hence, the level of mercury falls in a barometer while taking it to a mountain "due to a relative decrease in atmospheric pressure in high places."

What are organs made of?
O Organs are made of colections of tissues,
O Organs are made of cells, but not tissues.
O Organs are made of collections of other
O Organs are made of muscle and bone.
DONE

Answers

Organs are made of tissues

Tissues are made of cells though so it’s kinda a weird question lol

Answer:

Organs are made of collections of tissues, which are groups of cells.

Explanation:

Other Questions
Who is the founder of a new lineage in the Kandyan kingdom ? 8.0 dm of NO is mixed with 6.0 dm3 of O, at room temperature and pressure (RTP).The reaction below takes place until one of the reactants is used up.2NO(g) + O2(g) + 2NO,(9)What is the volume of the mixture at RTP after the reaction has taken place?A)8.0 dm3B)10.0 dm3C)12.0 dm3D)14.0 dm3 what is the equation of the line in point slope form that has a slope of -7/8, going through point (12,-3) Solve for x 6x^2=2x-1 You will get brainliest! Someone pls help me!!! Sir Toby says, Then hes a rogue, and a passy-meausres pavin. I hate a drunken rogue. This line is an example of what literary device? what is the greatest common factor of 4x+2x Please help asap I suck at math :( ([tex]\sqrt{\frac{2}{3}[/tex]) plsexplain and solve hurry which specialized reproductive structures give spermathophytes their name? Switch the rule 2(x - 5) + 12 into simplified (or standard) form.Please show the work aswell Which hazard is generally not associated with avolcanic eruption? *A.Lava flowB. LaharC. AshD. Sinkhole 1. Kilometers and inches are some units used to measure length. What are some otherunits used to measure length?2. Tablespoons and liters are some units used to measure volume. What are someother units used to measure volume?100 point please helppp In a monarchy, who has the legitimate power to rule?A. The church leadersB. The mediaC. The peopleD. The kings Farmer John can till his field 1.5 times faster than Farmer Bob. If they work together, they can till the field in 6 hours. How long would it take Farmer John on his own can someone please help me with this question? Which will help your answer, "To what power must a student raise the number 5 to have an answer of 626"?a. log625(5)=xb. logx(5)=xc. log5(x)=625d. log5(625)=x On January 1, 2021, the general ledger of TNT Fireworks includes the following account balances:Accounts Debit CreditCash $ 60,100 Accounts Receivable 27,800 Allowance for Uncollectible Accounts $ 3,600 Inventory 37,700 Notes Receivable (5%, due in 2 years) 28,800 Land 169,000 Accounts Payable 16,200 Common Stock 234,000 Retained Earnings 69,600 Totals $ 323,400 $ 323,400 During January 2021, the following transactions occur:January1 Purchase equipment for $20,900. The company estimates a residual value of $2,900 and a four-year service life.January4 Pay cash on accounts payable, $10,900.January8 Purchase additional inventory on account, $96,900.January15 Receive cash on accounts receivable, $23,400.January19 Pay cash for salaries, $31,200.January28 Pay cash for January utilities, $17,900.January30 Sales for January total $234,000. All of these sales are on account. The cost of the units sold is $122,000.Information for adjusting entries:a. Depreciation on the equipment for the month of January is calculated using the straight-line method.b. The company estimates future uncollectible accounts. The company determines $4,400 of accounts receivable on January 31 are past due, and 50% of these accounts are estimated to be uncollectible. The remaining accounts receivable on January 31 are not past due, and 3% of these accounts are estimated to be uncollectible. (Hint: Use the January 31 accounts receivable balance calculated in the general ledger.)c. Accrued interest revenue on notes receivable for January.d. Unpaid salaries at the end of January are $34,000.e. Accrued income taxes at the end of January are $10,400.1. Record the adjusting entries on January 31 for the above transactions(Please write out)2. Prepare an adjusted trial balance as of January 31, 2021.(Please write out)3. Prepare a multiple-step income statement for the period ended January 31, 2021.(Please write out)4. Prepare a classified balance sheet as of January 31, 2021. (Deductible amounts should be indicated with a minus sign.)(Please write out).5. Record closing entries(Please write out)6. Analyze how well TNT Fireworks manages its assets:a-1. Calculate the return on assets ratio for the month of January.Return on Assets RatioChoose Numerator Choose Denominator = Return on Assets Ratio = Return on assets A DVD player with a list price of $100 is marked down 30%. If John gets an employee discount of 20% off the sale price, how much does John pay for the DVD player Steam Workshop Downloader