Why would theoretical muzzle velocity be lower than measured muzzle velocity?

Answers

Answer 1

Answer:

Explanation:

Theoretical muzzle velocity is calculated based on various physical models and assumptions, such as the conservation of energy and momentum, the properties of the propellant and barrel, and other factors that can affect the velocity of the projectile as it exits the muzzle of the firearm. However, in practice, there can be many factors that can influence the actual velocity of the projectile, which can result in a measured muzzle velocity that is higher than the theoretical value. Some possible reasons for this discrepancy include:

Variation in propellant burn rate: Theoretical models assume a constant burn rate for the propellant, but in practice, there can be variations in the rate at which the propellant burns due to differences in temperature, humidity, and other factors. This can affect the velocity of the projectile as it exits the muzzle.

Barrel condition: Theoretical models assume a perfectly smooth, straight barrel, but in practice, barrels can have imperfections such as rough spots or bends that can affect the velocity of the projectile as it travels through the barrel.

Environmental factors: Theoretical models assume ideal conditions, but in practice, there can be factors such as wind, temperature, and humidity that can affect the velocity of the projectile as it travels through the air.

Measurement errors: Measuring the muzzle velocity of a projectile can be challenging, and errors in measurement can result in a measured velocity that is higher than the actual value.

Human error: Human factors such as shooter error, inconsistency in handling and loading the firearm, and other factors can also contribute to discrepancies between theoretical and measured muzzle velocities.

Overall, while theoretical muzzle velocity can provide a useful estimate of the velocity of a projectile exiting a firearm, there are many factors that can influence the actual velocity in practice, leading to measured velocities that are higher than the theoretical value.


Related Questions

Liam pulls a box with a horizontal force of 17 N over a distance of 19 m. What is the change in energy of the box after the 19 m?

Answers

So the change in energy of the box after being pulled by Liam over 19 m is 323 J.

What are some illustrations of energy change?

Energy is capable of changing its forms. For instance, electrical energy transforms into thermal and light energy when a lightbulb is turned on. A automobile transforms the gasoline's molecular bonds' stored energy into a variety of other forms. Chemical energy is converted to light in the engine through a chemical reaction.

The work done on the box by Liam's force is:

work = force x distance x cos(theta)

where theta is the angle between the force and the direction of motion. Since the force is horizontal and the motion is also horizontal, theta is 0 degrees and cos(theta) is 1. Therefore, the work done on the box is:

work = 17 N x 19 m x 1 = 323 J

The change in energy of the box is equal to the work done on it, according to the work-energy principle. Therefore, the change in energy of the box is:

change in energy = work = 323 J

To know more about energy visit:-

brainly.com/question/26472013

#SPJ1

Student A has a mass of 95 kg and student B has a mass of 82 kg. If their centers of mass are
0.6 meters apart, what will be the gravitational force each student exerts on the other?
Round your answer to the nearest whole number.

Answers

Answer:

0 Newtons, to the nearest whole number

Explanation:

Using the formula attached to this answer,

F = (6.67 x 10-¹¹ • 95 • 82) / 0.6²

F = 5.19593 x 10-⁷ / 0.36

F = 1.4433 x 10-⁶ N

F = 0.000001443 N

To the nearest whole number

F = 0 N

Please mark brainliest.

Thanks

A 300 g football is kicked with an initial velocity of 140 m/s in a direction that
makes a 30° angle with the horizon. Find the peak height of the football.

Answers

Answer:

Explanation:

Assuming that air resistance is negligible, we can use the following kinematic equations to solve for the peak height:

v_f^2 = v_i^2 + 2ad

where v_f = 0 m/s (at the peak height) and a = -9.8 m/s^2 (acceleration due to gravity)

and

d = v_i t + (1/2)at^2

where d is the displacement or the peak height we want to find, v_i is the initial velocity, t is the time it takes to reach the peak height.

First, we need to resolve the initial velocity into its vertical and horizontal components:

v_i_x = v_i cos(30°) = 121.1 m/s

v_i_y = v_i sin(30°) = 70.0 m/s

Next, we can use the vertical component of the initial velocity to find the time it takes to reach the peak height:

v_f = v_i_y + at

0 m/s = 70.0 m/s + (-9.8 m/s^2)t

t = 7.14 s

Finally, we can use the time we found and the kinematic equation for displacement to find the peak height:

d = v_i_y t + (1/2)at^2

d = (70.0 m/s)(7.14 s) + (1/2)(-9.8 m/s^2)(7.14 s)^2

d = 247.5 m

Therefore, the peak height of the football is 247.5 meters.

A block of mass m1=3.0kg rests on a frictionless horizontal surface. A second block of m2=2.0kg hangs from an ideal cord of negligible mass that runs over an ideal pulley and then is connected to the first block . the blocks are released from rest . determine the displacement of the velocityA block of mass m1=3.0kg rests on a frictionless horizontal surface. A second block of m2=2.0kg hangs from an ideal cord of negligible mass that runs over an ideal pulley and then is connected to the first block . the blocks are released from rest . Determine how far has block 1 moved during the 1.2-s interval? A) 13.4 m B) 2.1m C) 28.2m D) 7.6mA block of mass m1=3.0kg rests on a frictionless horizontal surface. A second block of m2=2.0kg hangs from an ideal cord of negligible mass that runs over an ideal pulley and then is connected to the first block . the blocks are released from rest . determine the displacement of the velocityA block of mass m1=3.0kg rests on a frictionless horizontal surface. A second block of m2=2.0kg hangs from an ideal cord of negligible mass that runs over an ideal pulley and then is connected to the first block . the blocks are released from rest . Determine how far has block 1 moved during the 1.2-s interval?​

Answers

To solve this problem, we can use the conservation of mechanical energy principle. When the blocks are released from rest, the potential energy of the system is converted to kinetic energy. Since the surface is frictionless, the mechanical energy of the system is conserved.

Using the principle of mechanical energy conservation, we can write:

m1*g*h = (m1+m2)*v^2/2

where m1 is the mass of the first block, m2 is the mass of the second block, g is the acceleration due to gravity, h is the height that the second block falls, and v is the velocity of the system after the blocks have moved a distance x.

The displacement of the first block can be found by using the time it takes the system to reach this velocity. The time t can be found using the formula:

x = (1/2) * a * t^2

where a is the acceleration of the first block.

The acceleration of the first block is equal to the acceleration of the system, which can be found by using the equation:

m1*a = m2*g - m1*g

Substituting the value of a in the previous formula, we get:

x = (1/2) * (m2*g - m1*g) * t^2 / m1

Substituting the values we get:

x = (1/2) * (2.0 kg * 9.81 m/s^2 - 3.0 kg * 9.81 m/s^2) * (1.2 s)^2 / 3.0 kg

x ≈ 7.6 m

Therefore, the correct answer is D) 7.6 m.

13 Which of these fitness events happened LAST? OA. PE becomes part of American school curriculum. OB. Title IX forbids gender discrimination in sports. O C. The YMCA opens a gym in America. O D. The adjustable plate-loaded barbell is invented.​

Answers

The answer is A. PE becomes part of American school curriculum.

Title IX, which forbids gender discrimination in sports, was enacted in 1972.

The YMCA opened its first gym in America in Boston in 1851.

The adjustable plate-loaded barbell was invented in the late 1940s by a man named George Snyder.

Physical Education (PE) has been a part of American school curriculums for well over a century, with the first school gymnasiums being built in the 1800s.

What is an american school curriculum?

The American school curriculum is the set of educational standards and guidelines used by schools in the United States to structure their academic programs. The curriculum typically includes courses in core academic subjects such as English, math, science, and social studies, as well as elective courses in areas such as the arts, foreign languages, and physical education.

To know more about gender discrimination, visit:

https://brainly.com/question/29404586

#SPJ1

What might happen if people did not have the rights established in Miranda v. Arizona

Answers

Answer:

If people did not have the rights established in Miranda v. Arizona, they could be subjected to police coercion and forced confessions without a lawyer present. This could lead to wrongful convictions and denial of due process, which are essential components of the American justice system

(a) Find the frequency ratio between the two frequencies fi =256 Hz and f2 = 320 Hz. (b) Add the interval of a fifth to f2 to obtain fs, and find the frequency ratio fs/fi. (c) Find the frequency of f3.

Answers

(a) The frequency ratio between the two frequencies fi = 256 Hz and f2 = 320 Hz is:

[tex]\frac{f_2}{f_i} = \frac{320}{256} = \frac{5}{4} = 1.25[/tex]

So the frequency ratio is 1.25.

(b) Adding the interval of a fifth to f2 = 320 Hz gives:

fs = f2 * (3/2) = 320 * (3/2) = 480 Hz

The frequency ratio fs/fi is:

[tex]\frac{f_s}{f_i} = \frac{480}{256} = \frac{15}{8} = 1.875[/tex]

So the frequency ratio is 1.875.

(c) To find the frequency of f3, we need to add the interval of a fourth to f2:

f3 = f2 * (4/3) = 320 * (4/3) = 426.67 Hz

Therefore, the frequency of f3 is 426.67 Hz.

Describe the change to the graph of Y= X +3 when Y=2X -3 is graphed 

Answers

Answer:  a stretch of 2

Explanation: because it 2 (x) - 3

it the frequency of a wave is increased it’s
and
will decrease but its
will stay the same.

Answers

Answer:

Wavelength will decrease but frequency will stay the same.

Explanation:

The higher the frequency, the shorter the wavelength. The relationship between wavelength and frequency is called an inverse relationship, because as the frequency increases, the wavelength decreases.

However, the frequency usually remains the same because it is like a driven oscillation and maintains the frequency of the original source. If v changes and f remains the same, then the wavelength λ λ must change. Since v = f λ v = f λ , the higher the speed of a sound, the greater its wavelength for a given frequency.



A metal filament Lamp rated at 750w, 100v into be connected in series with a capacitor across a 230v, 60hz supply. Calculate the capacitance required

Answers

Answer : 0.00885 farads or 8.85 microfarads

Explanation: To calculate the capacitance required, we can use the following formula:

C = 1 / [2 * pi * f * ((V^2 - Vlamp^2)/P)]

where:

C = capacitance in farads (F)

pi = 3.14159...

f = frequency in hertz (Hz)

V = voltage in volts (V)

P = power in watts (W)

Vlamp = voltage of the lamp in volts (V)

Using the given values, we have:

C = 1 / [2 * pi * 60 * ((230^2 - 100^2)/750)]

C = 1 / [2 * 3.14159 * 60 * ((230^2 - 100^2)/750)]

C = 1 / [113.09724]

C = 0.00885 farads (F)

Therefore, the capacitance required is approximately 0.00885 farads or 8.85 microfarads.

A girl with a mass of 32 kg is playing on a swing. There are three main forces
acting on her at any time: gravity, force due to centripetal acceleration, and
the tension in the swing's chain (ignore the effects of air resistance). At the
instant shown in the image below, she is at the bottom of the swing and is
traveling at a constant speed of 4 m/s. What is the tension in the swing's
chain at this time? (Recall that g = 9.8 m/s²)
Tension
Weight
A. 333.6 N
OB. 817.8 N
C. 562.8 N
D. 441.6 N
4 m/s

Answers

The tension in the swing's chain at the instant shown in the image is 441.6 N.

option D

What is the tension at bottom swing?

At the bottom of the swing, the girl is traveling at a constant speed, so her acceleration is zero. Therefore, the net force acting on her is also zero.

Thus, we have:

0 = T - mg - mv²/r

where;

T is the tension in the swing's chain, m is the girl's mass, g is the acceleration due to gravity, v is her speed, and r is the radius of the swing.

At the bottom of the swing, the radius is equal to the length of the chain, so we have:

r = L = 4.0 m

Substituting the values we have:

T = (32 kg)(9.8 m/s²) + (32 kg)(4 m/s)²/4.0 m

Solving for T, we get:

T = (32 kg)(9.8 m/s²) + (32 kg)(4 m/s)²/4.0 m

T = 441.6 N.

Learn more about tension in swing here: https://brainly.com/question/5843488

#SPJ1

Which type of marco molecules help a cell break down food?

Answers

Answer: Each macromolecule is broken down by a specific enzyme. For instance, carbohydrates are broken down by amylase, sucrase, lactase, or maltase. Proteins are broken down by the enzymes pepsin and peptidase, and by hydrochloric acid. Lipids are broken down by lipases.

Explanation:

Hope this will help

Which of the following does a scientist NOT need to calculate the age of something?
Amount of radioactive isotope within a sample
Half-life of radioactive isotope
Abundance on Earth
100g of the sample

Answers

Answer:

Abundance on Earth is not necessary for calculating the age of something using radioactive dating methods.

In contrast, the amount of radioactive isotope within a sample and its half-life are crucial for determining the age of the sample using radioactive dating methods. The amount of sample, such as 100g, is also important for determining the quantity of radioactive isotopes present, which is used in the calculation of the age of the sample.

If you lift one load up one story, how much more work do you do lifting one load up
three stories?

Answers

Answer:

Explanation:

alot

What factors would create an ideal circuit?

Answers

An ideal circuit is a theoretical representation of an electrical circuit, where all components are perfect and all parameters such as resistance, capacitance, and inductance are zero.

The ideal circuit also has no energy losses, making it an ideal electrical system. To create an ideal circuit, the following factors must be considered:

1. Perfectly Conductive Wires: The wires and other conductors used in the circuit should be perfect conductors, which means the resistance should be zero. This will ensure that no energy is lost in the form of heat.

2. Zero Inductance: Inductance is a property of a circuit which causes a voltage drop when current flows through it. The ideal circuit should have no inductance so that the current can flow freely.

3. Zero Capacitance: Capacitance is a property in which electric charge builds up when current passes through it. To create an ideal circuit, the capacitance should be zero.

4. Zero Impedance: Impedance is the opposition to the flow of current in an electrical circuit. The ideal circuit should have zero impedance so that the current can flow freely.

learn more about circuit Refer:brainly.com/question/12608491

#SPJ1

A stuntman of mass 55 kg is to be launched horizontally out of a spring- loaded cannon. The spring that will launch the stuntman has a spring coefficient of 266N / m and is compressed 5 m prior to launching the stuntman. If friction and air resistance can be ignored, what will be the approximate velocity of the stuntman once he has left the cannon?

Answers

The approximate velocity of the stuntman, once he has left the cannon, is 11 m/s.

Steps

We can use the conservation of energy, where the potential energy stored in the compressed spring is converted into the kinetic energy of the stuntman as he is launched out of the cannon.

The potential energy stored in the spring is given by:

PE = (1/2)kx²

where k is the spring constant and x is the distance the spring is compressed.

PE = (1/2)(266 N/m)(5 m)² = 3325 J

This potential energy is then converted into kinetic energy:

KE = (1/2)mv²

where m is the mass of the stuntman and v is his velocity.

3325 J = (1/2)(55 kg)v²

v² = (2*3325 J) / 55 kg

v²  = 121 m²/s²

v = √(121 m²/s²) = 11 m/s

Therefore, the approximate velocity of the stuntman, once he has left the cannon, is 11 m/s.

learn more about velocity here

https://brainly.com/question/25749514

#SPJ1

When a disrupted part of a wetland ecosystem is left alone so that nature can help restore it to what it once was, what are people counting on occurring? explain..

Answers

Answer: When a disrupted part of the ecosystem is left alone so that nature can help restore itself what people are counting on happening is secondary succession

Explanation:

Explain how a balloon is able to keep its shape?

Answers

Answer:

It depends on how they are made.

Explanation:

Rubber balloons are not always spherical in shape. When filled with air, the inflation forms a balance between the balloon material, including its shape and thickness and its elasticity and the pressure of the air. That’s what determines its shape. Although a sphere is often the shape, it could be tubular, offset, and most other shapes.

PLEASE HELP WILL MARK BRAINLIEST!!
A 4.0-kg mass is moving to the right at 3.0 m/s. An 8.0 kg mass is moving to the left at 2.0 m/s. If after collision the two
masses join together, what is their velocity after collision?
O-0.33 m/s
O-0.20 m/s
O +1.4 m/s
O +2.3 m/s

Answers

Answer:

- 0.33 m/s

Explanation:

An illustration is shown above,

In this case, since the two objects move in opposite directions before collision, then move together, the formula to be used is,

m1u1 - m2u2 = (m1 + m2)v

Where,

m1 = mass of the first object

u1 = initial velocity of the first object

v1 = final velocity of the first object

m2 = mass of the second object

u2 = initial velocity of the second object

v2 = final velocity of the second object

Therefore,

(4.0 • 3.0) - (8.0 • 2.0) = (4.0 + 8.0)v

12 - 16 = 12v

-4 = 12v

Divide both sides by 12,

-4 / 12 = 12v / 12

-1 / 3 = v

v = -0.33 m/s

Please mark brainliest.

Thanks

460miles per hour with the wind nd 420 per hour gainst the wind

Answers

The speed of the wind is 20 miles per hour.

To solve this problem, we can use the formula:

Speed = Distance/Time

Let's assume that the speed of the wind is x miles per hour.

With the wind, the plane travels at a speed of 460 miles per hour. This means that its speed relative to the ground is the sum of its airspeed and the speed of the wind:

460 = Airspeed + x

Against the wind, the plane travels at a speed of 420 miles per hour. This means that its speed relative to the ground is the difference between its airspeed and the speed of the wind:

420 = Airspeed - x

We can solve this system of equations to find the airspeed of the plane:

460 = Airspeed + x

420 = Airspeed - x

Adding the two equations gives:

880 = 2Airspeed

Dividing both sides by 2 gives:

Airspeed = 440 miles per hour

Now that we know the airspeed of the plane, we can find the speed of the wind by substituting this value into one of the equations we obtained earlier:

460 = Airspeed + x

460 = 440 + x

x = 20

To learn more about speed visit;

https://brainly.com/question/28224010

#SPJ9

Is this statement is correct ?? According to Newton's 4rd law, Action and reaction never start from the same point.
help me...​

Answers

Explanation:

I'm sorry, but the statement you provided is incorrect. There is no such thing as Newton's 4th law. Newton's laws of motion consist of three laws, which are:

An object at rest tends to stay at rest, and an object in motion tends to stay in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

The acceleration of an object is directly proportional to the force applied to it and inversely proportional to its mass.

For every action, there is an equal and opposite reaction.

None of these laws state that action and reaction never start from the same point. However, it is true that the action and reaction forces act on different objects, not necessarily at the same point. This is because Newton's third law states that every action has an equal and opposite reaction, which means that when one object exerts a force on another object, the second object exerts an equal and opposite force back on the first object.

how long will be required for a car to go from a speed of 20.0 m/s to a speed of 25.0 m/s if the acceleration is 3.0 m/s2?

Answers

Answer:

Explanation:

We can use the following kinematic equation to solve for the time required:

v_f = v_i + at

where:

v_f = final velocity = 25.0 m/s

v_i = initial velocity = 20.0 m/s

a = acceleration = 3.0 m/s^2

t = time

Rearranging the equation to solve for t, we get:

t = (v_f - v_i) / a

Substituting the given values, we get:

t = (25.0 m/s - 20.0 m/s) / 3.0 m/s^2

t = 1.67 s

Therefore, it will take 1.67 seconds for the car to go from a speed of 20.0 m/s to a speed of 25.0 m/s, assuming a constant acceleration of 3.0 m/s^2.

A loudspeaker of mass 15.0 kg is suspended a distance of h = 1.00 m below the ceiling by two cables that make equal angles with the ceiling. Each cable has a length of l = 2.70 m .
1. What is the tension T in each of the cables?
Use 9.80 m/s2 for the magnitude of the free-fall acceleration.

Answers

Answer:

To solve the problem, we use the equations of equilibrium to find the tension in each cable holding up the loudspeaker. Since the loudspeaker is in equilibrium, the sum of the forces acting on it is zero. The weight of the loudspeaker is calculated first, and then we use trigonometry to find the horizontal and vertical components of the tension in one of the cables. We then apply the equation of equilibrium in the y direction to find the tension in each cable. The final answer is that the tension in each cable is approximately 81.1 N, which balances the weight of the loudspeaker.

___

Given:

Mass of loudspeaker (m) = 15.0 kg

Distance from ceiling (h) = 1.00 m

Length of cable (l) = 2.70 m

Acceleration due to gravity (g) = 9.80 m/s^2

Weight of loudspeaker:

Fg = mg

Fg = (15.0 kg)(9.80 m/s^2)

Fg = 147 N

Horizontal and vertical components of tension in one cable:

sinθ = h/l

sinθ = 1.00 m / 2.70 m

θ = sin^(-1)(1.00/2.70)

θ ≈ 21.6°

T_x = T sinθ

T_y = T cosθ

where T is the tension in the cable.

Equation of equilibrium in y direction:

ΣF_y = 2T cosθ - Fg = 0

Solving for T:

2T cosθ = Fg

T = Fg / (2 cosθ)

Plugging in the values:

T = (147 N) / (2 cos(21.6°))

T ≈ 81.1 N

Please HELP me answer these three questions!! (show work)

Answers

Answer:

2) 42.6

3) 1500000 m

4) no he will not be late, it will take 3s

Explanation:

 #2:

Formula for average velocity:
 ⇒  [tex]v=\frac{d}{t}[/tex]

Substitute

 ⇒ [tex]\frac{2560}{60}[/tex]

⇒ [tex]42.6[/tex]

#3:

   

1st convert 60km to m/s (correct si unit must always come first)

to convert kilometer to meter, multiply by 1000 (prefix 'kilo' = 1000)

60 km x 1000 = 60000 m

use the formula for speed, distance, & time

60000 = d/25

to find displacement just multiply the speed and time together

60000 x 25

1500000m is the displacement

#4:

s = d/t

given are displacement and speed/velocity

d = 25m

v = 8.5 m/s

to find the time just divide displacement by speed

8.5 = 25/t

25/8.5

≈ 3 seconds

so he will not be late for class.

Select in the ticker-timer a frequency of 25 Hz or 50 Hz. Determine the period of the ticker-timer. ​

Answers

Answer:

The period of a ticker-timer is the time interval between two consecutive dots made by the ticker.

If the frequency of the ticker-timer is 25 Hz, then it makes 25 dots in one second. Therefore, the period of the ticker-timer can be calculated as:

Period = 1/frequency = 1/25 Hz = 0.04 seconds

If the frequency of the ticker-timer is 50 Hz, then it makes 50 dots in one second. Therefore, the period of the ticker-timer can be calculated as:

Period = 1/frequency = 1/50 Hz = 0.02 seconds

So, the period of the ticker-timer is 0.04 seconds for a frequency of 25 Hz and 0.02 seconds for a frequency of 50 Hz

Explanation:

please Mark Me As Brainlist.

When heal flows between systems Entropy

Answers

Increase increase increase

Answer: increases

Explanation:

A carpenter tosses a shingle off a 9.4 m high roof, giving it an initial horizontal velocity of 7.2 m/s.] How far does it move horizontally in this time

Answers

Answer:

Explanation:

Assuming negligible air resistance, the horizontal velocity of the shingle will remain constant and the vertical motion will be influenced by gravity.

We can use the kinematic equations of motion to determine the horizontal distance traveled by the shingle. The relevant equation is:

d = v * t

where d is the distance, v is the initial horizontal velocity, and t is the time of flight.

To find the time of flight, we can use the equation for the vertical displacement of an object under constant acceleration:

y = v0t + (1/2)at^2

where y is the vertical displacement, v0 is the initial vertical velocity (which is zero), a is the acceleration due to gravity (-9.8 m/s^2), and t is the time of flight. Solving for t, we get:

t = sqrt((2y)/a)

where sqrt means square root.

Substituting the given values, we have:

y = 9.4 m

a = -9.8 m/s^2

t = sqrt((2*9.4 m) / -9.8 m/s^2) = 1.45 s (using the positive root since time cannot be negative)

Now, we can use the horizontal velocity to find the distance traveled in this time:

d = v * t = 7.2 m/s * 1.45 s = 10.44 m

Therefore, the shingle moves a horizontal distance of 10.44 meters in this time.

Work Energy Theorem Question: You apply 50 N to a 10 kg object to cause it to move from rest to 2.5 m/s. What distance was the object moved?

Answers

Answer:

0.625 meters

Explanation:

We can use the work-energy that the work done on an object is equal to the change in its kinetic energy:

Work = ΔK = Kf - Ki

Where:

Work is the work done on the object

ΔK is the change in kinetic energy of the object

Kf is the final kinetic energy of the object

Ki is the initial kinetic energy of the object (which is zero since the object is at rest)

The work done on the object is equal to the force applied to the object multiplied by the distance over which the force is applied:

Work = F × d

Where:

F is the force applied to the object (50 N)

d is the distance over which the force is applied (unknown)

So we can write:

F × d = Kf - Ki

Substituting the given values:

50 N × d = 1/2 × 10 kg × (2.5 m/s)^2 - 0

Simplifying:

50 N × d = 31.25 J

Solving for d:

d = 31.25 J / 50 N = 0.625 m

Therefore, the object was moved a distance of 0.625 meters.

please rate

A 0.5kg wooden block is placed on top of a 1.0kgwooden block. The coefficient static friction between the two blocks is 0.35. The coefficient of kinetic friction between the lower block and the level table is 0.20 wht is the maximum horizontal force that can be applied to the lower block

Answers

A block of 0.5 kg is placed on top of another wooden block which weighs 1.0 kg. The coefficient of static friction between the two blocks is 0.35, whereas the coefficient of kinetic friction between the lower block and the level table is 0.20.

To calculate the maximum horizontal force that can be applied to the lower block, we need to determine the limiting frictional force between the two blocks.

Since the upper block is not moving, the force of static friction is acting on it. We can calculate this force as follows:

`F_static = friction coefficient * normal force`

where, normal force = weight of upper block = 0.5 kg * 9.81 m/s^2 = 4.905 N

`F_static = 0.35 * 4.905 = 1.718 N`

Therefore, the static frictional force acting on the upper block is 1.718 N.

Now, we need to find the maximum force that can be applied to the lower block before it starts moving. This force is equal to the force of static friction acting on the lower block.

Since the upper block is not moving, the force of static friction acting on the lower block is equal to the force of static friction acting on the upper block.

`F_static(lower block) = F_static(upper block) = 1.718 N`

This means that the maximum horizontal force that can be applied to the lower block is 1.718 N.

However, if the applied force exceeds this value, the lower block will start moving and the force of kinetic friction will be acting on it, which is equal to:

`F_kinetic = friction coefficient * normal force`

`F_kinetic = 0.20 * 4.905 = 0.981 N`

Hence, if the applied force exceeds 1.718 N, the lower block will start moving and the force of kinetic friction will act on it, which is 0.981 N.

Therefore, the maximum horizontal force that can be applied to the lower block is 1.718 N.

Answer:

Explanation:

To determine the maximum horizontal force that can be applied to the lower block without causing the blocks to move, we need to calculate the maximum static friction force between the two blocks. This force is given by:

F_friction = coefficient of static friction * normal force

where the normal force is the force perpendicular to the surface of contact between the blocks. Since the blocks are resting on a level table, the normal force acting on the lower block is equal to the weight of both blocks, which is:

N = (m1 + m2) * g

where m1 is the mass of the lower block, m2 is the mass of the upper block, and g is the acceleration due to gravity (9.81 m/s^2).

Plugging in the given values, we have:

N = (1.0 kg + 0.5 kg) * 9.81 m/s^2 = 14.715 N

The maximum static friction force is then:

F_friction = 0.35 * 14.715 N = 5.15025 N

Therefore, the maximum horizontal force that can be applied to the lower block without causing the blocks to move is 5.15025 N. If a greater force is applied, the blocks will start to move and the kinetic friction force will take effect, which is given by:

F_kinetic = coefficient of kinetic friction * normal force

where the coefficient of kinetic friction is 0.20 in this case.

A rocket takes off from a space station, where there is no gravity other than the negligible gravity due to the space station, and reaches a speed of 110 m/s in 10.0 s. If the exhaust speed is 1,600 m/s and the mass of fuel burned is 118 kg, what was the initial mass (in kg) of the rocket?

Answers

The initial mass of the rocket was 106 kg.

What is the initial mass of the rocket?

We can use the principle of conservation of momentum to solve this problem.

The momentum of the rocket before takeoff is zero, since it is at rest, and the momentum after takeoff is the product of the mass of the rocket and its velocity.

However, during the takeoff, the rocket ejects a mass of fuel at a certain velocity, which creates a backward force (thrust) that propels the rocket forward.

This thrust can be calculated using the equation:

Thrust = (mass flow rate) x (exhaust velocity)

mass flow rate = (mass of fuel burned) / (burn time)

The mass of the rocket at any given time can be calculated using the equation:

mass = (initial mass) - (mass of fuel burned)

Using these equations, we can solve for the initial mass of the rocket:

Calculate the thrust:

Thrust = (118 kg / 10.0 s) x 1600 m/s = 1,888 N

Calculate the mass of the rocket at the end of the burn:

mass(end) = (initial mass) - (mass of fuel burned) = (initial mass) - 118 kg

Use the principle of conservation of momentum to find the initial mass:

momentum before = momentum after

0 = (mass(end) + 118 kg) x 110 m/s

mass(end) = -118 kg / 110 m/s = -1.07 kg/s

mass(end) = (initial mass) - 118 kg

(initial mass) = mass(end) + 118 kg

(initial mass) = (-1.07 kg/s x 10.0 s) + 118 kg

(initial mass) = 106 kg

Learn more about linear momentum here: https://brainly.com/question/7538238

#SPJ1

Other Questions
During the 1700s the first estate comprised of the Roman Catholic clergy had which privileges?A. nobility and powered positions B. tac exempt, lived on and controlled church landC. extravagant living, servants what is the number of degrees of freedom associated with the appropriate t-test for testing to see if there is a difference between the mean number of lesions per leaf produced by the two strains? what is the islamic sharia on invitation? consider a moving charged particle in region of magnetic field. which if the folowing angles between the magnatic field and the particle velocity will result in the largest force on the particle? on the math portion of the sat the scores are roughly normal with a mean of 500 and a standard deviation of 100. between what two values do approximately 95% of scores lie? 5. Does a person's physical appearance affect their ability to persuade? Why or why not? what is the answer of 10.9% of $8.85 in a model ensemble system, what do meteorologists change each time they run a simulation of the same model?(1 point) responses Please help lost on this Help pls!A scale drawing of a famous statue uses a scale factor of 250:1. If the height of the drawing is 1.2 feet, what is the actual height of the statue?O248.8 feetO 250 feetO251.2 feet300 feet a client asks the nurse why miotic eye solutions were prescribed in the treatment of the clients glaucoma. which is the best nursing rationale for the use of this medication? Mrs lee buys 10 pounds of vegetables to make traditional kimchi. If the cabbages alone weigh 7 pounds, what is the percentage of the weight of the cabbages the components of GIS adeline identifies the location of a squirrel out of her window. the first point in the visual system where the location of the squirrel would be coded is in her: When Poe found out that his childhood sweetheart became engaged to another man, what did he do?A. wrote scary storiesB. joined the armyC. gambledD. began drinking heavily which of the following statements regarding fringe benefits is false? multiple choice the general rule is that an employee fringe benefit is taxable unless the benefit is specifically excluded from the employee's gross income. employers are not allowed to deduct the cost of nontaxable employee fringe benefits. nontaxable fringe benefits must be provided to employees on a nondiscriminatory basis. none of these choices are false. in the context of systematic observation, which methodological issue refers to the possibility that the presence of the observer will affect people's behaviors? reactivity reliability validity contiguity Hi can someone please help me with this question Im struggling with it!! A self-serve car wash charges $5.96 to use its facilities, plus an additional $0.50 for each minute the customer is at the self-serve car wash. If Tiffany was at the car wash for 9 minutes, how much was she charged? A. $6.46 B. $10.46 C. $4.50 D. $14.96 Describe how the change in the United States has been achieved through peaceful protests. DO NOT PLAGIARIZE! YOU CAN FIND MATERIAL FROM SITES AND USE IT BUT DO NOT PLAGIARIZE WORK! Identify actions that peaceful protest movements have taken.Identify changes that Americans have made through peaceful protests.Describe successful protests and movements led by Indigenous people.Using the information you found/read, create a script for a public service announcement commercial that describes how various groups have peacefully impacted change. Your script should: Contain 20-25 lines of dialog. Discuss two of the groups of people, or individuals, that you read about. Cite evidence from the materials you read to support your points.