Write a equation to calculate d for any star

The solution set to the system of inequalities will be the overlapping region or the intersection of the shaded regions from all three inequalities.

The system of inequalities consists of three inequalities:

y ≤ 2x + 2

(1/2)x + y < 7

y - 3 ≥ 0

Let's analyze each inequality:

y ≤ 2x + 2 represents a shaded region below the line with a slope of 2 and a y-intercept of 2.

(1/2)x + y < 7 represents a shaded region below the line with a slope of -1/2 and a y-intercept of 7.

y - 3 ≥ 0 represents a shaded region above the line with a slope of 0 and a y-intercept of 3.

The solution set to the system of inequalities will be the overlapping region or the intersection of the shaded regions from all three inequalities.

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Based on the Triangle Inequality Theorem the possible lengths of the sides of a triangle are:

The Triangle Inequality Theorem which states that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side, is used to determine if three lengths can be the lengths of the sides of a triangle.

Considering each option:

A. 12cm, 5cm, 17cm:

12 + 5 > 17 (not satisfied)

5 + 17 > 12 (satisfied)

12 + 17 > 5 (satisfied)

B. 10cm, 15cm, 24cm:

10 + 15 > 24 (satisfied)

15 + 24 > 10 (satisfied)

10 + 24 > 15 (satisfied)

C. 9cm, 22cm, 11cm:

9 + 22 > 11 (satisfied)

22 + 11 > 9 (satisfied)

9 + 11 > 22 (not satisfied)

D. 21cm, 7cm, 6cm:

21 + 7 > 6 (satisfied)

7 + 6 > 21 (not satisfied)

21 + 6 > 7 (satisfied)

Hence, option B and D are correct.

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Answer: To calculate the distance the beetle walks diagonally across the table, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.

In this case, the two sides of the right triangle formed by the table are 160 cm and 90 cm. Let's call the hypotenuse (the distance the beetle walks) "d."

So, applying the Pythagorean theorem, we have:

d^2 = 160^2 + 90^2

Simplifying:

d^2 = 25600 + 8100

d^2 = 33700

Taking the square root of both sides:

d ≈ √33700

d ≈ 183.54 cm

Therefore, the beetle walks approximately 183.54 cm diagonally across the kitchen table.

Answer:

First, we need to figure out how many circular rugs can fit in the living room without overlap.

One way to approach this is to find the area of each circular rug (using the formula A = πr^2, where r = 3 feet since the diameter is 6 feet).

A = π(3)^2 = 28.26 square feet

Next, we can find the area of the living room:

A = 12 x 18 = 216 square feet

To figure out how many circular rugs can fit, we can divide the living room area by the rug area:

216/28.26 ≈ 7.64

Since we can't have partial rugs, we need to round down, which means Shannon can fit 7 circular rugs in her living room without overlap.

The total area covered by the circular rugs would be:

7 x 28.26 = 197.82 square feet

Therefore, the closest answer choice to the nearest square foot is A) 170 ft².

Answer:A

Step-by-step explanation:

She can put 2 circles together width wise because 6+6 = 12

She can put 3 circles together length wise because 6+6+6 = 18

So she can put 6 circles in total.

The area of one circle is found with the equation A=πr^2

The diameter is 6ft, so the radius is 3ft, so

A=π*3ft^2

A=28.26ft²

This is the area of one circle. We need to find the area of 6 because 6 can fit in total.

28.26ft² * 6= 169.56 ft²

A square and a traingle are present in a large rectangle with given dimensions in the figure.

[tex]\qquad\displaystyle \tt \dashrightarrow \: 12 \times 8[/tex]

[tex]\qquad\displaystyle \tt \dashrightarrow \: 96 \: \: unit {}^{2} [/tex]

[tex]\qquad\displaystyle \tt \dashrightarrow \: 4 \times 4[/tex]

[tex]\qquad\displaystyle \tt \dashrightarrow \: 16 \: \: unit {}^{2} [/tex]

[tex]\qquad\displaystyle \tt \dashrightarrow \: \frac{1}{2} \times 4 \times 5[/tex]

[tex]\qquad\displaystyle \tt \dashrightarrow \: \frac{1}{2} \times 4 \times 5[/tex]

[tex]\qquad\displaystyle \tt \dashrightarrow \: 2 \times 5[/tex]

[tex]\qquad\displaystyle \tt \dashrightarrow \: 10 \: \: unit {}^{2} [/tex]

[ area of square / total area ]

[tex]\qquad\displaystyle \tt \dashrightarrow \: p(inside \: \: the \: \: square) = \frac{16}{96} [/tex]

[tex]\qquad\displaystyle \tt \dashrightarrow \: p(inside \: \: the \: \: square) = \frac{1}{6} [/tex]

[ total area except area of triangle / total area ]

[tex]\qquad\displaystyle \tt \dashrightarrow \: p(outside \: the \: triangle) = \frac{96 - 10}{96} [/tex]

[tex]\qquad\displaystyle \tt \dashrightarrow \: p(outside \: the \: triangle) = \frac{86 }{96} [/tex]

[tex]\qquad\displaystyle \tt \dashrightarrow \: p(outside \: the \: triangle) = \frac{43}{48} [/tex]

Answer:

Infinite solutions (D).

Step-by-step explanation:

Here is how:

To determine the true statement about the given equation, let's simplify it step by step:

-9(x + 3) + 12 = -3(2x + 5) - 3x

Distributing the -9 and -3 on the left and right sides respectively:

-9x - 27 + 12 = -6x - 15 - 3x

Combining like terms:

-9x - 15 = -9x - 15

Now, let's analyze the equation. We have -9x on both sides, and -15 on both sides. By subtracting -9x from both sides and -15 from both sides, we obtain:

0 = 0

This equation is true regardless of the value of x. In other words, it holds for all values of x. Therefore, the equation has infinitely many solutions.

Answer:

The correct answer is: "The equation has one solution, x = 0"

Answer: is X = 5 within the diagram.

Answer:

Part A: The actual measurement of the piece of wood could be between 9.65 and 9.75 inches.

Part B: The measurement has three significant digits.

Step-by-step explanation:

Significant digits are the digits in a number that carry meaning in terms of the precision or accuracy of the measurement. In this case, the number 9.7 has three significant digits, which means that the measurement is accurate to the tenths place.

The statement indicates that in practical applications, it is common to extend the basic logical language with additional symbols and allow for some degree of informality in the representation of formulas, as long as it is clear that these additional symbols and formulas can be formalized in terms of the basic logical language.

The statement means that when working with formulas in a particular context or domain, it is common to introduce additional symbols beyond the basic logical symbols such as "E" (for existential quantification) and "∧" (for conjunction). These additional symbols can include defined predicates, operations, and constants.

Defined predicates refer to predicates or relations that are defined in terms of other predicates or relations. They can be used to express complex concepts or conditions in a concise manner. For example, in mathematics, one may define a predicate "Prime(x)" to represent the concept of a number being prime.

Operations refer to functions or operations that can be applied to terms or formulas. They allow for combining or manipulating expressions in a meaningful way. For instance, addition, multiplication, and exponentiation are common operations in mathematics.

Constants are symbols that represent specific, fixed values. They can be used to denote specific objects or elements within the domain of discourse. For example, in logic, "0" and "1" can be used as constants to represent the truth values "false" and "true," respectively.

Furthermore, the statement suggests that formulas may be used informally, meaning that they can be expressed or written in a less strict or precise manner. While the informal representation of formulas may be easier to understand or work with, it is understood that each of these formulas can be translated or reformulated in a way that only involves the basic logical symbols (such as "E" and "∧") and the specified nonlogical symbols (such as defined predicates, operations, and constants).

Overall, the statement acknowledges that in practical applications, it is common to extend the basic logical language with additional symbols and allow for some degree of informality in the representation of formulas, as long as it is clear that these additional symbols and formulas can be formalized in terms of the basic logical language.

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Answer:

x = 12

Step-by-step explanation:

sin45 = x/17         (sin = opposite/hypotenuse)

x = (sin45)(17) = 12.02 ≈ 12

Answer:  if the length of the second rectangular field is 200 meters, the width should be 35 meters to have the same perimeter but a larger area.

Step-by-step explanation:

STEP1:- Let's denote the length of the second rectangular field as L2 and the width as W2.

The perimeter of a rectangle is given by the formula:

Perimeter = 2(length + width).

For the first rectangular field with length L1 = 135 meters and width W1 = 100 meters, the perimeter is:

Perimeter1 = 2(135 + 100) = 470 meters.

STEP 2:- To find the length and width of the second rectangular field with the same perimeter but a larger area, we need to consider that the perimeters of both rectangles are equal.

Perimeter1 = Perimeter2

470 = 2(L2 + W2)

STEP 3 :- To determine the larger area, we need to find the corresponding length and width. However, there are multiple solutions for this problem. We can set an arbitrary value for one of the dimensions and calculate the other.

For example, let's assume the length of the second rectangular field as L2 = 200 meters:

470 = 2(200 + W2)

470 = 400 + 2W2

2W2 = 470 - 400

2W2 = 70

W2 = 35 meters

HENCE L2 = 200 meters and W2 = 35 meters

No, the given two fractions/ratios do not form a proportion.

Two ratios are said to be forming proportions if and only if the reduced forms of fractions of the two ratios are the same or are equal to each other.  For example - [tex]\frac{3}{6}[/tex] and [tex]\frac{1}{2}[/tex] are in proportion because [tex]\frac{3}{6}[/tex] when reduced to the simplest form gives [tex]\frac{1}{2}[/tex] which is the same as the other given ratio.

In the given question, one ratio given is [tex]\frac{1}{3}[/tex] and the other one is [tex]\frac{28}{36}[/tex]. Reducing the second ratio to the simplest form we get [tex]\frac{7}{9}[/tex]. Clearly, the two fractions are not equal. Hence, the given two ratios are not in proportion.

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The length of side b in triangle ABC is 18.7 units.

In Mathematics and Geometry, the law of sines is also referred to as sine law or sine rule and it can be defined as an equation that relates the side lengths of a triangle to the sines of its angles.

In Mathematics and Geometry, the law of sine is modeled or represented by this mathematical equation (ratio):

[tex]\frac{sinA}{a} =\frac{sinB}{b} =\frac{sinC}{c}[/tex]

In this context, the value of b can be determined as follows;

sin112/37 = sin28/b

b = 37sin28/sin112

b = 17.3705/0.9272

b = 18.7 units.

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Answer:

1/4+1/3+1/8

=17/24

Step-by-step explanation:

1-17/24

=7/24

7/24×240

=70

Answer: its D! not 8!!!

Step-by-step explanation:

A true statement based on the given information is that ΔCAT and ΔDOG are similar triangles, meaning their corresponding angles are congruent and their corresponding sides are in proportion.

If all pairs of corresponding angles and sides in triangles ΔCAT and ΔDOG are congruent, it implies that the two triangles are similar. In similar triangles, the corresponding angles are congruent, and the corresponding sides are in proportion.

Based on this information, the following true statement can be made:

The ratio of the lengths of the corresponding sides in ΔCAT and ΔDOG is equal.

For example, if the corresponding sides are CA and DO, the ratio CA/DO will be equal to the ratio of the lengths of the other corresponding sides.

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Answer:

  y < 2x +6

Step-by-step explanation:

You want an inequality for the given graph.

Here are some steps you can follow, in no particular order.

When you have this information, you can write the inequality in slope-intercept form.

When the boundary line is dashed, the inequality symbol you use will not include the "or equal to" case. It will be one of < or >.

When the shading is below the line, the values of y that satisfy the inequality will be less than (<) those on the boundary line. If shading is above, the y-values will be greater than (>) those on the line.

The slope and intercept go into the inequality like this:

  y < mx + b . . . . . . where m is the slope, and b is the y-intercept

For a dashed line, shaded below, with m=2 and b=6, the inequality is ...

  y < 2x +6

__

Additional comment

There are two points identified on the boundary line: (-2, 2) and (0, 6). The slope formula can be used to find the slope:

  m = (y2 -y1)/(x2 -x1)

  m = (6 -2)/(0 -(-2)) = 4/2 = 2

The point (0, 6) on the y-axis is the y-intercept. The y-value there is 6.

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Answer: The value of x = 1  and y = -1

Step-by Step Explanation:

We have 5x + 2y = 3 -----(i)

and 2x + 3y = -1 -----(ii)

By substitution method,

from (i), x = 3-2y/5

Putting the value of x in equation (ii),

we get, 2(3-2y/5) + 3y = -1

6 - 4y/5 + 3y =-1

6 - 4y + 15y = -5

6 - 11y = -5

-11y = -5 - 6

-11y = -11

y = -1

And, x = 3-2(-1)/5

x = 3+2/5

x = 1

Therefore,  x=1 and y=−1

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Miguel has 3 friends and he packed sandwiches for everyone to share equally means that Miguel packed 3 sandwiches for each camper.

If Miguel packed 4 sandwiches, then he would have packed 1 sandwich for each camper:

Number of sandwiches per camper = Total number of sandwiches / Number of campers

There are 4 campers, so plug that into the equation to get:

Number of sandwiches per camper = Total number of sandwiches / 4

Solve for the total number of sandwiches by multiplying both sides of the equation by 4:

Total number of sandwiches = Number of sandwiches per camper × 4

So, the total number of sandwiches is 4 × Number of sandwiches per camper.

Each camper will get 1 sandwich, so plug that into the equation to get:

Total number of sandwiches = 1 × 4

Which means there are a total of 4 sandwiches.

Therefore, Miguel packed 1 sandwich for each camper.

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The equation of the line with a slope of 1/4 that passes through the point (3,0) is y = 1/4x - 3/4.

To find the equation of a line with a slope of 1/4 that passes through the point (3,0), we can use the point-slope form of the equation of a line.

The point-slope form of a line is:

y - y1 = m(x - x1)

where (x1, y1) is the given point and m is the slope.

Substituting the values into the formula, we have:

y - 0 = 1/4(x - 3)

Simplifying:

y = 1/4(x - 3)

Distributing 1/4 throughout the expression:

y = 1/4x - 3/4

Therefore, the equation of the line with a slope of 1/4 that passes through the point (3,0) is y = 1/4x - 3/4.

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Incorrect,  the correct exponential growth equation as it accurately represents a starting value of 300 and a growth rate of 2%. Scott's equation

Neither Pierre nor Scott has the correct exponential growth equation.

The exponential growth equation represents a relationship where a quantity increases or grows exponentially over time. It is typically represented as y = a(1 + r)^x, where "a" represents the initial or starting value, "r" represents the growth rate (expressed as a decimal), "x" represents the time or number of periods, and "y" represents the resulting value after the growth.

In this case, Pierre's equation is y =[tex]300(1.02)^x.[/tex]This equation suggests a growth rate of 2% (0.02 as a decimal), which means that the quantity would increase by 2% with each period. This aligns with the given growth rate of 2%. Thus, Pierre's equation is correct.

On the other hand, Scott's equation is y = [tex]300(1.2)^x[/tex]. This equation suggests a growth rate of 20% (0.2 as a decimal), which means that the quantity would increase by 20% with each period. However, the given growth rate is 2%, not 20%. Therefore, Scott's equation is incorrect.

To summarize, Pierre's equation, y = 300(1.02)^x, is the correct exponential growth equation as it accurately represents a starting value of 300 and a growth rate of 2%. Scott's equation, y = 300(1.2)^x, does not match the given growth rate and is therefore incorrect.

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1. The total in mass of the ingredients used is 2.35kg

2. The cost of sugar needed is R25.78.

A word problem is a few sentences describing a 'real-life' scenario where a problem needs to be solved by way of a mathematical calculation.

These statements are interpreted into mathematical equation or expression.

1. The recipes are ;

0.8kg = 800g

sugar = 650g

butter = 900000 mg = 900000/1000 = 900g

Therefore the total mass of ingredients

= 800 + 650 +900

= 2350g

in kilograms, 1000g is 1kg

2350g = 2350/1000

= 2.35kg

2. If 150g = R5.95

1g = 5.95/150

650g = 5.95 × 650/150

= R25.78.

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The average utility price in Orlando for the 6 month period, and the way it compares to the national average is d. $ 308. 83 ; higher than the national average .

The information for Orlando is April, the cost was 288 dollars; May, 310 dollars; June, 325 dollars; July, 294 dollars; August, 293 dollars; September, 343 dollars.

The average is:

= ( 288 + 310 + 325 + 294 + 293 + 343 ) / 6

= 1, 853 / 6

= $ 308. 83

This average is higher than the national average of $ 308. 83.

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Full question is:

The average national utility price is $270.48. Over a 6-month period, what is the average utility price in Orlando? How does this compare with the national average?

A graph titled Orlando, Florida, has month on the x-axis and utility price on the y-axis. In April, the cost was 288 dollars; May, 310 dollars; June, 325 dollars; July, 294 dollars; August, 293 dollars; September, 343 dollars.

a. $370.60; higher than the national average

b. $292.17; higher than the national average

c. $38.35; lower than the national average

d. $308.83; higher than the national average

a. The total length of the painted white line in the javelin throwing arena is approximately 255.984 meters.

b. The total area of grass in the shaded landing area of the javelin throwing arena is approximately 1624.6 square meters.

To find the total length of the painted white line, we need to calculate the length of the two straight segments and the two circular arcs.

a) Total length of the painted white line:

Let's break it down into components:

1. The two straight segments: Each straight segment is 95 meters long, and there are two of them.

Length of straight segments = 2 * 95 = 190 meters

2. The two circular arcs:

The throwing arena is a sector of a circle with a radius of 100 meters. The angle of the sector can be calculated using trigonometry. The angle can be found by taking the inverse cosine of the ratio of the adjacent side (which is the radius minus the throwing line distance) to the hypotenuse (which is the radius).

Angle (in radians) = cos⁻¹((radius - throwing line distance) / radius)

Now, the length of each circular arc can be calculated using the formula for the length of an arc of a circle:

Length of circular arc = radius * angle

Let's calculate the angle first:

Angle (in radians) = cos⁻¹((100 - 5) / 100)

Angle = cos⁻¹(95 / 100)

Angle ≈ 0.32492 radians

Now, we can calculate the length of each circular arc:

Length of each circular arc = 100 * 0.32492 ≈ 32.492 meters

Since there are two circular arcs, the total length of the painted white line is:

Total length = 190 (straight segments) + 2 * 32.492 (circular arcs)

Total length ≈ 255.984 meters

b) Total area of grass in the shaded landing area:

The shaded landing area is the sector of the circle with a radius of 100 meters and the angle we calculated above.

The formula to calculate the area of a sector of a circle is:

Area of sector = (angle / 2π) * π * radius²

Area of the shaded landing area = (0.32492 / (2π)) * π * 100²

Area of the shaded landing area ≈ (0.32492 / 2) * 10000

Area of the shaded landing area ≈ 1624.6 square meters

So, the total area of grass in the shaded landing area is approximately 1624.6 square meters.

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Answer:

Step-by-step explanation: On the left side find the number that is able to make that sum true for that equation. on the right side you just subtract the answer with the number to get your answer.

Answer:

Step-by-step explanation:

I Think this is the  answer

On the left side find the number that is able to make that sum true for that equation. on the right side you just subtract the answer with the number to get your answer

The value of AB is,

⇒ AB = 5.9

(rounded to nearest tenth)

We have to given that,

A right triangle ABC is shown.

Now, By trigonometry formula,

we get;

⇒ cos 33° = Base / Hypotenuse

Substitute all the values, we get;

⇒ cos 33° = AB / 7

⇒ 0.84 = AB / 7

⇒ AB = 0.84 × 7

⇒ AB = 5.88

⇒ AB = 5.9

(rounded to nearest tenth)

Thus, We get;

AB = 5.9

(rounded to nearest tenth)

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The height of the average fourth grader is 137cm 1mm. This height can be determined by multiplying 3 by the average height of a newborn baby.

Given information,

The average height of babies = 45 cm 7mm

45 cm 7 mm is equivalent to 45.7 cm (since there are 10 millimeters in a centimeter).

Let the height of a fourth grader be x.

According to the question,

The height of a fourth grader (x) = 3 × the average height of a newborn baby

The height of a fourth grader (x) = 3 × 45.7

The height of a fourth grader (x)= 137.1 = 137cm 1mm

Therefore, the height of a fourth grader is 137cm 1mm.

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The quadratic equation with roots 5 + i√2 and 5 - i√2 is:

x^2 - 10x + 27 = 0

To write a quadratic equation with roots 5 + i√2 and 5 - i√2, we can use the fact that complex roots occur in conjugate pairs. Therefore, the equation will have the form:

(x - root1)(x - root2) = 0

Substituting the given roots:

(x - (5 + i√2))(x - (5 - i√2)) = 0

Now, we expand the equation:

(x - 5 - i√2)(x - 5 + i√2) = 0

Using the difference of squares formula:

((x - 5)^2 - (i√2)^2) = 0

Simplifying the equation:

(x - 5)^2 + 2 = 0

Expanding the square:

x^2 - 10x + 25 + 2 = 0

Combining like terms:

x^2 - 10x + 27 = 0

Therefore, the quadratic equation with roots 5 + i√2 and 5 - i√2 is:

x^2 - 10x + 27 = 0

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