You are trying to make a hole in one on the miniature golf green
3
3
5
7
9 X
a. Write an absolute value function that represents the path of the golf ball.
3
$ (z) = – 31x/+6
b. Write the function in part (a) as a piecewise function.
f(x) =
if x < 6
if x26

Answer:

3 batches but you will have some left over

Step-by-step explanation:

Answer:

y= 6x - 30

Step-by-step explanation:

First yu would take the 30 dollars you spent then you will subtract 6 times  how many cars you have done.

Answer:

3.5 × 102 = 357

2.4 × 103 = 247.2

357 × 247.2 = 88250.4

Answer:

[tex]4a + 9a \\ \\ = (4 + 9).a \\ \\ = 13a \\ \\ 9y + 3y - 5x \\ \\ (9y + 3y) - 5x \\ \\ (9 + 3).y - 5x \\ \\ 12y - 5x[/tex]

Answer:

ninguna respuesta lo siento pero si es que puedo lo cmletare

Answer:

When you divide 3.2 by 0.8 you get 4.

Answer:

-3

Step-by-step explanation:

Answer:

-4.5, -3, 22/7 , 16/5, sqrt(17)

Step-by-step explanation:

x=5

Step-by-step explanation:

x-2=3(x-4)

x-2=3x-12

12-2=3x-x

10=2x

x=10/2

x=5

Answer:

x = 5

Step-by-step explanation:

x - 2 = 3(x - 4)

x - 2 = 3x - 12

-2x - 2 = -12

-2x = -10

x = 5

Answer:

6x-5

Step-by-step explanation:

14x-4- (3x-2)-(5x+3)= 14x-4-3x+2-5x-3= 6x-5

Answer:

10980 is the correct answer

Answer:

the answer is 3. but the workings are so long

Step-by-step explanation:

1. k = 76°

2. r = 25cm

3. as the drawing attached

one pair of parallel lines : AB and DC

one pair of equal angles : L A and L D

4. (7²× 3`¹)⁴×7^5 / (3² × 7^(-6))³

= (7^8 × 3`⁴)×7^5/ (3² × 7^(-6))³

= (7^13 × 3`⁴)/ (3^6 × 7^(-18))

= (7^(31) × 3^(-10))

= 7^31 / 3^10

The value of d = 6 and the value of YZ = 42

Since XY=32, YZ=7d, and XZ=74

Based on this question, it should be noted that the addition of XY and YZ will equal to the value of XZ. Therefore,

XY + YZ = XZ

32 + 7d = 74

Collect like terms

7d = 74 - 32

7d = 42

Divide through by 7

7d/7 = 42/7

d = 6

Since d is 6, the value of YZ will be:

= 7d = 7 × 6 = 42

In conclusion, the value of d = 6 and the value of YZ = 42.

Read related link on:

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Answer:

15.87%

Step-by-step explanation:

*Probability-Below 15.87%

Z1=-1

*x-1 38

*µ 44

*σ 6

The probability that a randomly selected student has a typing speed of less than 38 words per minute is 15.87%.

The Z-score, or standard score, is the number of standard deviations a given data point lies above or below mean.

z = (x -μ)/σ

Where,

Z is standard score.

x is observed value.

μ is mean of the sample.

σ is standard deviation of the sample.

The area under the normal distribution curve represents probability.

According to the given question.

Mean, μ = 44

Standard deviation, σ = 6

Observed value, x = 38

Therefore, z-score = [tex]\frac{38-44}{6}= -1[/tex]

So, the are P(z > -1) = 15.87%

Hence, the probability that a randomly selected student has a typing speed of less than 38 words per minute is 15.87%.

Find out more information about z-score and probability here:

https://brainly.com/question/25638875

#SPJ2

Answer:

200 each.

Step-by-step explanation:

400 divided by 2 is 200

Answer:

u=6

Step-by-step explanation:

5u+3=-3u-1=8

COMBINE LIKE TERMS(so 5u and -3u and then combine your positive 4 and your negative 1 then bring down your 8

2u-4=8

opposite inverse so add 4 to 8

2u=12

divide 2 into 12

u=6

so your final answer is 6.

Answer:

AUB = {2,3,4,6,8,9,10,12}

The proportional relationship between drawing court lengths x in centimeters and court lengths in y centimeters is y = 22.5x

Your question is not complete, it seems to be missing the following information;

"write an equation for the proportional relationship between drawing court lengths x in centimeters and court lengths in y centimeters"

The drawing court length is given as;

x = 40 cm or 80 cm

drawing scale = 1 cm : 22.5 cm

The corresponding length of the court is calculated as;

when x = 40 cm;

[tex]y = \frac{22.5}{1} \times 40 cm = 900 \ cm[/tex]

when x = 80 cm;

[tex]y = \frac{22.5}{1} \times 80 \ cm = 1,800 \ cm[/tex]

The proportional relationship between drawing court lengths x in centimeters and court lengths in y centimeters is calculated as;

[tex]\frac{y}{x} = \frac{900}{40} = \frac{1800}{80} \\\\\frac{y}{x} = 22.5\\\\y = 22.5 x[/tex]

Thus, the proportional relationship between the lengths is y = 22.5x

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True because if a number is negative 4 the absolute value will be 4

answer:

sorry i don't know the answer but are you an army ?

Answer:

y=9-7x

If x= -1, y=16

If x= 0, y=9

If x=2, y= -5

Step-by-step explanation:

Because you are solving the equation for y, you want to have y by itself on one side. The only way to do that in this problem is by subtracting the 7x on both sides.

y+7x=9

-7x -7x ---> y=9-7x

The next part of the question says to find the value of Y for each value of X. Using the given X values, we plug them into the equation we just got in order to find Y.

y=9-7(-1) ----> y=16

y=9-7(0) ----> y=9

y=9-7(2) ----> y=-5

Answer:

(-3,-4)

Step-by-step explanation:

Answer:

2.8, 4.6, V7, V17

i hope it help n im sorry i can't explain

Answer:

z = 5y/2 - 1

Step-by-step explanation:

Solve for  z

by simplifying both sides of the equation, then isolating the variable.

Answer:

Step-by-step explanation:

Fraction:

[tex]869214.951=\dfrac{869214951}{1000}\\[/tex]

Power of 10:

[tex]869214.951=8.69214951 * 10^{5}[/tex]

Answer:

Step-by-step explanation:

[tex]\left\{\begin{array}{ccc}2x+1y+2z&=&13\\1x+1y-2z&=&8\\1x+2y+1z&=&11\\\end{array}\right.\\\\\\\Delta=\left| \begin{array}{ccc}2&1&2\\1&1&-2\\1&2&1\end{array}\right| =2*\left| \begin{array}{ccc}1&\frac{1}{2}&1\\1&1&-2\\1&2&1\end{array}\right| =2*\left| \begin{array}{ccc}1&\frac{1}{2}&1\\0&\frac{1}{2}&-3\\0&1&3\end{array}\right| =2*(\frac{3}{2}+3)=9\\\\[/tex]

[tex]\Delta_1=\left| \begin{array}{ccc}13&1&2\\8&1&-2\\11&2&1\end{array}\right| =2*\left| \begin{array}{ccc}13&1&2\\8&1&-2\\\frac{11}{2}& 1&\frac{1}{2}\end{array}\right| =2*\left| \begin{array}{ccc}13&1&2\\-5&0&-4\\\frac{-5}{2}& 0&\frac{5}{2}\end{array}\right| \\\\=2*(-1)*(\frac{-25}{2}-\frac{20}{2}) =45\\[/tex]

[tex]\Delta_2=\left| \begin{array}{ccc}2&13&2\\1&8&-2\\1&11&1\end{array}\right| \\\\\\=\left| \begin{array}{ccc}3&21&0\\3&30&0\\1&11&1\end{array}\right| \\\\\\=1*(90-63) =27\\[/tex]

[tex]\Delta_3=\left| \begin{array}{ccc}2&1&13\\1&1&8\\1&2&11\end{array}\right| \\\\\\=\left| \begin{array}{ccc}0&-1&-3\\0&-1&-3\\1&2&11\end{array}\right| \\\\\\=0\\[/tex]

[tex]\left\{\begin{array}{ccc}x=\dfrac{\Delta_1}{\Delta}=\dfrac{45}{9}=5\\\\y=\dfrac{\Delta_2}{\Delta}=\dfrac{27}{9}=3\\\\z=\dfrac{\Delta_3}{\Delta}=\dfrac{0}{9}=0\\\end{array}\right.[/tex]