Please help with my question.

Answer:

If several points are graphed on a number line, the point that is farthest from 0 need NOT be always greater. Consider x axis, our Real number line. We can traverse in positive number direction and negative number direction.

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Answer:

No

Step-by-step explanation:

Answer:

5280

Step-by-step explanation:

12% of 8000 = 960

960 x 5.5 = 5280

If my answer is incorrect, pls correct me!

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-Chetan K

Answer:

2 and 4

1 and 5

3 and 3

Step-by-step explanation:

Answer:

1 + 5

2 + 4

3 + 3

I hope I helped out

Answer:

The answer is 9.

Step-by-step explanation:

6x - 2 < 5x + 7

6x - 5x < 7 + 2

x < 9

Hi ;-)

Calculate

[tex]6-(-11)=6+11=\boxed{17}[/tex]

Answer:

17

Step-by-step explanation:

6-(-11)

Subtracting a negative is like adding

6+11

17

Answer:

[tex](x + 7) \times (3x - 4)[/tex]

Step-by-step explanation:

[tex] {3}^{2} + 17x - 28[/tex]

[tex]3 {x}^{2} + 21x - 4x - 28[/tex]

[tex]3 \times x(x + 7) - 4x - 28[/tex]

[tex]3x \times ( x + 7) - 4(x + 7)[/tex]

[tex](x + 7) \times (3x - 4)[/tex]

Answer:

1.22

Step-by-step explanation:

89/23=3.87

90/19=4.74

4.74/3.87=1.22

Or

3.87/4.74=0.82

Hope I got it

Answer:

[tex] \frac{2070}{1691} [/tex]

Step-by-step explanation:

[tex] \frac{23}{89} \div \frac{19}{90} [/tex]

➡️ [tex] \frac{23}{89} \times \frac{90}{19} [/tex]

➡️ [tex] \frac{23 \times 90}{89 \times 19} = \frac{2070}{89 \times 19} [/tex]

➡️ [tex] \frac{2070}{1691} [/tex] ✅

Answer:

No

Step-by-step explanation:

<JAC = 93

< DBE = 90

The two angles are not equal

Answer:

A

Step-by-step explanation:

We know that it is A because the two smaller angles are being added, and we know the sum is 90 degrees. The only equation that satisfies both of these is A.

Answer:

A

Step-by-step explanation:

because it is a right angled

Answer:

V = pi R^2 * h       volume of cylinder    (area of base * height)

pi R^2 = 64 / 8 = 8

R^2 = 8 / pi = 2.865

R = 1.69 ft

Answer:

(8, 6)

Step-by-step explanation:

2x - y = 10

2x - 2y = 4

=>

x - y = 2

x = y + 2

we put that into the first equation

2×(y+2) - y = 10

2y + 4 - y = 10

y + 4 = 10

y = 6

=>

x = y + 2 = 6 + 2 = 8

so, we have a ordered pair (x, y) = (8, 6)

Answer:

x = 3

13 miles between Madison and Jamie's house.

Step-by-step explanation:

If we add the distance between Anoa's and Madison's house with the distance between Jamie's and Madison's house, then we get the total distance between Anoa's and Jamie's house.

(3x + 2) + (3x + 4) = 9x - 3

Let's add up the terms first

3x + 2 + 3x + 4 = 9x - 3

6x + 6 = 9x - 3

Let's move the variables to the right side by subtract 6x from both sides

6x + 6 = 9x - 3

-6x         -6x

6 = 3x - 3

Add 3 to both sides

6 = 3x - 3

+3        +3

9 = 3x

Isolate the variable, x, by dividing both sides by the coefficient, 3.

9/3 = 3x/3

x = 3

Now we need to find the distance between Madison's and Jamie's house.

3x + 4

Plug in 3 in place of the x

3(3) + 4

9 + 4 = 13

Answer:

Step-by-step explanation:

If we add the distance between Anoa's and Madison's house with the distance between Jamie's and Madison's house,then we get the total distance between anoa's and Jamie's house.

Answer:

Step-by-step explanation:

Given,

6(x-3) = 11x + 7

=> 6x - 18 = 11x + 7

=> 11x - 6x = -18 - 7

=> 5x = -25

[tex] = > x = \frac{ - 25}{5} [/tex]

=> x = -5 (Ans)

[tex]\large\bf{\red{ \bullet}} \: \tt \:\: 6(x - 3) \: = \: 11x + 7[/tex]

[tex]\large\bf{\red{ \bullet}} \: \tt \:\:6x \: - \: 18 \: = \: 11x \: + \: 7[/tex]

[tex]\large\bf{\red{ \bullet}} \: \tt \:\: - 7 \: \: - 18 \: = \: 11x \: - \: 6x[/tex]

[tex]\large\bf{\red{ \bullet}} \: \tt \: \: - 25 \: = \: 5x[/tex]

[tex]\large\bf{\red{ \bullet}} \: \tt \: \cancel\frac{-25}{5} \: = \: x[/tex]

[tex]\large\bf{\red{ \bullet}} \: \tt \: - 5 \: = \: x[/tex]

[tex]\large\bf{\red{ \bullet}} \: \tt \: \: x \: = \: - 5[/tex]

If the integral is

[tex]\displaystyle \int (ax^2+2bx+c)^{3/2}(2ax+2b)\,\mathrm dx[/tex]

substitute [tex]u = ax^2+2bx+c[/tex] and [tex]\mathrm du=(2ax+2b)\,\mathrm dx[/tex]. Then you end up with

[tex]\displaystyle \int u^{3/2}\,\mathrm du = \frac25u^{5/2} + C[/tex]

which in terms of x is

[tex]\boxed{\dfrac25(ax^2+2bx+c)^{5/2} + C}[/tex]

Answer:

18.63

Step-by-step explanation:

[tex] \frac{6}{10} = 0.6 \\ \frac{3}{100} = 0.03[/tex]

[tex]10 + 8 + 0.6 + 0.03 = 18.63[/tex]

1/2 divided by 2/12 or 1/6 would be 3.The reciprocal of 1/6 is 6 and multiplied with 1/2 = 3.

Answer:

3

Step-by-step explanation:

[tex] \frac{1}{2} \div \frac{2}{12} [/tex]

➡️ [tex] \frac{1}{2} \times \frac{12}{2} [/tex]

➡️ [tex] \frac{1}{2} \times 6[/tex]

➡️ [tex] = 3[/tex] ✅

Answer:

3.14159265358979

Step-by-step explanation:

Answer:

NO

Step-by-step explanation:

xbsndjejejxkxkekejejejejs

Answer:

The decimal 1.0227 is a rational number. First of all, it is a terminating decimal, which means that the decimal has a definite ending point.

Step-by-step explanation:

Step-by-step explanation:

Adding \sqrt{-2}\,\,and\,\,\sqrt{-18}

−2

and

−18

we get 4\sqrt{2i}4

2i

Option C 4 StartRoot 2 EndRoot i is correct.

Step-by-step explanation:

We need to find the sum of: \sqrt{-2}\,\,and\,\,\sqrt{-18}

−2

and

−18

Finding sum:

\sqrt{-2}+\sqrt{-18}

−2

+

−18

\sqrt{-2}

−2

can be written as \sqrt{2}i

2

i

\sqrt{-18}

−18

can be written as \sqrt{18}i

18

i

We know 18 = 2x3x3 = 2x3^2 so,

\sqrt{2i}+\sqrt{2\times 3^2}i

2i

+

2×3

2

i

\sqrt{2i}+3\sqrt{2}i

2i

+3

2

i

Adding like terms:

4\sqrt{2i}4

2i

So, adding \sqrt{-2}\,\,and\,\,\sqrt{-18}

−2

and

−18

we get 4\sqrt{2i}4

2i

Option C 4 StartRoot 2 EndRoot i is correct.

Keywords: Square root

Answer:

in 20 kilometers round they will meet

Answer:

day 8

Step-by-step explanation:

the rate of change is 2 (x2) which is making the amount saved double each day you can write a formula to represent this sequence:

f(n)=0.01x2^n-1

you put in the day number for n

f(n)=0.01x2^8-1

this gives you 1.28 which is the first day with an amount above 1.00

Answer:

The test was not statistically significant because if the null hypothesis is true, one could expect to get a test statistic at least as extreme as that observed 21% of the time.

Step-by-step explanation:

This is the right answer,since this result is only observed 21% of the time, so in general it's not significant, so the first 2 are eliminated. The 2 x 0.21 doesn't matter since, the percent is 21% not 42%, so it doesn't even matter. The last question we eliminate is:"The test was not statistically significant because if the null hypothesis is true, one could expect to get a test statistic at least as extreme as that observed 79% of the time" 79% of the time is a pretty good amount to say it's significant, but it only says 21% of the time.So, it leaves us with:The test was not statistically significant because if the null hypothesis is true, one could expect to get a test statistic at least as extreme as that observed 21% of the time.

Hope this helps lol (: is this a psat or somethin?

Answer:

Step-by-step explanation:

To find the cost of each box divide the total cost by the number of boxes:

In store A:

→ A box of cotton candy cost = $ 1

→ 12 boxes cost = $ 12

In store B:

→ 12 boxes cost = $ 48

Now we have to,

find the cost of each box in the store B.

→ Total cost in B ÷ Total boxes in B

→ 48 ÷ 12 = 4

So, $ 4 is cost of each box in store B.

9514 1404 393

Answer:

  [tex]\displaystyle\int^5_2 {(3x^3-7x)} \, dx[/tex]

Step-by-step explanation:

The interval of interest becomes the limits of integration. ∆x becomes dx, and the xi are replaced by the variable of integration, x.

let x be the number:

1st = 4

2nd = 4+1 = 5

3rd = 4+2 = 6

HOPE THIS HELPS. GOODLUCK:)

Answer:

15 dollars

Step-by-step explanation:

We can write a ratio to solve

6 cones         9 cones

------------   = --------------

10 dollars       x dollars

Using cross products

6*x = 10 *9

6x = 90

Divide each side by 6

6x/6 = 90/6

x = 15

9514 1404 393

Answer:

  (b) dilation by 2, reflection in y-axis

Step-by-step explanation:

Each of the dimensions of ΔA'B'C' is double the corresponding dimension of ΔABC, so dilation by a factor of 2 has occurred.

The sequence of vertices in ΔA'B'C' is CCW, opposite that of ΔABC. Hence, a reflection has taken place. (Rotation keeps the same order.)

The transformation is a dilation by a factor of 2 and a reflection across the y-axis.