2. A machine fills bags with 24 ounces of M&Ms. After the bags are filled, another
machine weighs them. If a bag's weight differs from the desired 24-ounce weight
by more than 0.25 ounces, the bag is rejected.
Part A: Define a variable and write an absolute value inequality that represents the
weight a bag must be in order to not be rejected.
Can someone help me??

Answer:

87

Step-by-step explanation:

Mean(or average) = 82

let 'x' be the last test marks

Sum of marks of tests/Number of tests = Mean

(78 + 83 + 80 + x)/4 = 82

241 + x = 82 × 4

241 + x = 328

x = 328 - 241

x = 87

Answer:

y = 3 suh slid este ob cine este a, b și g au nevoie de acel kinfo pentru a termina

Step-by-step explanation:

Answer:

4x _ 8 + 90 = 144

Step-by-step explanation:

you do parentheses then the rest you follow that order and it will all work ot really easy

Answer:

Step-by-step explanation:

APE - adding 8 on both sides (first line)

DPE - dividing by 7 on both sides (second line)

Answer:

The choose D. 4¹⁵

I hope I helped you^_^

Answer:

Step-by-step explanation:

Given that x = 3 and y = 2 we can figure these out

3x = 3x3 = 9

5y = 5 x 2 = 10

9+10=19

X times y - 1

3x2-1=5

X*+y* =

3x3+2x2 = 13

2x3*-2 =

2x3x3 - 2 = 16

-5x3+9

= -6

2x2-3+5+3*-3x2 =

9

The scale is 2 cm to 12 in so the actual length of the shorter side is 12 in, and the actual side of the longer side is (8/2)×12=48 in. So, the actual area of the ramp is (1/2)×12×48=288 Sq. in.

Scale used to convert the dimensions from drawing to actual is,

2 cm : 12 in

Height of the ramp in a skateboard park = 2 cm

Therefore, actual height 'x' of the ramp will be,

[tex]\frac{2}{12}=\frac{2}{x}[/tex]

x = 12 inches

Since, measure of the base of the ramp = 8 cm

Length of the base 'y' of the actual ramp will be,

[tex]\frac{2}{12}=\frac{8}{y}[/tex]

y = [tex]\frac{8\times 12}{2}[/tex]

y = 48 inches

Area of a triangle = [tex]\frac{1}{2}(\text{Base})(\text{Height})[/tex]

                             = [tex]\frac{1}{2}(48)(2)[/tex]

                             = 48 square inches

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Answer:

nice TV

Step-by-step explanation:

Answer:

a=2, b=-3

Step-by-step explanation:

f(x) = ax+b

f(3)=3, 3a+b=3

f(2)=1, 2a+b=1

Solving these two equations, we get a=2, b=-3

Answer:

whats the choices?

Step-by-step explanation:

Answer:

I think this is if it is right then help me plz this is false ..

Answer:

I would first tell people to evacuate

Answer:

- 8x + 3

Step-by-step explanation:

(f + g)(x)

= f(x) + g(x)

= - 5x + 3 + (- 3x)

= - 5x + 3 - 3x ← collect like terms

= - 8x + 3

Answer:

-27

Step-by-step explanation:

-3 x -3=9

9 x -3= -27

Answer:

-27

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex]y^2+6y+8x+1=0\\\\y^2+2*3y+9+8x+1-9=0\\(y+3)^2+8x-8=0\\8x=-(y+3)^2+8\\\\x=-\dfrac{(y+3)^2}{8}+1 \\Vertex=(1,-3)[/tex]

The vertex is (1,-3).

To find the the vertex of the parabola.

A symmetrical open plane curve formed by the intersection of a cone with a plane parallel to its side.,

Given that:

[tex]y^{2} +6y+8x+1=0\\\\y^{2} +2*3y+8x+1+9-9=0\\\\(y+3)^{2}+8x-8=0\\\\8x=-(y+3)^{2}+8\\\\x=-\frac{(y+3)^{2}}{8} +1\\\\vertex=(1,-3)\\[/tex]

So, the vertex is (1,-3).

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Answer:

jsjwbsihdn3oiansjsos

Answer:

x — 4

Step-by-step explanation:

Difference means subtraction, so x — 4 is the expression for your question.

Answer:

Step-by-step explanation:

Between the fourth and tenth there are:

The total number is:

Step-by-step explanation:

a. 4x = 3x+3

4x-3x=3

x = 3

b. L ABC = 3x+3= 3(3)+3= 12°

c. L CBD = 4x = 4(3) = 12°

d. L ABD = 12+12 = 24°

Answer:

4 triangles

Step-by-step explanation:

the number of triangles in a polygon is (the number of sides in the polygon - 2)

The number of triangles inside a polygon with six sides are 4.

Given is that the number of sides in a polygon is 6.

Therefore, the number of triangles inside a polygon with six sides are 4.

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the answer is 7/9. ...........

Answer:

8. ☐ A Up

☑ B Down 1

☑ C Left [tex]\displaystyle \frac{\pi}{2}[/tex]

☐ D Right

7. [tex]\displaystyle 3\pi[/tex]

6. ☑ A x = −2π

☐ B x = −π

☐ C x = [tex]\displaystyle \frac{\pi}{2}[/tex]

☑ D x = π

5. [tex]\displaystyle y = -1[/tex]

Explanation:

[tex]\displaystyle y = Atan(Bx - C) + D \\ \\ \boxed{y = tan\:(\frac{1}{3}x + \frac{\pi}{6}) - 1} \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow -1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{\pi}{2}} \hookrightarrow \frac{-\frac{\pi}{6}}{\frac{1}{3}} \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \hookrightarrow \boxed{3\pi} \hookrightarrow \frac{\pi}{\frac{1}{3}} \\ Amplitude \hookrightarrow N/A[/tex]

Here is all the information you will need. Now, what you need to know is that ALL tangent, secant, cosecant, and cotangent functions have NO amplitudes. Second, to find the period in this case, you need to take a look at the distanse between each vertical asymptote. Now, accourding to this graph, on a universal scale of [tex]\displaystyle \frac{\pi}{4}[/tex] with a range of [tex]\displaystyle -2\pi\:to\:2\pi,[/tex] the vertical asymptotes are [tex]\displaystyle -2\pi = x\:and\:\pi = x.[/tex] From here, you will then find the distanse between these asymptotes by simply perfourming the operation of Deduction, and doing that will give you [tex]\displaystyle \boxed{3\pi} = \pi + 2\pi.[/tex] So, the period of this function is [tex]\displaystyle 3\pi.[/tex] Now, you will instantly get the jist of the horisontal shift by looking at the above formula. Just keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must pay cloce attention to what is given to you inside those parentheses. Finally, the midline is the centre of your graph, also known as the vertical shift, which in this case is at [tex]\displaystyle y = -1.[/tex]

Well, that just about wraps it up. Now that everything has been explained, you should understand it better. If you still have questions, do not hesitate to comment any you have.

I am delighted to assist you at any time.