What is the condition for block b to move downwards
A) mb/ma > sin theta - mew cos theta
B) mb/ma > cos theta + mew sin theta
C) mb/ma > sin theta + mew cos theta
D) mb/ma > cos theta - mew sin theta
And what would the condition for the block to move upwards
A) mb/ma < sin theta - mew cos theta
B) mb/ma < cos theta + mew sin theta
C) mb/ma < sin theta + mew cos theta
D) mb/ma < cos theta - mew sin theta
Answers
Answer:
Solution in Photo
Explanation:
To solve this question, draw the Free Body Diagram (FBD) for the whole system such that
theta < 90, it will be more clearer that way.
Related Questions
An object is dropped from an airplane and takes 72 seconds to hit the ground what is the magnitude of its Vfy
Answers
The magnitude of its Vfy i.e Vertical componet is mathematically given as
V=705.6 m/s
This is further explained below.
What is the magnitude of its Vfy?Generally, At this point, we need to do an analysis of the vertical motion of the item, which may be thought of as a free fall motion with a constant acceleration.
g = 9.8
As a result, we are able to employ the suvat equation that is as follows:
v = u +at
As a result, the following expression may be used to determine the magnitude of the object's vertical velocity after t = 72 seconds:
v = 0 + (9.8) (72)
V=705.6 m/s
In conclusion, the magnitude
V=705.6 m/s
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An electric stove is rated 1200,
240v-calculate?
Answers
(a) The current drawn is 5A.
(b) The resistance of the filament is 48Ω.
(a) The formula for power is:
P = VI
therefore, current drawn is;
[tex]I = \frac{P}{V}[/tex]
[tex]I = \frac{1200}{240}[/tex]
I = 5A
Therefore, the current drawn is 5A.
(b) Using, ohm's law:
V = IR
therefore, resistance of the filament is:
[tex]R = \frac{V}{I}[/tex]
[tex]R = \frac{240}{5}[/tex]
R = 48Ω
Therefore, the resistance of the filament is 48Ω.
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A rock is thrown vertically upwards at a velocity of 11 meters per second from an initial height of 1.5 meters.
Considering “up” to be the positive y direction, answer the following questions:
How high above the ground does the rock go?
How long does it take to get to the top of its travel?
What is the velocity of the rock half of a second after it is released?
What is the velocity of the rock 1.5 seconds after release?
Answers
The height above the ground reached by the rock is 7.7 m.
The time taken for the rock to travel half of a second after it is released is 1.12 seconds.
The velocity of the rock half of a second after it is released is 15.9 m/s.
The velocity of the rock 1.5 seconds after release is 25.7 m/s.
Height travelled by the rock
The vertical height traveled by the rock is calculated as follows;
h = u²/2g
h = (11²)/(2 x 9.8)
h = 6.2 m
Height above the ground reached by the rock = 1.5 m + 6.2 m = 7.7 m
Time of motion of the rockt = √2h/g
t = √(2 x 6.2/9.8)
t = 1.12 seconds
Velocity of the rock half a second after it was releasedv = u + gt
v = 11 m/s + (9.5 x 0.5)
v = 15.9 m/s
Velocity of the rock 1.5 seconds laterv = u + gt
v = 11 m/s + (9.5 x 1.5)
v = 25.7 m/s
Thus, the height above the ground reached by the rock is 7.7 m.
The time taken for the rock to travel half of a second after it is released is 1.12 seconds.
The velocity of the rock half of a second after it is released is 15.9 m/s.
The velocity of the rock 1.5 seconds after release is 25.7 m/s.
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Trenton is a middle-aged man with Down syndrome. Compared to unaffected adults his age, Trenton is at greater risk of developing ______.
Answers
Answer:
because
Explanation:
ok just because
A charge of 10 coulomb passes through a cross-section of a conductor in 20 seconds. What is the magnitude of current flowing through it?
Answers
The magnitude of current flowing through the conductor is 0.5A.
The charge flowing through the cross-section of the conductor is q = 10C.The time taken by the charge to flow is t = 20s.A stream of charged particles, such as electrons or ions, travelling through an electrical conductor or a vacuum is known as an electric current. The net rate of electric charge flowing through a surface or into a control volume is how it is calculated.The equation for the current flowing in the circuit is I = q/t. Where I is the current in the circuit.Substitute the values of q and t,I = 10C/20sI = 1/2AI = 0.5AThus, the current flowing through the conductor is 0.5 A.To learn more about current, visit :
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Summarize the article in a paragraph .
Answers
Words are too small for me -_-
An airplane acceleration is 3m/s^2. The minimum take-off speed is 102 m/s. The minimum runway length is ____ meter.
Answers
The airplane starts form rest, then accelerates by rate of [tex]3m/s^2[/tex] until it reaches 102m/s at the end of the runway. so we have:
[tex]Vo=0m/s\\Vf=102m/s\\a=3m/s^2\\\\[/tex]
From the equations of uniformly accelerated motion (since the airplane's acceleration is uniform) [tex]'Vf^2=Vo^2+2aS' \\[/tex] is compatible to find the minimum runway length (S).
[tex]Vf^2=Vo^2+2aS\\Vf^2-Vo^2=2aS\\S=Vf^2-Vo^2/2a\\[/tex]
[tex]S=((102m/s)^2-(0m/s)^2)/2m/s^2\\S=(10404m^2/s^2-0m^2/s^2)/2m/s^2\\S=(10404m^2/s^2)/2m/s^2\\S=5202m[/tex]
Purpose
Students will us vector addition on
the Flat-Earth Model.
Theory
Vector addition is easy and useful.
To add (24,0) to (0,-7), the 1st numbers
are added, as are the 2nd, and the order
stays the same: (24,-7). These can be x-
and y-positions, velocities, forces, etc.
Which way are the streaks on the
side windows of a car going 24 MPH if
driving through rain falling at 7 MPH?
That's a vector of (24,-7). The angle is
found by taking the arctangent of the
second 2nd over the 1st: tan¹(-4)=16⁰.
The Flat-Earth Model claims earth
is a horizontal disk. The north pole is at
the center, "Antarctica" is a rim wall at
the edge, and the sun and moon move
in circular paths above the disk. If true,
it should be easy to measure the sun's
altitude and make predictions.
Procedure
1. Find a cardboard box about the size
of a microwave, cut off the top flaps,
and set it on its side outdoors at noon.
2. Cut a coffee-cup-sized hole in the
middle of the upper wall and tape a
sheet of aluminum foil over it. Poke a
small hole in that with a pin or tack.
3 With the sun overhead, even if it is
slightly cloudy, a spot of light should
show on the bottom surface in the box.
Propping the box at a tilted angle may
be necessary, but then don't move it.
Mark the box bottom where the spot is
at noon, and then again at 1PM.
4. Find a ruler and measure the height
from the noon mark up to the foil hole.
Let this be y. Also measure the distance
between the marks. Let this be x. Units
can be inches, centimeters, whatever.
The sun's ray vector in the box is (x,y).
This vector can also be used to find the
sun's angle above the horizon.
Figure 02: The box as described.
5. The sun apparently moves 1000 mi
in an hour. (Call someone in Ft. Worth
and ask them what time of day the sun
is highest in the sky, if skeptical.) The
sun's height in miles is h = 1000-y/x.
6 If the Flat-Earth model is right, the
sun always keeps this height, so after
seven hours, the spot goes 7-x laterally.
Find the predicted sun angle above the
horizon at 7 PM using tan-¹(). Wait
for 7 PM and see if that's nearly right.
Analysis
Please answer each of the following
in Canvas using complete sentences:
1. How high up (h) is the sun using the
Flat-Earth Model?
2. At what angle above the horizon is
the sun at 10 PM using this model?
3. What is the diagonal distance to the
sun at 10 PM by this model when its
position vector is (10000,h) miles?
4. Did this lab disprove all unpopular
scientific viewpoints? Why or why not?
* I’ve already found my sun’s ray vector in the box which was (4.25, 17.25). *
Answers
On the day of the summer solstice, at noon, Eratosthenes was aware of a deep well on the Nile close to Aswan where the sun shone all the way to the bottom. Because the sun was not overhead in Alexandria, the length of that shadow was not zero.
We believe that the light rays from the sun that reach us are all traveling in the same direction; they are parallel, as the sun is thought to be extremely far away. No shadow would be formed by a vertical stick at point A, a "moderate" shadow by a stick at point B, and a very long shadow by a stick at point C. A radius of the earth leading to point A is shown on the diagram, and another leading to point B. A little geometry reveals that the angle between those two radii and the difference between the shadow angles are the same. In our example, the shadows indicate that during our journey from Florida to Pennsylvania, we had rotated the earth by about 10 degrees.
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If there is 100 ml of liquid mercury in a graduated cylinder that weighs 25 grams. What must be the density of the liquid mercury, if the combined mass of the liquid mercury and the graduated cylinder is 1,385.0 grams?
Answers
The density of 100 ml of liquid mercury in the graduated cylinder that weighs 25 grams is 13.6 g / ml
ρ = m / V
ρ = Density
m = Mass
V = Volume
V = 100 ml
Mass of cylinder = 25 g
Combined mass of cylinder and mercury = 1385 g
Mass of mercury = 1385 - 25 = 1360 g
ρ = 1360 / 100
ρ = 13.6 g / ml
Density is the amount of molecules present in a given volume of the substance. It is denoted by ρ.
Therefore, the density of 100 ml of liquid mercury in the graduated cylinder that weighs 25 grams is 13.6 g / ml
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What is the volume of a rock with a density of 45 g/mL and a mass of 855 grams?
Your answer must have units
Answers
The volume of the rock with a density of 45 g/mL and a mass of 855 grams is 19 ml
We know that,
ρ = m / V
where,
ρ = Density
m = Mass
V = Volume
Given that,
ρ = 45 g / ml
m = 855 g
V = 855 / 45
V = 19 ml
Density is the measure of amount of molecules present in substance. It is denoted by ρ. Its unit is usually g / ml.
Therefore, the volume of the rock with a density of 45 g/mL and a mass of 855 grams is 19 ml
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26. Which of the following is NOT a result of the Earth's precession?
a. the Earth wobbles (like a spinning top) with a period of 26,000 years
b. where the Earth's axis points in the sky changes over the centuries and millennia
c. Polaris will no longer be the North Star in several thousand years
d. the stars twinkle when seen from the surface of planet Earth
e. the signs of the zodiac most astrologers use are no longer in accord with the constellations in which
the Sun is currently found over the course of the year
Answers
The Earth's axis' orientation in space gradually shifts due to the precession.
Precession is the name given to this motion, which is characterized by a cyclic wobble in the direction of the Earth's axis of rotation over a period of 25,772 years. The third motion of the Earth to be discovered, following the much more evident daily rotation and yearly revolution, is precession. The axial tilt of the Earth gradually changes over time as a result of precession. The points on the Earth's orbit where the equinoxes and solstices fall will shift over time. As a result, 13,000 years from now, the location of the summer solstice will change to that of the winter solstice. The Earth's axis changes its direction due to precession. In relation to the stars, the celestial poles steadily shift.
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a sailboat moves faster as the wind pick up this is an example Of?
Answers
It is an example of acceleration due to the wind.
Acceleration: the rate at which the speed and direction of a moving object vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting. Both effects contribute to the acceleration of all other motions.
Acceleration is a vector quantity since it has both a magnitude and a direction. A vector quantity is also velocity. The velocity vector change during a time interval divided by the time interval is the definition of acceleration.
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NEED HELP ASAP PLS
If a basketball player jumps and lands on the ground after 3.2 seconds with a final velocity of −5.5 m/s, what is the player’s initial velocity? Assume (a=−9.8 m/s2) (NOTE: Only 1 point if no work is shown)
Answers
The player’s initial velocity, given the data from the question is 15.68 m/s
How to determine the time to reach the maximum heightWe'll begin by obtaining the time taken for the player to reach the maximum height. This can be obtannnned as follow:
Time for the entire trip (T) = 3.2 sTime to reach maximum height (t) = ?T = 2t
3.2 = 2t
Divide both sides by 2
t = 3.2 / 2
t = 1.6 s
How to determine the initial velocity of the playerTime to reach maximum height (t) = 1.6 sAcceleration due to gravity (g) = -9.8 m/s²Final velocity (v) = 0 (at maximum height)Initial velocity (u) = ?v = u + gt
0 = u + (-9.8 × 1.6)
0 = u - 15.68
Collect like terms
u = 0 + 15.68
u = 15.68 m/s
Thus, the initial velocity of the player is 15.68 m/s
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Pleaseee help me with this question?!!!!!!!!!!
In a road with speed limit of 30 miles per hour, how much time (in minutes) will you gain by driving at an average speed of 5 miles per hour over the speed limit if it would take 30 minutes to reach your destination driving at the posted speed limit?
Answers
You will gain 150 minutes by driving at an average speed of 5 miles per hour
What is speed?Speed is the distance travelled per unit. Mathematically, it can be expressed as:
Speed = distance / time
How to determine the distance travelledWe'll begin by calculating the distance travelled. This can be obtained as follow:
Speed = 30 miles per hourTime = 30 minutes = 30 / 60 = 0.5 hourDistance =?Speed = Distance / time
Cross multiply
Distance = speed × time
Distance = 30 × 0.5
Distance = 15 miles
How to determine the time taken to travel at 5 miles per hourSpeed = 5 miles per hourDistance = 15 milesTime = ?Speed = distance / time
5 = 15 / time
Cross multiply
5 × time = 15
Divide both side by 5
Time = 15 / 5
Time = 3 hours
How to determine the time gainedTime for 30 miles per hour = 30 minutesTime for 5 miles per hour = 3 hours = 3 × 60 = 180 minutesTime gained =?Time gained = 180 - 30
Time gained = 150 minutes
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Suppose the elevator starts from rest and maintains a constant upward acceleration of 2.90 m/s2 . A bolt in the elevator ceiling 3.00 m above the elevator floor works loose and falls. It falls out the instant the elevator begins to move. a.)How long does it take for the bolt to reach the floor of the elevator? b.)Just as it reaches the floor, how fast is the bolt moving according to an observer in the elevator? c.)Just as it reaches the floor, how fast is the bolt moving according to an observer standing on the floor landings of the building? d.)According to an observer in the elevator, how far has the bolt traveled between the ceiling and floor of the elevator? e.)According to an observer standing on the floor landings of the building, how far has the bolt traveled between the ceiling and floor of the elevator?
Answers
The correct answer is 2.26 m.
Initial velocity of elevator u =0
Constant upward acceleration of the elevator a= 2.90 m/s²
Height of the bolt from the floor of the elevator h=3.00 m
Initial velocity of the bolt in the elevator u = 0 m/s
Elevator is moves upward with a constant acceleration 2.90 m/s²
so the net acceleration a' = (a+g) m/s²
=( 2.90 + 9.8) m/s²
a' = 12.7 m/s²
Initial velocity of the bolt u = 0 m/s
Distance traveled by the bolt h = 3.00 m
Substitute these values in the equation
h=ut+ 1/2 ( a )t², we get
3.00 = (0)x+1/2 (12.7)(t^2)
3.00 = 6.35 t²
t²= 3.00/6.35
t = 0.68 s
i.e., after 0.68 s the bolt reaches the floor of the elevator.
(b)For the observer in the elevator acceleration
a'=(a+g) m/s²
=( 2.90 + 9.8) m/s²
a'= 12.7 m/s²
Time taken bolt to reach the floor of the elevator t = 0.68 s From the equation v=u+a't we get
v=(0)+(12.7) (0.68)
v = 8.636 m/s
Velocity of the bolt when it reaches the floor of the elevator according to an observer into elevator 8.636 m/s
ii) An observer standing on the floor landings of the buildings: for observer standing on the floor landing, the acceleration of the
bolt
appears a = g m/s²
= 9.8m/s²
Time taken the bolt to reach the floor t = 0.68 s
Initial velocity of the bolt u = 0 m/s
Substitute these values in the equation
v=u+at we get
v=0+(9.8) (0.68 s)
v= 8.636 m/s
Velocity of the bolt when it reaches the floor of the elevator according to
an observer standing on the floor landing = 8.636 m/s
c) i) According to an observer in the elevator in this situation acceleration a= 12.7 m/s²
time t= 0.68 s initial velocity u = 0
substitute these values in the equation 1
s = ut +1/2 at²
We get
s =(0) (0.659)+1/2(12.7 ) (0.68)²
= 2.93 m
Distance traveled by the bolt according to the observer on the elevator 2.93 m
iii)According to an observer standing on the floor landing in this situation
acceleration a=g m/s²
= 9.8m/s²
Time t= 0.68 s
Initial velocity u = 0 m/s Substitute these values in the equation
1 ut + 1/2 at ²,
s=ut+1/2at²
we get
s=(0)+1/2(9.8) (0.68)²
= 2.26 m
Distance traveled by the bolt according to the observer standing on the floor landing 2.26 m.
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An atom of a _____________________ has two electrons in its outer level and will lose these when it combines with another atom.
a. alkali metal
b. noble gas
c. alkaline earth metal
d. halogen
Answers
Answer:
A alkali metals hope this helps
Answer: c. alkaline earth metal
Explanation: group II elements in the periodic table are generally found as 2+ ions. This is because they have lost two electrons to ionic bonding.
An object’s weight is equal to the force of gravity on it. The Moon has a gravity of 1/6 that of earth’s, while Jupiter has a gravity of 2.64 times that of the earth how much more would a 5.00 kg turtle weigh on Jupiter than the moon?
Answers
Answer:
See below
Explanation:
On Earth , turtle weight = 5 * 9.81 =49 N
Moon = 490.5 * 1/6 = 8.18 N
Jupiter 490.5 * 2.64 = 129.4 N
129.4 - 8.18 N = 121.2 N more on Jupiter than moon
How much work is done to lift a 5.36kg box off the ground 2.2m?
Answers
Answer:
Explanation:
Given:
m = 5.36 kg
h = 2.2 m
___________
A -?
Work:
A =m·g·h
A = 5.36·9.8·2.2 ≈ 116 J
A horizontal net force F is exerted on an object at rest. The object starts at x = 0 m and has a speed of 4.0 m/s after moving 4.0 m along a horizontal frictionless surface. The net force F as a function of the object's position x is shown below.
What is the mass of the object?
Answer: 15 kg
THIS IS THE QUESTION AND THE ANSWER! SEE ATTACHED.
Answers
A horizontal net force F is exerted on an object at rest and with a speed of 4.0 m/s. The object will be 5 kg in weight.
What is Force?An influence with the capacity to change the motion of an object is called a force. A force acting on an object with mass can cause it to accelerate or modify its velocity. Pushing or pulling is a simple way to explain the force.
According to the question, the given values are :
Initial Velocity, u = 0 at x = 0
Final Velocity, v = 4 m/s at x = 4 m
Work done=Area on graph
1/2 m(v²-u²) = 1/2 × base × height
m (4²-0²) = 4 × 20
m = 5 kg
Hence, the mass of the object will be 5 kg.
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A football is punted to its maximum height. As soon as it starts to fall to the ground it starts to gain kinetic energy. What happens to the potential energy of the football as it starts to gain kinetic energy?
Answers
From conservation of energy, the potential energy will begin to reduce as soon as it starts to fall to the ground to gain kinetic energy.
What is Conservation of Energy ?Conservation of energy state that energy can not be created nor destroyed but can only be transformed from one form to another.
Given that a football is punted to its maximum height. At this maximum height, the kinetic energy is zero while the potential energy is maximum.
As soon as it starts to fall to the ground it starts to gain kinetic energy. And what will happen to the potential energy of the football as it starts to gain kinetic energy is the reduction of the potential energy.
Therefore, the potential energy will begin to reduce as soon as it starts to fall to the ground to gain kinetic energy.
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What Happens When Two Objects Are Charged By Rubbing Or Peeling?
a. One object has only one type of charge. The other object has only the other type of charge.
b. Both objects have the same type of charge.
c. Both objects have both types of charge, but there are different amounts of each type on each object. (One object has more negative charges than positive and the other object has more positive charges than negative charges.)
Answers
When Two Objects Are Charged By Rubbing Or Peeling, both objects have both types of charge, but there are different amounts of each type on each object. (One object has more negative charges than positive chrages and the other object has more positive charges than negative charges); option C.
What happens when two objects are charged by rubbing or peeling?Charges are the inherent properties of the particles of matter which determines how the atoms will react when placed in an electric filed.
There are two types of charges in an atom:
positive charges which are present on the protonsnegative charges that which are present on the electrosThe electrons in an atom can be easily transferred from one atom to another, hence objects can be charged by rubbing or peeling one against the other.
When when two objects are rubbed or peeled against each other, electrons move from one object to the other.
The object that acquires the electrons become negatively charged whereas the object that loses the electrons become positively charged. However, both objects have both electrons and protons present in them.
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A car is stopped for a traffic signal. When the light turns green,
the car accelerates, increasing its speed from 0 to 5.20 m/s in
0.832 s. What are the magnitudes of (a) the linear impulse and
(b) the average total force experienced by a 70.0-kg passenger
in the car during the time the car accelerates?
Answers
The impulse of the car is 365kgm/s and average force experienced is 437.5N.
acceleration is defined as the change in velocity per unit time.
average force is defined as the force experienced by a body while the acceleration is constant.
given:
initial velocity (u)=0m/s
final velocity(v)=5.20m/s
time(t)=0.832s
mass (m)=70 kg
a)
first we will find acceleration
a=5.2/0.832
=6.25m/s²
now average force experienced (F)= mass*acceleration
F=70×6.25F
=437.5N
now impulse (I) is given by F×t=437.5×0832I
=365kg×m/s
therefore the impulse is 365kg×m/s
b)
Now we will find the average force applied.
Average force experienced is 437.5N
therefore,
The impulse of the car is 365kgm/s and average force experienced is 437.5N.
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The hammer is the closest of the three bones in the middle ear to the cochlea true or false
Answers
False. The hammer is not the closest of the three bones in the middle ear to the cochlea.
The three bones in the middle ear are Malleus, Incus and Stapes. Malleus is commonly known as Hammer, Incus as anvil and stapes as stirrup. Hammer is attached to the ear drum, Anvil is the chain of the bones and Stirrup is attached to the oval window.
Cochlea is a hollow, spiral shaped bone present in the inner ear. So the order of bones from outside to cochlea is Hammer first, followed by Anvil in the middle and Stirrup near the inner ear where cochlea is present.
Therefore, the hammer is not the closest of the three bones in the middle ear to the cochlea
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ighth grade F.1 Identify reactants and products MGX
This passage describes a chemical reaction. Read the passage. Then, answer the question
below.
The cheesemaking process sometimes includes a step called lactic acid fermentation.
This step occurs when a certain type of bacteria is added to milk. The bacteria form
lactic acid (C3H603) by combining water (H₂O) and lactose (C12H22011) in the milk.
When lactic acid forms, the milk's proteins clump into curds that can later be used to
make many types of cheese.
In the chemical reaction described in the passage, which of the following are reactants?
Select all that apply.
water (H₂O)
lactose (C12H22011)
Submit
lactic acid (C3H603)
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HR
Q
ar
Cha
Stage
Get 5
in a
Answers
What subatomic particle is responsible for the observed properties of an atom?
Answers
Electrons are responsible for the properties of atoms.
What is an atom?The atom is the smallest particle of a substance that can take part in chemical reaction. We know that an atom is composed of smaller particles that are called subatomic particles. The basic subatomic particles are; electrons proton and neutrons.
The protons and the neutrons are bond up in the nucleus and do not contribute to the properties of the atom. The properties of the atom are due to loss or gain of electrons.
Thus electrons are responsible for the properties of atoms.
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If a bat hits a ball with 85 N of force, how much force does the ball exert on the bat?
Answers
If a bat hits a ball with 85 N of force the bat will also exert the same force
85N.
You are probably already aware of the force the ball applies to the wall when it is thrown against it. Similar to how the wall exerts a force on the ball, the ball bounces off the wall. Similar to how the earth drags you down with gravity. You might not be aware of it, but you are also pushing the planet with the same amount of power. The third law of Newton is a result of this amazing event.
Newton's Third Law states that if object A exerts a force on object B, then object B must apply a force on object A that is equal in magnitude and directed in the opposite direction.
An object interacts with another object when a push or pull is applied to it. A product of interaction is force. Frictional force, for example, falls into the category of contact force. Non-contact force, on the other hand, includes gravitational force. Newton's third rule of motion explains that when two bodies contact, they exert force on one another. This force is referred to as an action and reaction pair.
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A baseball player throws a ball horizontally.
Which statement best describes the ball's
motion after it is thrown? [Neglect the effect of
friction.]
Answers
The vertical speed of the ball increases and its horizontal speed remains constant as usual because air friction is being neglected.
By definition, air resistance refers to the forces that work against an object's relative motion as it travels through the atmosphere. These drag forces cause the object to move more slowly by acting in opposition to the speed of the incoming flow. Since drag is the part of the net aerodynamic force operating in the opposite direction to the direction of the movement, it differs from other resistance forces in that it directly depends on velocity.
Fluid friction includes friction in the air. These friction forces differ from the conventional model of surface friction in that they rely on velocity. Only rare examples can be dealt with analytically since the velocity dependence may be extremely intricate. Air resistance is roughly proportional to velocity and can be represented in the form of very low speeds for microscopic particles.
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1. A radiographic technique calls for a 2000 ms (time) exposure, What is
this time in s?
Answers
Answer:
2 s
Explanation:
2000 ms / 1000 ms/s = 2 s
Ignore air drag. Drop two balls, one big and one small. The big ball drops ___ the small ball.
A- the same speed as
B- slower than
C- faster than
D- sooner than
Answers
Direction of the vector A
Answers
The direction of vector A which is parallel but opposite to the vector I is is 305°
Direction of vector I = 125°
Vector I makes a parallel line with vector A. Consider vector A and I to be collinear. Collinear lines makes up an angle of 180°
[tex]Angle_{A}[/tex] + [tex]Angle_{I}[/tex] = 180°
[tex]Angle_{A}[/tex] + 125° = 180°
[tex]Angle_{A}[/tex] = 55°
Direction of vector A = 360° - 55° = 305°
The direction of a vector is the angle, the vector creates with positive x-axis in counter clockwise direction.
Therefore, the direction of vector A is 305°
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